Lecture 6 Static Logic

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CMPEN 411
VLSI Digital Circuits
Spring 2012
Lecture 06: Static CMOS Logic
[Adapted from Rabaey’s Digital Integrated Circuits, Second Edition, ©2003
J. Rabaey, A. Chandrakasan, B. Nikolic]
Sp12 CMPEN 411 L06 S.1
Review: CMOS Process at a Glance
Define active areas
Etch and fill trenches

One full photolithography
sequence per layer
(mask)

Built (roughly) from the
bottom up
Implant well regions
Deposit and pattern
polysilicon layer
Implant source and drain
regions and substrate contacts
Create contact and via windows
Deposit and pattern metal layers
Sp12 CMPEN 411 L06 S.2
4
2
3
1
metal
polysilicon
exception!
source and drain diffusions
tubs (aka wells, active areas)
CMOS Circuit Styles

Static complementary CMOS - except during switching,
output connected to either VDD or GND via a lowresistance path

high noise margins
- full rail to rail swing
- VOH and VOL are at VDD and GND, respectively





low output impedance, high input impedance
no steady state path between VDD and GND (no static power
consumption)
delay a function of load capacitance and transistor resistance
comparable rise and fall times (under the appropriate transistor
sizing conditions)
Dynamic CMOS - relies on temporary storage of signal
values on the capacitance of high-impedance circuit
nodes


simpler, faster gates
increased sensitivity to noise
Sp12 CMPEN 411 L06 S.3
Static Complementary CMOS

Pull-up network (PUN) and pull-down network (PDN)
VDD
PMOS transistors only
In1
In2
PUN
InN
In1
In2
InN
pull-up: make a connection from VDD to F
when F(In1,In2,…InN) = 1
F(In1,In2,…InN)
PDN
pull-down: make a connection from F to
GND when F(In1,In2,…InN) = 0
NMOS transistors only
Question : How many transistors are used to implement
N-input function F(In1,In2,…InN) ?
Sp12 CMPEN 411 L06 S.4
Construction of PDN

NMOS devices in series implement a NAND function
A•B
A
B

NMOS devices in parallel implement a NOR function
A+B
A
Sp12 CMPEN 411 L06 S.5
B
Dual PUN and PDN

PUN and PDN are dual networks


DeMorgan’s theorems
A+B=A•B
[!(A + B) = !A • !B or !(A | B) = !A & !B]
A•B=A+B
[!(A • B) = !A + !B or !(A & B) = !A | !B]
a parallel connection of transistors in the PUN corresponds to a
series connection of the PDN

Complementary gate is naturally inverting (NAND,
NOR, AOI, OAI)

Number of transistors for an N-input logic gate is 2N
Sp12 CMPEN 411 L06 S.6
CMOS NAND
A
A
B
F
0
0
1
0
1
1
1
0
1
1
1
0
B
A•B
A
B
A
B
Sp12 CMPEN 411 L06 S.7
CMOS NOR
B
A
A+B
A
B
A
B
Sp12 CMPEN 411 L06 S.8
A
B
F
0
0
1
0
1
0
1
0
0
1
1
0
Complex CMOS Gate
B
A
C
D
OUT = !(D + A • (B + C))
A
D
B
Sp12 CMPEN 411 L06 S.10
C
Static Complementary CMOS

Naturally inverting, implementing only functions such as
NAND, NOR, and XNOR in a single stage.
VDD
PMOS transistors only
In1
In2
PUN
InN
In1
In2
InN
pull-up: make a connection from VDD to F
when F(In1,In2,…InN) = 1
F(In1,In2,…InN)
PDN
pull-down: make a connection from F to
GND when F(In1,In2,…InN) = 0
NMOS transistors only
Question1: why PUN are PMOS only and PDN
are NMOS only?
Sp12 CMPEN 411 L06 S.11
Threshold Drops
VDD
PUN
VDD
S
D
VDD
D
0  VDD
VGS
S
CL
VDD  0
PDN
D
VDD
S
Sp12 CMPEN 411 L06 S.13
CL
0  VDD - VTn
CL
VGS
VDD  |VTp|
S
D
CL
Standard Cell Layout Methodology
Routing
channel
VDD
signals
GND
What logic function is this?
Sp12 CMPEN 411 L06 S.14
OAI21 Logic Graph
X
A
j
C
C
B
X = !(C • (A + B))
C
i
A
i
X
B
VDD
j
B
A
B
C
Sp12 CMPEN 411 L06 S.15
PUN
GND
A
PDN
Two Stick Layouts of !(C • (A + B))
crossover requiring vias
A
C
B
A
B
C
VDD
VDD
X
X
GND
GND
uninterrupted diffusion strip
Sp12 CMPEN 411 L06 S.16
Consistent Euler Path

An uninterrupted diffusion strip is possible only if there
exists a Euler path in the logic graph

Euler path: a path through all nodes in the graph such that
each edge is visited once and only once.
X
C
i
X
B
VDD
j
GND

A
A B C
For a single poly strip for every input signal, the Euler
paths in the PUN and PDN must be consistent (the same)
Sp12 CMPEN 411 L06 S.18
OAI22 Logic Graph
A
C
B
D
X
D
X = !((A+B)•(C+D))
C
D
A
B
Sp12 CMPEN 411 L06 S.19
C
VDD
X
B
A
B
C
D
PUN
A
GND
PDN
OAI22 Layout
A
B
D
C
VDD
X
GND

Some functions have no consistent Euler path like
x = !(a + bc + de) (but x = !(bc + a + de) does!)
Sp12 CMPEN 411 L06 S.20
XNOR/XOR Implementation
XNOR
XOR
A
A
AB
B
A
B
B
AB
A
B
AB

How many transistors in each?

Can you create the stick transistor
layout for the lower left circuit?
Sp12 CMPEN 411 L06 S.21
AB
Static CMOS Full Adder Circuit (page 565)
Cout=AB+BCin+ACin
Sum = ABCin+!Cout(A+B+Cin)
B
A
B
B
A
Cin
A
B
Cin
Cin
!Cout
!Sum
A
A
B
A
Cin
B
A
B
Cin
A
B
Cout = Cin & (A | B) | (A & B)
Sp12 CMPEN 411 L06 S.24
Sum = !Cout & (A | B | Cin) | (A & B & Cin)
# transistors = 24+4
Two chips you are seeing today
Microprocessor
Sp12 CMPEN 411 L06 S.25
ASIC (Application Specific IC)
Standard Cell Library
NAND
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INV
Standard Cell Library
NAND
Sp12 CMPEN 411 L06 S.27
INV
NAND
The design flow
Simulation
VHDL
Synthesis
(decoder.vhd)
Standard
Verilog netlist
(decoder.v)
Place/Route
Physical layout
(decoder.cif)
Sp12 CMPEN 411 L06 S.28
Cell Lib
The IBM ASIC Design Flow
Sp12 CMPEN 411 L06 S.29
Next Lecture and Reminders

Next lecture

Pass transistor logic
- Reading assignment – Rabaey, et al, 6.2.3
Sp12 CMPEN 411 L06 S.30
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