INTRODUCTION TO ELECTRONICS EHB 222E Bipolar Junction Transistors (BJT) Asst. Prof. Onur Ferhanoğlu 1 BJTs • Transistors are 3-terminal devices. • Basic principle: Controlling the voltage between 2 terminals to control the current flowing in the 3rd terminal. • Transistors are used as amplifiers & switches. • Invention: 1948: Bell Lab`s Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 2 BJTs npn transistor • 3 terminals: emitter, base, collector • 2 junction: EBJ, CBJ • 3 modes: active: amplifer cutoff: switch saturation: switch pnp transistor Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 3 BJTs (npn) in Active mode Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 4 BJTs (npn) in Active mode • Electrons diffuse into the p region • Since base is narrow, with some loss, the electrons will reach the collector • Since collector is more positive (voltage) than base, the electrons reaching the collector will be swept across to the collector gate ELECTRONS ARE COLLECTED AT THE COLLECTOR GATE Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 5 BJTs (npn) in Active mode CURRENT FLOW • iC = Isexp(VBE/VT) • iC is independent of vCB -> since collector is positive with respect to the base electrons will reach the collector side • iB = iC /β = (Is/ β)exp(VBE/VT) -> small fraction of the emitter current that does not reach the collector • iE = ic + ib = Is [(β +1)/ β]exp(VBE/VT) = (β +1)/ β. iC Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 6 BJTs (npn) in Active mode – Equivalent circuit • iC is independent of vCB , as long as vCB > 0 Therefore iC behaves as a voltage controlled current source alternatively, iC can be expresses as a current controlled current source • iC = β iB , β: COMMON EMITTOR CURRENT GAIN Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 7 BJTs – Circuit Symbols • Arrow heads point towards the emitter gate, shows the normal direction of current • npn -> collector collect electrons, current is in the opposite direction ACTIVE REGION Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 8 BJTs – Exercise Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 9 BJTs – Exercise Base is 0V IE = IC (β+1)/ β = 2.02 mA Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 10 BJTs – Graphical Representation • • • • Asst. Prof. Onur Ferhanoğlu Same as diode characteristics No current when vBE < 0.5 V Typically vBE = 0.7 V For pnp, replace vBE with vEB BJT/ INTRODUCTION TO ELECTRONICS 11 BJTs – Saturation mode • 1 diode between base and emitter (pn junction) • 1 more diode between base and collector (OFF in active region, ON in saturation) Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 12 BJTs – Saturation mode ACTIVE Add diode currents: KCL at node C SAT Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 13 BJTs – Early effect COMMON EMITTER (emitter grounded) • vCE increases width of depletion region • Depletion width increases • Base width decreases • iC increases (more electrons are collected) Early voltage Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 14 BJTs – Early effect Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 15 BJTs – Early effect Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 16 BJTs – Exercise Determine the value of VBB that results in a) Active mode with VCE = 5V b) At the edge of saturation c) Deep saturation with β = 10 Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 17 BJTs – Exercise Determine the value of VBB that results in a) Active mode with VCE = 5V b) At the edge of saturation c) Deep saturation with βforced = 10 Assume VBE = 0.7 and β = 50 Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 18 BJTs – Exercise Determine the value of VBB that results in a) Active mode with VCE = 5V b) At the edge of saturation c) Deep saturation with βforced = 10 Assume VBE = 0.7 and β = 50 Edge of saturation: Still use β = 50, as in active mode Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 19 BJTs – Exercise Determine the value of VBB that results in a) Active mode with VCE = 5V b) At the edge of saturation c) Deep saturation with βforced = 10 Assume VBE = 0.7 and β = 50 Deep saturation: Use βforced instead Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 20 BJTs – determining the mode of operation • Assume active mode • Check if VBC < 0.4 V -> YES -> active • NO -> assume SAT -> check IC/IB < β Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 21 BJTs – Exercise Determine node voltages & branch currents Assume β = 100 Transistor is assumed to be active -> VBC = -1.3 V (reverse biased) -> It is active Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 22 BJTs – Exercise Determine node voltages & branch currents Assume β = 50 Assume ACTIVE BC is forward biased XXX Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS Assume SAT βforced = 1.5 23 BJTs – Exercise Determine node voltages & branch currents BASE is grounded! BE & BC are both reverse biased Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 24 BJTs – Exercise Determine node voltages & branch currents (assume β = 100) `pnp` transistor Assume ACTIVE Asst. Prof. Onur Ferhanoğlu BJT/ INTRODUCTION TO ELECTRONICS 25