Research Journal of Environmental and Earth Sciences 6(7): 389-393, 2014

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Research Journal of Environmental and Earth Sciences 6(7): 389-393, 2014
ISSN: 2041-0484; e-ISSN: 2041-0492
© Maxwell Scientific Organization, 2014
Submitted: ‎
May ‎04, ‎2014
Accepted: May ‎25, ‎2014
Published: July 20, 2014
Solving Fuzzy Linear Systems by District Matrix’s: An Application in GIS
J. Naghiloo and R. Saneifard
Department of Mathematics, Urmia Branch, Islamic Azad University, Urmia, Iran
Abstract: In this study we want to investing the ways for solving the fuzzy linear systems that the coefficient is a
fuzzy number, which is equals a classic number and our aim is to show the fact that whether the answer can be fuzzy
systems or not and at the end complete the discussion by a numerical example.
Keywords: Block matrix, fuzzy linear systems, fuzzy numbers, inverse matrix
INTRODUCTION
In applied mathematics Linear functions systems
and solving the large proportions is very important for
getting the result. Normally in most applied program
the result are shown with fuzzy numbers instead of
classic hence the use of different methods of math and
developing different solutions and getting a suitable is
more important than the fuzzy systems or solving them.
A general solution for a common fuzzy system n×n
that coefficient matrix is the fuzzy number and he right
hand Column is a number into fuzzy vector and draw a
system and replace the main fuzzy system with a classic
linear system 2×2 n and solve it by matrix linear system
approach. Ezzati (2008, 2011), Friedman et al. (1998,
2000), Ma et al. (1999) and Wu and Ma (1991) and
some other suggested over the fuzzy systems which is
the right hand column is fuzzy vector and they
investigate the numerical fuzzy systems. In this study,
the researchers want to investing the ways for solving
the fuzzy linear systems that the coefficient is a fuzzy
number, which is equals a classic number and our aim
is to show the fact that whether the answer can be fuzzy
systems or not and at the end complete the discussion
by a numerical example.
Fig. 1: A fuzzy number
aria {u (r), ลซ (r)} is out come an E convex carroty
which replacing in isomorphic, isometric shape into the
Banakh space (Ezzati, 2011).
PROPOSED METHODOLOGY
Linear system n×n:
๐‘Ž๐‘Ž11 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž12 ๐‘ฅ๐‘ฅ2 + โ‹ฏ + ๐‘Ž๐‘Ž1๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘›1 = ๐‘ฆ๐‘ฆ1
๐‘Ž๐‘Ž21 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž22 ๐‘ฅ๐‘ฅ2 + โ‹ฏ + ๐‘Ž๐‘Ž2๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘›1 = ๐‘ฆ๐‘ฆ2
โ‹ฎ
๐‘Ž๐‘Ž๐‘›๐‘›1 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž๐‘›๐‘›2 ๐‘ฅ๐‘ฅ2 + โ‹ฏ + ๐‘Ž๐‘Ž๐‘›๐‘›๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘›1 = ๐‘ฆ๐‘ฆ๐‘›๐‘›
Which matrix coefficients ๐ด๐ดฬƒ = (๐‘Ž๐‘Ž๐‘–๐‘– ๐‘—๐‘— ) = (๐‘Ž๐‘Ž๐‘–๐‘– ๐‘—๐‘— , ๐‘Ž๐‘Ž๏ฟฝ๐‘–๐‘– ๐‘—๐‘— ),
0≤i, j≤1 is a fuzzy matrix:
Fuzzy systems:
Definition 1: by the use of a couple of functions such
as: (u (r), ลซ (r)), 0≤r≤1:
•
•
•
(1)
๐‘›๐‘› × ๐‘›๐‘›, ๐‘ฆ๐‘ฆ๐‘–๐‘– : 1≤i≤n
Is a part of classic vector?
