PHYS-1150(9)(Kaldon-40203)
WMU - Fall 2014
Quiz 6 - 30,000 points
Name ________________________________
Section:
Rev. 10/06/14
9a
9b
9c
9d
9e
28f
A to D
E to M
N to S
T to Z
Q to S
T to Z
1150
2 and 3, and 4 and 5 in SERIES
1 and 23 are in PARALLEL
R23  R2  R3  263  363  626.0
1
1
1
1
1
 


R123 R1 R23 163 626.0
R45  R4  R5  463  563  1026
R123  129.3
Show all work/Circle your final answer:
6.) Reduce this resistor network to a single resistor. Then use this
information, along with the rules about how current (I) and voltage
difference (V) are split or shared for series and parallel resistors, as
well as the dissipated power (P) to completely fill in the table. All five
resistors are different.
Attach all work to this sheet – don’t worry if it’s not pretty.
123 and 45 are in SERIES
V
6
9
10
5
163 
0.002957 A
263 
12
0.002300 W
0.002957 A
363 
13
0.003174 W
0.014325 A
463 
14
0.095034 W
563 
15
0.115531 W
3
6.632 V
R4
0.011368 A
P
11
0.021065 W
8
1.0734 V
R3
R
8
0.7777 V
R2
I
7
1.853 V
R1
4
R5
=
3
8.065 V
0.014325 A
2
Req
16.55 V
R12345  R123  R45
 129.3  1026
 1155.3
1155.3 
0.2371 W
I  I 45  I 4  I 5
V45  V4  V5  6.632V  8.065V
 14.697V
V  V123  V45
V123  V  V45  16.55V  14.697V
 1.853V  V1
0.2371 W
1
0.014325 A
P=IV
<<< Check!
I  I1  I 23
I 23  I  I1  0.014325 A  0.011368 A
 0.002957 A  I 2  I 3
NOTE: While I usually find that keeping an extra digit around is
useful, 3+1 sig. figs. for example, filling in the table is one
of those cases where even 1 extra sig. fig. in the intermediate
calculations isn’t always quite enough to get the fractions to
come out right. Here’s the data in the table run through a
Excel spreadsheet:
1
2
3
4
5
Total
volts
V
1.852259
0.778935
1.075108
6.632606
8.065135
16.55
amps
I
0.011364
0.002962
0.002962
0.014325
0.014325
0.014325
ohms
R
163
263
363
463
563
1155.3
Watts
P
0.021048
0.002307
0.003184
0.095014
0.115535
0.237083
0.237089
BLACK = given values, RED = calculated values, BLUE = copied values
Now we get pretty good agreement between the Power
of the Equivalent Resistance and the Sum of the Resistors!
Yet the individuals values are not that different,
though even here, V2 + V3 isn’t quite the same as V1 .