Vin

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EE 330
Lecture 33
• Cascaded Amplifiers
• High-Gain Amplifiers
• Current Source Biasing
Review from Last Time
Can use these equations only when small signal circuit is EXACTLY like that shown !!
Review from Last Time
Basic Amplifier Structures
1. Common Emitter/Common Source
2. Common Collector/Common Drain
3. Common Base/Common Gate
4. Common Emitter with RE/ Common Source with RS
5. Cascode (actually CE:CB or CS:CD cascade)
6. Darlington (special CE:CE or CS:CS cascade)
The first 4 are most popular
Review from Last Time
Basic Amplifier Characteristics Summary
VDD
RC
Vout
CE/CS
C
B
Vin
E
•
•
•
•
Large noninverting gain
Low input impedance
Moderate (or high) output impedance
Used more as current amplifier or, in conjunction with CD/CS to form
two-stage cascode
VEE
VDD
•
•
•
•
C
B
CC/CD
Vin
Vout
E
RE
VSS
VDD
RC
Vout
C
CB/CG
B
VBB
E
Vin
VDD
RC
CEwRE/
CSwRS
Vout
C
B
Vin
E
RE
VEE
Gain very close to +1 (little less)
High input impedance for BJT (high for MOS)
Low output impedance
Widely used as a buffer
•
•
•
•
Large noninverting gain
Low input impedance
Moderate (or high) output impedance
Used more as current amplifier or, in conjunction with CD/CS to form
two-stage cascode
•
•
•
•
Reasonably accurate but somewhat small gain (resistor ratio)
High input impedance
Moderate output impedance
Used when more accurate gain is required
Cascaded Amplifier Analysis and Operation
Adjacent Stage Coupling Only
•
Systematic Methods of Analysis/Design will be Developed
One or more couplings of nonadjacent stages
•
•
Less Common
Analysis Generally Much More Involved, Use Basic Circuit Analysis Methods
Cascaded Amplifier Analysis and Operation
Adjacent Stage Coupling Only
•
Systematic Methods of Analysis/Design will be Developed
Case 1: All stages Unilateral
Case 2: One or more stages are not unilateral
Repeat from earlier discussions on amplifiers
Cascaded Amplifier Analysis and Operation
Case 1: All stages Unilateral
RS
Vin
Vout
V1
RiX1
A v01V1
RoX1
V2
RL1
V3
RiX2
A v02V3
RoX2
V4
RL




Vout  RiX1 
RL1//RiX2
RL
AV 

 A V01 
 A V02 

Vin  RiX1+RS 
R
//R
+R
R
+R
 L1 iX2 0X1 
 L 0X2 
Accounts for all loading between stages !
Cascaded Amplifier Analysis and Operation
Case 2: One or more stages are not unilateral
 Standard two-port cascade
RS
V11
Rin1
Two-Port Model 1
Ro1
V12
Rin2
A v0V1 Model 2
Two-Port
Ro2
V21
Vin
A v01V11
A v0r1V21
V13
Two-Port Model 3
Rin3
Ro3
V23
V OUT
V22
A v0r2V22
A v02V12
RL
A v03V13
A v0r3V23
Analysis by creating new two-port of entire amplifier quite tedious because of the reverse-gain elements
 Right-to-left nested Rinx,AvX approach
RS
Vin
V1
V1
RinX-AVoX Model
Rin1X
V2
Av1XV1
•
•
•
•
RinX-AV Model
Rin2X
V3
Av2XV2
RinX-AV Model
Rin3X
Vout
Av3XV3
Rinx includes effects of all loading
AVX is the voltage ratio from input to output of a stage
AVX’s include all loading
Can not change any loading without recalculating everthing!
RL=∞
Example:
Determine the voltage gain of the following circuit in terms of the smallsignal parameters of the transistors. Assume Q1 and Q2 are operating in
the Forward Active region and C1…C4 are large.
VDD
R1
R5
R3
VOUT
C1
C3
Q1
RS
R6
C4
Q1
R8
R2
R4
C2
VIN
R7
VEE
In this form, does not look “EXACTLY” like any of the basic amplifiers !
Example:
VDD
R1
R5
R3
VOUT
C1
C3
Q1
RS
R6
C4
Q1
R8
R2
R4
C2
VIN
R7
VEE
VA
RS
Vin
VB
Q1
Vout
Q2
R6//R8
R1//R2
R3//R5
R7
Will calculate AV by determining the three ratios (not voltage gains of dependent source):
AV =
Vout Vout VB VA

 A V2 A V1A V0
Vin
VB VA Vin
Example:
RS
Vin
VB
VA
Q1
Vout
Q2
R6//R8
R1//R2
R3//R5
R7
CE with RE
Rin2
A V2 =
Vout
VB
Rin2

R6 //R8
R7
βR7
Example:
Vout
Q2
R6//R8
R7
One-Port
Rin2
Rin2
βR7
Rin2
Example:
RS
VA
VB
Q1
R1//R2
Vin
Vout
Q2
Rin2
R3//R5
R6//R8
R7
CE with RE
Rin2
Vout
A V2 =
VB
Rin2
R6 //R8