With replacing fuzzy coefficients, we have:
u (r) is a bounded monotonic increasing left
continuous function
ลซ (r) is a bounded monotonic decreasing left
continuous function
u (r) ≤ลซ (r), 0≤r≤1
(๐‘Ž๐‘Ž11 , ๐‘Ž๐‘Ž๏ฟฝ11 ) ๐‘ฅ๐‘ฅ1 + (๐‘Ž๐‘Ž12 , ๐‘Ž๐‘Ž๏ฟฝ12 ) ๐‘ฅ๐‘ฅ2 + … + (๐‘Ž๐‘Ž1๐‘›๐‘› , ๐‘Ž๐‘Ž๏ฟฝ1๐‘›๐‘› ) ๐‘ฅ๐‘ฅ๐‘›๐‘› =
๐‘ฆ๐‘ฆ1
(๐‘Ž๐‘Ž21 , ๐‘Ž๐‘Ž๏ฟฝ21 ) ๐‘ฅ๐‘ฅ1 + (๐‘Ž๐‘Ž22 , ๐‘Ž๐‘Ž๏ฟฝ22 ) ๐‘ฅ๐‘ฅ2 + … + (๐‘Ž๐‘Ž2๐‘›๐‘› , ๐‘Ž๐‘Ž๏ฟฝ2๐‘›๐‘› ) ๐‘ฅ๐‘ฅ๐‘›๐‘› =
๐‘ฆ๐‘ฆ2
โ‹ฎ
(๐‘Ž๐‘Ž๐‘›๐‘›1 , ๐‘Ž๐‘Ž๏ฟฝ๐‘›๐‘›1 ) ๐‘ฅ๐‘ฅ1 + (๐‘Ž๐‘Ž๐‘›๐‘›2 , ๐‘Ž๐‘Ž๏ฟฝ๐‘›๐‘›2 ) ๐‘ฅ๐‘ฅ2 + … + (๐‘Ž๐‘Ž๐‘›๐‘›๐‘›๐‘› , ๐‘Ž๐‘Ž๏ฟฝ๐‘›๐‘›๐‘›๐‘› ) ๐‘ฅ๐‘ฅ๐‘›๐‘› =
๐‘ฆ๐‘ฆ๐‘›๐‘›
(2)
For example the fuzzy number (1+r, 4-2r) as
illustrated in Fig. 1 a classic number a simply is
calculated. With specialty of definition of fuzzy number
Corresponding Author: R. Saneifard, Department of Mathematics, Urmia Branch, Islamic Azad University, Urmia, Iran
389
Res. J. Environ. Earth Sci., 6(7): 389-393, 2014
So conversion to the two system like down which is a classic coefficient:
and,
๐‘Ž๐‘Ž11 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž12 ๐‘ฅ๐‘ฅ2 + … + ๐‘Ž๐‘Ž1๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘› = ๐‘ฆ๐‘ฆ1
๐‘Ž๐‘Ž21 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž22 ๐‘ฅ๐‘ฅ2 + … + ๐‘Ž๐‘Ž2๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘› = ๐‘ฆ๐‘ฆ2
โ‹ฎ
๐‘Ž๐‘Ž๐‘›๐‘›1 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž๐‘›๐‘›2 ๐‘ฅ๐‘ฅ2 + … + ๐‘Ž๐‘Ž๐‘›๐‘›๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘› = ๐‘ฆ๐‘ฆ๐‘›๐‘›
(3)
๐‘Ž๐‘Ž๏ฟฝ11 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž๏ฟฝ12 ๐‘ฅ๐‘ฅ2 + … +๐‘Ž๐‘Ž๏ฟฝ1๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘› = ๐‘ฆ๐‘ฆ1
๐‘Ž๐‘Ž๏ฟฝ21 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž๏ฟฝ22 ๐‘ฅ๐‘ฅ2 + … + ๐‘Ž๐‘Ž๏ฟฝ2๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘› = ๐‘ฆ๐‘ฆ2
โ‹ฎ
๐‘Ž๐‘Ž๏ฟฝ๐‘›๐‘›1 ๐‘ฅ๐‘ฅ1 + ๐‘Ž๐‘Ž๏ฟฝ๐‘›๐‘›2 ๐‘ฅ๐‘ฅ2 + … + ๐‘Ž๐‘Ž๏ฟฝ๐‘›๐‘›๐‘›๐‘› ๐‘ฅ๐‘ฅ๐‘›๐‘› = ๐‘ฆ๐‘ฆ๐‘›๐‘›
(4)
If B was matrix coefficient of first system and C matrix coefficient of second system, matrix equation is such as:
or,
๐‘ฅ๐‘ฅ1
๐‘Ž๐‘Ž11 โ‹ฏ ๐‘Ž๐‘Ž1๐‘›๐‘›
๐‘ฆ๐‘ฆ
0 โ‹ฏ 0
โŽก . โŽค โŽก 1โŽค
โŽก โ‹ฎ
โ‹ฑ
โ‹ฎ โŽคโŽก โ‹ฎ โ‹ฑ โ‹ฎ โŽค
.
