Chapter 4 Basic Nodal and Mesh Analysis 4.1 Nodal Analysis 4.2 The Supernode 4.3 Mesh Analysis 4.4 The Supermesh 4.5 Nodal vs. Mesh Analysis: A Comparison 4.6 Computer-aided Circuit Analysis 회로이론-І 2013년2학기 이문석 1 4.1 Nodal Analysis - Method • • • • We select one node in the circuit to be a reference node. Node voltage = The voltage of each of the nonreference nodes with respect to the reference node. Use Node voltages as unknown variables to set up Independent KCL equations (node equations). Find node voltages. We can find all branch voltages and currents if we know node voltages 3.1 2 → 3.1 5 2 1.4 → 1.4 1 1 5 , 0 5 5 0 5 2 3 Nodal analysis is based on KCL 회로이론-І 2013년2학기 이문석 2 4.1 Nodal Analysis Example 4.1 Determine the current through 15 resistor Node 1: 2 →5 Node 2: 4 2 → 20 , 60 4 60 0 20 Example 4.2 Determine the nodal voltages as referenced to the bottom node Node 1: → 8 3 0.5833 0.3333 11 Node 2: → 3 0.3333 1.4762 0.1429 Node 3: → 25 0.25 5,412 , 회로이론-І 2013년2학기 이문석 0.1429 0.5929 7.736 , 3 25 46.32 3 4.1 Nodal Analysis Example 4.3 Determine the power supplied by the dependent source Node 1: 15 → 3 2 30 2 Node 2: 3 → 3 40 75 20 → 3 3 4500 20 15 8 0 75 Example 4.4 Determine the power supplied by the dependent source Node 1: 15 → 3 Node x : 3 → 5 50 7 30 7 회로이론-І 2013년2학기 이문석 2 30 3 0 3 55.1 4 4.2 The Supernode To solve the circuit (a) on the left side, a branch current between v2 and v3 should be assigned. Four equations and four unknowns - Supernode • • • A closed region which encloses each voltage source KCL is available to the supernode All current flowing into the region sum to zero Example 4.5 Determine the node voltage v1 Node 1 : 8 3 → 0.5833 0.3333 11 Supernode 2-3 : 3 → 0.5833 25 1.3333 0.45 22 회로이론-І 2013년2학기 이문석 28 1.071 5 4.2 The Supernode Example 4.6 Determine the node-to-reference voltages 12 Node 2 : 14 → 2 → 2.5 . 2.5 0.5 0.5 Supernode 3-4 : 0.5 → 0.1 → 0.5 14 10 0.5 1.4 1.4 1.2 1.2 2.4 . 0 0.2 0.2 → 0.2 ∴ 회로이론-І 2013년2학기 이문석 1.2 12 , 0.2 0 → 4 , 0 , 2 6 4.3 Mesh Analysis • Loop and mesh • • • • • • Loop : Any closed path in the circuit Mesh : A loop that does not contain any other loops within it Mesh Current = The current that flows only around the perimeter of the mesh. (Independent loop current) Use Mesh Current as unknown variables to set up Independent KVL equations (mesh equations) We can find all branch voltages and currents if we know mesh currents. We restrict attention only to planar circuits (No branch passes over or under any other branch) Non-planar circuit 회로이론-І 2013년2학기 이문석 7 4.3 Mesh Analysis Loop and Mesh No path, no loop Loop, No mesh 회로이론-І 2013년2학기 이문석 No path, no loop Loop, No mesh Loop and Mesh Loop and Mesh 8 4.3 Mesh Analysis Loop 1: 42 6 3 Loop 2: 3 0 → 9 4 6 , Loop 1: 0 → 3 6 3 0 → 9 3 Loop 2: 10 4 3 0 → 3 7 3 Loop 2: 10 4 6 , 42 10 4 , 6 3 42 10 2 42 Loop 1: 42 7 