LECTURE 11 A general formula • Let Y = g(X) g strictly monotonic. Derived distributions; convolution; covariance and correlation • Readings: Finish Section 4.1; Section 4.2 slope y dg (x) dx g(x) [y, y+?] Example y x f X ,Y(y,x)=1 [x, x+d] 1 • Event x ≤ X ≤ x + δ is the same as g(x) ≤ Y ≤ g(x + δ) or (approximately) g(x) ≤ Y ≤ g(x) + δ|(dg/dx)(x)| x 1 • Hence, Find the PDF of Z = g(X, Y ) = Y /X FZ (z ) = z≤1 FZ (z) = z≥1 where y = g(x) The distribution of X + Y • W = X + Y ; X, Y independent y . dx ! ! (x)!! The continuous case • W = X + Y ; X, Y independent . ! ! dg δfX (x) = δfY (y) !! y (0,3) . w (1,2) . (2,1) . (3,0) . x w pW (w) = P(X + Y = w) = = " x " x x x +y=w P(X = x)P(Y = w − x) • fW |X (w | x) = fY (w − x) pX (x)pY (w − x) • fW,X (w, x) = fX (x)fW |X (w | x) • Mechanics: = fX (x)fY (w − x) – Put the pmf’s on top of each other – Flip the pmf of Y • fW (w) = – Shift the flipped pmf by w (to the right if w > 0) – Cross-multiply and add 1 # ∞ −∞ fX (x)fY (w − x) dx Two independent normal r.v.s The sum of independent normal r.v.’s • X ∼ N (0, σx2), Y ∼ N (0, σy2), independent • X ∼ N (µx, σx2), Y ∼ N (µy , σy2), independent fX,Y (x, y) = fX (x)fY (y) $ (x − µx)2 (y − µy )2 1 = exp − − 2πσxσy 2σx2 2σy2 • Let W = X + Y % fW (w) = = • PDF is constant on the ellipse where Correlation coefficient & • cov(X, Y ) = E (X − E[X]) · (Y − E[Y ]) ' • Dimensionless version of covariance: ρ = E . . . . .... . .. . . ... ...... ... .. . . . . .. ... . .... ... . .. .. . ... . . . . . . .. . . . .. .. . . ... .. . . . . . . x i=1 Xi = n " i=1 var(Xi) + 2 " - • −1 ≤ ρ ≤ 1 y • |ρ| = 1 ⇔ (X − E[X]) = c(Y − E[Y ]) (linearly related) • Independent ⇒ ρ = 0 (converse is not true) • cov(X, Y ) = E[XY ] − E[X]E[Y ] • var , (X − E[X]) (Y − E[Y ]) · σX σY cov(X, Y ) = σX σY • Zero-mean case: cov(X, Y ) = E [XY ] 2 – same argument for nonzero mean case Covariance n " # ∞ 2 2 2 2 1 e−x /2σx e−(w−x) /2σy dx 2πσxσy −∞ – mean=0, variance=σx2 + σy2 • Ellipse is a circle when σx = σy fX (x)fY (w − x) dx • Conclusion: W is normal is constant . . . . .... . .. . . . ... ...... ... .. . . . . .. ... . ... ... . .. .. . ... . . . . . .. .. . y . . . .. . . ... .. . . . . . . −∞ (algebra) = ce−γw (x − µx)2 (y − µ y ) 2 + 2σx2 2σy2 x # ∞ cov(Xi, Xj ) & (i,j ):i=j • independent ⇒ cov(X, Y ) = 0 (converse is not true) 2 MIT OpenCourseWare http://ocw.mit.edu 6.041SC Probabilistic Systems Analysis and Applied Probability Fall 2013 For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.