Errata for First Printing of
Discrete-Time Signal Processing
by Oppenheim and Schafer with Buck
Page
xxv
Where
2nd paragraph, 4th line
55
2 lines after Eq. (2.154c)
87
Prob. 2.67(a), Last sentence
91
Prob. 2.82, 1st line
91
Prob. 2.82, 1st line
91
Prob. 2.83, 1st line
137
148
Fig. P3.46-2
Eq. (4.21)
160
Ex. 4.6, 3rd Eq. from end
164
165
171
Last line before Example 4.9
Last line before Example 4.10
Fig. 4.22(c)
171
Fig. 4.22(e)
178
Fig. 4.29(e)
182
Fig. 4.34
187
1st paragraph, 5th line
295
Line after Eq. (5.135)
419
Fig. P6.2-1
432
Fig. 6.34-1
513
Prob. 7.8, second sentence
Correction
Delete “e” from “Kelley” to it reads
“thanks W. Kelly Mosley for his . . . ”
Insert minus sign so it reads
xo [n] = −xo [−n]
Change ω in exponent to π so it reads
(−1)n = ejπn
Change 2nd x[n] to s[n] so it reads
x[n] = s[n] + e[n]
Insert “zero-mean” so it reads
. . . are independent zero-mean stationary. . .
Insert |a| < 1 so it reads
an u[n] with |a| < 1.
Label on left-most pole should be − 34 .
Insert k so the RHS reads
∞
1 Xc (j (Ω − kΩs ))
T
k=−∞
Remove ] at end. Insert π (2x) so RHS reads
jΩ0 πδ(Ω − Ω0 ) − jΩ0 πδ(Ω + Ω0 )
Change Example 4.5 to Example 4.10
Change Example 4.5 to Example 4.10
Slope for ω > 2π should be the same as
slope for 0 ≤ ω ≤ 3π/2.
See attached artwork correction.
Slopes for ω > 2π and ω < −2π are wrong.
Slope for ω > 2π should match slope for 0 ≤ ω ≤ π.
Slope for ω < −2π should match slope for −π ≤ ω ≤ 0.
See attached artwork correction.
Heights should be TL , not T1 .
See attached artwork correction.
Output should be labeled y[n], not w[n].
See attached artwork correction.
Insert 2 so it reads
“. . . e.g. at 2M ΩN .”
Change 1st ω to α so it reads
. . . where α and β are constants. . .
Upper arrow of left side should point upwards.
See attached artwork correction.
All three arrows along the bottom should point to the right
See attached artwork correction.
Change 9 to 11, 4 to 5, and -4 to -5 so it reads
The impulse response of the desired filter has length 11; i.e., h[n] = 0 for n
1
Page
566
Where
3 lines from bottom
577
577
606
Last sentence before 8.7.1
First sentence of 8.7.2
Prob. 8.20
614
626
Table P8.37-2
Prob 8.65(d)
627
Fig. P8.67-1
671
Prob. 9.4(c), 1st sentence
697
2nd paragraph of Example 10.2
737
Eq. (10.70)
758
Prob. 10.16, 2nd sentence
760
Prob. 10.24(a), 2nd sentence
830
Ans. to 2.2(a)
833
Ans. to 3.3(c)
834
Ans. to 3.12(a)
834
Ans. to 3.12(b)
835
Ans. to 4.4(b)
839
Ans. to 6.9(b)
843
Ans. to 7.6(a)
843
Ans. to 7.8(a)
843
Ans. to 7.8(b)
846
Ans. to 8.19
859
865
865
Index
Index
Index
Correction
Insert − sign so equation reads
−(N −m)k
WNmk = WN
Change Example 8.15 to Example 8.11
Change Example 8.15 to Example 8.11
Change sign of exponent so it reads
X1 [k] = X[k]ej2πk2/N .
Change X3 [k] to H3 [k].
Change last term on RHS of Eq. (P8.65-7) to read
XH [((−k))N ]SN [n0 k]
3rd Box should be H[k]
Output of 3rd Box should be Y [k], no subscript.
Output of 4th Box should be y[n], no subscript.
See attached artwork corrections.
Insert “for n ≥ 0 ” so it reads
h[n] should be periodic for n ≥ 0.
Insert comma so equation reads
V [k] = V ∗ [((−k))N ], k = 0, 1, . . . , N − 1
Insert
{ so LHS reads
¯
E I(ω)
Insert “continuous-time” so it reads
Determine the continuous-time frequency spacing . . .
Insert “continuous-time” so it reads
What is the effective continuous-time frequency spacing. . .
Change equation for N5 to read
N5 = N1 + N3 .
Insert z −1 so it reads
−N 2
−1 1 − z
Xc (z) = z
2
(1 − z −1 )
Leave ROC as is.
Change art so pole is at z = −2, not z = 2.
See attached art correction.
Change art so poles are at z = − 12 and z = 23 .
See attached art correction.
Change answer to read
Not unique. T = 11/100.
Add x[n − 2] − 8x[n − 3] to RHS so equation is
y[n] + y[n − 1] − 8y[n − 2] = x[n] + 3x[n − 1] + x[n − 2] − 8x[n − 3]
Change to read
δ = 0.03, β = 2.181.
Change answer to read
Six alternations. L = 5, so this does not satisfy the alternation theorem
Change answer to read
Seven alternations, which satisfies the alternation theorem for L = 5.
Change “-2” to “2” (2x) so it reads
m = 2. This is not unique. Any m = 2 + 6 works
Delete “k” of “Bankdpass filters.”
“Group delay and attenuation, effects of” should be 243-245.
“Group delay defined” should be 243.
2