SHR Chapter 7 Binary Distillation 1 BinaryDistillation.key - March 28, 2014 SHR §7.1 Introduction st Dates back to 1 century AD • first used in a batch mode (distillate changes in time) Goal: separate “heavy key” (less volatile) from “light key” (more volatile) by exploiting α≠1. • for α≫1 or α≪1, this can be done very effectively unless an azeotrope exists (where α=1). ‣ then we recover the azeotrope and the light or heavy key, depending on which side the feed lies. th • By 16 century, multiple stages were in use to improve separation. By 1976, distillation accounted for nearly 3% of the US energy consumption! • mostly in petroleum refineries Binary distillation is simplest & most wellunderstood. • we will limit our discussion to binary distillation Third Law of Thermo - typically low thermodynamic efficiency. 2 BinaryDistillation.key - March 28, 2014 Design Considerations Operating pressure - “knob 1” • below ambient pressure requires vacuum operation • many things may influence choice of operating pressure ‣ Thermo: azeotrope formation, α, etc. ‣ Column operating temperature range (avoiding reactions, corrosion, etc.) • most analyses do not account for pressure variation V L F through the column Operating temperature - “knob 2” • Reboiler & Condenser: D V B L ‣ Bottoms above ambient requires additional energy input to the reboiler ‣ Distillate below ambient requires energy removal from the condenser. • Thermodynamics: critical points of fluids 3 BinaryDistillation.key - March 28, 2014 Batch Distillation Conceptually, follows the T-x-y diagram. More rigorous analysis in SHR chapter 13 4 BinaryDistillation.key - March 28, 2014 SHR §7.2 The McCabe-Thiele Graphical Method 1925 Continuous (staged) distillation 5 BinaryDistillation.key - March 28, 2014 Nomenclature Results Specifications F total (molar) feed rate D Distillate (molar) flow rate z LK mole fraction in feed B Bottoms (molar) flow rate P Column operating pressure N minimum number of stages x LK mole fraction in distillate R minimum reflux flow rate x LK mole fraction in bottoms V Boilup ratio reflux ratio N Number of equilibrium stages R/R Feed phase condition Feed stage location VLE data (y/x plot) Type of condenser (partial/total) Stage compositions ( Type of reboiler (partial/total) • “Light Key” (LK) - more volatile component • “Heavy Key” (HK) - less volatile component 6 BinaryDistillation.key - March 28, 2014 Preliminaries Rectifying section - like an absorber • Feed & reboiler supply vapor • Condenser supplies liquid Stripping section - like a stripper • Feed & condenser supply liquid • Reboiler supplies vapor overall mole balance: F = D + B light-key mole balance: F zF = xD D + xB B combine to eliminate D=F B & solve for D: 7 ✓ zF xD xB xB ◆ BinaryDistillation.key - March 28, 2014 SHR §7.2.1 Rectifying Section Operating Line Overall mole balance: V = L + D Light key mole balance: V yn+1 = Lxn + DxD yn+1 = L D xn + xD V V relates light-key compositions in passing streams (streams on a stage are assumed to be in equilibrium) If L and V are constant, then this is a straight line. The “McCabe-Thiele Assumptions” • Both components have equal and constant molar enthalpies of vaporization (latent heats). • Sensible heat, CpΔT, is negligible compared to latent heat. • Column is insulated (no heat loss on each stage). • Column pressure is constant (thermodynamics can be done at a single pressure). Big assumptions, but allow for simple analysis, since L and V are constant under these assumptions. li ing ne rat e op L/D L L R L reflux R⌘ = =L = D ratio V L+D /D + D/D R+1 D 1 ✓ ◆ ✓ ◆ = 1 R V R+1 x+ xD y= R+1 R+1 8 BinaryDistillation.key - March 28, 2014 Range of Reflux Ratios