Chapter 2 Algebraic Methods for the Analysis and Synthesis of Logic Circuits Chapter 2 1 Fundamentals of Boolean Algebra (1) • • • • • • • • Basic Postulates Postulate 1 (Definition): A Boolean algebra is a closed algebraic system containing a set K of two or more elements and the two operators and +. Postulate 2 (Existence of 1 and 0 element): (a) a + 0 = a (identity for +), (b) a 1 = a (identity for ) Postulate 3 (Commutativity): (a) a + b = b + a, (b) a b = b a Postulate 4 (Associativity): (a) a + (b + c) = (a + b) + c (b) a (bc) = (ab) c Postulate 5 (Distributivity): (a) a + (bc) = (a + b) (a + c) (b) a (b + c) = ab + ac Postulate 6 (Existence of complement): (a) a a 1 (b) a a 0 Normally is omitted. Chapter 2 2 Fundamentals of Boolean Algebra (2) • Fundamental Theorems of Boolean Algebra • • Theorem 1 (Idempotency): (a) a + a = a Theorem 2 (Null element): (a) a + 1 = 1 Theorem 3 (Involution) • a a Properties of 0 and 1 elements (Table 2.1): • OR a+0=0 a+1=1 Chapter 2 AND a0 = 0 a1 = a (b) aa = a (b) a0 = 0 Complement 0' = 1 1' = 0 3 Fundamentals of Boolean Algebra (3) • • • • Theorem 4 (Absorption) (a) a + ab = a (b) a(a + b) = a Examples: – (X + Y) + (X + Y)Z = X + Y – AB'(AB' + B'C) = AB' [T4(a)] [T4(b)] Theorem 5 (a) a + a'b = a + b (b) a(a' + b) = ab Examples: – B + AB'C'D = B + AC'D – (X + Y)((X + Y)' + Z) = (X + Y)Z Chapter 2 [T5(a)] [T5(b)] 4 Fundamentals of Boolean Algebra (4) • • Theorem 6 (a) ab + ab' = a (b) (a + b)(a + b') = a Examples: – ABC + AB'C = AC [T6(a)] – (W' + X' + Y' + Z')(W' + X' + Y' + Z)(W' + X' + Y + Z')(W' + X' + Y + Z) = (W' + X' + Y')(W' + X' + Y + Z')(W' + X' + Y + Z) [T6(b)] = (W' + X' + Y')(W' + X' + Y) [T6(b)] = (W' + X') [T6(b)] Chapter 2 5 Fundamentals of Boolean Algebra (5) • • Theorem 7 (a) ab + ab'c = ab + ac Examples: – wy' + wx'y + wxyz + wxz' (b) (a + b)(a + b' + c) = (a + b)(a + c) = wy' + wx'y + wxy + wxz' = wy' + wy + wxz' = w + wxz' =w – (x'y' + z)(w + x'y' + z') = (x'y' + z)(w + x'y') Chapter 2 [T7(a)] [T7(a)] [T7(a)] [T7(a)] [T7(b)] 6 Fundamentals of Boolean Algebra (6) • Theorem 8 (DeMorgan's Theorem) (a) (a + b)' = a'b' (b) (ab)' = a' + b' • Generalized DeMorgan's Theorem (a) (a + b + … z)' = a'b' … z' (b) (ab … z)' = a' + b' + … z' • Examples: – (a + bc)' = (a + (bc))' = a'(bc)' = a'(b' + c') = a'b' + a'c' – Note: (a + bc)' a'b' + c' Chapter 2 [T8(a)] [T8(b)] [P5(b)] 7 Fundamentals of Boolean Algebra (7) • More Examples for DeMorgan's Theorem – (a(b + z(x + a')))' = a' + (b + z(x + a'))' = a' + b' (z(x + a'))' = a' + b' (z' + (x + a')') = a' + b' (z' + x'(a')') = a' + b' (z' + x'a) = a' + b' (z' + x') – (a(b + c) + a'b)' Chapter 2 = (ab + ac + a'b)' = (b + ac)' = b'(ac)' = b'(a' + c') [T8(b)] [T8(a)] [T8(b)] [T8(a)] [T3] [T5(a)] [P5(b)] [T6(a)] [T8(a)] [T8(b)] 8 Fundamentals of Boolean Algebra (8) • • Theorem 9 (Consensus) (a) ab + a'c + bc = ab + a'c (b) (a + b)(a' + c)(b + c) = (a + b)(a' + c) Examples: – AB + A'CD + BCD = AB + A'CD – (a + b')(a' + c)(b' + c) = (a + b')(a' + c) – ABC + A'D + B'D + CD = ABC + (A' + B')D + CD = ABC + (AB)'D + CD = ABC + (AB)'D = ABC + (A' + B')D = ABC + A'D + B'D Chapter 2 [T9(a)] [T9(b)] [P5(b)] [T8(b)] [T9(a)] [T8(b)] [P5(b)] 9 Switching Functions • • • Switching algebra: Boolean algebra with the set of elements K = {0, 1} If there are n variables, we can define 22 switching functions. Sixteen functions of two variables (Table 2.3): n AB f0 f1 f2 f3 f4 f5 f6 f7 f8 f9 f10 f11 f12 f13 f14 f15 00 01 10 11 • • • 0 0 0 0 1 0 0 0 0 1 0 0 1 1 0 0 0 0 1 0 1 0 1 0 0 1 1 0 1 1 1 0 0 0 0 1 1 0 0 1 0 1 0 1 1 1 0 1 0 0 1 1 1 0 1 1 0 1 1 1 1 1 1 1 A switching function can be represented by a table as above, or by a switching expression as follows: f0(A,B)= 0, f6(A,B) = AB' + A'B, f11(A,B) = AB + A'B + A'B' = A' + B, ... Value of a function can be obtained by plugging in the values of all variables: The value of f6 when A = 1 and B = 0 is: 1 0'1'0 = 0 + 1 = 1. Chapter 2 10 Truth Tables (1) • • Shows the value of a function for all possible input combinations. Truth tables for OR, AND, and NOT (Table 2.4): Chapter 2 ab f(a,b)=a+b ab f(a,b)=ab a f(a)=a' 00 01 10 0 1 1 00 01 10 0 0 0 0 1 1 0 11 1 11 1 11 Truth Tables (2) • Truth tables for f(A,B,C) = AB + A'C + AC' (Table 2.5) Chapter 2 ABC f(A,B,C) ABC f(A,B,C) 000 001 010 011 0 1 0 1 FFF FFT FTF FTT F T F T 100 101 110 111 1 0 1 1 TFF TFT TTF TTT T F T T 12 Algebraic Forms of Switching Functions (1) • • • Literal: A variable, complemented or uncomplemented. Product term: A literal or literals ANDed together. Sum term: A literal or literals ORed together. • • • SOP (Sum of Products): ORing product terms f(A, B, C) = ABC + A'C + B'C • • • POS (Product of Sums) ANDing sum terms f (A, B, C) = (A' + B' + C')(A + C')(B + C') Chapter 2 13 Algebraic Forms of