Bellringer 2.)  |2z ­ 1| = 3z + 4 Unit 2 Section 11 Literal Equations.notebook November 09, 2015

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Unit 2 Section 11 Literal Equations.notebook
November 09, 2015
Bellringer
1.) |2x ­ 1| = 4x
2.) |2z ­ 1| = 3z + 4
3.) Five times the absolute value of the difference of four times a number and 4 is 20.
Nov 8­11:06 AM
Nov 5­10:00 AM
Unit 2 Section 11 Literal Equations.notebook
Oct 29­7:12 AM
Literal Equations
Unit 2
Oct 19­10:00 AM
November 09, 2015
Unit 2 Section 11 Literal Equations.notebook
November 09, 2015
What value of k would make this equation "No Solution"?
2(3x ­ 5) = 4x ­ 14 + kx
Oct 29­10:14 AM
Literal Equation ­ an equation that involves two or more variables
Solve for the underlined variable:
1) A = bh
3) V = 1
3
2) P = a + b + c
πr 2 h
Nov 5­1:21 PM
Unit 2 Section 11 Literal Equations.notebook
November 09, 2015
Solve for the underlined variable:
4) A = πr2
5) m = a + b
2
6) A = h(b 1 + b2 )
2
Nov 5­1:19 PM
Solve for x in the following equations.
7.) rx + sx = 1
8.) 2m ­ nx = x + 4 t
Jul 28­8:00 PM
Unit 2 Section 11 Literal Equations.notebook
You are ordering pizzas and sandwiches. You have a budget of $80. Write an equation to model the problem. How many sandwiches can you buy if you buy 4 pizzas? 5 pizzas?
November 09, 2015
Menu
Pizza $10
Sandwich $5
It is easier if you solve your equation for s. Then you can use your rewritten equation to find s when p = 4 and p = 5.
Apr 20­8:23 AM
Homework:
Homework Packet
page 31, 32
Nov 4­9:59 AM
Unit 2 Section 11 Literal Equations.notebook
Nov 11­7:27 AM
Oct 29­2:21 PM
November 09, 2015
Unit 2 Section 11 Literal Equations.notebook
Oct 30­10:23 AM
November 09, 2015
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