โŽข๐‘Ž๐‘Ž
โŽฅ โŽข 0 โ‹ฏ 0 โŽฅ โŽข๐‘ฅ๐‘ฅ๐‘›๐‘› โŽฅ โŽข๐‘ฆ๐‘ฆ โŽฅ
โ‹ฏ
๐‘Ž๐‘Ž
๐‘›๐‘›๐‘›๐‘› โŽฅ โŽข
โŽฅ × โŽข โŽฅ = โŽข ๐‘›๐‘› โŽฅ
โŽข 1๐‘›๐‘›
โŽข 0 โ‹ฏ 0 โŽฅ โŽข ๐‘Ž๐‘Ž11 โ‹ฏ ๐‘Ž๐‘Ž1๐‘›๐‘› โŽฅ โŽข ๐‘ฅ๐‘ฅ1 โŽฅ โŽข๐‘ฆ๐‘ฆ1 โŽฅ
โ‹ฑ
โ‹ฎ โŽฅ โŽข . โŽฅ โŽข.โŽฅ
โŽข โ‹ฎ โ‹ฑ โ‹ฎ โŽฅโŽข โ‹ฎ
โŽฃ 0 โ‹ฏ 0 โŽฆ โŽฃ ๐‘Ž๐‘Ž1๐‘›๐‘› โ‹ฏ ๐‘Ž๐‘Ž๐‘›๐‘›๐‘›๐‘› โŽฆ โŽฃ๐‘ฅ๐‘ฅ๐‘›๐‘› โŽฆ โŽฃ๐‘ฆ๐‘ฆ๐‘›๐‘› โŽฆ
(5)
๐ด๐ดฬƒ X = Y
๐ต๐ต
๏ฟฝ
0
(6)
0 ๐‘‹๐‘‹
๏ฟฝ๏ฟฝ ๏ฟฝ = Y
๐ถ๐ถ ๐‘‹๐‘‹
๐ต๐ต
0
If district matrix ๏ฟฝ
๐ธ๐ธ
๐บ๐บ
๏ฟฝ
๏ฟฝ
๐น๐น ๐ต๐ต
๏ฟฝ๏ฟฝ
๐ป๐ป 0
(7)
0
๐ธ๐ธ
๏ฟฝ was invisible and suppose that it's inverse is ๏ฟฝ
๐บ๐บ
๐ถ๐ถ
0
๐ผ๐ผ 0
๏ฟฝ =๏ฟฝ
๏ฟฝ
๐ถ๐ถ
0 ๐ผ๐ผ
๐ธ๐ธ ๐ต๐ต + 0 0 + ๐น๐น ๐ถ๐ถ
๐ผ๐ผ 0
๏ฟฝ=๏ฟฝ
๏ฟฝ
๐บ๐บ ๐ต๐ต + 0 0 + ๐ป๐ป ๐ถ๐ถ
0 ๐ผ๐ผ
๐น๐น
๏ฟฝ then:
๐ป๐ป
(8)
(9)
E = ๐ต๐ต−1
F = 0,
H = ๐ถ๐ถ −1
G=0
−1
So ๏ฟฝ๐ต๐ต
0
0 ๏ฟฝ will be inverse of ๏ฟฝ๐ต๐ต
0
๐ถ๐ถ −1
−1
๐‘‹๐‘‹
๏ฟฝ ๏ฟฝ = ๏ฟฝ๐ต๐ต
0
๐‘‹๐‘‹
0 ๏ฟฝY
๐ถ๐ถ −1
0
๏ฟฝ. Thus the answer of system is:
๐ถ๐ถ
(10)
Then the answer X = (๐‘‹๐‘‹, ๐‘‹๐‘‹) is a fuzzy number.
