Natural and Step Responses of RLC Circuits Qi Xuan Zhejiang University of Technology Nov 2015 Electric Circuits 1 Structure • Introduc)on to the Natural Response of a Parallel RLC Circuit • The Forms of the Natural Response of a Parallel RLC Circuit • The Step Response of a Parallel RLC Circuit • The Natural and Step Response of a Series RLC Circuit • A Circuit with Two Integra)ng Amplifiers Electric Circuits 2 An Igni)on Circuit The rapidly changing current in the primary winding induces via magne)c coupling (mutual inductance) a very high voltage in the secondary winding. Electric Circuits 3 Introduc)on to the Natural Response of a Parallel RLC Circuit The ini)al voltage on the capacitor, V0 represents the ini)al energy stored in the capacitor. The ini)al current through the inductor, I0 represents the ini)al energy stored in the inductor. Second-ordered circuit Electric Circuits 4 General Solu.on for the Second-­‐ Order Differen.al Equa.on Two roots: Electric Circuits 5 Some Useful Nota.ons Deno)ng the two corresponding solu)ons v1 and v2, respec)vely, we can show that their sum also is a solu)on. Denoting (Proof from Eq. 8.10 to 8.12) Only when s1 ≠ s2 Unit: radians per second (rad/s) We have Electric Circuits 6 Over damped: ω02 < α2 , both roots will be real and dis)nct Under damped: ω02 > α2, two roots will be complex and conjungates Cri.cal damped: ω02 = α2, two roots will be real and equal Electric Circuits 7 Example #1 a) Find the roots of the characteris)c equa)on that governs the transient behavior of the voltage if R = 200 Ω, L=50 mH,and C = 0.2 µF. b) Will the response be overdamped, underdamped, or cri)cally damped? c) Repeat (a) and (b) for R = 312.5 Ω. d) What value of R causes the response to be cri)cally damped? Electric Circuits 8 Solu.on for Example #1 a) For the given values of R, L, and C, we have = 5000 rad/s = 20000 rad/s b) In this case, α2 > ω02, thus the voltage response is overdamped. c) Increase of R will result in decrease of α, thus the voltage response will be from overdamped to underdamped. Electric Circuits 9 d) For cri)cal damping, α2 = ω02, so Electric Circuits 10 The Forms of the Natural Response of a parallel RLC Circuit • Calculate the two roots s1 and s2, based on the given R, L and C; • Determine whether the response is over-­‐, under-­‐, or cri)cally damped; • Find the unknown coefficients, such as A1 and A2 Electric Circuits 11 Overdamped Voltage Response = V0 Electric Circuits 12 We summarize the process for finding the overdamped response, v(t), as follows: 1. Find the roots of the characteris)c equa)on, s1 and s2, using the values of R, L, and C. 2. Find v(0+) and dv(0+)/dt using circuit analysis. 3. Find the values of A1 and A2 by solving the following Equa)ons simultaneously: v(0+) = A1 + A2 dv(0+)/dt = iC(0+)/C = s1A1 + s2A2 4. Subs)tute the values for s1, s2, A1, and A2 into Eq. 8.18 to determine the expression for v(t) for t > 0. Electric Circuits 13 Underdamped Voltage Response B1 Electric Circuits Real! B2 14 Because α determines how quickly the oscilla)ons subside, it is also referred to as the damping factor (or damping coefficient). The oscillatory behavior is possible because of the two types of energy-­‐ storage elements in the circuit: the inductor and the capacitor. Rè∞,αè0 The oscilla)on at ωd = ω0 is sustained! No Dissipa)on on R. Electric Circuits 15 Overdamped or Underdamped? • When specifying the desired response of a second order system, you may want to reach the final value in the shortest .me possible, and you may not be concerned with small oscilla.ons about that final value. If so, you would design the system components to achieve an underdamped response. • On the other hand, you may be concerned that the response not exceed its final value, perhaps to ensure that components are not damaged. In such a case, you would design the system components to achieve an overdamped response, and you would have to accept a rela.vely slow rise to the final value. Electric Circuits 16 Cri.cally Damped Voltage Response In the case of a repeated root, the solu)on involves a simple exponen)al term plus the product of a linear and an exponen)al term. You will rarely encounter cri)cally damped systems in prac)ce, largely because ω0 must equal α exactly. Both of these quan))es depend on circuit parameters, and in a real circuit it is very difficult to choose component values that sa)sfy an exact equality rela)onship. Electric Circuits 17 Example #2 In the given circuit, V0 = 0 and I0 = -12.25 mA. a) Calculate the roots of the characteris)c equa)on. b) Calculate v and dv/dt at t = 0. c) Calculate the voltage response for t ≥ 0. d) Plot v(t) versus t for the )me interval 0 ≤ t ≤ 11 ms. Electric Circuits 18 a) Solu.on for Example #2 Underdamped b) Electric Circuits 19 =0 = 98,000 V/s Electric Circuits 20 Step Response of a Parallel RLC Circuit Electric Circuits 21 The Indirect Approach Electric Circuits 22 The Direct Approach =I =0 Electric Circuits 23 Example #3 The ini)al energy stored in the given circuit is zero. At t = 0, a dc current source of 24 mA is applied to the circuit. The value of the resistor is 400 Ω. a) What is the ini)al value of iL? b) What is the ini)al value of diL/dt? c) What are the roots of the characteris)c equa)on? d) What is the numerical expression for iL(t) when t > 0? Electric Circuits 24 Solu.on for Example #3 a) No energy is stored in the circuit prior to the applica)on of the dc current source, so the ini.al current in the inductor is zero. The inductor prohibits an instantaneous change in inductor current; therefore iL(0) = 0 immediately a`er the switch has been opened. b) The ini.al voltage on the capacitor is zero before the switch has been opened; therefore it will be zero immediately a`er. Now, because v = LdiL/dt, we have Electric Circuits 25 c) From the circuit elements, we obtain Overdamped d) If = I = 24 mA Electric Circuits 26 The Natural Response of a Series RLC Circuit Differen)ate Rearrange Electric Circuits 27 Electric Circuits 28 The Step Response of a Series RLC Circuit Compare Eq. 8.66 and Eq. 8.41: the procedure for finding vC parallels that for finding iL Electric Circuits 29 Example #4 No energy is stored in the 100 mH inductor or the 0.4 µF capacitor when the switch in the given circuit is closed. Find vC(t) for t > 0. Electric Circuits 30 Solu.on for Example #4 Calculate the two roots: The roots are complex, so the voltage response is underdamped. Thus, we have No energy is stored in the circuit ini)ally, so both vC(0) and dvC(0+)/dt are zero, then Electric Circuits 31 A Circuit with Two Integra)ng Amplifier Two integra)ng amplifiers connected in cascade: the output signal of the first amplifier is the input signal for the second amplifier. For the first integrator: For the second integrator: Second-­‐order Electric Circuits 32 Example #5 No energy is stored in the given circuit when the input voltage vg jumps instantaneously from 0 to 25 mV. a) Derive the expression for vo(t) for 0 < t < tsat. b) How long is it before the circuit saturates? Electric Circuits 33 Solu.on for Example #5 a) Integrate b) When t = 3 s, the second amplifier saturates, at that time we get: = -3 V > -5 V Electric Circuits The first amplifier doesn’t saturates! 34 Summary • characteris)c equa)on • Second-­‐order differen)al equa)on • Overdamped, underdamped, and cri)cal damped • Natural Step responses Electric Circuits 35