Outline 1 Electrical Drive Systems 324 Synchronous Generators Dr. P.J Randewijk Stellenbosch University Dep. of Electrical & Electronic Engineering Stephan J. Chapman Chapter 4 (5th Edition) Chapter 4 – Synchronous Generator 4.1 – Synchronous Generator Construction 4.2 – The Speed of Rotation of a Synchronous Generator 4.3 – The Internal Generated Voltage of a Synchronous Generator 4.4 – The Equivalent Circuit of a Synchronous Generator 4.5 – The Phasor Diagram of a Synchronous Generator 4.6 – Power and Torque in Synchronous Generators 4.7 – Measuring Synchronous Generator Model Parameters 4.8 – The Synchronous Generator Operating Alone 4.9 – Parallel Operation of Synchronous Generators 4.11 – Synchronous Generator Ratings 1 / 36 4.1 Construction 2 / 36 4.1 Construction (cont.) Salient pole rotor machines There are basically two types of synchronous generators for “low speed” applications (> 4 poles) e.g. hydro-electrical turbines Cylindrical or non-salient pole rotor machines for “high speed” applications e.g. steam turbines Usually limited to 2 or 4 pole machines 3 / 36 4 / 36 4.1 Construction (cont.) 4.2 The Speed of Rotation Small machine may employ sliprings and brushes to supply the field From (3–34) in Chapter 3, it can be seen that in order to generate at a certain frequency, a certain speed is required This is still better than using a DC machine with a commutator and brushes – Why? Large machines use “brushless” excitation fse = This implies no brushes and sliprings are used to supply DC power to the field winding – see Fig. 4.3 (just for interest sake) nsm poles · 60 2 (3–34’) Also from section 4.1, the higher the speed, the lower the number of poles must be Or, the lower the speed, the larger the number of poles must be to generate a voltage at the required frequency 5 / 36 4.3 The Internal Generated Voltage 6 / 36 4.4. The Equivalent Circuit The rotor’s magnetic field, BR (produced by a DC field current on the rotor, IF ) produces EA See section 3.4 again Also due to hysteresis and the B-H characteristic, see section 1.4, saturation occurs if the field current becomes to high The current in the stator winding, IA , produces a flux in the stator, BS The “magnetisation curve” (Fig. 4–7) looks exactly the same as for a DC machine – Fig. 8–4 This flux also produces a voltage in the stator windings, Estat The terminal voltage of the machine, Vφ = Enet = EA + Estat (4–4’) Bnet = BR + BS (4–5) and with The difference in the angle between BR and Bnet 7 / 36 8 / 36 4.4. The Equivalent Circuit (cont.) 4.4. The Equivalent Circuit (cont.) and the difference in the angle between EA and Vφ the equivalent circuit of the synchronous machine can be deduced as shown in Fig. 4–9 and is almost similar (an AC dual) of the equivalent circuit of the DC machine as shown in Fig. 8–2(b) will be the same and equal to δ, the torque – or power angle of the machine + Remember P = ωm τind and ωm is constant for a synchronous machine With Estat = −jX IA (4–6) Vφ = EA − jXS IA − RA IA where X is equal to the magnetising reactance of the machine – similar to a transformer (4–11) with the synchronous reactance given by Thus from Vφ = EA − jX IA A more accurate/“full” equivalent circuit, will also have to take into account the stator leakage reactance, XA , and the stator resistance, RA , so that the KVL equation becomes (4–7) XS = X + XA (4–10) 9 / 36 4.4. The Equivalent Circuit (cont.) 10 / 36 4.5 The Phasor Diagram The “full” equivalent circuit is shown in Fig. 4–10 for all three phases For generator operation, IA is defined as flowing out of the machine We only need to consider 1 phase (1φ) as shown in Fig. 4–12 and multiply the power or torque by three (×3) Just apply KVL, i.e. e.q. (4–11) and remember the phasors must add up graphically. . . And that IA lags jXS IA by 90◦ (CIVIL) – see Fig. 4-13 & 4–14 + Note: Synchronous machines are usually connected in Y (also called “star” or “wye”) – Fig. 4–11 (a) + Note: We will always use Y connection. . . 