NUMERICAL EXAMPLE
Example 1: In this example, the coefficients of trigonometric equations are fuzzy numbers. And in the right, the
numbers are classics:
390
Res. J. Environ. Earth Sci., 6(7): 389-393, 2014
๏ฟฝ
(0.1, 0.4, 0.9 )๏ฟฝ๐‘ฅ๐‘ฅ1 , ๐‘ฅ๐‘ฅ1 ๏ฟฝ + (1,1.4,1.9)๏ฟฝ๐‘ฅ๐‘ฅ2 , ๐‘ฅ๐‘ฅ2 ๏ฟฝ = 2
(0.1,0.15,0.2)๏ฟฝ๐‘ฅ๐‘ฅ1 , ๐‘ฅ๐‘ฅ1 ๏ฟฝ + (0.11,0.14,0.2)๏ฟฝ๐‘ฅ๐‘ฅ2 , ๐‘ฅ๐‘ฅ2 ๏ฟฝ = 1
Conversion of fuzzy equations to interval form, we get:
(0.3๐‘Ÿ๐‘Ÿ, 0.1 , −0.5๐‘Ÿ๐‘Ÿ + 0.9 )๏ฟฝ๐‘ฅ๐‘ฅ1 , ๐‘ฅ๐‘ฅ1 ๏ฟฝ + (0.4๐‘Ÿ๐‘Ÿ + 1, −05๐‘Ÿ๐‘Ÿ + 1.9)๏ฟฝ๐‘ฅ๐‘ฅ2 , ๐‘ฅ๐‘ฅ2 ๏ฟฝ
๏ฟฝ (0.05๐‘Ÿ๐‘Ÿ + 0.1, −0.05๐‘Ÿ๐‘Ÿ + 0.2)๏ฟฝ๐‘ฅ๐‘ฅ1 , ๐‘ฅ๐‘ฅ1 ๏ฟฝ +
(0.03๐‘Ÿ๐‘Ÿ + 0.11, −0.06๐‘Ÿ๐‘Ÿ + 0.2 )๏ฟฝ๐‘ฅ๐‘ฅ2 , ๐‘ฅ๐‘ฅ2 ๏ฟฝ
If we write the matrix form:
๐‘ฅ๐‘ฅ1
0.3๐‘Ÿ๐‘Ÿ + 0.1
0.4๐‘Ÿ๐‘Ÿ + 1 0
0
2
๐‘ฅ๐‘ฅ
2
0.05๐‘Ÿ๐‘Ÿ + 0.1
0.03๐‘Ÿ๐‘Ÿ + 0.11 0
0
1
๏ฟฝ
๏ฟฝ ๏ฟฝ๐‘ฅ๐‘ฅ ๏ฟฝ = ๏ฟฝ ๏ฟฝ
0 0 − 0.5๐‘Ÿ๐‘Ÿ + 0.9 − 0.5๐‘Ÿ๐‘Ÿ + 1.9
2
1
0
0
− 0.05๐‘Ÿ๐‘Ÿ + 0.2
− 0.06๐‘Ÿ๐‘Ÿ + 0.2 ๐‘ฅ๐‘ฅ2
1
Assuming that:
0.3๐‘Ÿ๐‘Ÿ + 0.1
−0.4๐‘Ÿ๐‘Ÿ + 1
0.5๐‘Ÿ๐‘Ÿ + 0.9 −0.5๐‘Ÿ๐‘Ÿ + 1.9
C=๏ฟฝ
๏ฟฝ
๏ฟฝ, B = ๏ฟฝ
0.05๐‘Ÿ๐‘Ÿ + 0.1 −0.03๐‘Ÿ๐‘Ÿ + 0.11
0.5๐‘Ÿ๐‘Ÿ + 0.2 −0.06๐‘Ÿ๐‘Ÿ + 0.2
By calculating๐ถ๐ถ −1 , ๐ต๐ต−1 :
1
๐ต๐ต−1 =11๐‘Ÿ๐‘Ÿ 2 −54๐‘Ÿ๐‘Ÿ−81 ๏ฟฝ
30๐‘Ÿ๐‘Ÿ + 110
−50๐‘Ÿ๐‘Ÿ − 100
1
60๐‘Ÿ๐‘Ÿ + 200
๐ถ๐ถ −1 =5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200 ๏ฟฝ
50๐‘Ÿ๐‘Ÿ − 200
Placement in the equation:
๐‘ฅ๐‘ฅ1
๐‘ฅ๐‘ฅ2
−1
๏ฟฝ๐‘ฅ๐‘ฅ ๏ฟฝ = ๏ฟฝ๐ต๐ต
1
0
๐‘ฅ๐‘ฅ2
−400๐‘Ÿ๐‘Ÿ − 1000
๏ฟฝ
300๐‘Ÿ๐‘Ÿ + 100
500๐‘Ÿ๐‘Ÿ − 1900
๏ฟฝ
−500๐‘Ÿ๐‘Ÿ + 900
2
0 ๏ฟฝ=๏ฟฝ1๏ฟฝ, ๏ฟฝ๐‘‹๐‘‹๏ฟฝ = ๏ฟฝ๐ต๐ต −1
๐ถ๐ถ −1 2
0
๐‘‹๐‘‹
1
30๐‘Ÿ๐‘Ÿ+110
−400๐‘Ÿ๐‘Ÿ−1000
โŽก11๐‘Ÿ๐‘Ÿ 2 −54๐‘Ÿ๐‘Ÿ−81 11๐‘Ÿ๐‘Ÿ 2 −54๐‘Ÿ๐‘Ÿ−81
๐‘ฅ๐‘ฅ1
300๐‘Ÿ๐‘Ÿ+100
โŽข −50๐‘Ÿ๐‘Ÿ−100
๐‘ฅ๐‘ฅ2
2 −54๐‘Ÿ๐‘Ÿ−81
2 −54๐‘Ÿ๐‘Ÿ−81
11๐‘Ÿ๐‘Ÿ
11๐‘Ÿ๐‘Ÿ
๏ฟฝ๐‘ฅ๐‘ฅ ๏ฟฝ = โŽข
1
โŽข
0 0
๐‘ฅ๐‘ฅ2
โŽข
0 0
โŽฃ
๐‘ฅ๐‘ฅ๏ฟฝ1 =
๐‘ฅ๐‘ฅ2 =
๐‘ฅ๐‘ฅ1 =
