Example Calculation of Air Velocity from Pitot-static Tube Measurement: Given: A pitot-static tube via a manometer measures a dynamic pressure of 0.201 in H2O in a wind tunnel. The ambient temperature and pressure are 72.0 ˚F and 14.55 psia. Find: Calculate the air velocity in ft/s Assume: Steady, incompressible, isentropic flow of air; good alignment of pitot-static tube (streamlines parallel to stagnation tap and perpendicular to static tap); air as an ideal gas Analysis: Convert pressure from in H2O to lbf/ft2 using Equation 1-6 and Table A.7* for ρ H 2O at 72.0 ˚F. ( pT − p ) = ρH O g h 2 ( pT − p ) = 1.93 € 1 ft 1 lbf€ slug ft 32.174 0.201 in ( ) 2 ft 3 s2 12 in 1 slug ⋅ ft/s ( pT − p ) = 1.040 lbf /ft 2 which is the dynamic pressure € Calculate density of air at patm = 72.0 ˚F, Tatm = 14.55 psia using ideal gas law where R is the universal gas constant for air from Table A.6*. € p ρ air = atm R Tatm 2 ρ air f f € 2 1 slug (14.55 lb /in ) (12 in 1 ft) = (53.33 ft ⋅ lb lb ⋅ R) [(72.0 + 459.69) R] 32.174 lb m m ρ air = 0.002297 slug/ft 3 € Calculate air velocity using Equation 1-5. € V= 2 ( pT − p ) ρ air 2 (1.040 lbf /ft 2 ) 1 slug ⋅ ft/s2 V= (0.002297 slug/ft 3 ) 1 lbf € V = 30.1 ft/s €* € Fox, R. W., Pritchard, P. J., and McDonald, A. T., Introduction to Fluid Mechanics, 7th edition, John Wiley & Sons, Inc., 2009.