11 / 36 12 / 36 4.6 Power and Torque 4.6 Power and Torque (cont.) + N.B. From Fig. 4–16, The mechanical input power to the generator that is converted to electrical power, Pconv = τind ωm = 3EA IA cos γ (4–14) (4–15) Which is similar to a DC machine, with the only difference that: + this is an AC circuit, hence the angle between EA and IA needs to be taken into account + there are three (3) phases that contributes to the delivery of power & torque If we assume that RA ≈ 0 (which is true for very large synchronous generators) Pconv = Pout = 3Vφ IA cos θ it can be proven that: Pconv = (4–17) 3Vφ EA sin δ XS (4–20) 13 / 36 4.6 Power and Torque (cont.) 4.7 Measuring the Model Parameters With δ the torque angle of power angle of the machine, i.e. the angle between Vφ and EA This is the same angle as the angle between Bnet and BR with Vφ ≈ Enet – see eq. (4–4’) Also with P = ωm τind , τind 3Vφ EA = sin δ ωm X S 14 / 36 (4–22) The open- circuit characteristic (OCC) curve, Fig. 4–17(a) is the same as the magnetisation curve, Fig. 4–7(b) Saturation occurs if the DC field current, IF , becomes to high Without saturation, EA (which is equal to Vφ because the machine is open-circuit, i.e. IA = 0) would have followed the air-gap line For the short-circuit characteristic (SCC) curve, the relationship between IA and IF is linear. This is due to the fact that with XA & RA X , BR ≈ BS so that Bnet ≈ 0 and thus Enet ≈ 0 and thus the total flux, φ ≈ 0 – see eq. (3–38) 15 / 36 16 / 36 4.7 Measuring the Model Parameters (cont.) 4.7 Measuring the Model Parameters (cont.) The unsaturated synchronous reactance, XS , assuming RA XS can thus be calculated as Vφ |OCC,air-gap line XS|unsat ≈ (4–26’) IA |SCC IF =x A with EA |OC,air-gap line measured from the air-gap line during the open-circuit test, IA |SC measured during the short-circuit test, both measure at the same value of IF , say x A Similarly, the saturated synchronous reactance can be calculated as Vφ |OCC,actual curve XS|sat ≈ (4–26) IA |SCC IF =x A The rated voltage value of the synchronous generator will be used to determine the rated field current from the OCC curve The current value from the SCC curve for the same rated field current will be used to determine XS|sat + XS|sat will always be smaller than XS|unsat – see Fig. 4–19 (next slide) + See Example 4–1 also with regard to the DC test in order to determine RA + Note: We will always work with XS|sat 17 / 36 4.7 Measuring the Model Parameters (cont.) 18 / 36 4.8 Operating Alone In a nutshell: EA is determined from the OCC and depends on IF , the DC field current IA is determined by the impedance of the load, and the value of EA , IA = EA 0◦ RA + jXS + Zload + Note: You can choose any angle for EA – but 0◦ is nice – as the angle of IA will always be with respect to the angle chosen for EA Vφ is determined by the phase/load current, Vφ = IA Zload The Short-Circuit Ration – Skip 19 / 36 20 / 36 4.8 Operating Alone (cont.) 4.9 Parallel Operation When asked to draw phasor diagram, similar to that shown in Fig. 4–22 – which are with respect to Vφ = Vφ 0◦ , all the phasor are just rotated by the angle of Vφ as calculated above In this section we can clearly see the effect a unity, lagging or leading power factor have on the voltage regulation of the terminal voltage + Note: From Fig. 4–25 we can see that with a fixed excitation (i.e. fixed field current), the terminal voltage of the synchronous generator when feeding a load with a leading power factor, actually increases with an increase in line current – which is somewhat counter intuitive. . . A synchronous generator needs to be synchronised with the infinite bus before it can be connected to the infinite bus This implies that: the line (or phase) voltage of both must be the same the phase sequence for both must be the same the phase angles of both phase voltage must be the same the frequency of both must be the same + both ⇐ the generator and the infinite bus Frequency – Power and Voltage – Reactive Power Characteristics of a Synchronous Generator – skip – together with the speed droop (SD) characteristics and all the house diagrams 21 / 36 4.9 Parallel Operation (cont.) 22 / 36 4.9 Parallel Operation (cont.) The only thing that is important to remember with regard to frequency, is that if the frequency of the synchronous machine is + Note: This will lead to a change in the power angle, δ – see Fig. 4–36 (b) slightly higher than the infinite bus – see Fig. 4–34, the machine will immediately start operating as a generator and start delivering power slightly lower than the infinite bus – see Fig. 4–35, the machine will immediately start operating as a motor and