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BSNL JE (TTA) 26 September 2016 Shift 1 Paper

- 50%
- 35%
- 70%
- 40%

Option 1 : 50%

Effective modulation index will be:

\({\rm{\mu }} = \sqrt {{\rm{\mu }}_1^2 + {\rm{\mu }}_2^2}\)

Given \({{\rm{\mu }}_1} = 0.3\) and \({{\rm{\mu }}_2} = 0.4\)

The overall modulation index will be:

\({\rm{\mu }} = \sqrt {0.09 + 0.16} = \sqrt {0.25} = 0.5\)

In percentage, \({\rm{\mu }} = 50{\rm{\;\% }}\)
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