Switching Functions (2) • • • A minterm is a product term in which all the variables appear exactly once either complemented or uncomplemented. Canonical Sum of Products (canonical SOP): – Represented as a sum of minterms only. – Example: f1(A,B,C) = A'BC' + ABC' + A'BC + ABC (2.1) Minterms of three variables: Minterm A'B'C' A'B'C A'BC' A'BC AB'C' AB'C ABC' ABC Chapter 2 Minterm Code 000 001 010 011 100 101 110 111 Minterm Number m0 m1 m2 m3 m4 m5 m6 m7 14 Algebraic Forms of Switching Functions (3) • • • • Compact form of canonical SOP form: f1(A,B,C) = m2 + m3 + m6 + m7 A further simplified form: f1(A,B,C) = S m (2,3,6,7) (minterm list form) The order of variables in the functional notation is important. Deriving truth table of f1(A,B,C) from minterm list: Row No. Inputs (i) ABC 0 000 1 001 2 010 3 011 4 100 5 101 6 110 7 111 Chapter 2 Outputs f1(A,B,C)=Sm(2,3,6,7) 0 0 1 m2 1 m3 0 0 1 m6 1 m7 (2.2) (2.3) Complement f1'(A,B,C)=Sm(0,1,4,5) 1 m0 1 m1 0 0 1 m4 1 m5 0 0 15 Algebraic Forms of Switching Functions (4) • • • Example: Given f(A,B,Q,Z) = A'B'Q'Z' + A'B'Q'Z + A'BQZ' + A'BQZ, express f(A,B,Q,Z) and f '(A,B,Q,Z) in minterm list form. f(A,B,Q,Z) = A'B'Q'Z' + A'B'Q'Z + A'BQZ' + A'BQZ = m0 + m1 + m6 + m7 = S m(0, 1, 6, 7) f '(A,B,Q,Z) = m2 + m3 + m4 + m5 + m8 + m9 + m10 + m11 + m12 + m13 + m14 + m15 = S m(2, 3, 4, 5, 8, 9, 10, 11, 12, 13, 14, 15) 2 n 1 m i 0 i 1 (2.6) AB + (AB)' = 1 and AB + A' + B' = 1, but AB + A'B' 1. Chapter 2 16 Algebraic Forms of Switching Functions (5) • • • A maxterm is a sum term in which all the variables appear exactly once either complemented or uncomplemented. Canonical Product of Sums (canonical POS): – Represented as a product of maxterms only. – Example: f2(A,B,C) = (A+B+C)(A+B+C')(A'+B+C)(A'+B+C') (2.7) Maxterms of three variables: Maxterm A+B+C A+B+C' A+B'+C A+B'+C' A'+B+C A'+B+C' A'+B'+C A'+B'+C' Chapter 2 Maxterm Code 000 001 010 011 100 101 110 111 Maxterm Number M0 M1 M2 M3 M4 M5 M6 M7 17 Algebraic Forms of Switching Functions (6) • f2(A,B,C) = M0M1M4M5 = PM(0,1,4,5) (maxterm list form) • The truth table for f2(A,B,C): (2.8) (2.9) Rwo No. Inputs M0 M1 M4 M5 Outputs (i) ABC A+B+C A+B+C' A'+B+C A'+B+C' f2(A,B,C) 0 000 0 1 1 1 0 1 001 1 0 1 1 0 2 010 1 1 1 1 1 3 011 1 1 1 1 1 4 100 1 1 0 1 0 5 101 1 1 1 0 0 6 110 1 1 1 1 1 7 111 1 1 1 1 1 Chapter 2 18 Algebraic Forms of Switching Functions (7) • • • Truth tables of f1(A,B,C) of Eq. (2.3) and f2(A,B,C) of Eq. (2.7) are identical. Hence, f1(A,B,C) = S m (2,3,6,7) = f2(A,B,C) = PM(0,1,4,5) (2.10) Example: Given f(A,B,C) = ( A+B+C')(A+B'+C')(A'+B+C')(A'+B'+C'), construct the truth table and express in both maxterm and minterm form. – f(A,B,C) = M1M3M5M7 = PM(1,3,5,7) = S m (0,2,4,6) Chapter 2 Row No. (i) 0 1 2 3 4 5 6 7 Inputs ABC 000 001 010 011 100 101 110 111 Outputs f(A,B,C)= PM(1,3,5,7) = Sm(0,2,4,6) 1 m0 0 M1 1 m2 0 M3 1 m4 0 M5 1 m6 0 M7 19 Algebraic Forms of Switching Functions (8) • Relationship between minterm mi and maxterm Mi: – For f(A,B,C), (m1)' = (A'B'C)' = A + B + C' = M1 – In general, (mi)' = Mi (Mi)' = ((mi)')' = mi Chapter 2 (2.11) (2.12) 20 Algebraic Forms of Switching Functions (9) • Example: Relationship between the maxterms for a function and its complement. – For f(A,B,C) = ( A+B+C')(A+B'+C')(A'+B+C')(A'+B'+C') – The truth table is: Row No. Inputs (i) ABC 0 000 1 001 2 010 3 011 4 100 5 101 6 110 7 111 Chapter 2 Outputs f (A,B,C) 1 0 1 0 1 0 1 0 Outputs f '(A,B,C)= PM(0,2,4,6) 0 M0 1 0 M2 1 0 M4 1 0 M6 1 21 Algebraic Forms of Switching Functions (10) – From the truth table f '(A,B,C) = PM(0,2,4,6) and f(A,B,C) = PM(1,3,5,7) – Since f(A,B,C) f '(A,B,C) = 0, (M0M2M4M6)(M1M3M5M7) = 0 or M 0 – In general, M 0 – Another observation from the truth table: f(A,B,C) = S m (0,2,4,6) = PM(1,3,5,7) f '(A,B,C) = S m (1,3,5,7) = PM(0,2,4,6) 2 3 1 i 0 2 n 1 i 0 Chapter 2 i i (2.13) 22 Derivation of Canonical Forms (1) • • Derive canonical POS or SOP using switching algebra. Theorem 10. Shannon's expansion theorem (a). f(x1, x2, …, xn) = x1 f(1, x2, …, xn) + (x1)' f(0, x2, …, xn) (b). f(x1, x2, …, xn) = [x1 + f(0, x2, …, xn)] [(x1)' + f(1, x2, …, xn)] • Example: f(A,B,C) = AB + AC' + A'C – f(A,B,C) = AB + AC' + A'C = A f(1,B,C) + A' f(0,B,C) = A(1B + 1C' + 1'C) + A'(0B + 0C' + 0'C) = A(B + C') + A'C – f(A,B,C) = A(B + C') + A'C = B[A(1+C') + A'C] + B'[A(0 + C') + A'C] = B[A + A'C] + B'[AC' + A'C] = AB + A'BC + AB'C' + A'B'C – f(A,B,C) = AB + A'BC + AB'C' + A'B'C = C[AB + A'B1 + AB'1' + A'B'1] + C'[AB + A'B0 + AB'0' + A'B'0] = ABC + A'BC + A'B'C + ABC' + AB'C' Chapter 2 23 Derivation of Canonical Forms (2) • • Alternative: Use Theorem 6 to add missing literals. Example: f(A,B,C) = AB + AC' + A'C to canonical SOP form. – AB = ABC' + ABC = m6 + m7 – AC' = AB'C' + ABC' = m4 + m6 – A'C = A'B'C + A'BC = m1 + m3 – Therefore, f(A,B,C) = (m6 + m7) + (m4 + m6) + (m1 + m3) = Sm(1, 3, 4, 6, 7) • Example: f(A,B,C) = A(A + C') to canonical POS form. – A = (A+B')(A+B) = (A+B'+C')(A+B'+C)(A+B+C')(A+B+C) = M3M2M1M0 – (A+C')= (A+B'+C')(A+B+C') = M3M1 – Therefore, f(A,B,C) = (M3M2M1M0)(M3M1) = PM(0, 1, 2, 3) Chapter 2 24 Incompletely Specified Functions • • • • • A switching function may be incompletely specified. Some minterms are omitted, which are called don't-care minterms. Don't cares arise in two ways: – Certain input combinations never occur. – Output is required to be 1 or 0 only for certain combinations. Don't care minterms: di Don't care maxterms: Di Example: f(A,B,C) has minterms m0, m3, and m7 and don't-cares d4 and d5. – Minterm list is: f(A,B,C) = Sm(0,3,7) + d(4,5) – Maxterm list is: f(A,B,C) = PM(1,2,6)·D(4,5) – f '(A,B,C) = Sm(1,2,6) + d(4,5) = PM(0,3,7)·D(4,5) – f (A,B,C)= A'B'C' + A'BC + ABC + d(AB'C' + AB'C) = B'C' + BC (use d4 and omit d5) Chapter 2 25 Electronic Logic Gates (1) • Electrical Signals and Logic Values Electric Signal High Voltage (H) Low Voltage (L) Logic Value Positive Logic Negative Logic 1 0 0 1 – A signal that is set to logic 1 is said to be asserted, active, or true. – An active-high signal is asserted when it is high (positive logic). – An active-low signal is asserted when it is low (negative logic). Chapter 2 26 Electronic Logic Gates (2) AND OR a b a b NOT a NAND NOR a b a b a EXCLUSIVE OR b f(a, b) =ab f(a, b) =a + b f(a) =a f(a, b) =ab f(a, b) =a + b f(a, b) =a b Symbol set 1 Chapter 2 AND OR NOT NAND NOR a b a & f(a, b) =ab ³ 1 f(a, b) =a + b 1 f(a) =a & f(a, b) =ab ³ 1 f(a, b) =a + b b a b a b a b a EXCLUSIVE OR b =1 f(a, b) =a b Symbol set 2 (ANSI/IEEE Standard 91-1984) 27 Electronic Logic Gates (3) Vcc 14 4B 13 4A 12 4Y 11 3B 10 3A 9 3Y 8 Vcc 14 4Y 13 4B 12 4A 11 3Y 10 3B 9 3A 8 1 1A 2 1B 3 1Y 4 2A 5 2B 6 2Y 7 GND 1 1Y 2 1A 3 1B 4 2Y 5 2A 6 2B 7 GND 7400: Y =AB Quadruple two-input NAND gates Vcc 14 6A 13 6Y 12 5A 11 5Y 10 4A 9 4Y 8 Vcc 14 4B 13 4A 12 4Y 11 3B 10 3A 9 3Y 8 1 1A 2 1Y 3 2A 4 2Y 5 3A 6 3Y 7 GND 1 1A 2 1B 3 1Y 4 2A 5 2B 6 2Y 7 GND 7404: Y =A Hex inverters Chapter 2 7402: Y =A + B Quadruple two-input NOR gates 7408: Y =AB Quadruple two-input AND gates 28 Electronic Logic Gates (4) Vcc 1C 1Y 3C 3B 3A 3Y Vcc 2D 2C NC 2B 2A 2Y 14 13 12 11 10 9 8 14 13 12 11 10 9 8 1 2 3 4 5 6 7 1 2 3 4 5 6 7 1A 1B 2A 2B 2C 2Y GND 1A 1B NC 1C 1D 1Y GND 7410: Y =ABC Triple three-input NAND gates Chapter 2 7420: Y =ABCD Dual four-input NAND gates 29 Electronic Logic Gates (5) Vcc NC H G NC NC Y Vcc 4B 4A 4Y 3B 3A 3Y 14 13 12 11 10 9 8 14 13 12 11 10 9 8 1 2 3 4 5 6 7 1 2 3 4 5 6 7 A B C D E F GND 1A 1B 1Y 2A 2B 2Y GND 7430: Y =ABCDEFGH 8-input NAND gate 7432: Y =A + B Quadruple two-input OR gates Vcc 4B 4A 4Y 3B 3A 3Y 14 13 12 11 10 9 8 1 2 3 4 5 6 7 1A 1B 1Y 2A 2B 2Y GND 7486: Y =A Å B Quadruple two-input exclusive-OR gates Chapter 2 30 Basic Functional Components (1) • AND a b 0 0 1 1 0 1 0 1 fAND(a, b) =ab 0 0 0 1 (a) A B Y L L H H L H L H (b) L L L H A B Y (c) A B & Y (d) (a) AND logic function. (b) Electronic AND gate. (c) Standard symbol. (d) IEEE block symbol. Chapter 2 31 Basic Functional Components (2) • OR a b fOR(a, b) =a + b A B Y 0 0 1 1 L L L H HL HH 0 1 0 1 0 1 1 1 (a) (b) L H H H A B Y (c) A B Y (d) (a) OR logic function. (b) Electronic OR gate. (c) Standard symbol. (d) IEEE block symbol. Chapter 2 32 Basic Functional Components (3) • Meaning of the designation 1 in IEEE symbol: ab 00 01 10 11 Chapter 2 sum(a, b) 0 1 1 2 sum(a, b) 1 False True True True fOR(a, b) = a + b 0 1 1 1 33 Basic Functional Components (4) • NOT A a 0 1 fNOT(a) =a 1 0 (a) (c) A Y L H H L (b) Y A 1 Y (d) (a) NOT logic function. (b) Electronic NOT gate. (c) Standard symbol. (d) IEEE block symbol. Chapter 2 34 Basic Functional Components (5) • Positive Versus Negative Logic 1 is represented by 0 is represented by Chapter 2 Positive Logic High Voltage Low Voltage Negative Logic Low Voltage High Voltage 35 Basic Functional Components (6) • AND Gate Usage in Negative Logic A B Y 1 1 0 0 1 0 1 0 (a) 1 1 1 0 a b A B Y (b) y =a +b (c) a b y = ab (d) – – – – – – Chapter 2 (a) AND gate truth table (L = 1, H = 0) (b) Alternate AND gate symbol (in negative logic) (c) Preferred usage (d) Improper usage y = a·b = a b a b fOR(a , b ) y (a ) (b ) a b fOR(a, b) (2.14) (2.15) 36 Basic Functional Components (7) • OR Gate Usage in Negative Logic A B Y 1 1 0 0 1 0 1 0 (a) 1 0 0 0 a b A B Y (b) y = ab (c) a b y =a +b (d) – – – – – – Chapter 2 (a) OR gate truth table(L = 1, H = 0) (b) Alternate OR gate symbol (in negative logic) (c) Preferred usage (d) Improper usage y a b a b a b fAND(a , b ) y (a ) (b ) a b fAND(a, b) (2.16) (2.17) 37 Basic Functional Components (8) • Example 2.32: Building smoke alarm system – Components: two smoke detectors, a sprinkler, and an automatic telephone dialer – Behavior: • Sprinkler is activated if either smoke detector detects smoke. • When both smoke detector detect smoke, fire department is called. – Signals: • D1, D 2 : Active-low outputs from two smoke detectors. • : Active-low input to the sprinkler SPK • DIAL : Active-low input to the telephone dialer. – Logic equations • SPK D1 D2 (2.18) • (2.19) DIAL D1 D 2 Chapter 2 38 Basic Functional Components (9) • Logic diagram of the smoke alarm system Smoke detectors D1 D2 G1 D1 + D2 Sprinkler SPK G2 D1 D2 Telephone dialer DIAL Chapter 2 39 Basic Functional Components (10) • NAND a b 0 0 1 1 fNAND(a, b) =ab 0 1 0 1 A B Y 1 1 1 0 L L H L H H HL H HH L (b) (a) A B Y (c) – – – – Chapter 2 A B Y (d) A B & Y (e) (a) NAND logic function (b) Electronic NAND gate (c) Standard symbol (d) IEEE block symbol 40 Basic Functional Components (10) • Matching signal polarity to NAND gate inputs/outputs – (a) Preferred usage (b) Improper usage a b y a b y a b y a b y (a) • (b) Additional properties of NAND gate: fNAND (a, a) a a a fNOT (a) fNAND (a, b) a b a b fAND(a, b) • fNAND (a , b ) a b a b fOR(a, b) Hence, NAND gate may be used to implement all three elementary operators. Chapter 2 41 Basic Functional Components (11) • AND, OR, and NOT gates constructed exclusively from NAND gates a b ab f(a, b) =ab= ab AND gate a a f(a, a) = aa = a NOT gate a f(a, b) =a + b = a + b b b OR gate Chapter 2 42 Basic Functional Components (12) • NOR a b 0 0 1 1 fNOR(a, b) =a + b 0 1 0 1 A B Y 1 0 0 0 L L H H (a) A B Y (c) – – – – Chapter 2 A B Y (d) A B L H H L L L H L (b) ³1 Y (e) (a) NAND logic function (b) Electronic NAND gate (c) Standard symbol (d) IEEE block symbol 43 Basic Functional Components (13) • Matching signal polarity to NOR gate inputs/outputs – (a) Preferred usage (b) Improper usage a b y a b y a b y a b y (a) • (b) Additional properties of NAND gate: fNOR (a, a) a a a fNOT (a) fNOR (a, b) a b a b fOR(a, b) • fNOR (a , b ) a b a b fAND(a, b) Hence, NAND gate may be used to implement all three elementary operators. Chapter 2 44 Basic Functional Components (14) • AND, OR, and NOT gates constructed exclusively from NOR gates. a b a +b f(a, b) =a + b a OR gate a f(a, a) =a + a = a NOT gate a f(a, b) =ab= ab b b AND gate Chapter 2 45 Basic Functional Components (15) • Exclusive-OR (XOR) – fXOR(a, b) = a b = a b ab ab 00 01 10 11 fXOR(a, b) = a b 0 1 1 0 (2.24) AB LL LH HL HH Y L H H L (a) XOR logic function (b) Electronic XOR gate A B Y (c) Standard symbol Chapter 2 A B =1 Y (d) IEEE block symbol 46 Basic Functional Components (16) • POS of XOR a b a b ab a a a b ab bb a ( a b) b ( a b) (a b )(a b) • Some other useful relationships – aa=0 – a a =1 – a0=a – a1= a – a b a b – ab=ba – a (b c) = (a b) c Chapter 2 [P2(a), P6(b)] [P5(b)] [P5(b)] (2.25) (2.26) (2.27) (2.28) (2.29) (2.30) (2.31) 47 Basic Functional Components (17) • Output of XOR gate is asserted when the mathematical sum of inputs is one: ab 00 01 10 11 • sum(a, b) 0 1 1 2 sum(a, b) = 1? False True True False f(a, b) = a b 0 1 1 0 The output of XOR is the modulo-2 sum of its inputs. Chapter 2 48 Basic Functional Components (18) • Exclusive-NOR (XNOR) – fXNOR(a, b) = a b a a b fXNOR(a, b) =a b AB Y 0 0 1 1 LL H LH L HL L HH H (b) 0 1 0 1 1 0 0 1 (a) – – – – Chapter 2 b (2.32) A B Y (c) A B =1 Y (d) (a) XNOR logic function (b) Electronic XNOR gate (c) Standard symbol (d) IEEE block symbol 49 Basic Functional Components (19) • SOP and POS of XNOR a b ab a b ab a b ab (a b )(a b) aa ab a b b b ab a b • a b = a Chapter 2 [P2] [T8(a)] [T8(b)] [P5(b)] [P6(b), P2(a)] b 50 Analysis of Combinational Circuits (1) • Digital Circuit Design: – Word description of a function a set of switching equations hardware realization (gates, programmable logic devices, etc.) • Digital Circuit Analysis: – Hardware realization switching expressions, truth tables, timing diagrams, etc. • Analysis is used – To determine the behavior of the circuit – To verify the correctness of the circuit – To assist in converting the circuit to a different form. Chapter 2 51 Analysis of Combinational Circuits (2) • Algebraic Method: Use switching algebra to derive a desired form. • Example 2.33: Find a simplified switching expressions and logic network for the following logic circuit (Fig. 2.21a). a b a c b c P1 P4 f (a, b, c) P2 P3 (a) Chapter 2 52 Analysis of Combinational Circuits (3) • • • Write switching expression for each gate output: – P ab, P a c, P3 b c , P4 P1 P2 ab (a c) 1 2 The output is: f (a, b, c) P P (b c ) ab (a c) 3 4 Simplify the output function using switching algebra: f (a, b, c) (b c ) ab a c [Eq. 2.24] bc b c ab a c [T8] bc b c (a