consume power, not delivering power To change the amount of real power, P, delivered to the infinite bus, the input power from the prime mover, e.g. stream turbine needs to be changed To change the amount of reactive power, Q, delivered to the infinite bus, the DC field current, IF , or the excitation of the machine needs to be changed + Note: This will lead to a change in the internal generated voltage, EA – see Fig. 4–37 23 / 36 24 / 36 4.9 Parallel Operation (cont.) 4.9 Parallel Operation (cont.) + Note: With Vφ fixed – because it is connected to the infinite bus – the net flux in the machine is fixed, thus EA ∝ IF and does not follow the OCC curve line, but has a linear relationship to one another through the rated operating point. . . + See Fitzgerald et al, Fig. 5–10 (on the next slide) 25 / 36 4.9 Parallel Operation (cont.) 26 / 36 4.11 Synchronous Generator Ratings With the net flux fixed the synchronous generator will operate on the Op–line through the rated operating point with a linear relationship between EA and IF Various ratings apply to a synchronous machine – voltage, frequency, speed, apparent power, power factor, field current, service factor For synchronous machines, the frequency is determined by the speed of operation and vice versa Operation of Generators in Parallel with Other Generators of the Same Size – skip fse = nm · poles2 60 (3–34) The peak flux in the machine is determined not only by the frequency, but also by the supply voltage Bmax = 27 / 36 Emax 2πNC Agap f 28 / 36 4.11 Synchronous Generator Ratings (cont.) 4.11 Synchronous Generator Ratings (cont.) + N.B. The power loss in the stator windings is determined by the magnitude of the stator current, and is not influenced by the power factor This implies that there must be a constant volts-per-hertz ratio and also why 480 V, 60 Hz machines will operate at the same flux-density value when connected to a 400 V, 50 Hz supply – albeit at a different speed. . . PSCL = 3IA2 RA The maximum AC current the machine can supply is limited by the stator copper wire diameter and the maximum allowable heat (i.e. power) this windings can dissipate With the voltage of the machine set (always given as a line-to-line value), the maximum stator current is indirectly given by the apparent power rating (measured in kVA or MVA) of the machine √ Srated = 3VL,rated IL,rated (4–37) (4–38) The maximum DC field current possible is limited by the field copper wire diagram and the maximum heat (i.e. power) this windings can dissipate PPCL = IF2 RF (4-39) The maximum IF directly influence the maximum EA as E A ∝ IF 29 / 36 4.11 Synchronous Generator Ratings (cont.) 30 / 36 4.11 Synchronous Generator Ratings (cont.) The maximum value of IA and IF or more specifically EA , limits the phasor diagram as shown in Fig. 4-47 By noting that the length of the “circle” with its origin at Vφ 0◦ is proportional to IA ∝ S with Vφ and XS constant 3V We scale the phasor diagram of Fig. 4–48 (a) by Xsφ with its origin at Vφ 0◦ , to yield a power diagram as shown in Fig. 4–48 (b) 31 / 36 32 / 36 4.11 Synchronous Generator Ratings (cont.) 4.11 Synchronous Generator Ratings (cont.) By swapping the x– and y–axis around, we obtain a “traditional” power triangle type diagram with the operational limits as shown in Fig. 4–49 If the prime mover’s (e.g. steam turbine) maximum output power is lower than that of the generator, that limit can be added to the generator’s capability diagram to reflex the real operational limits of the generator – see Fig. 4–50 (next slide) Short-Time Operation and Service Factor Unfortunately the power diagram has reactive power, Q, as its x–axis and real of active power, P, a its y–axis All electrical machines (not just synchronous machines) can operate above their rated current values for short periods of time The time the current can be above the rated current value depends on the thermal capacity or thermal time constant of the machine 33 / 36 4.11 Synchronous Generator Ratings (cont.) 34 / 36 4.11 Synchronous Generator Ratings (cont.) The service factor of a machine indicates at what level the machine can operate indefinitely Per-Unit System Revisited – see also 2.6 & 2.10 S3φ,base = S3φ,rated S3φ,base S1φ,base = 3 VL,rated V1φ,base = √ 3 S1φ,base I1φ,base = V1φ,base V1φ,base Zbase = I1φ,base 35 / 36 36 / 36