Department of Materials Science and Engineering Massachusetts Institute of Technology 3.044 Materials Processing- Spring 2011 Exam II Wednesday, April27, 2011 The Rules: 1) No books allowed; no computers allowed; etc. 2) A simple calculator is allowed 3) One hand written 3x5 index card may be prepared as a crutch . 4) Complete 5 out ofthe 6 problems. If you do more than 5 problems, I will grade the first 5 that are not crossed out. 5) Make sure that you READ THE QUESTIONS CAREFULLY 6) Supplementary materials are attached to the end of the test ( eqns ., etc.) 7) WRITE YOUR NAME HERE: s 0 l u -rt s 0 ('J Problem #1: Swimming for Their Lives (the particles, not the students) In continuous casting, one major problem is that small inclusion particles can be caught in the casting. Let's analyze this problem , for small inclusions of AI 20 3 (which are actually quite common in steel). . - + - --me lt Particle 'A' The key consideration is that the alumina particles float in molten steel. For such a particle in the melt region at point 'A', the particle is (a) trying to float to the top due to the buoyancy force (F = ~p·g·V , with V the particle volume), (b) but being propelled downward at the casting velocity Vc (= I m/min) at the same time. so lid metal Part A: \ Write down a reasonable and simple condition that decides whether the particle will eventually escape at the top surface, or be carried down and get incorporated in the metal in the sump. . I 4' ~ Vel OL. 4-/ {!r0 jNI hv::>yc,J;t c! 1"3, () (~ #,...... /i."'-"- 1-0. Jo (;) Y1 ,vd k(_ J " v __./~ v v(_ > +tat - Part B: ~ -- _____./ ftq_( w ,?l fla-..+ ~...... oJI- Let's calculate the velocity at which the particle would rise. Write down the force balance for particle 'A', and indicate with what velocity it rises. (For this part of the problem, ignore the Vc effect.) Fdr(.__j::: :S1i;v Vfla-t cL L:>y· ~ 37t(;)3 ~ ' . - ' I vn ~ Part C: v~Jo<-+ d 3-rrI 2_ ov ·l\ ·d V~lo ...f :: J .1 (e_vr._,~J2 ;~ jJ Some particles will escape, and some will not- calculate which size particles will escape and which will not. You may need the information at the back ofthe test, and the viscosity ofthe meltis7·10-3 Pa ·s. ./ 5-e + v+lo.-+ :: Vc 6o\VL ,._; for d_ Icvs~r d -Pio . . t S v1--l l-tr J 5t)t ~ J _,- - 'h. I~ ;v .o \b r-"ts bJ~ V},o... t L-bo /\- j ;~ (?A11- oJ - JSi-e~ ~ ~h~7D b] · j d ~ I Prohlcm #2: A Question you arc in H Super Position to Answer It i-. Slllllctimes possihk tu usc the principle or-.upcrpnsition for fluid now probkm .... (01 course thi" is no '-'Urprise. seeing the pervasive analogies between lluw and di!Tusinn.) l3clow an.: SL)fllC common situations in nuid now. Exp lain whether or not you can usc supcrpn..,ition to sulvc J'or the flow J'i cld in each case. If superposition is possible, explain what geometries/solutions are "-Uperposed. II it is nol pnssible. explain why nul. Part 13) Gravity drives !low down a l. s fk_ b--'+ /, r~.::ctangular chanlll:l open to the air on top. w~-..l h 0"'.. 