Low-Power Design of Digital VLSI Circuits Power Dissipation of CMOS Circuits Vishwani D. Agrawal James J. Danaher Professor Dept. of Electrical and Computer Engineering Auburn University, Auburn, AL 36849 vagrawal@eng.auburn.edu http://www.eng.auburn.edu/~vagrawal Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 1 nMOS Logic (Inverters) For logic 1 input, continuous static power is dissipated. Pseudo-nMOS Saturated-load nMOS R. C. Jaeger and T. N. Blalock, Microelctronic Circuit Design, Third Edition, McGraw-Hill, 2006, Chapter 6. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 2 CMOS Logic (Inverter) VDD No current flows from power supply! Where is power consumed? GND F. M. Wanlass and C. T. Sah, “Nanowatt Logic using Field-Effect Metal-Oxide-Semiconductor Triodes,” IEEE International SolidState Circuits Conference Digest, vol. IV, February 1963, pp. 32-33. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 3 Components of Power Dynamic Signal transitions Logic activity Glitches Short-circuit (small) Static Leakage Copyright Agrawal, 2011 Ptotal = = Pdyn + Pstat Ptran + Psc + Pstat Lectures 2, 3, 4: CMOS Circuits 4 Power of a Transition: Ptran V = VDD R = Ron i(t) vi (t) Large resistance v(t) C = CL Ground C = Total load capacitance for gate; includes transistor capacitances of driving gate + routing capacitance + transistor capacitances of driven gates; obtained by layout analysis. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 5 Charging of a Capacitor R t=0 v(t) i(t) C V Charge on capacitor, q(t) = C v(t) Current, i(t) = C dv(t)/dt Copyright Agrawal, 2011 = dq(t)/dt Lectures 2, 3, 4: CMOS Circuits 6 C dv(t)/dt = [V – v(t)] /R dv(t) V – v(t) ─── = ───── dt RC dv(t) dt ∫ ───── = ∫ ──── V – v(t) RC –t ln [V – v(t)] = ── + A RC i(t) = Initial condition, t = 0, v(t) = 0 → A = ln V –t v(t) = V [1 – exp(───)] RC Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 7 v(t) = i(t) Copyright Agrawal, 2011 = –t V [1 – exp( ── )] RC dv(t) C ─── dt = Lectures 2, 3, 4: CMOS Circuits V –t ── exp( ── ) R RC 8 Total Energy Per Charging Transition from Power Supply Etrans = = Copyright Agrawal, 2011 ∞ ∫ V i(t) dt = 0 CV ∞V 2 –t ∫ ── exp( ── ) dt 0 R RC 2 Lectures 2, 3, 4: CMOS Circuits 9 Energy Dissipated per Transition in Resistance ∞2 R ∫ i (t) dt 0 Copyright Agrawal, 2011 = V ∞ – 2t R ── ∫ exp( ── ) dt R2 0 RC = 1 2 ─ CV 2 2 Lectures 2, 3, 4: CMOS Circuits 10 Energy Stored in Charged Capacitor ∞ ∞ –t V –t ∫ v(t) i(t) dt = ∫ V [1-exp( ── )] ─ exp( ── ) dt 0 0 RC R RC 1 2 = ─ CV 2 Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 11 Transition Power Gate output rising transition 2 Energy dissipated in pMOS transistor = CV /2 2 Energy stored in capacitor = CV /2 Gate output falling transition 2 Energy dissipated in nMOS transistor = CV /2 2 Energy dissipated per transition = CV /2 Power dissipation: 2 Ptrans = Etrans α fck = α fck CV /2 α = activity factor fck = clock frequency Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 12 Components of Power Dynamic Signal transitions 2 0 Delay =1 Logic activity Glitches Short-circuit Static Leakage Copyright Agrawal, 2011 GLITCH Delay=2 1 3 0 Ptotal = = Pdyn + Pstat Ptran + Psc + Pstat Lectures 2, 3, 4: CMOS Circuits 13 Short Circuit Power of a Transition: Psc VDD vi (t) isc(t) vo(t) CL Ground Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 14 Short Circuit Current, isc (t) VDD VDD - VTp Vi (t) Volt p-transistor starts conducting n-transistor cuts-off Vo(t) VTn 0 Iscmaxf isc(t) Isc 0 Copyright Agrawal, 2011 tB tE Lectures 2, 3, 4: CMOS Circuits 1 Time (ns) 15 Peak Short Circuit Current Increases with the size (or gain, β) of transistors Decreases with load capacitance, CL Largest when CL = 0 Reference: M. A. Ortega and J. Figueras, “Short Circuit Power Modeling in Submicron CMOS,” PATMOS ’96, Aug. 1996, pp. 147-166. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 16 Short-Circuit Energy per Transition Escf = = tE ∫tB VDD isc(t)dt (tE – tB) Iscmaxf VDD / 2 Escf = tf (VDD - |VTp| - VTn) Iscmaxf / 2 Escr = tr (VDD - |VTp| - VTn) Iscmaxr / 2 Escf = Escr = 0, when VDD = |VTp| + VTn Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 17 Short-Circuit Power Increases with rise and fall times of input. Decreases for larger output load capacitance; large capacitor takes most of the current. Small, about 5-10% of dynamic power; momentary shorting of supply and ground during opening and closing of transistor switches. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 18 Short-Circuit Power Calculation Assume equal rise and fall times Model input-output capacitive coupling (Miller capacitance) Use a spice model for transistors T. Sakurai and A. Newton, “Alpha-power Law MOSFET model and Its Application to a CMOS Inverter,” IEEE J. Solid State Circuits, vol. 25, April 1990, pp. 584-594. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 19 Short Circuit Power Psc = Copyright Agrawal, 2011 α fck Esc Lectures 2, 3, 4: CMOS Circuits 20 Psc, Rise Time and Capacitance VDD Ron vi (t) tf VDD ic(t)+isc(t) vo(t) CL R = large vo(t) tr Ground Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits vo(t) ─── R↑ 21 isc, Rise Time and Capacitance Isc(t) = Copyright Agrawal, 2011 –t VDD[1 – exp (─────)] vo(t) R↓(t) C ──── = ─────────────── R↑(t) R↑(t) Lectures 2, 3, 4: CMOS Circuits 22 iscmax, Rise Time and Capacitance i Small C vo(t) Large C vo(t) 1 ──── R↑(t) iscmax t tf Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 23 Psc, Rise Times, Capacitance For given input rise and fall times short circuit power decreases as output capacitance increases. Short circuit power increases with increase of input rise and fall times. Short circuit power is reduced if output rise and fall times are longer than the input rise and fall times. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 24 Summary: Short-Circuit Power Short-circuit power is consumed by each transition (increases with input transition time). Reduction requires that gate output transition should not be faster than the input transition (faster gates can consume more short-circuit power). Increasing the output load capacitance reduces short-circuit power. Scaling down of supply voltage with respect to threshold voltages reduces short-circuit power; completely eliminated when VDD ≤ |Vtp| + Vtn . Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 25 Components of Power Dynamic Signal transitions Logic activity Glitches Static Copyright Agrawal, 2011 Short-circuit Leakage Lectures 2, 3, 4: CMOS Circuits 26 Leakage Power IG Ground Gate VDD R Source Drain n+ Bulk Si (p) Isub IPT IGIDL n+ ID nMOS Transistor Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 27 Leakage Current Components Subthreshold conduction, Isub Reverse bias pn junction conduction, ID Gate induced drain leakage, IGIDL due to tunneling at the gate-drain overlap Drain source punchthrough, IPT due to short channel and high drain-source voltage Gate tunneling, IG through thin oxide; may become significant with scaling Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 28 Drain to Source Current IDS = μ0 Cox (W/L) Vt2 exp{(VGS –VTH ) / nVt } μ0: carrier surface mobility Cox: gate oxide capacitance per unit area L: channel length W: gate width Vt = kT/q: thermal voltage n: a technology parameter Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 29 IDS for Short Channel Device IDS= μ0 Cox(W/L)Vt2 exp{(VGS –VTH + ηVDS)/nVt} VDS = drain to source voltage η: a proportionality factor W. Nebel and J. Mermet (Editors), Low Power Design in Deep Submicron Electronics, Springer, 1997, Section 4.1 by J. Figueras, pp. 81-104 Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 30 Subthreshold Current, Isub Example: 90nm CMOS inverter L = 90nm, Wp = 495nm, Wn = 216nm Temperature 300K (room temperature) Input set to 0 volt Vthn = 0.291V, Vthp =0.209V at VDD = 1.2V (nominal) PTM (predictive technology model) Spice simulation for leakage current Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 31 Subthreshold Current, Isub Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 32 Subthreshold Current, Isub Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 33 Increased Subthreshold Leakage Log (Drain current) Scaled device Ic Isub 0 VTH’ VTH Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits Gate voltage 34 Summary: Leakage Power Leakage power as a fraction of the total power increases as clock frequency drops. Turning supply off in unused parts can save power. For a gate it is a small fraction of the total power; it can be significant for very large circuits. Scaling down features requires lowering the threshold voltage, which increases leakage power; roughly doubles with each shrinking. Multiple-threshold devices are used to reduce leakage power. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 35 CMOS Gate Power R = Ron V i(t) vi (t) Large resistance v(t) v(t) i(t) C isc(t) isc(t) Ground Leakage current Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits time 36 Technology Scaling Scaling down 0.7 micron by factors 2 and 4 leads to 0.35 and 0.17 micron technologies Constant electric field assumed Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 37 Constant Electric Field Scaling B. Davari, R. H. Dennard and G. G. Shahidi, “CMOS Scaling for High Performance and Low Power—The Next Ten Years,” Proc. IEEE, April 1995, pp. 595-606. Other forms of scaling are referred to as constant-voltage and quasi-constantvoltage. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 38 Bulk nMOSFET Polysilicon Gate Drain W Source n+ n+ L p-type body (bulk) SiO2 Thickness = tox Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 39 Technology Scaling A scaling factor (S ) reduces device dimensions as 1/S. Successive generations of technology have used a scaling S = √2, doubling the number of transistors per unit area. This produced 0.25μ, 0.18μ, 0.13μ, 90nm and 65nm technologies, continuing on to 45nm, 32nm and 22nm. A 5% gate shrink (S = 1.05) is commonly applied to boost speed as the process matures. N. H. E. Weste and D. Harris, CMOS VLSI Design, Third Edition, Boston: Pearson Addison-Wesley, 2005, Section 4.9.1. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 40 Constant Electric Field Scaling Device Parameter Scaling Length, L 1/S Width, W 1/S Gate oxide thickness, tox 1/S Supply voltage, VDD 1/S Threshold voltages, Vtn, Vtp 1/S Substrate doping, NA Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits S 41 Constant Electric Field Scaling(Cont.) Device Characteristic β Scaling W / (L tox) S β (VDD – Vt ) 2 1/S Resistance, R VDD / Ids 1 Gate capacitance, C W L / tox 1/S Gate delay, τ RC 1/S Clock frequency, f 1/ τ S CV 2 f 1/S 2 Current, Ids Dynamic power per gate, P 1/S 2 Chip area, A Power density P/A 1 Current density Ids /A S Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 42 Problem: A Design Example A battery-operated 65nm digital CMOS device is found to consume equal amounts (P ) of dynamic power and leakage power. The short-circuit power is negligible. The energy consumed by a computing task, that takes T seconds, is 2PT. Compare two power reduction strategies for extending the battery life: A. B. Clock frequency is reduced to half, keeping all other parameters constant. Supply voltage is reduced to half. This slows the gates down and forces the clock frequency to be lowered to half of its original (full voltage) value. Assume that leakage current is reduced by a ratio 10/2 = 5 (see slides 32 and 33). Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 43 Solution: Strategy A. Clock Frequency Reduction Reducing the clock frequency will reduce dynamic power to P / 2, keep the static power the same as P, and double the execution time of the task. Energy consumption for the task will be, Energy = (P / 2 + P ) 2T = 3PT which is greater than the original 2PT. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 44 Solution: Part B. Supply Voltage Reduction When the supply voltage and clock frequency are reduced to half their values, dynamic power is reduced to P / 8 and static power to P / 10. The time of task is doubled and the total energy consumption is, Energy = (P / 8 + P / 10) 2T = 9PT / 20 =0.45PT The voltage reduction strategy reduces energy consumption while a simple frequency reduction consumes more energy. Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 45 Comparing Strategies A and B Original A B Voltage V V V/2 Clock Frequency F F/2 F/2 Task Duration T 2T 2T Power 2P 1.5P 0.225P Energy 2PT 3PT 0.45PT Copyright Agrawal, 2011 Lectures 2, 3, 4: CMOS Circuits 46