y= 0 • • L D x + xD V V ✓ L R = V R+1 R= ◆ L D 1 because 0 R 1 What happens at R = 0? What happens at R = ∞? What is the minimum R that allows separation? (We will answer this question shortly) 9 BinaryDistillation.key - March 28, 2014 SHR §7.2.2 Stripping Section Operating Line Overall mole balance: L = V + D Light key mole balance: Lxm = V ym+1 + BxB McCabe-Thiele assumptions have been applied. The feed stage material balance relates L and V to L and V 1 VB ◆ xB lin V boilup B ratio ing VB ⌘ x ✓ relates light-key compositions in passing streams (streams on a stage are assumed to be in equilibrium) e VB + 1 VB ◆ B xB V rat y= ✓ L xm V op e ym+1 = 10 BinaryDistillation.key - March 28, 2014 SHR §7.2.3 Feed Stage & the “q-Line” rectifying section stripping section q= q= L subcooled liquid saturated liquid q>1 q=1 L F F vapor hsat. F vapor hsat. F saturated vapor superheated vapor q=0 q<0 V liquid flow increase across feed V =1+ partially vaporized q = LF/F rate normalized by feed rate. hF liquid hsat. F Operating lines & qline must intersect at a single point. ∴ cannot specify q, VB and R independently. 11 BinaryDistillation.key - March 28, 2014 More on the q-line rectifying section: stripping section: L y= x V L D y = x + xD V V B xB V q= L L F =1+ V V F subtract y V V =x L L + DxD + BxB | {z } F zF y ✓ V F y (1 V ◆ = ✓ L L ◆ x + zF F q) = qx + zF ✓ ◆ q zF x y = q 1 q 1 Typically the feed condition is known (specifying q). Then we can choose VB or R. Note: specifying R implies VB. 12 BinaryDistillation.key - March 28, 2014 SHR §7.2.4 Feed Stage & Number of Stages too low just right too high Locate feed stage nearest to the intersection of the operating lines & q-line as possible (just after the horizontal line on the staircase passes “P” 13 BinaryDistillation.key - March 28, 2014 Partial Reboilers & Condensers Total Reboiler: • all liquid is turned back to vapor Partial reboiler: • bottoms product is liquid, boilup is vapor • This is another equilibrium stage! • very common... Total condenser: • all vapor is condensed back to liquid Partial condenser: • distillate is vapor, reflux is liquid • This is another equilibrium stage! 14 D V L F V B L BinaryDistillation.key - March 28, 2014 SHR §7.2.4 Limiting Cases: Rmin, Nmin. D V “Total reflux” • • • • • “Minimum reflux” • N = ∞. L R = ∞, VB = ∞. L = V, D = B = F = 0. F = 0, N = Nmin. y = x is operating line. No product... Rmin Rmin + 1 (L/V )min Rmin = 1 (L/V )min ⇥ ⇤ L (VB )min = /V max 1 (L/V )min = F V B L 1.0 1.0 1.0 1 “pinch point” ve cur y 3 y x= x y x= x = zF x = xD x = xB x = xB 1.0 ilibr ium x= equ y equ y ilibr ium cur ve 2 0 1 0 x higher operating costs y x = zF x = xD x = xD x = xB 1.0 0 x 1.0 higher capital costs 15 BinaryDistillation.key - March 28, 2014 SHR §7.2.4 Perfect Separation - Another “Limiting Case” operating line = Rmin/(Rmin+1). 1.0 y Perfect separation: xB = 0, xD = 1. Pinch points form in each section of the column. Theoretical value for minimum reflux ratio and boilup to achieve perfect separation. To find this: • Obtain x-y data from thermo. • Determine q-line • Determine slope of rectifying x= y x = zF 0 For saturated liquid feed, Rmin = 16 x 1.0 1 zF (↵ 1) BinaryDistillation.key - March 28, 2014 Example We want to separate a mixture of n-heptane and n-octane using distillation at atmospheric pressure. If the feed is 40 mole% n-heptane as a saturated vapor, determine the minimum reflux ratio and minimum number of stages required to obtain product streams with 95% and 5% n-heptane. D V Known: Needed: • xD = 0.95 • K-values (equilibrium curve) • xB = 0.05 • q-line • zF = 0.4, saturated vapor • operating lines L F V B L 17 BinaryDistillation.key - March 28, 2014