Method of Assumed Profiles Here are the basic steps: 1. Assume some basic boundary velocity profile for u ( x, y ) . For example, this is a crude approach but illustrates the ideas: y ,0 ≤ y < δ ( x ) u( x, y ) = δ ( x) ue ( x ) 1, y ≥ δ ( x ) where δ (x) is the single unknown describing the velocity distribution. 2. Calculate δ * , θ (or H ) , and C f for the assumed profile: δ δ u y 1 y2 δ = ∫ 1 − dy = ∫ 1 − dy = y − δ 2 δ 0 ue 0 0 ∞ * 1 ⇒ δ* = δ 2 δ δ 1 y2 1 y3 u u y y − θ = ∫ 1 − dy = ∫ 1 − dy = 2 δ δ u ue 2 δ 3 δ 0 0 e 0 ∞ 1 ⇒θ= δ 6 1 δ δ = 2 =3 H= θ 1δ 6 * Note: Finally, to find C f we need τ w = µ ∂u ∂y y =0 ∂u ∂ y u = ue = e , for 0 ≤ y < δ ∂y ∂y δ δ Method of Assumed Profiles τw ⇒ Cf = 1 ρ eue2 2 = µ ue δ 1 ρ eue2 2 = 2µ ρ eueδ 3. Plug results from step 2 into integral b.l. equation: Cf = 2 du dθ θ + (2 + H ) e dx u e dx So, for our assumed linear profile: µ ρ eueδ = 1 d δ 5δ due + 6 dx 6ue dx (1) where δ (x) is the only unknown. We can solve this by specifying u e (x) , setting an initial value for δ at x = 0 (i.e. the leading edge) and then integrate in x . Note: in many cases, this integration will need to be done numerically. Example: Flat Plate 8 Ue(x)=U ρe=ρ 8 8 U ρ 8 y δ*(x) x Since u e ( x) = u ∞ is a constant, the governing equation (1) becomes: µ ρ ∞ u ∞δ = 1 dδ 6 dx Re-arrange and integrate: 16.100 2002 2 Method of Assumed Profiles 6µ dδ =δ ρ ∞U ∞ dx 6µ 1 d (δ 2 ) = ρ ∞U ∞ 2 dx 6µ 1 d (δ 2 ) dx dx = ∫0 ρ ∞U ∞ 2 ∫0 dx x x 6µ 1 x = δ 2 ( x ) − δ 2 (0) ρ ∞U ∞ 2 But, our initial condition is δ (0) = 0 . 6µ 1 x = δ 2 ( x) 2 ρ ∞U ∞ δ ⇒ ⇒ x δ* δ* x = x = = 12 µ 2 3 3.464 = = ρ ∞U ∞ x Re x Re x 1 2 δ x 3 Re x = = 1 2 3 2 Re x 1.732 Re x and C f : Re x 2µ 2µ = ρ eueδ ρ ∞u∞ x 2 3 1 Cf = 3 Re x Cf = Cf = 16.100 2002 0.577 Re x 3 Method of Assumed Profiles Comparison with Blasius solution: Blasius δ* Int. Method with linear velocity Re x 1.720 1.732 C f Re x 0.664 0.577 x 16.100 2002 4