R7
βR7
Example:
VB
VA
RS
Q1
R1//R2
Vin
R3//R5
Rin2
RS
Vin
V
A V1= B
VA
Rin1
gm1 R3 //R5 //Rin2 
r 1
VA
VB
Q1
R1//R2
R3//R5//Rin2
CE Config
Rin1
Example:
VB
Q1
Rin1
R3//R5//Rin2
Rin1
Example:
RS
Vin
A V0 =
VA
Vin
R1//R2
R1//R2 // Rin1
RS  R1//R2 // Rin1
VA
VB
Q1
Rin1
R3//R5//Rin2
Example:
RS
VA
Vout
VB
Q2
Q1
R6//R8
R1//R2
Vin
R3//R5
R7
VEE
Thus we have
V
V V V
A V = out  out B A
Vin
VB VA Vin
where
Vout
R //R
 6 8
VB
R7
VB
VA
gm1 R3 //R5 //Rin2 
VA
Vin
R1//R2 // Rin1
RS  R1//R2 // Rin1
Rin2
βR7
Rin1
r 1
Example:
VB
VA
RS
Vout
Q2
Q1
R6//R8
R1//R2
Vin
R3//R5
R7
VEE
Observation: By working from the output back to the input we were able to
create a sequence of steps where the circuit at each step looked EXACTLY
like one of the four basic amplifiers even though stages were not unilateral.
Engineers often follow a design approach that uses a cascade of the basic
amplifiers and that is why it is often possible to follow this approach to analysis.
Will formalize what we have done (consider 3-stage unilateral cascade)
Exactly same approach when not unilateral
iB
iB
Stage 1
iB
Stage 2
Stage 3
VOUT
RB1
Vin
VBE
gπ
gmVBE
g0
RB2
VBE
gπ
gmVBE
g0
RB3
VBE
gπ
gmVBE
g0
RL
Formalization of cascade circuit analysis working
from load to input: (consider 3-stage unilateral cascade)
V1
iB
iB
V2
Stage 1
V3
Stage 2
iB
Stage 3
VOUT
RB1
Vin
VBE
gmVBE
gπ
g0
RB2
VBE
gmVBE
gπ
g0
VBE
RB3
gmVBE
gπ
g0
RL
VOUT V1 V2 V3 VOUT

VIN
VIN V1 V2 V3
V1
iB
V2
Stage 1
iB
V3
Stage 2
iB
Stage 3
VOUT
RB1
Vin
VBE
gπ
gmVBE
g0
RB2
VBE
gπ
gmVBE
g0
RB3
VBE
gπ
gmVBE
g0
RL
Formalization of cascade circuit analysis working
from load to input: (consider 3-stage unilateral cascade)
V1
iB
V2
Stage 1
iB
V3
Stage 2
iB
Stage 3
VOUT
RB1
Vin
VBE
gmVBE
gπ
g0
RB2
VBE
gmVBE
gπ
g0
RB3
VBE
gπ
gmVBE
g0
RL
Starting at output stage obtain:
V3
iB
VBE
VOUT
Stage 3
gπ
gmVBE
g0
RL
VOUT
V1 V2 V3 VOUT

VIN
VIN V1 V2 V3
Formalization of cascade circuit analysis working
from load to input: (consider 3-stage unilateral cascade)
V1
iB
iB
V2
Stage 1
V3
Stage 2
iB
Stage 3
VOUT
RB1
Vin
VBE
gmVBE
gπ
g0
VBE
RB2
gmVBE
gπ
g0
RB3
VBE
gπ
gmVBE
g0
RL
Replace Stage 3 with RIN3
V1
iB
V2
Stage 1
iB
V3
Stage 2
Stage 3
RB1
Vin
VBE
gmVBE
gπ
g0
RB2
VBE
gπ
gmVBE
g0
RB3
RIN3
Analyze Stage 2:
V2
iB
VBE
V3
Stage 2
gπ
gmVBE
g0
RB3
RIN3
VOUT V1 V2 V3 VOUT

VIN
VIN V1 V2 V3
Formalization of cascade circuit analysis working
from load to input: (consider 3-stage unilateral cascade)
V1
iB
V2
Stage 1
iB
V3
Stage 2
iB
Stage 3
VOUT
RB1
Vin
VBE
gmVBE
gπ
g0
RB2
VBE
gmVBE
gπ
g0
RB3
VBE
gπ
gmVBE
g0
RL
Replace Stage 2 with RIN2
V1
iB
V2
Stage 1
RB1
Vin
VBE
gmVBE
gπ
g0
RB2
RIN2
Analyze Stage 1:
V1
iB
VBE
V2
Stage 1
gπ
gmVBE
g0
RB2
RIN2
VOUT
V V V V
 1 2 3 OUT
VIN
VIN V1 V2 V3
Formalization of cascade circuit analysis working
from load to input: (consider 3-stage unilateral cascade)
V1
iB
V2
Stage 1
iB
V3
Stage 2
iB
Stage 3
VOUT
RB1
Vin
VBE
gπ
gmVBE
g0
RB2
VBE
gmVBE
gπ
Replace Stage 1 with RIN1
V1
RB1
Vin
RIN1
Analyze Stage 0:
V V V V
VOUT
 1 2 3 OUT
VIN
VIN V1 V2 V3
g0
RB3
VBE
gπ
gmVBE
g0
RL
Formalization of cascade circuit analysis working
(when stages are not unilateral)
from load to input:
RS
Vin
V1
V1
RinX-AVoX Model
Rin1X
V2
Av1XV1
RinX-AV Model
Rin2X
V3
Av2XV2
RinX-AV Model
Rin3X
Vout
Av3XV3
RL=∞
Rinx includes effects of all loading
AVX includes all loading (not typical dependent voltage source since dependent upon other circuit elements)
Can not change any loading
Analysis systematic and rather simple
VOUT V1 V2 V3 VOUT V1


