MATH 0930
Beginning Algebra Part 1
K.Rigdon
Name_________________________
Practice Test for Exam 3 – Sections 2.1-2.3
Due (optional) on Exam Day – Tuesday, 10/07/2014
This practice test will give you a good idea of the type and number of problems you will see on the
actual test. Working through this practice test will, therefore, provide you with a good idea of how
well you know the material you will be tested over.
You have the opportunity to earn 3 extra credit points toward your test grade if you show all
work possible for all the problems and, of course, get all the answers correct (partial points can
be earned as well; answers are included on the back for you to check your work). If you would like
to earn these extra points, you will need to turn in this paper, with your work attached (done
on separate lined paper), on the day of the Exam.
In addition to the questions over the Section 2.1-2.3 material, you will have
4 questions like the Cumulative Review Questions you have been having in your homework
assignments or on Cumulative Review Worksheets, so be certain to go over them (but, you don’t have to
rework them to turn in with this). Specifically, these homework problems were:
Problems 1), 2), 3),& 4):
Page 104; #135-139 all
Page 111; #76-79 all
Page 118; #73-77 all
Combine Like terms, if possible. If not possible, rewrite the expression as is:
5)
9x – 4y – 6 + 7y
6)
4 – x2 + 4x – 10 + 5x2
-2mn + 5m + 4mn – 3n + 7n
7)
8)
Use the distributive property to remove parentheses:
9)
7 (n – 4)
10)
11)
-4 (n + m + 6)
2
1 3 3
x   x
3
4 5 4
-3 (x – 5)
12)
1
2
  4x  
2
7
Simplify:
13)
- (x – 2y)+ 4y – 3
14)
4 – (y – x) + 3x
15)
-8x – 1 + x + 6
16)
2
1 
3
x  x  
5
3 
7
17)
2 (x + 5) – (x – 7)
18)
- (x + y) + 2 (x – 7)
Determine whether the value given for the variable is a solution to each equation (show your
work):
19)
20)
Is x = 3 a solution of the equation -4 + 2x = 2x – 6 + x ?
Is x = 4 a solution of the equation 12 – 3x + 7x = -2 (-5x + 6) ?
21)
Is x = 0 a solution of the equation
5
2
1
?
( x  2)  ( 2 x  1) 
12
3
6
Solve for x.
22)
x + 5 = -12
23)
x – 4 = -10
24)
7=x–3
25)
x
(OVER)
1 3

4 8
Page 2
26)
x – 3.5 = -7
27)
28)
–x = -8
29)
x   94
30)
2
3
32)
2x  
31)
3
4
33)
-3x = 12
x
 3
4
x 1
 
3 6
-0.5x = 1.25
Practice Test Answer Key
1, 2, 3), & 4) Check answers in book
5)
9x + 3y – 6
21)
Yes
6)
4x + 4x – 6
22)
x = -17
7)
5m + 2mn + 4n
23)
x = -6
8)
 121 x  207
24)
x = 10
9)
7n – 28
25)
x  81
10)
-3x + 15
26)
X = -3.5
11)
-4m – 4n – 24
27)
x = -4
12)
 2 x  17
28)
x=8
13)
–x + 6y – 3
29)
x = -12
14)
4x – y + 4
30)
x= 
15)
-7x + 5
2
3
16)
 53 x  212
31)
x= 
1
2
17)
X + 17
32)
x= 
3
8
33)
x = -2.5
2
18)
X – y – 14
19)
No
20)
Yes