4 , 6 , 회로이론-І 2013년2학기 이문석 10 3 0 → 9 0 → 3 4 , 2 3 42 7 10 2 9 4.3 Mesh Analysis Example 4.7 Determine the power supplied by the 2 V source Loop 1: Loop 2: 2 5 4 2 2 2 5 1 43 , 38 2 , 19 0 → 6 2 0 → 2 7 2 47 38 2 7 3 2.474 Example 4.8 Determine the three mesh currents Loop 1 : 7 → 3 Loop 2 : 1 → 1 2 6 Loop 3 : 2 → 2 2 3 6 3 3 , 회로이론-І 2013년2학기 이문석 6 1 2 0 3 0 0 3 6 2 , 0 6 3 10 4.3 Mesh Analysis Example 4.9 Determine the current i1 Loop 1 : 5 4 4 → 8 8 5 Loop 2 : 2 → 6 3 4 4 4 0 0 3 , Example 4.10 Determine the current i1 Loop 1: 5 2 4 5 2 4 5 →4 Loop 2 : 2 → 6 3 4 4 4 4 0 4 0 0 3 5 4 회로이론-І 2013년2학기 이문석 11 4.4 Supermesh • • Circuits with current sources The current sources reduce the # of simultaneous mesh equations Example 4.11 Using conventional method Loop 1: 7 Loop 2: 2 → 1 0 → 3 1 6 Loop 3: 7 0 3 0 3 0 → 3 2 , 7 9 , 4 15 , 6 0 0.5 Using supermesh Loop 1: 7 → Loop 2: 1 → 7 1 4 4 2 6 3 7 1 3 0 3 0 0 2 , 9 , 15 6 3 equations and 3 unknowns 회로이론-І 2013년2학기 이문석 12 4.4 Supermesh Example 4.12 Evaluate the three unknown currents 3 15 15 9 1 3 1 3 → → 6 11 , 회로이론-І 2013년2학기 이문석 1 3 2 1 3 3 9 2 3 3 0 → 6 15 0 3 15 17 13 4.5 Nodal vs. Mesh analysis: A Comparison - In choosing nodal or mesh analysis, • • • • • • Non-planar circuit Nodal analysis N nodes N-1 KCL equations (Each supernode reduce the # of equations by 1) M meshes M KVL equations (Each supermesh reduce this number by 1) Controlling quantity in dependent sources : nodal voltage nodal analysis mesh current mesh analysis Location of source : current source in mesh line mesh analysis voltage source connected to ref. nodal analysis Asking current mesh analysis, asking voltage nodal analysis Find ix Node 1: → 0.875 Node 2: → 회로이론-І 2013년2학기 이문석 20.31 12.5 8 0.5 Node 3: 8 → 0.1 25.89 , 0.5 0.933 0.1 0.3 8 2 8 2.79 14 4.5 Nodal vs. Mesh analysis: A Comparison Loop 1: 100 → 12 Loop 2: 2 → 8 4 4 100 3 4 4 9 Loop 3: 3 → 0 3 3 10 18 0 0 8 80 5 0 2.79 회로이론-І 2013년2학기 이문석 15 4.6 Computer-aided Circuit Analysis - To analyze a complex circuit, a computer software package is useful SPICE (Simulation Program with Integrated Circuit Emphasis) Pspice : SPICE with intuitive graphical interface by MicroSim Corp. Loop 1: 42 6 Loop 2: 3 3 0 → 9 4 6 , 10 3 0 → 3 4 , 42 7 10 2 Hand analysis using KCL, KVL, and ohm’s law Orcad schematic capture software 회로이론-І 2013년2학기 이문석 Circuit after simulation run 16 4.6 Computer-aided Circuit Analysis - Circuit simulation example with dependent source 회로이론-І 2013년2학기 이문석 17 4.6 Computer-aided Circuit Analysis - Node-based Pspice schematic creation (Text-based input format) Input Deck Output Deck Homework : 4장 Exercises 4의 배수 문제 (57번 문제까지) - Due day : 4장 수업 끝나고 일주일 후 수업시작 전까지 제출. 회로이론-І 2013년2학기 이문석 18 이 자료에 나오는 모든 그림은 McGraw·hill 출판사로부터 제공받은 그림을 사 용하였음. All figures at this slide file are provided from The McGraw-hill company. 회로이론-І 2013년2학기 이문석