ELECTRIC FIELDS DUE TO CONTINUOUS CHARGE DISTRIBUTIONS Approach: Break charge distribution into small elements (treat each as a point charge) Write vector sum of contributions from elements Take limit as elements become infinitesimally small → INTEGRAL Steps: 1st: Draw a picture showing contribution from one charge element o r̂i is unit vector pointing from qi toward P o Ei is the contribution to E due to qi 2 : treat qi as a point charge and find Ei nd qi E k rˆ i e 2 i o ri 3rd: Do a vector sum over contributions q from all i to get an expression for E q Ei k e 2 i rˆi ri i 4th: go to limit of small elements so sum becomes exact → integral! q E lim ke 2 i rˆi qi 0 ri i ke dq rˆ 2 r VECTOR INTEGRAL! – don’t panic, symmetry helps dq E ke 2 rˆ r CHARGE DENSITY (Important concept) Use to convert integral over dq into integral over spatial variables (i.e. x, y, z) o Linear charge density: for a uniformly charged line of length L and total Q charge Q, the linear charge density is L o Surface charge density: for a uniformly charged plane of area A and Q total charge Q, the surface charge density is A o Volume charge density: for a uniformly charged space of volume V and Q total charge Q, the volume charge density is V PROBLEM SOLVING STRATEGY: see page 631 ASK: Does symmetry simplify the problem? Approach: o For point charges, use superposition o For continuous charge: Identify charge elements Build an integral Look for symmetry to simplify the integral We will mostly stick to rods and rings for now. Example: What is the electric field at a point P a distance x from the left end of a uniformly-charged (positive) rod of length L and charge Q? Example: What is the electric field at a point P a distance y above the midpoint of a uniformly-charged (positive) rod of length L and charge Q? Example: What is the electric field at a distance x from the centre of a uniformly charged ring along an axis through the centre of the ring and perpendicular to the plane of the ring? The ring has radius a and total charge Q.