b )ac [T5(b)] bc b c ab c [T4(a)] bc b c [Eq. 2.32] f (a, b, c) = b c Therefore, f (a,b,c) = (b c)' = b c b c Chapter 2 f (a, b, c) 53 Analysis of Combinational Circuits (4) • Example 2.34: Find a simplified switching expressions and logic network for the following logic circuit (Fig. 2.22). a b b c a b a c a b (a b b)(b c) c f (a, b, c) a +b a +b +a +c a +c Given circuit Chapter 2 54 Analysis of Combinational Circuits (5) • Derive the output expression: f(a,b,c) = (a b)(b c) (a b a c) = (a b)(b c) a b a c) = (a b)(b c) (a b )(a c) = (ab a b)(bc b c) (a b )(a c) = ab bc ab b c a bbc a bb c a a a c ab b c = ab c a bc a c ab b c = a bc a c ab b c = a bc a c ab a = a b a c ab c f (a, b, c) = ac a b a b [T8(b)] [T8(a)] [Eq. 2.24] [P5(b)] [P6(b), T4(a)] [T4(a)] [T9(a)] [T7(a)] [Eq. 2.24] Simplified circuit Chapter 2 55 Analysis of Combinational Circuits (6) • Truth Table Method: Derive the truth table one gate at a time. • The truth table for Example 2.34: abc 000 001 010 011 100 101 110 111 Chapter 2 ac 0 1 0 1 0 0 0 0 a b 0 0 1 1 1 1 0 0 f(a,b,c) 0 1 1 1 1 1 0 0 56 Analysis of Combinational Circuits (7) • Analysis of Timing Diagrams – Timing diagram is a graphical representation of input and output signal relationships over the time dimension. – Timing diagrams may show intermediate signals and propagation delays. Chapter 2 57 Analysis of Combinational Circuits (8) • Example 2.35: Derivation of truth table from a timing diagram A A B B Y = fa (A, B, C) C Inputs Outputs Z = fb (A, B, C) Y = fa (A, B, C) Z = fb (A, B, C) C t0 (a) t2 t3 t4 t5 t6 t7 (b) Inputs Time Chapter 2 t1 ABC Outputs fa(A, B, C) fb(A, B, C) t0 000 0 0 t1 001 1 1 t2 010 1 0 t3 011 0 1 t4 100 0 0 t5 101 0 1 t6 110 1 1 t7 111 1 0 (c) 58 Analysis of Combinational Circuits (9) • Propagation Delay – Physical characteristics of a logic circuit to be considered: • Propagation delays • Gate fan-in and fan-out restrictions • Power consumption • Size and weight – Propagation delay: The delay between the time of an input change and the corresponding output change. – Typical two propagation delay parameters: • tPLH = propagation delay time, low-to-high-level output • tPHL = propagation delay time, high-to-low-level output – Approximation: • t t PLH t PHL PD Chapter 2 2 59 Analysis of Combinational Circuits (10) • Propagation delay through a logic gate a b a b c c (a) Two-input AND gate a a b b c c tPD tPD (c)tPD = tPLH= tPHL Chapter 2 (b) Ideal (zero) delay tPLH tPHL (d)tPLH<tPHL 60 Analysis of Combinational Circuits (11) • Power dissipation and propagation delays for several logic families (Table 2.7) Logic Family 7400 74H00 74L00 74LS00 74S00 74ALS00 Propagation Delay tPD(ns) 10 6 33 9.5 3 3.5 Power Dissipation Per Gate (mW) 10 22 1 2 19 1.3 74AS00 74HC00 3 8 8 0.17 Chapter 2 Technology Standard TTL High-speed TTL Low-power TTL Low-power Schottky TTL Schottky TTL Advanced low-power Schottky TTL Advanced Schottky TTL High-speed CMOS 61 Analysis of Combinational Circuits (12) • Propagation delays of primitive 74LS series gates (Table 2.8) Chip 74LS04 74LS00 74LS02 74LS08 74LS32 Function NOT NAND NOR AND OR tPLH Typical Maximum 9 15 9 15 10 15 8 15 14 22 tPHL Typical Maximum 10 15 10 15 10 15 10 20 14 22 22 Chapter 2 62 Analysis of Combinational Circuits (13) • Example 2.36: Given a circuit diagram and the timing diagram, find the truth table and minimum switching expression. D C A F ABC f (A, B, C) 0 0 0 0 1 1 1 1 Y = f (A, B, C) E B G A 0 0 1 1 0 0 1 1 0 1 0 1 0 1 0 1 0 1 0 0 1 1 1 0 B C f ( A, B, C) D E m(1,4,5,6) F A B C AB C AB C AB C G f (A, B, C) t0 t1 t3 t1 + 2t2 t2 + 2 t1 + 1 Chapter 2 t2 + 1 t4 t5 t4 + 3 t4 + 2 t4 + 1 t6 t7 AC B C t7 + 3 t7 + 2 t7 + 1 63 Synthesis of Combinational Logic Circuits (1) • AND-OR and NAND Networks – Switching expression must be in SOP form. – Example: f ( p, q, r , s) pr qrs ps Bubbles Òcancel Ó p r q r s p r fd (p, q, r, s) p s p s (a) AND-OR network – Chapter 2 q r s p r x1 fd (p, q, r, s) x2 x3 (b) NAND network f ( p, q, r , s ) pr qrs ps pr qrs ps x1 x2 x3 where x pr , x qrs, and x ps 1 2 3 q r s x1 x2 fd (p, q, r, s) p x3 s (c) NAND network (preferred form) [T3] [T8(a)] 64 Synthesis of Combinational Logic Circuits (2) • OR-AND and NOR Networks – Switching expression must be in POS form. – Example: f ( A, B, C , D) ( A B C )( B C D)( A D) A B C B C D A B C fe (A, B, C, D) B C D A D A D (a) OR-AND network y1 fe (A, B, C, D) y2 y3 (b) NOR network A B C B C D y1 fe (A, B, C, D) y2 A D y3 (c) NOR network (preferred form) – f ( A, B, C, D) ( A B C )( B C D)( A D) A BC BC D A D [T3] [T8(b)] y1 y2 y3 where y A B C, 1 Chapter 2 y2 B C D, and y3 A D 65 Synthesis of Combinational Logic Circuits (3) • Two-level Circuits – Input signals pass through two levels of gates before reaching the