Matthew Feickert PHYS 1304: Introductory Electricity and Magnetism Quiz 7 Key March 31th, 2015 Problems 1. (6 points) A particle with positive charge q = 4.00 × 10−18 C moves with a velocity of v = 2.50 × 106 m/s (− ŷ) perpendicularly toward a long straight wire with current I = 800 mA flowing along x̂. At a certain instant in time, the particle’s radial distance from the wire is d = 4.00 cm. What is the magnitude and direction of the force on the particle due to the current? 2. (4 points) Check all the statements that are correct. (a) A beam of moving protons generates a magnetic field around it. (b) The force between two anti-parallel currents is attractive. (c) The magnetic field inside a toroid is uniform. (d) The magnetic field lines inside a solenoid go from the south pole to the north pole. 1 Solutions 1. (6 points) A particle with positive charge q = 4.00 × 10−18 C moves with a velocity of v = 2.50 × 106 m/s (− ŷ) perpendicularly toward a long straight wire with current I = 800 mA flowing along x̂. At a certain instant in time, the particle’s radial distance from the wire is d = 4.00 cm. What is the magnitude and direction of the force on the particle due to the current? From Ampère’s law, ∫ B · dl = µ0 Ienc , it is seen that for a circular Amperian loop of radius r, B (2πr) = µ0 I, that at a radial distance of r from the wire, the magnetic field experienced by the particle— according to the “right hand rule”—is µ0 I ẑ. B= 2πr From the Lorentz force law, F = q (E + v × B) , it is seen that at a radial distance d, the particle experiences a force of F = qv × B µ0 I = qv (−ŷ × ẑ) 2πd q vµ0 I = − x̂ 2πd ( ) (4.00 × 10−18 C) (2.50 × 106 m/s) 4π × 10−7 V · s · A−1 · m−1 (0.8 A) =− x̂ 2π (0.04 m) = −4 × 10−17 N x̂. Points: • 2 points for correct expression of magnetic field magnitude, |B| – If they have incorrect B, but used Ampère’s law they receive 1 point • 1 point for Lorentz force law (qv × B) • 2 point for correct algebraic expression of magnitude (q vµ0 I/2πd) • 0.5 points for correct numeric magnitude (4 × 10−17 N) • 0.5 points for correct direction (−x̂) • -1 point for wrong units 2 2. (4 points) Check all the statements that are correct. (a) A beam of moving protons generates a magnetic field around it. ✓ Current is moving charges, dQ , dt and it is known from Ampère’s law that current produces a magnetic field. I= (b) The force between two anti-parallel currents is attractive. 7 Use the “right hand rule” and see that the force is repulsive. (c) The magnetic field inside a toroid is uniform. 7 Btoroid = µ0 IN , 2πr a≤r≤b (d) The magnetic field lines inside a solenoid go from the south pole to the north pole. 7 Magnetic field lines go from the north pole to the south pole. Points: • 1 point for each correctly checked box (✓). • 1 point for each incorrect box left blank (7). 3 Alternative Solutions 1. (6 points) A particle with positive charge q = 4.00 × 10−18 C moves with a velocity of v = 2.50 × 106 m/s (− ŷ) perpendicularly toward a long straight wire with current I = 800 mA flowing along x̂. At a certain instant in time, the particle’s radial distance from the wire is d = 4.00 cm. What is the magnitude and direction of the force on the particle due to the current? From Ampère’s law, ∫ B · dl = µ0 Ienc , it is seen that for a circular Amperian loop of radius r, B (2πr) = µ0 I, that at a radial distance of r from the wire, the magnetic field is B= µ0 I ϕ̂. 2πr From the Lorentz force law, F = q (E + v × B) , it is seen that—switching to cylindrical coordinates (r, ϕ, z) with ẑ being along the direction of the current—at a radial distance d, the particle experiences a force of F = qv × B ) µ0 I ( = qv −r̂ × ϕ̂ 2πd q vµ0 I q vµ0 I = − ẑ cylind = − x̂cart . 2πd 2πd 4