Fundamentals of Physics Chapter 26 Capacitance 1. 2. 3. 4. 5. 6. 7. 8. The Uses of Capacitors Capacitance Calculating the Capacitance Capacitors in Parallel & Series Energy Stored in an Electric Field Capacitor with a Dielectric Dielectrics: An Atomic View Dielectrics & Gauss Law Review & Summary Chapter Questions Exercises & Problems 2006 Physics 2112 Fundamentals of Physics Chapter 25 1 Capacitor 2006 Physics 2112 Fundamentals of Physics Chapter 25 2 Capacitors A Capacitor accumulates, stores or supplies charge in response to a potential difference being placed across it. A parallel-plate capacitor: Equal and opposite charges on its plates. The plates are conductors; hence each plate is an equipotential surface. The Capacitor stores electric potential energy in the electric field between its plates. 2006 Physics 2112 Fundamentals of Physics Chapter 25 3 Capacitance A parallel-plate capacitor: The charge on the plates is proportional to the potential difference between the plates: q = CV C = capacitance C only depends on the geometry of the plates, such as their area and separation. SI Unit: the farad 1F = 1C/V 2006 Physics 2112 Fundamentals of Physics Chapter 25 4 Charging a Capacitor Initially there is no charge on the capacitor. The power supply or battery does work to move charges onto the plates of the capacitor until the potential difference across the capacitor reaches V. Potential energy is being stored up in the electric field between the plates. q CV Battery Switch Capacitor 2006 Physics 2112 Fundamentals of Physics Chapter 25 5 Calculating the Capacitance Use Gauss Law to calculate the charge on the capacitor: q 0 0 E dA qenc Calculate the potential difference across the capacitor: V Vf Vi E ds Calculate the capacitance : C 2006 Physics 2112 q V Fundamentals of Physics Chapter 25 6 Calculating the Capacitance for Parallel Plates qenc 0 q 0 C C 2006 V EA V q V E ds Ed EA Ed 0 0 d Physics 2112 A 0 = 8.85 x 10-12 F/m = 8.85 pF/m) Fundamentals of Physics Chapter 25 7 Calculating the Capacitance for Parallel Plates Consider 2 Parallel Charged Planes: E 2 2 0 0 0 +++++++++++++++++++++++++++++ E 2 2 0 A >> d 0 0 ----------------------------E 2006 2 0 Physics 2112 2 0 0 Fundamentals of Physics Chapter 25 8 Example: Variable Capacitor in an old radio C Area Turning the knob changes the capacitance Increasing or decreasing overlapping area of plates Capacitance determines the resonant frequency of the radio 2006 Physics 2112 Fundamentals of Physics Chapter 25 9 Example: Capacitance Switching in a Computer Keyboard q CV Depressing the key changes the capacitance Charge changes and electric current flows Electronic Detection of Current Signal to Computer 2006 Physics 2112 Fundamentals of Physics Chapter 25 10 Cylindrical Capacitor qenc 0 qenc 0 qenc 0 E 2006 V E ds E dA V E r dr E 2 rL V E dA q 2 q 2 0 Lr V 0 q 2 0 L Lr ln dr q 2 b 0 L a dr r b a Physics 2112 Fundamentals of Physics C q V 2 0 L b ln a Chapter 25 11 Capacitance of Concentric Spherical Shells C q V qenc 0 qenc 0 qenc E 0 E dA V E ds V E r dr E dA E 4 r2 q 4 0 r 2 q V V C 4 0 q 4 4 0 r dr 2 1 a 1 b q b 4 0 q b a 4 0a b ab 0 b a An Isolated Sphere; let b get very large: C 2006 Physics 2112 a dr r2 Fundamentals of Physics 4 0 a Chapter 25 12 Capacitors in Parallel Common potential difference on each capacitor V Va Vb Qi 2006 Physics 2112 Ci V Fundamentals of Physics Chapter 25 13 Capacitors in Parallel Each capacitor in parallel has the same potential difference across it. The total charge stored on the capacitors is the sum of the charges on all of the capacitors. q q1 q C1 V q C1 q2 q3 C2 V C2 C3 V C3 V Capacitors in parallel can be replaced with an equivalent capacitor that has the same total charge q and the same potential difference V. Ceq q V C1 C2 C3 n Ceq Ci i 1 2006 Physics 2112 Fundamentals of Physics Chapter 25 14 Capacitors in Series Common amount of charge on each capacitor: isolated from the circuit Each plate has the same charge 2006 Physics 2112 Fundamentals of Physics Chapter 25 15 Capacitors in Series For capacitors in series, each capacitor holds the same charge. The sum of the potential differences across all the capacitors is equal to the applied potential difference V. q Vi Ci V V q V1 V2 V3 1 C1 1 C2 1 C3 Capacitors in series can be replaced with