Announcements 11/14/11 Prayer HW 29 problem Labs 8 & 9 due Saturday Progress Reports… Review: phaseshift 2 (PL ) Approx.1: PL d sin E stuff e e E stuff 1 ei i 2 i 2 E stuff cos( 2) I I0 cos2 ( 2) Approx.2: sin y L Rubes Fourier Transforms? How can our two-slit analysis possibly have anything to do with Fourier transforms? E stuff 1 e e E~ e E~ i ieach slit i dY (this is the y-coordinate on the slits, not the y-coordinate on the screen) open areas E~ compare to: 2 " aperture function " e dY an L i L2 L 2 2 nx f ( x) cos dx L Adding up phases … In short, we need to add up a bunch of vectors that have the same magnitude (1), but angles (phases) that go like 0, 20, 40, 60, etc. For a different position on the screen (measured by y slits or , we need to add up a different set of phases… irel.to ref. islit1 islit 2 screen ifinal slit Etot perhaps E0e e42, 63, ... etc. e likee0, 21, 2 y PL I E two-slit PL d sin d 2 for each slit L For an equally-spaced pattern of slits, how do the PLs compare? Each is a multiple of 2! (Could have an overall reference phase for 1…not too important.) Adding up phases, cont. … slits Etot E0e irel.to ref. PL 2 for each slit e islit1 e islit 2 ... e ifinal slit two-slit PL d sin d y L screen I Quick writing: graphically add these three vectors: 10 + 120 + 140 What about 10 + 190 + 1180 E 2 Three Slit Problem: Scanning Theta Credit: this animation and the next one are from Dr. Durfee Note: for some reason he picked the overall reference phase to be about 20 Thought question How many “sub” peaks are there between the “main” peaks in a 5-slit interference pattern? a. 1 b. 2 c. 3 d. 4 e. 5 Five Slit Problem: Scanning Theta Note: for some reason he picked the overall reference phase to be about 20-30 Reading Quiz When a light wave travels from a low index to a high index material at normal incidence (perpendicular to surface), what is the phase shift of the reflected wave? a. 0 b. 45 c. 90 d. 180 e. depends on whether it is s- or p-polarization Remember these? “Fresnel Equations” If near perpendicular (1-D problem) v2 v1 n1 n2 r v1 v2 n1 n2 R r t 2 The Truth (overlooked by textbook): Fordon’t arbitrary angle you always get a phase shift, even if going n1 cosfast 1 tonslow. 2 cos 2 rs(Brewster polar . marks boundary) n1 cos1 n2 cos2 n1 cos2 n2 cos1 rp polar. n1 cos2 n2 cos1 2v2 2n1 v1 v2 n1 n2 T 1 r Same as strings 2 2n1 cos1 ts polar . More Truth: sometimes phase n1 cos 1 n180: 2 have 2 coscan shifts not just complex n, complex , etc. 2n1 cos1 t p polar. n1 cos2 n2 cos1 Air to glass (n=1 to n=1.5) p-polarization field amplitudes vs 1.0 t 0.8 0.6 0.4 r 0.2 20 40 60 80 0.2 Brewster 180 phase shift (close to perpendicular) 0 phase shift (close to glancing) Back to “near normal incidence” From low to high index: 180 phase shift From high to low index: no phase shift What does the thickness of this slab need to be to get constructive interference between the two rays? If rays at an angle… air thin glass air determine if above/ Rays drawn at an angle to make below Brewster angle viewing easier. They’re really perpendicular to surface. (if p-polarization). thickness t Optical path length OPL = Path Length n since wavelength inside the material is reduced by a factor of n, the distance “looks” bigger than it actually is Constructive interference: OPL ( any phase shifts) = m Destructive interference: OPL ( any phase shifts) = (m+1/2) New situation What does the thickness of the COATING need to be to get constructive interference between the two rays? air thin coating, n = 1.3 thick glass, n = 1.5 Rays drawn at an angle to make viewing easier. They’re really perpendicular to surface. thickness t Pretty pictures What’s going on here? http://superphysics.netfirms. com/pp_optics.html http://twilit.wordpress.com/2008/ 03/15/bubbles-and-interference/ Demo Demo: Soap film Interferometer From lab 9: changing optical path length, yields ngas Interference! How does this disprove the ether?