Ch. 16 Electrical Energy and Capacitance Concept questions: 2, 7, 8, 16 Problems: 2, 5, 7, 10, 11, 13, 16, 19, 22, 23, 25, 30, 32, 40, 47, 66 Electric potential From physics 1, work done by a conservative force depends only on the initial and final positions. (path independent) Produces Potential Energy Coulomb force and gravitational force are both proportional to 1/r2. They are both conservative forces. Gravity FG m1m2 G 2 r gravitational pot. energy Electric FE q1q2 k 2 r electric pot. energy Work and potential energy Work done on a force to move an object is the product of the component of the force parallel to the displacement and the displacement. W = F d cos in figure 16.1 Wab = F x = qEx(xf – xi) This is the work that moves a charge from A to B. Work and Energy • Work Energy theorem: Wnet = KE • From Ch 5, the work done by a cons. force is equal to the negative of the change in potential energy associated with the force. Gravity example: yi y yf W = mg y PEg = mg (yf – yi) For a charge in an electric field: PE = -WAB = - qEx x In fig. 16, as the charge moves from left to right, positive work is done on the charge, the charge loses some electrical potential energy. (Note that this equation is valid when the field is constant.) Similar to how we treated gravitational potential energy. Conservation of Energy KE + PE = 0 If a charge was moving or released in an electric field, it will gain or lose electric potential energy. The change will be equal to the change in kinetic energy. field lines + starts here, released from rest x + KE = - PE KE = qE x ½ mv2 = qE x Electric Potential Earlier we defined: F = qE E = F/q Do the same thing for potential energy PE = q V V = PE/q Potential Difference Electric potential difference is defined as the change in electric potential energy between two points, divided by the charge. V = Vb – Va = PE/q SI units Joule/Coulomb, or volt J/C = V Potential difference is a scalar quantity. 1 Joule is needed to move 1 Coulomb of charge through a potential difference of 1 Volt. For uniform electric field in x-direction: PE = - qE x (eq. 16.1) combined with PE/q = V (eq. 16.2) Gives: V = -E x Potential difference (Volts) has same units as electric field times distance (N/C) m 1 N/C = 1 V/m If you release a positive charge from rest, it will accelerate from regions of high potential to low potential. If you release a negative charge from rest, it will accelerate from regions of low potential to high potential. V x TV tube example. A proton is injected between two parallel plates with a speed o 1x106 m/s. The plates are 5 cm apart. a) what must be the potential difference if the proton is to exit with a speed of 3x106 m/s? b) What is the magnitude of the electric field between the two plates. Page 537-538 KE + PE = KE + q V = 0 V V KE q 1.67 x10 27 kg 6 2 6 2 [( 3 x 10 m / s ) ( 1 x 10 m / s ) ] 19 2(1.6 x10 C ) V = -4.18x104 V E = - V/ x = (4.18x104 V)/(0.05m) = 8.35x105N/C Electrical Potential fro Point Charges The electric field of a point charge extends throughout space. So does the electric potential. The electric potential can be taken to be zero anywhere. Usually picked to be infinitely far away from the charge. V q k r see graphs of electric field and potential as function of distance. If you have two or more charges, you can find the electric potential via the superposition principle. Find the potential from each charge and add up these values. Potential is scalar so no need to worry about vectors this time. See example of dipole. Potential energy of a pair of charges If two charges are a distance r apart you can find the potential energy of the pair. This is equivalent to finding the work needed to bring the pair together from infinity (very far apart). Work = PE = q V when far apart PE = 0 PE = PEf (when separated by r) PE q 2V1 q1q2 k r or PE = q1V2 Potentials and Charged Conductors W = - PE PE = q(Vb – Va) W = -q(Vb – Va) No net work is needed to move a charge between two points that are at the same electric potential. If Vb – Va= 0 Then W = 0 Remember that for a conductor in equilibrium, all the charge is on the surface and there is no electric field inside the conductor. The electric field is perpendicular to the surface of the conductor. Because the electric field is normal to the surface, it takes no work to move a charge along the surface. Because of this, all points on the surface of a charges conductor in equilibrium are at the same potential. Also since there is no charge and thus no electric field inside the conductor: No net work is needed to move a charge around in the interior and from the interior to the surface. the electric potential is constant everywhere inside a conductor and equal to the same value at the surface. Doesn’t have to be zero, just constant. Electron Volt Conveniently sized unit of energy. An electron volt is the kinetic energy that an electron gains when accelerated through a potential difference of 1V. 1V = 1 J/C charge of electron = 1.6x10-19 C 1eV = 1.6x10-19C V = 1.6x10-19 J This is convenient because 1 J is a lot of energy to give an electron. What would happen to an electron with 1 J of kinetic energy? KE = ½ mv2 1 J = ½ (9.11x10-31kg)v2 v = 1.5 x 1015 m/s The electrons would be moving about 5 million times faster