an equivalent capacitor that has the same total charge q and the same potential difference V. 1 Ceq 1 Ceq 2006 Physics 2112 1 C1 n i 1 1 C2 1 C3 1 Ci Fundamentals of Physics Chapter 25 16 Example Series Capacitors V 18V Q Ci Vi 12 Vi V4 1 Ceq 1 C2 1 C4 1 Ceq 1 2 F 1 4 F Q Physics 2112 V4 V2 Ceq 2006 V2 6 Vi 3 4 F 1.33 F Ceq V Fundamentals of Physics 24 C Chapter 25 17 Example Series and Parallel Capacitors n in parallel in series Ceq 2006 Physics 2112 Ceq Cn 2 4 6 i 1 1 Ceq n i 1 1 Ci 1 6 1 3 1 2 2 F Fundamentals of Physics Chapter 25 18 Example C1 = 3.55 mF V0 = 6.30 V Battery removed and C2 attached C2 = 8.95 mf Switch is closed, find V 2006 Physics 2112 Fundamentals of Physics Chapter 25 19 Energy Stored in Electric Field The work required to move an element of charge through a potential difference V is: dW W V dq q dq C V dq 1 2 q2 C This work is stored as electrostatic potential energy in the capacitor: U 2006 W 1 2 Physics 2112 q2 C 1 2 CV 2 Fundamentals of Physics Chapter 25 20 Energy Stored in an Electric Field This work done in charging a capacitor is stored as electrostatic potential energy in the capacitor: U W C 0 1 2 q2 C 1 2 CV 2 A d This energy is stored in the electric field between the plates of the capacitor. The energy density, u, is the potential energy per unit volume of electric field: u = ½ 0 E2 Where ever an electric field exists, u is the electric potential energy per unit volume at that point. 2006 Physics 2112 Fundamentals of Physics Chapter 25 21 Example 4 Isolated Sphere has R = 6.85 q = 1.25 nC a) What is potential energy stored in sphere b) What is the energy density at the surface of the sphere? 2006 Physics 2112 Fundamentals of Physics Chapter 25 22 Capacitor with a Dielectric If an insulator (aka a dielectric) is used in a capacitor, the capacitance is increased by a factor k, the dielectric constant. V Cair V C = Cair In a region filled with a material with dielectric constant , all electrostatic equations containing 0 are modified by replacing 0 by 0. 2006 Physics 2112 Fundamentals of Physics Chapter 25 23 Example 5 A parallel-plate capacitor whose capacitance is 13.5 pF is charged by a battery to a potential difference V=12.5 V between its plates. The charging battery is now disconnected and a porcelain slab ( = 6.50) is slipped between the plates. What is the potential energy of the capacitorslab both before and after the slab is put into place. 2006 Physics 2112 Fundamentals of Physics Chapter 25 24 Molecular View of a Dielectric Dipoles, permanent or induced, tend to align with an electric field, producing an internal electric field in the opposite direction. 2006 Physics 2112 Fundamentals of Physics Chapter 25 25 Surface Charge of a Dielectric Electrically neutral atoms in a dielectric material. The atoms acquire an induced dipole moment in an electric field, and align with the field direction. The aligned atoms induce charges on the surfaces of the dielectric, resulting in an electric field in the opposite direction of the original field. The surface charge induced on the surface of the dielectric weakens the original electric field between the plates. 2006 Physics 2112 Fundamentals of Physics Chapter 25 26 Surface Charge of a Dielectric The surface charge induced on the surface of the dielectric weakens the original electric field between the plates. E polystyrene: dry air: 2006 Dielectric Constant = 2.6 Dielectric Constant = 1.0005 Physics 2112 E0 Dielectric Strength = 24 kV/mm Dielectric Strength = 3 kV/mm Fundamentals of Physics Chapter 25 27 Dielectrics and Gauss Law 0 0 E dA qenc E0 q 0 qenc (qenc includes only the charge on the plates) E E E dA E A q q 0 A In a region filled with a material with dielectric constant k, all electrostatic equations containing e0 are modified by replacing 0 by k 0. 2006 Physics 2112 Fundamentals of Physics Chapter 25 28 Example 6 A= 115 cm2 d=1.24 m V0=85.5 V b = 0.780 cm k = 2.61 (inserted after battery disconnected) a) Capacitance C0 before slab is inserted b) Free charge appearing on plates c) E0 in gap between plate and slab d) E1 in slab 2006 Physics 2112 Fundamentals of Physics Chapter 25 29 This document was created with Win2PDF available at http://www.daneprairie.com. The unregistered version of Win2PDF is for evaluation or non-commercial use only.