Section 1: Sets of Numbers

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Name
Q1 Test 1 Review
DUE: Thursday, 10/13/05
TEST: Friday, 10/14/05
Section 1: Sets of Numbers
1) Which number is a rational number but not an integer?
a) – 6
b) 0
c) ⅝
d) none
2) Which number is an integer but not a natural number?
a) π
b) -¾
c) 0
d) none
3) Which number is an integer, but not rational?
a) π
b) 4
c) -.25
d) none
4) Which number is whole, but not natural?
a) 0
b) 4
c) .75
d) none
5) Which number is natural, but not whole?
a) ¼
b) 4
c) 0
d) none
6) Give an example of a number that is rational, but not an integer.
7) Give an example of a number that is an integer, but not a whole number.
8) Give an example of a number that is a whole number, but not a natural number.
9) Give an example of a number that is a whole number, but not an integer.
10) Give an example of a number that is rational, but not a whole number.
Section 2: Properties
A. Complete the Matching Column (put the corresponding letter next to the number)
1)
6-9=6-9
a) Reflexive
2)
4(5 + 2) = 4(5) + 4(2)
b) Additive Identity
3)
17 · 8 = 8 · 17
c) Multiplicative identity
4)
6 · (2 · 12) = (6 · 2) · 12
d) Associative Property of Mult.
5)
32 + 0 = 32
e) Transitive
6)
11 + (3 + 18) = (11 +3) + 18
f) Associative Property of Add.
7)
If 40 + 4 = 44 and 44 = 4 · 11, then 40 + 4 = 4 · 11
g) Symmetric
8)
22 · 0 = 0
h) Commutative Property of Mult.
9)
If 30 = 5 · 6, then 5 · 6 = 30
i) Multiplicative property of zero
10)
26 · 1 = 26
j) Distributive
Name
Q1 Test 1 Review
DUE: Thursday, 10/13/05
TEST: Friday, 10/14/05
Section 3: Operations with Signed Numbers
Numbers 7-12 will be given in class (mixed numbers are very difficult to type!)
1) 76 + (-28)=
4) -51 – 64
2) -85 + (-23) =
5) 67 – (-74) =
3) –48 + 37 =
6) -101 – (-44) =
7)
8)
9)
10)
11)
12)
Section 4: Order of Operations:
1) 256 – 46 · 3 – 11=
5) Substitute and Evaluate:
3y3 - 2y2 ÷ 10 + 379 =
y = -5
2) 24 ÷ (6 – 3 · 4) · 13 =
6) Substitute and Evaluate: b = 7 and c = -2
bc2 ÷ (42 – 4b) – 11c =
2
3) 100 - 12 · ¼ + (6)(-2) =
7) Evaluate when a = -8, b = -3, and c = 9
4b3 + ac – ab - 1
c2 – 16b ÷ a + 8a + 2b
Section 5: Simplifying and Solving Equations
1) (6x - 5) + (7x + 7)
2) (6x2 – 5x + 7) + (9x2 – 4x + 8)
3) 4(3x – 5) + 6(4x + 3)
4) 5(6x – 9) – 7(4x – 8)
5)8(3x2 – 4x + 9) + 6(4x2 + 5x – 12)
6) 9(4x2 + 3x – 8) – 7(6x2 – 4x + 10)
7) 6(2x – 5) + 3(3x + 2) = 102
8) 5(5x – 6) = 6(3x + 2)
9) 63 – ¾ x = 27
10) 10(3x + 1) – 6(7x + 2) = 4
11) 8(7x – 12) = 6(5x – 3)
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