離散數學 南台科技大學 資工系 蕭天泉

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離散數學

南台科技大學

資工系

蕭天泉

加法運算法則

• 某人想由 A 地到 B 地,搭乘火車有 3 類車種可

選擇,搭乘汽車有 2 類車種可選擇。搭乘火

車或汽車由 A 地到 B 地有多少種方式可選擇?

• 3 + 2 = 5

The Rule of Sum

• If a first task can be performed in m ways, while a second task can be performed in n ways, and the two tasks cannot be performed simultaneously, then performing either task can be accomplished in any one of m + n ways.

乘法運算法則

• 一餐廳點主菜附加甜點及飲料,有 4 種甜點

及 5 種飲料可供挑選 ( 只能各挑一種 ) ,有多

少種挑選甜點及飲料的方式?

• 4*5=20

The Rule of Product

• If a procedure can be broken down into first and second stages, and if there are m possible outcomes for the first stage and if, for each of these outcomes, there are n possible outcomes for the second stage, then the total procedure can be carried out, in the designated order, in mn ways.

練習題

• 身份證編號 A 1 2 3 4 5 6 7 8 9

身份字號之格式 a b n n n n n n n c

– 第一個符號 a : 大寫英文字母 A~Z ( 代表地區 )

– 第二個符號 b : 1 ( 男 ) 或 2 ( 女 )

– 第三個符號 n : 0 ~ 9

– 第四個符號 c :檢查數字 ( 由前 9 個符號決定 )

• 此種编碼方式,可編的人數最多是多少?

• Ans:

26x2x10x10x10x10x10x10x10=520,000,000

排列 (Permutations) 與

組合 ( Combinations)

• Definition of factorial ( 階乘之定義 )

– For an integer n ≧ 0, n factorial (denoted n!) is defined by

0!= 1, n!= (n)(n-1)(n2) ···(3)(2)(1), for n ≧ 1.

• 5!=

5x4x3x2x1=120

• 1!=1

• 0!=1

• n!=nx(n-1)! 5!=5(4!)=5x24=120

排列 (Permutation)

線狀排列

• P(n, r) = n(n-1)(n-2)···(n-r +1) n ≧ r ≧ 1

= n(n-1)(n2) ···(n-r+1 )(n-r)(n-r1)···1/(n-r)(n-r-1)···1

= n!/(n-r)!

從n個相異的物件中,取 r 個來排列 ( 每次取 1 個,

取後不放回 )

If there are n distinct objects and r is an integer, with n ≧ r ≧ 1, then by the rule of product, the number of permutations of size r for n objects is

P(n,r).

例題

1.一個有10位成員的俱樂部,每次挑3位來拍照;共

有多少種拍照方式?

Ans : P(10, 3) =10x9x8=720=10!/(10-3)!

2. 一個有10位成員的俱樂部,從中任挑3位作為主

席、秘書長及出納;共有多少種選擇方式?

Ans : P(10, 3) =10x9x8=720=10!/(10-3)!

EXAMPLE 1.9

• In a class of 10 students, five are to be chosen and seated in a row for a picture. How many such linear arrangements are possible?

– The key word here is arrangement, which designates the importance of order.

– Ans: 10x9x8x7x6=10!/5!

EXAMPLE 1.10

• The number of permutations of the letters in the word COMPUTER is

8!

• If only five of the letters are used, the number of permutations (of size 5) is

P(8, 5)

EXAMPLE 1.11

• Unlike Example 1.10, the number of (linear) arrangements of the four letters in BALL is

12, not 4!(= 24).

The arrangements of the four letters in

BALL is 4!/2! = 12.

• If there are n objects with n

1 indistinguishable objects of a first type, n

2 indistinguishable objects of a second type, …, and n r indistinguishable objects of an r th type, where n

1

+ n

2

+…+ n r

= n , then there are (linear) n

1

!

n

2

!

 n r

!

arrangements of the given n objects.

EXAMPLE 1.14

• Determine the number of (staircase) paths in the xy-plane from (2, 1) to (7, 4), where each such path is made up of individual steps going one unit to the right (R) or one unit upward (U).

• Ans: Upward: 7- 2 = 5

Right: 4 -1 = 3

UUUUURRRR 8!/(5!3!)

環狀排列

• If 3 people, designated as a, b, c, are seated about a round table, how many different circular arrangements are possible, if arrangements are considered the same when one can be obtained from the other by rotation?

• a, b, c 三個物件的排列 (linear arrangements) 數目為 3! = 6

• abc cab bca acb bac cba

環狀排列 b a c c b a a c b c a b b c a a b c

Ans: 3!/3 = 2

習題

1. List all the permutations for the letters a, c, t.

(1.1, 1.2 #12)

2. Evaluate each of the following.

(1.1, 1.2 #14) c) P(10,7) d) P(12,3)

3. a) How many arrangements are there of all the letters in SOCIOLOGICAL?

(1.1, 1.2 #21) b) In how many of the arrangements in part (a) are A and G adjacent?

c) In how many of the arrangements in part (a) are all the vowels adjacent?

習題

4. Show that for all integers n, r ≧ 0, if n + 1 > r, then

(1.1, 1.2 #24) p ( n

1 , r )

 n n

1

1

 r p ( n , r )

習題

5. Find the value(s) of n in each of the following:

(1.1, 1.2 #25)

(a) P(n,2) = 90

(b) P(n,3) = 3P(n,2)

(c) 2P(n,2) + 50 = P(2n,2)

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