1/t--=-- ) ~ ~ ~ d:t -h (.I c) 6 ue ( <-4"1, + us~ '51Vfl>S ,' h'J"'. l'at·t.C) A cylinder or asp~.::ct ratio I is filled with water. c losed, and spun on its axi". lcuding tu rotaltllllal !low or the liquid inside . F! t ~ J Yl f.-,_ I CJW A-Jl I') bou!rldt-i,'e 5 So 0"1(7 c...fe_ I,A·rv.... -for So-L+. 6)"' 5~ 1'>-- lT +t re: cy {,\ul v ~ -fvo i) t?• C •<.J"\. r~ = 0 ~~.),(h..) -fwtJ-h)L~ (r ~~ +m rff.. ) Problem #3: The Students Face Down a Real Phase Diagram c c. l-; C--s (. q__ • <::.><. I / I Alo m u: Perce nt Ca bo l\ You are gtven a rod o 10 ~ ao IV Jo co ~o eo 1800 of titanium that ot contains I at% cobalt, ~ \, and asked to purify it. 1600 '' Looking at the Ti-Co L ' ' '' phase diagram, you ' liOO i reason that this alloy • '' ~ ' '\ could be zone refined, '= exactly as discussed '\ ... 1200 ., in your 3.044 class. '' You place the rod into .: TIC. {It!) !,-"' 1000 an induction coil and pull it through slowly, locally melting and BOO resolidifying the rod as the hot zone passes over it. ......... . .... - ... GOO . ~ ~ 0.. .. .. I . I .. ---,--L-.....J,..---'UI.~U-..-.....,.....--'-"- 10 0 10 !1(1 Yic•l i! h: Pe r ce n t T1 80 10 100 80 Co l><~ lt Co At the end of one pass, you analyze the leading end of the rod- this is the first part of the rod to be melted and resolidified. Part A: From the phase diagram, you estimate that the alloy composition at the end of the bar should be about 0.6 at% after one pass through the zone refiner. Explain this estimate. 1<. ~ 13 / 2..,_ (! L .y,'("j1 .-\?ra~ f k. . .se IIIA _Jnrn ( ~v"'-Tt:.-11._ h d.;-4-~l.:..~ ~oi;--J~-~7 ~G..) COVj05t-<ho, }t_ C0 1't- ? 1 ()_(, Part B: Ito You are shocked to find, however, that the end of the bar is quite substantially purer than you first suspected it might be! The composition is ~0.1 at% Co. Explain why the rod is so pure at this end, and why specifically it is at a value near 0.1 at% Co. (Note: your measurements are made after the rod is cooled back down to room temperature) . c) /1 -~ f ~ 5"eco~'~...J [ kc...s e ~ Dl ·kvt s tc.~" Vh--ko ._ LJ -6 ~1% -- Problem #4: Which Driving Force is Doing the Driving? In class, a long time ago, we looked at the problem of glass fiber production. We explicitly looked at the required cooling rate to keep a new fiber of diameter 20 11m, drawn from the fluid , from breaking up into droplets before it became rigid . A schematic of the process in shown at the right. Molten glass T ~ ~L lcm Now, back when we looked at this problem, we knew heat transfer but not fluid flow . Let 's talk about fluid flow this time around. Information: the material is glass at 900° C, 11 = I 02 Pa ·s, p = 2500 kg/m3, y = 0.5 J/m2 . • Part A) There are two driving forces for flow of the molten glass through the aperture. Name them , and determine which is dominant. (}./~ "l ) @ ~r~v , ~··(· tl 8 J';J(+!.S)vfe_ F.p -;: looJ( +'ort.e. · FJ -: : j _j (,J~,3~f of /ie_ heL J (;liVes b_P - J>Cjh «-- I""'- ~ L ~ L- c.~ ..t-' ~ore t~orh . -+~ Part B) There is one driving force for the breakup of the stream into drop lets : capillary stress, a 2y/r. Compare it to the driving forces from Part A and convince yourse lf (and me) that it is significant in this process. Pay attention to units here. = ()= c_o~ <I~ ·Jo ckJ~d-eA3k<_ /e . . ~il 5c . . /e · ~ - ?:> 0 '<I o q IJ/,..._J L - $u.rfc__ce ..J--e.., .s ,~."