Ampere’s Law Updated Hertz’s Discoveries Plane Electromagnetic Waves Energy in an EM Wave Momentum and Radiation Pressure The Electromagnetic Spectrum Ampère’s Law B.ds 0 I But there is a problem if I varies with time! Consider a parallel plate capacitor For S1, B.d s 0 I For S2, B.ds 0 I 0 (No current in the gap) Call I as the conduction current. Specify a new current that exists when a change in the electric field occurs. Call it the displacement current. d E Id 0 dt Electrical flux through S2: Q Q A E EA 0 0 A Id 0 d E dQ I dt dt Now the generalized form of Ampère’s Law, or Ampère-Maxwell Law becomes: d E B.ds 0 I I d 0 I 0 0 dt Magnetic fields are produced by both conduction currents and by time-varying electrical fields. Q E.dA 0 Gauss’ Law B.dA 0 Gauss’ Law for Magnetism – no magnetic monopoles d B E.ds dt d E B.ds 0 I 0 0 dt F qE qv B Faraday’s Law Ampère-Maxwell Law Lorentz Force Law By supplying short voltage bursts from the coil to the transmitter electrode we can ionize the air between the electrodes. In effect, the circuit can be modeled as a LC circuit, with the coil as the inductor and the electrodes as the capacitor. A receiver loop placed nearby is able to receive these oscillations and creates sparks as well. Circular (or Spherical in 3D) Waves Plane Waves d B E . d s dt d E B . d s I 0 0 0 dt E B x t B E 0 0 x t Free Space: I = 0, Q = 0 2E B B E 0 0 x 2 x t t x t t 2E 2E 0 0 2 2 x t d E B . d s 0 0 dt 2B 2B 0 0 2 x 2 t E Emax coskx t B Bmax cos kx t c E Emax coskx t B Bmax cos kx t 1 0 0 2f k k c f 2 c Speed of Light Angular Frequency Wavelength Wavenumber E B x t B E 0 0 x t E Emax coskx t B Bmax cos kx t kEmax Bmax E Emax c B Bmax k The solutions to Maxwell’s equations in free space are wavelike Electromagnetic waves travel through free space at the speed of light. The electric and magnetic fields of a plane wave are perpendicular to each other and the direction of propagation (they are transverse). The ratio of the magnitudes of the electric and magnetic fields is c. EM waves obey the superposition principle. a) =?, T=? c 3 108 7.5m f 40 106 1 1 8 T 2 . 5 10 s 6 f 40 10 b) If Emax=750N/C, then Bmax=? Bmax f 40MHz c) E(t)=? and B(t)=? Emax 750 2.5 106 T 8 c 3 10 Directed towards the z-direction 2 0.838rad / m 7.5 2f 2 40 106 2.51108 rad / s k 2 E Emax coskx t 750 N / C cos(0.838 x 2.51 108 t ) B Bmax coskx t 2.5 106 T cos(0.838 x 2.51 108 t ) 1 S EB 0 Poynting Vector (W/m2) S is equal to the rate of EM energy flow per unit area (power per unit area) E2 c 2 For a plane EM Wave: S B 0 0c 0 EB The average value of S is called the intensity: 2 Emax Bmax Emax c 2 I S av Bmax 20 20 c 20 uE uB 0E 2 2 B2 uB 20 2 0 0 2 1 E c E 20 20 2 0 E For an EM wave, the instantaneous electric and magnetic energies are equal. 2 2 1 B uE uB 0 E 2 2 20 u uE uB 0 E 2 B2 Total Energy Density of an EM Wave 0 2 Bmax 1 2 2 uav 0 E av 0 Emax 2 20 I Sav cuav The intensity is c times the total average energy density Which gives the largest average energy density at the distance specified and thus, at least qualitatively, the best illumination 1. a 50-W source at a distance R. 2. a 100-W source at a distance 2R. 3. a 200-W source at a distance 4R. P lamp= 150 W, 3% efficiency A = 15 m2 Pav Plamp 0.03 4.5W 2 Pav Emax I A 20c Emax Bmax 20cPav 18.42V / m A Emax 6.14 108 T c TER p c A Momentum for complete absorption P F 1 dp A A dt P 1 d TER A dt c Pressure on surface 1 dTER dt A c S P c For complete reflection: 2TER p c 2S P c P laser= 3 mW, 70% reflection, d = 2 mm P 0.003 2 S 955 W / m A 0.0012 S S S P 0.7 1.7 c c c 955 6 2 P 1.7 5 . 4 10 N / m 3 108 The fundamental mechanism for electromagnetic radiation is an accelerating charge Reading Assignment Chapter 35: Nature of Light and Laws of Geometric Optics WebAssign: Assignment 12