then the speed of light. Equipotential Surfaces A surface on which all points are at the same potential. No work is needed to move a charge at constant speed on an equipotential surface. Think of them as the contour lines on a topographical map. The electric field is always perpendicular to an equipotential surface. Van de graaf Van de graaf accelerator Using principles from chapters 15 and 16 to accelerate charged particles. Capacitance capacitor – electrical device used in many circuits that is used to store electrical energy to used later. Consists of two conductors separated from each other. Example: parallel plate capacitor. Two parallel metal plates separated by distance, d, and connected to positive and negative terminals of a battery. One plate loses electrons and receives a charge of +Q. The electrons are transferred through the battery to the other plate which obtains a charge of - Q. Capacitance Capacitance of a capacitor is the ratio of the magnitude of the charge on either conductor to the magnitude of the potential difference between the conductors. Capacitance (C) = Q/ V SI unit of capacitance: farad (F) farad = coulomb per volt F = C/V The charge on a capacitor is Q = C V Capacitance depends on the geometric arrangement of the conductors. For parallel plates, with surface charge density, C= q V A Ed A ( )d A d 0 0 for a parallel plate capacitor, the capacitance depends only on the size of the plates and their separation. We could also find the capacitance of capacitors made of concentric cylinders or spheres. The capacitances will still be determined by the geometry. -Q Concentric spheres: +Q b Va-b = kQ/a – kQ/b a b a Va-b = kQ ab use k = 1/(4 o) ab C = Q/ V = 4 0 b a Combinations of Capacitors We can combine capacitors in different ways to produce different values of capacitance. symbol of capacitor symbol for battery + - combine capacitors is parallel series Parallel Capacitors The capacitors share 2 points in common. (see figure 16.17) Both capacitors are each hooked up across the battery, so they have the same potential difference V across them. If each capacitor can hold charges Q1 and Q2, the total charge stored by both is Q = Q1+Q2 If we replaced the capacitors with an equivalent capacitor, it must hold the same charge and have the potential difference. Q1 = C1 V and Q2 = C2 V must add up to Q = Ceq V Ceq V = C1 V + C2 V V is the same for all of the capacitors, so: Ceq= C1+ C2 For two capacitors, we found: Ceq = C1 + C2 We can extend this to more capacitors. Ceq = C1 + C2 + C3 +C4 + …… The total capacitance of capacitors is parallel is the sum of the capacitances. Thus the equivalent capacitance is larger than any of the individual capacitances. (Electrical devices in parallel have the same potential difference across each device.) Capacitors in Series Capacitors in series share 1 common point. For capacitors in series, the magnitude of the charges must be the same on all plates. see figure 16.19 After the series capacitors are fully charged, an equivalent capacitor must have a charge of –Q on the plate nearest the + terminal of the battery and a charge of +Q on the plate near the negative terminal. Apply V = Q/Ceq, for each capacitor: V1 = Q/C1 and V2 = Q/C2 V = V1 + V2 Q/Ceq = Q/C1 + Q/C2 1/ Ceq = 1/C1 + 1/C2 This happens, since the potential difference across any number of capacitors in series equals the sum of the potential differences across the individual capcitors. For two capacitors 1/ Ceq = 1/C1 + 1/C2 For any number of capacitors in series: 1/Ceq = 1/C1 + 1/C2 + 1/C3 + 1/C4 + …… The equivalent capacitance of a series combination is always smaller than any of the individual capacitances in the combination. Energy Stored in a capacitor • capacitors store electrical energy • That energy is the same as the work required to move charge, Q, onto the plates of the capacitor. • When a capacitor discharges, it releases the V energy. (sparks) V=Q/C W= V Q W=½Q V Q charge Energy stored is equal to the work Energy stored = W = ½ Q V Using the substitution Q = C V, we can also show: Energy stored= ½ C( V)2 = Q2/(2C) Capacitors with dielectrics • dielectric – an insulating material such as plastic • can be inserted into a capacitor to change the capacitance without changing the geometry of the capacitor • If dielectric completely fills the capacitor, the capacitance is multiplied by the dielectric constant ( ) 1 • = 1 for vacuum • Capacitor without dielectric: V = Q0/C0 • By inserting the dielectric between the plates, the voltage across the plates is reduced by factor . V = V0/ • Because > 1, then V is less than V0 • The charge on the plates is fixed. C C Q0 V C0 Q0 V0 Q0 V0 Parallel plate capacitor • capacitance without dielectric: C 0 A d • capacitance with dielectric: C 0 A d Dielectric strength • dielectric strength – the maximum electric field that can be produced in a dielectric before it breaks down and begins to conduct • For air, the dielectric strength is about 3x106 V/m • If the electric field is increased above this value, a spark will be thrown. Sparks in air dielectric strength of air is 3x106 V/m A spark 1 meter long requires a potential difference of 3x106 V. A 1cm long spark requires 3x104 V So even a small spark can involve voltages in the thousands.