A V1X A V2X A V3X
VIN VIN V1 V2 V3 VIN
This was the approach used in analyzing the previous cascaded amplifier
Example:
RS
Vin
VA
Vout
VB
Q2
Q1
R6//R8
R1//R2
R3//R5
R7
VEE
Observation: By working from the output back to the input we were able to
create a sequence of steps where the circuit at each step looked EXACTLY
like one of the four basic amplifiers. Engineers often follow a design approach
that uses a cascade of the basic amplifiers and that is why it is often possible
to follow this approach to analysis.
Two other methods could have been used to analyze this circuit
What are they?
Example:
RS
Vin
VA
Vout
VB
Q2
Q1
R6//R8
R1//R2
R3//R5
R7
VEE
Two other methods could have been used to analyze this circuit
1. Create a two-port model of the two stages
(for this example, since the first-stage is unilateral, it can be shown that )
 RiX1 




V
RL1//RiX2
RL
A V  out  
 A V01 
 A V02 

Vin  RiX1+RS 
 RL1//RiX2 +R0X1 
 RL +R0X2 
AV01 and AV02 are open-loop two-port gain and are different than what used above
1. Small signal model could have been put in for Q1 and Q2
Example:
RS
Vin
VA
Vout
VB
Q2
Q1
R6//R8
R1//R2
R3//R5
R7
VEE
Two other methods could have been used to analyze this circuit
2. Put in small-signal model for Q1 and Q2 and solve resultant
circuit
(not too difficult for this specific example )
1. Small signal model could have been put in for Q1 and Q2
Example:
AV =
Vout
?
Vin
Express in terms of small-signal parameters
VDD
M2
RC
RB1
Q3
RB2
I1
-VSS
Vout
C
M4 2
C1
M1
Vin
RD
RL
Example:
VDD
M2
RC
V1
RB1
Q3
C1
V2
M1
Vin
RD
Vout
C
M4 2
RL
RB2
I1
-VSS
Note: Even though the second stage has a resistor in the collector, the
gain expressions developed for the common collector amplifier still apply
V V V
A V = out 2 1
V2 V1 Vin


-g
m1

-gm4 RD //RL   1 
1
 gm2 +  β3 RB1//RB2   


High-gain BJT amplifier
-gm
AV 
g0  GC
VDD
RC
Vout
C
B
Vin
E
VEE
-gmRC
To make the gain large, it appears that all one needs
to do is make RC large !
AV
-ICQRC
-gmRC 
Vt
But Vt is fixed at approx 25mV and for good signal
swing, ICQRC<(VDD-VEE)/2
VDD  VEE
AV 
2Vt
If VDD-VEE=5V,
5V
AV 
 100
2  25mV
Gain is practically limited with this supply voltage to around 100
High-gain MOS amplifier
-gm
AV 
g0  GD
VDD
To make the gain large, it appears that all one needs
to do is make RD large !
RD
Vout
G
Vin
D
S
VSS
-gmRD
AV
-2IDQRD
-gmRD 
VEB
But VEB is practically limited to around 100mV and
for good signal swing, IDQRD<(VDD-VSS)/2
VDD  VSS
AV 
VEB
If VDD -VSS=5V and VEB=100mV,
5V
AV 
 50
100mV
Gain is practically limited with this supply voltage to around 100
Are these fundamental limits on the gain of the BJT and MOS Amplifiers?
High-gain amplifier
VDD
iB
VOUT
IB
VOUT
VIN
VIN
VIN
VBE
VOU
gπ
gmVBE
Q1
Q1
-gm
AV 
 
0
VEE
This gain is very large !
Too good to be true !
Need better model of MOS device!
High-gain amplifier
VDD
VOUT
iB
VOUT
IB
VOUT
VIN
VIN
Q1
VIN
Q1
VEE
This gain is very large (but realistic) !
But how can we make a current source?
VBE
gπ
gmVBE
g0
-gm
AV 
g0
AV 
-ICQ
V
 - AF
VtICQ /VAF
Vt
V
A V  - AF
Vt
200V
 8000
25mV
High-gain amplifier
VDD
AV
8000
IB
VOUT
VIN
Q1
VEE
How can we build the ideal current source?
What is the small-signal model of an actual current source?
End of Lecture 33
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