output. p r q r s p s p r x1 fd (p, q, r, s) x2 x3 Level 2 Level 1 (a) Two-level network q r s p s x1 fd (p, q, r, s) x2 x3 Level 3Level 2 Level 1 (b) Three-level network – Implementation procedure for NAND (NOR) logic: • Step 1. Express the function in minterm (maxterm) list form. • Step 2. Write out the minterms (maxterms) in algebraic form. • Step 3. Simplify the function in SOP (POS) form. • Step 4. Transform the expression into the NAND (NOR) form. • Step 5. Draw the NAND (NOR) logic diagram. Chapter 2 66 Synthesis of Combinational Logic Circuits (4) • Circuits with more than two levels are often needed due to fan-in constraints. a b c f = abcde d e (a) A single five-input AND gate a b a b c c d f = abcde e d e (b) Three-level network of two-input gates Chapter 2 f = abcde (c) Four-level network of two-input gates. 67 Synthesis of Combinational Logic Circuits (5) • Example 2.37: NAND implementation of f (X,Y,Z) = Sm(0,3,4,5,7) 1. f (X,Y,Z) = Sm(0,3,4,5,7) 2. f (X,Y,Z) = m0 + m3 + m4 + m5 + m7 XYZ XYZ XYZ XYZ XYZ 3. f ( X , Y , Z ) YZ YZ XZ [T6(a)] 4a. f ( X , Y , Z ) YZ YZ XZ or 4b. f ( X , Y , Z ) YZ YZ XZ Y Z YZ XZ [T4] [T3] [T8(a)] Y Z Y Z X Z Chapter 2 f (X, Y, Z) (a) NAND implementation 68 Synthesis of Combinational Logic Circuits (6) • AND-OR-invert Circuits – A set of AND gates followed by a NOR gate. – Used to readily realize two-level SOP circuits. – 7454 circuit: F AB CD EF GH Make no external connection Vcc 14 B 13 12 11 H 10 G 9 Y 8 Y1 A B Y2 C D Y 1 A Chapter 2 2 C 3 D 4 E 5 F 6 NC 7 GND (a) 7454 circuit package (top view) Y3 E F Y4 G H Output Enable lines (b) 7454 used as a 4-to-1 multiplexer 69 Synthesis of Combinational Logic Circuits (7) • • Factoring – A technique to obtain higher-level forms of switching functions. – Higher-level forms: • May need less hardware • May be used when there are fan-in constraints • More difficult to design • Slower Example 2.39: f ( A, B, C, D) AB AD AC A( B D C ) A( BCD) A B A D A C Chapter 2 A f (A, B, C, D) f (A, B, C, D) B C D (a) Original form (b) After factoring 70 Synthesis of Combinational Logic Circuits (8) • Example 2.40: f (a,b,c,d) = Sm(8,13) with only two-input AND and OR gates. – Write the canonical SOP form: f (a,b,c,d) = Sm(8,13) = ab c d abc d (2.34) Two four-input AND gates and one two-input OR gate are needed. – Apply factoring: (2.35) f (a, b, c, d ) ab c d abc d (ac )(bd b d ) b d f = (a, b, c, d) c a Chapter 2 71 Synthesis of Combinational Logic Circuits (9) • Example 2.41: A burglar alarm with four control switches, each of which produces logic 1 when: Switch A: Secret switch is closed Switch B: Safe is in its normal position in the closet Switch C: Clock is between 1000 and 1400 hours Switch D: Closet door is closed. Write the equations of the control logic that produces logic 1 when the safe is moved AND the secret switch is closed, OR the closet is opened after banking hours, OR the closet is opened with the control switch open. f ( A, B, C , D) AB C D A D Chapter 2 72 Synthesis of Combinational Logic Circuits (10) • Example 2.42: The Doe family voter: – Vote for either hamburgers (0) or chicken (1). – Majority wins. – If Mom and Dad agree, they win. – John (Dad): A, Jane (Mom):B, Joe: C, Sue: D. – The logic function is: f ( A, B, C , D) A BCD AB CD AB C D AB C D ABC D ABCD A BCD AB CD AB AB ACD A BCD AB ACD BCD A B C D Chapter 2 f (A, B, C, D) 73 Synthesis of Combinational Logic Circuits (11) • Example 2.43: Logic equations for a circuit that adds two 2-bit binary numbers (A1A0)2 and (B1B0)2, and produces sum bits (S1S0)2 and carry bit C1; A1A0 + B1B0 C1S1S0 Chapter 2 74 Synthesis of Combinational Logic Circuits (12) • Truth Table: A1 A0 B1 0 0 0 0 0 0 0 0 1 0 0 1 0 1 0 0 1 0 0 1 1 0 1 1 1 0 0 1 0 0 1 0 1 1 0 1 1 1 0 1 1 0 1 1 1 1 1 1 Chapter 2 • B0 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1 C1 0 0 0 0 0 0 0 1 0 0 1 1 0 1 1 1 S1 0 0 1 1 0 1 1 0 1 1 0 0 1 0 0 0 S0 0 1 0 1 1 0 1 0 0 1 0 1 1 0 1 0 Logic equations: S0 = A A B B A A B B A A B B 1 0 1 0 1 0 1 0 1 0 1 0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 S1 = A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 C1 = A A B B A A B B A A B B 1 0 1 0 1 0 1 0 1 0 1 0 A1 A0 B1B0 A1 A0 B1B0 A1 A0 B1B0 75 Synthesis of Combinational Logic Circuits (13) • Reduced equations: S0 = A0 B0 A0 B0 S1 = A A B A B B A A B B 1 0 1 1 1 0 1 0 1 0 A1 A0 B1B0 A1B1B0 A1 A0 B1 C1 = A0 B1B0 A1 A0 B0 A1B1 Chapter 2 76 Computer-aided Design (1) • Design Cycle Concept Modeling and design capture Synthesis Design optimization Design database Test vectors Logic simulation Analysis Fail Results ? Pass Realization Implementation Physical design Testing Test Finished circuit Chapter 2 77 Computer-aided Design (2) • Digital Circuit Modeling – Purpose of