Section 6.5 1 Computing definite integrals Suppose we wish to compute the total accumulated change in a given rate function f (t) over the interval a ≤ t ≤ b. That is, we wish to compute the definite integral ∫ab f (t)dt . € One way to do this is to view the definite integral € as a specific value of the indefinite integral € function F(x) = ∫ ax f (t) dt obtained by setting x = b. But in order to do this, we would like a formula for F(x). € € € We know that F(x) is one of the infinitely many antiderivative functions that can be found by applying the integration rules we have identified (by reversing the differentiation rules). This gives € ∫ f (x)dx = F (x) +C for some (unknown) value of C. It appears that we cannot give a complete formula for F(x) since we € cannot specify the value of C. But consider what happens when we compute the difference of the values of the general antiderivative at x = b and € x = a: on the one hand we get (F (b) +C ) − ( F(a) +C ) =€F(b) − F(a) € € Section 6.5 2 while on the other hand, F(b) − F (a) = ∫ab f (t)dt − ∫aa f (t)dt = ∫ab f (t)dt − 0 since there is zero area over an interval of zero length! If we rewrite this last equation in the form € b ∫a f (t)dt = F (b) − F(a), we see that it does not matter what the value of C is in the antiderivative computation, as it is € in the computation of the difference cancelled F(b) − F (a). Therefore, to compute the definite integral ∫ab f (t)dt , find any antiderivative F(x), and the integral is computed via ∫ab f (t)dt = F (b) − F(a). € € € € Section 6.5 3 Sum Property for Integrals € € One way to interpret the integral ∫ab f (t)dt is as the (signed) area under the graph of f over the interval a ≤ t ≤ b. If we choose an input value c in this interval so that a < c < b, then it is clear that the € integral can be total area described by this partitioned into two areas by a vertical line at x = c . The area to the left of this line is represented € by the integral ∫ac f (t)dt , while the area to the right is represented by ∫cb f (t)dt . It follows that b c b ∫a f (t)dt = ∫ a f (t)dt + ∫c f (t)dt . € € € Section 6.5 4 Differences of accumulated changes Suppose we wish to compute the difference between total accumulated changes for two rate functions f (t) and g(t ) over the interval a ≤ t ≤ b. That is, we wish to compute the quantity b € b dt − ∫ a g(t)dt . ∫a f (t)€ € These two integrals measure the signed areas between the horizontal axis and the graphs of the € f (t) and g(t ) over the interval a ≤ t ≤ b. two curves Their difference, therefore, corresponds to the signed area between the two curves above the interval a ≤ t ≤ b. € € € But if F(x) is an antiderivative of f (t) and G(x) is an € antiderivative of g(t ), then F(x) − G(x) is an antiderivative of f (t) − g(t) and we can calculate € ∫ab f (t)dt € −€∫ ab g(t)dt € € =€F(b) − F (a) − G(b) − G(a) ( ) ( ) = ( F(b) − G(b)) − ( F(a) − G(b)) = ∫ ( f (t) − g(t))dt b a € Section 6.5 5 Note that if the two curves cross over in the interval a ≤ t ≤ b, the signs of the areas on either side of the intersection point are counted as having opposite sign. €