- 1 s v~1 Co~.eff,~) ~r~ Problem #5: Stretchy or not so Stretchy? Polyethylene is a very nice material to form into shapes with vi scous forming operations. At the right are data for the rheology of polyethylene. NOTE: These data are plotted on LOGARITHM IC SCALES . The slope tells you about the strain rate sensitivity. Part A) For a fixed forming rate (a shear rate of, say, I 0 s-1) , hi gher temperatures lead to more stable flow . Provide an estimate of the tensile ductility at 300° C vs. 120° N e lr:i u ..... 41) cu c: >- ~ en en 1.1.1 0: I- en 0: ct 1.1.1 :X: en 10 1 c. 10 103 2 SHEAR RATE (sec- 1 ) Flow curves at various temperatures for a low density polyethylene. [Reproduced from R. Mendelson, Polymer Eng. Sci., ~.. lo~ 235 (1968)]. .No-+e- cA..+- ·-c_:: slo~e P\. +- C-\._+- ~ ';{ /Z-0 JoI -I L fh:= C 1M.-::;:_ 6 3~() I 5 y'L I jz_o"c ~f ~ z_oa% 3l)t/ c 2·-+ ~ 1-(6o /o Part B) As a process designer, you would like to operate at the lowest possible temperature and the highest possible rate. Explain briefly how, with the help of this data, you would identify an optimum processing condition? What data would you need to do such an analysis? ~rork ti.e_ pc..r·~ 5~o~~~ we WoJ)d ltc_x,e ~ .dc'S,Y~J s+r?t,-~ _/ ~+·ftt~ J ;L.~+e_~ I In ViA H.~ c.Jaove fvih J,e-hi-t-5 tk 5'/ ~~e w~t« L .5if ec ; -h' e 5 eo~ L,)t__-k;,.., o ~ -{it,'> ,n_ <.> (_ i'R. I wr·fL eR?v4. -h-r>v... t'r..._ . ~ Ckc~+ ~-J-() t'h > KJ- } c.,re_ 4.{CtpAlle ~~+-~) Pmhlcm #6: Amazing Brazing .. ... Copper L31li/e allo\ - I / _,.~- I 13 A The prncess or hra;.ing i-. C'.Selltia ll y like ca-.ting: il melt is placed between two nhjn·ts to he joined : tile melt then solidifie-; _ holding the uhjcch tugethcr . These pil'lure-. show cro-.s--.cctiun-. llf hr:11.e j11illts het\\cent\\·u copper piece-. (\\.hich arc on the top and hntlonl) . I !ere arc three variables in this process: (i) braLe al loy composition, (ii) thickness of the hr:11.c region. (iii) temperature or the copper sheets Part.'\) lr ( i) <IIlLi (ii) arc exactly the same between the twu cases A and I) , L'xplain how (iii) must he dirkrcnt het\Vl'ell thl'lll . Provide tln l' '>elllencc or physical explanation . . • tt1 . MO f(. 1. ·~ " rw,~ :Je.AeD-.I.S \5,/ rl J , .L- L l-'LIIC'- u ~ 'l..t ~ /:'~ ~p~<- . , A ' , / / 2 c-Ctrc.-l b ,. (~ Wl -'5+- i"'>\ ~ /(I h.._.ve_ "- ~~L_b f3 }k... s+e_qe,.- ~ ~ H- ~ p~s Ls ~~'-"""- dlih..c.kJ A-I Jt. ....dr.-1-~s -r ') f1..c) ·~-+ 1 A~I!. [.._vS t' ) c.a IJu '"" ~kr-t!T • I Part B) If (ii) ami (iii) arc exactly the \arne between the two cases A a11d 13. exp l <~in how (i) lllll'>l he dil"lcrelll llL'tWL:ell them. Pruvide lllle seil!CilCC or physical explanatinn . ftvt. ~ . u.ulereo o l.~ L {3 ' 1 ~ llo7 A M Jt.-\- ~ ....v'.L q_ sl-ro'J e' /t1u/OJ5 011 ~ \_ d~ t~.)fl....c.<_ Q ~ (!;:; ()$. 'T\0 '- - "5~ay e.r (,, u1-z>v!> J lo(<.. a" pL S<- Jr:...:/........___. 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