modeling: • Helps the designer formalize a solution. • To check errors, verify correctness, and predict timing characteristics. – CAD tools are available for design optimization and transformation of design from abstract form to a physical realization. – Model can represent different levels of design abstraction. Level Behavioral Register Transfer Gate Transistor Layout Chapter 2 Abstraction Algorithms to be realized Structure of modules Data flow among modules and control algorithm Structure of primitive logic gates Structure of transistors and low-level components Geometric patterns of materials for IC layout 78 Computer-aided Design (3) • High-level abstract model (behavioral model) – Describes only desired behavior. – Usually represented using a hardware description language (HDL), e.g., VHDL or Verilog. – Other representation mechanisms: logic equations, truth tables, and minterm or maxterm lists. Chapter 2 79 Computer-aided Design (4) • Behavioral models of a full-adder circuit: (a) block diagram, (b) truth table, (c) logic equations. a b cin Full_adder s cout (a) Chapter 2 a b cin cout s 0 0 0 0 1 1 1 1 0 1 0 1 0 1 0 1 0 0 0 1 0 1 1 1 0 1 1 0 1 0 0 1 0 0 1 1 0 0 1 1 s =a b cin cout = ab+ acin + bcin (c) (b) 80 Computer-aided Design (5) • VHDL behavioral model of a full adder circuit (Figure 2.38) – Entity defines the interface between the circuit and the outside world. – Architecture defines the function implemented within the circuit. – Multiple architectures may be defined for a given entity. • Structural model – Interconnection of components. – Behavior is deduced from the behavioral models of individual components and their interconnection. – Represented by: • Logic or schematic diagram • Netlist (textual representation of schematic diagram) • HDL description of circuit structures. Chapter 2 81 Computer-aided Design (6) • Structural models of a full-adder circuit: (a) schematic diagram, (b) netlist I1 I2 I3 a b X1 x1 X2 cin A1 A2 A3 s O1 a1 a2 a3 (a) R1 cout O2 I1 I2 I3 X1 X2 A1 A2 A3 R1 O1 O2 IN a IN b IN cin XOR2 x1 XOR2 s AND2 a1 AND2 a2 AND2 a3 OR3 cout OUT s OUT cout a x1 a a b a1 b cin b cin cin a2 a3 (b) – In a netlist, each circuit element is defined as follows: gate_name, gate_type, output, input1, input2, …, inputN – VHDL structural model of a full-adder circuit: Figure 2.40. Chapter 2 82 Computer-aided Design (7) • Mixed-mode model – Contains both behavioral and structural components. – Mixed-mode model of the full-adder circuit: (a) full-adder block diagram, (b) circuit for sum function, (c) truth table for carry function. a b a b cin Sum module s Carry module cout 0 0 0 0 1 1 1 1 0 0 1 1 0 0 1 1 cin cout 0 1 0 1 0 1 0 1 0 0 0 1 0 1 1 1 (c) (a) a b s cin (b) Chapter 2 83 Computer-aided Design (8) • Design synthesis process Behavioral models Function library HDL model Truth tableLogic equations Automatic synthesis Automatic synthesis Structural models Schematic Logic equations Constraints Component library Netlist Design optimization Minimize Schematic Optimized logic equations Back annotation Component library Netlist generation Map design onto circuit elements Circuit netlist Chapter 2 84 Computer-aided Design (9) • Capture tools – Each circuit model in the design process must be captured in a format that can be stored and processed by a digital computer. – Schematic capture: an interactive graphics tool with which a designer draws a logic diagram. Chapter 2 85 Computer-aided Design (10) • Schematic capture process MENU DRAWING AREA MENU DRAWING AREA Parts Library ZOOM ZOOM IN OUT and2 and3 or2 or3 nand2 nand3 nor2 nor3 xor2 not in out SELECT DELETE COPY MOVE PLACE DRAW COMP NET NAMEPARAM OPEN SAVE SHEET SHEET (a) MENU DRAWING AREA ZOOM ZOOM IN OUT MENU ZOOM ZOOM IN OUT SELECT DELETE SELECT DELETE COPY MOVE COPY MOVE PLACE DRAW COMP NET PLACE DRAW COMP NET NAMEPARAM NAMEPARAM OPEN SAVE SHEET SHEET OPEN SAVE SHEET SHEET (c) Chapter 2 (b) DRAWING AREA 11 12 13 a b X1 x1 X2 s O1 cin A1 A2 A3 a1 a2 R1 cout O2 a3 (d) 86 Computer-aided Design (11) • Logic Simulation – Three primary purposes: 1. Logic verification: only logical correctness is checked. 2. Performance analysis: propagation delays and potential timing problems are analyzed. 