SP212‐Spring‐2016  CH‐22‐B Assignment 

SP212‐Spring‐2016 CH‐22‐B Assignment First do the following Wiley‐Plus assignment: Assignment #22b After completing the Wiley‐Plus, in your homework notebook, complete the following problems: CH22 Question # 9 CH22 Problems #34 To check your work, the answers to the odd problems are in the back of the book. The answers to the even problems are: #34) 6.3
Homework Then complete the attached worksheets: (Note: the above problems were designed to ensure you have the skills to solve the worksheet problems. It is imperative to your learning of the problem solving technique to do the above problems BEFORE attempting the worksheet problems. You are graded on both! Homework notebooks are graded.) CH‐22‐B‐1: For each of the equations below, 1) State what each term is in your own words … 2) What the units of each term are… 3) What is the general use of that equation in your own words? A.
dq   ds B. dq   dA C. dq   dV D.
 k dq
dE  2 r̂ r
CH‐22‐B‐2: In the figure below, a uniformly distributed charge of q=+8.88 pC is spread along a plastic rod of length 15 cm. A physicist wants to determine the electric field at point P which is 6.00 cm above the rods perpendicular bisector. 
(a) Set up the integration to calculate the electric field ( E ) at P due to the rodʹs charge. (DO NOT TRY TO SOLVE THE INTEGRAL, only setup!) Ensure your answer includes the terms of Q and L though! Show all work (this means show every step you take to setup the integral, not just the final integral.) (b) Now evaluate that integral (Hint: You have a calculator!) and state the value including its direction. CH‐22‐B‐3: A uniformly charged thin insulating rod has a total charge of +Q and a length L. The rod lies
along the x-axis and one end is a distance d away from the origin as shown in the diagram.
The magnitude of the electric field at the origin is
Show all work: CH‐22‐B‐4: A ring of radius a = 0.35 m has a charge of Q = +14.0 x 10-6 C uniformly distributed on its
surface. The center of the ring is at the origin. The electric field at point P on the axis of the
ring, a distance x = 1.50 m from its center is closest to Show all work including vector diagrams!