Locate the
centroid of the
shaded area
straightforward
calculus
Compute the
area moment
of inertia about
its centroidal
x0 axis
(1) parallel
axis thm
(2) and (3)
use I about
end (Ix)
See Table D/3.
For rectangular pieces:
Ix = (b h^3)/3
Ix_bar = (b h^3)/12
Compute the
area moments
of inertia about
the centroidal
x0 and y0 axes
(1) parallel
axis thm
There are
two
number 1
pieces
See Table D/3.
For rectangular pieces:
Ix = (b h^3)/3
Ix_bar = (b h^3)/12
Compute the reactions at A and B
Essentially using
N2L and E2L
E2L
N2L
N2L
Compute the reactions at
support A as a function of w0
and b
This is
cute
Integrate to
compute total
load
In moments,
each force has
a "lever arm"
Use FBDs to construct the shear and moment
diagrams. Determine the internal moment at a section
0.5 m to the right of B
Compute
external
reactions
I don't like this.
Should use
FBDs to
compute V & M.
Let's not jump to
diagrams
Use FBDs to construct the shear and moment diagrams. Determine the
internal shear & moment at the middle of the beam
Compute
the
external
reactions
0<x<3
Use FBDs to find V and M
3<x<6
6<x<9
Middle:
x = 4.5
Use FBDs to construct the shear and moment diagrams. Determine the
internal moment at section C
Compute
the external
reactions
I don't like this.
Should use FBDs to
compute V & M.
Let's not jump to
diagrams
A sign convention:
Down = +ive
Up = -ive
Use FBDs to construct the shear and moment diagrams. Determine the
distance b from the left end to where the internal moment is zero between
the supports
Compute
the external
reactions
Again!
Here's a
nice FBD
treatment
Use FBDs to construct the shear and moment diagrams. Determine
the maximum magnitude of the internal moment
Compute
the external
reactions