3. Test development (fault simulation): helps develop optimal test set. – Simulation environment Design Netlist Component models Simulator Logic verification data Chapter 2 Test vectors Timing analysis data 87 Computer-aided Design (12) • Simulation Test Inputs – Test set: a carefully designed set of test inputs. – For logic verification, a list of input vectors is used (time is ignored). – For timing analysis, the time of each input change is also specified. functional test set for input tabular waveform full-adder waveform format format a b cin 0 0 0 0 1 1 1 1 Chapter 2 0 0 1 1 0 0 1 1 0 1 0 1 0 1 0 1 Time a b cin a 0 5 10 15 b c 0 5 10 0 0 1 1 0 1 1 0 0 0 0 0 a = 0:0, 10 :1; b = 0:0, 5:1,15:0; cin = 0:0; 15 88 Computer-aided Design (13) • Event-Driven Simulation – Event: a change in the value of a signal at a given time. – Event-driven simulation example for an AND gate: a b a b c c T0 (a) Chapter 2 T1 T1 + t T2 (b) 89 Computer-aided Design (14) • Event-driven simulation procedure – Input test set is converted into a set of events. – The set of events are entered into an event queue (or event list). – In each simulation step, the first event is retrieved and is made to occur. – Output of each affected gate is recomputed, and new event is created. – Record of all events along with output results are maintained. – Simulation continues until the event queue is empty or time limit expires. a b cin cout s 0 Chapter 2 5 7 10 12 15 17 20 Time a 0 0 2 0 4 0 6 0 8 1 10 1 12 1 14 16 1 18 1 20 1 b 0 0 0 1 1 1 1 1 0 0 0 cincout 0 0 0 0 0 0 0 0 0 0 0 X 0 0 0 0 0 1 1 1 0 0 s X 0 0 0 1 1 0 0 0 1 1 Time a b 0 2 5 7 10 12 15 17 0 0 0 0 1 1 1 1 0 0 1 1 1 1 0 0 cincout 0 0 0 0 0 0 0 0 X 0 0 0 0 1 1 0 s X 0 0 1 1 0 0 1 90 Computer-aided Design (15) • Debugging a full-adder using simulation erroneous full-adder circuit a b simulation output: error in s at time 3 n1 n2 n3 cin n4 Chapter 2 Time a s 0 3 5 10 13 15 18 0 0 0 1 1 1 1 b 0 0 1 1 1 0 0 cin s 0 0 0 0 0 0 0 X 1 1 1 0 0 1 expanded simulation: isolates error to n3 Time a b cin n1 n2 n3 n4 s 0 0 0 0 X X X X X 1 0 0 0 1 1 X 1 X 2 0 0 0 1 1 0 1 X 3 0 0 0 1 1 0 1 1 5 0 1 0 1 1 0 1 1 10 1 1 0 1 1 0 1 1 12 1 1 0 1 1 1 1 1 13 1 1 0 1 1 1 1 0 15 1 0 0 1 1 1 1 0 17 1 0 0 1 0 1 1 0 18 1 0 0 1 0 1 1 1 91 Computer-aided Design (16) • Detection of static hazard via simulation – A glitch in g at time t3 can be detected from the output waveforms. – This occurs because both e and f become 0 momentarily between t2 and t3. a b c d e f a b e g g d c f (a) Chapter 2 Time t1 t t2 t t3 t t4 (b) 92 Computer-aided Design (17) • Symbolic Logic Signal Values – Designers sometimes need signal values other than just 0 or 1. – Logic signal values are represented by a state and a strength. – A third state X represents an unknown state or a potential problem. – Truth tables for three-valued logic (with X added) AND 0 1 X 0 1 X 0 0 0 0 1 X 0 X X OR 0 1 X 0 1 X 0 1 X 1 1 1 X 1 X NOT 0 0 1 X 1 0 X – Signal strength values: • Forcing (F): signal line is strongly forced to a given state. • Resistive (R): signal line is weakly forced to a given state. • Floating (Z): signal line is not forced forced at all. • Unknown (U): signal strength cannot be determined. Chapter 2 93 Computer-aided Design (18) • Signal strengths are used to resolve conflicting gate outputs: output resolved in favor of stronger signal. output value unable to be resolved VCC F0 I1 F1 Ux F0 I1 F1 R1 F0 F1 I2 I2 F0 (b) F0 Chapter 2 94 Computer-aided Design (19) • Primitive Device Delay Models – Every primitive logic gate has an intrinsic delay. – A gate can be modeled as an ideal (zero-delay) gate and a transport delay element. a b c* Ideal gate t c Time delay – Different models of transport delays: • Unit/Nominal Delay • Rise Fall Delay • Ambiguous or Min/Max Delay Chapter 2 95 Computer-aided Design (20) • Unit/Nominal Delay – Unit delay: assign to each gate in a circuit the same unit delay. – Nominal delay: delays are determined separately for each type of gate (e.g., on time unit for NOR and two time units for XOR). a b c t Chapter 2 t 96 Computer-aided Design (21) • Rise/Fall Delay – Different delays for 0 to 1 transition and 1 to 0 transition. – tPLH (rise time): propagation delay from low to high. – tPHL (fall time): propagation delay from high to low. a b c tPLH (rise time) Chapter 2 tPHL (fall time) 97 Computer-aided Design (22) • Ambiguous or Min/Max Delay – Sometimes it is impossible to predict exact rise or fall time of a signal. – For worst-case performance analysis, {tmin, tmax} is specified for each timing parameter. a b c tmin tmax Chapter 2 98 Computer-aided Design (23) • A problem with min/max delay: the results tend to be pessimistic. circuit model a b c d worst-case delays: ambiguity region gets larger at each successive level f h e g d e g h 15 10 1214 16 Chapter 2 20 25 99 Computer-aided Design (24) • Inertial Delay – An input value must persist for some minimum duration of time to provide the output with the needed inertia to change. – The minimum duration is called inertial delay. – Effect of inertial delay: a a b b c c (a) Transport delay model (b) Inertial delay model – Gate model with both inertial delay and transport delay: a t a* c* b Chapter 2 t Inertial delay t c b* Ideal gate Transport delay 100