−340๐‘Ÿ๐‘Ÿ−890
11๐‘Ÿ๐‘Ÿ 2 −54๐‘Ÿ๐‘Ÿ−81
0 ๏ฟฝ = ๏ฟฝ๐‘Œ๐‘Œ๏ฟฝ
๐‘Œ๐‘Œ
๐ถ๐ถ −1
0
0
60๐‘Ÿ๐‘Ÿ+200
5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200
50๐‘Ÿ๐‘Ÿ−200
5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200
0
โŽค
2
โŽฅ
0
โŽฅ × ๏ฟฝ1๏ฟฝ
500๐‘Ÿ๐‘Ÿ−1900
2
โŽฅ
5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200
1
โŽฅ
−500๐‘Ÿ๐‘Ÿ+900
5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200 โŽฆ
200๐‘Ÿ๐‘Ÿ−100
11๐‘Ÿ๐‘Ÿ 2 −54๐‘Ÿ๐‘Ÿ−81
620๐‘Ÿ๐‘Ÿ−1500
5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200
๐‘ฅ๐‘ฅ2 =
−400๐‘Ÿ๐‘Ÿ+500
5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200
And finally:
๏ฟฝ1 =๏ฟฝ −340๐‘Ÿ๐‘Ÿ−890
,
๐‘‹๐‘‹
11๐‘Ÿ๐‘Ÿ 2 −54๐‘Ÿ๐‘Ÿ−81
๏ฟฝ2 =๏ฟฝ 200๐‘Ÿ๐‘Ÿ−100
,
๐‘‹๐‘‹
11๐‘Ÿ๐‘Ÿ 2 −54๐‘Ÿ๐‘Ÿ−81
620๐‘Ÿ๐‘Ÿ−1500
5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200
−400๐‘Ÿ๐‘Ÿ+500
5๐‘Ÿ๐‘Ÿ 2 +41๐‘Ÿ๐‘Ÿ−200
๏ฟฝ
๏ฟฝ
391
Res. J. Environ. Earth Sci., 6(7): 389-393, 2014
The device answers, which is a fuzzy number.
Example 2: In this example, the coefficients are either trapezoidal fuzzy numbers. The right numbers are
classics:
(0.1,0.4,0.6,0.9)๏ฟฝx1 , x1 ๏ฟฝ + (1,1.4,1.6,1.9)๏ฟฝx2 , x2 ๏ฟฝ = 1
๏ฟฝ
(5,5.1,5.2,5.4)๏ฟฝx1 , x1 ๏ฟฝ + (0.1,0.3,0.035,0.4)๏ฟฝx2 , x2 ๏ฟฝ = 0.5
The conversion equations to form an interval fuzzy:
(0.3α + 0.1, −0.3α + 0.9)๏ฟฝx1 , x1 ๏ฟฝ + (0.4α + 1, −0.3α + 1.9)๏ฟฝx2 , x2 ๏ฟฝ = 1
๏ฟฝ
(0.1α + 5, −0.2α + 5.4)๏ฟฝx1 , x1 ๏ฟฝ + (0.2α + 0.1, −0.05α + 0.4)๏ฟฝx2 , x2 ๏ฟฝ = 0.5
We write the above system as a matrix equation:
0.3α + 0.1
0.1α
+ 5.0
๏ฟฝ
0
0
x1
1
0
0
0.4α + 1
x
2
0.5
0
0
0.2α + 0.1
๏ฟฝ × ๏ฟฝx ๏ฟฝ = ๏ฟฝ ๏ฟฝ
−0.3α + 0.9 −0.3α + 1.9
0
1
1
−0.2α + 5.4 −0.05α + 0.4
0
x2
0.5
B
If we consider coefficient matrix as block matrices ๏ฟฝ
0
0
๏ฟฝ so:
C
0.3α + 0.1 0.4α + 1
−0.3α + 0.9 − 0.3α + 1.9
B=๏ฟฝ
๏ฟฝ, C = ๏ฟฝ
๏ฟฝ
−0.2α + 5.4 − 0.05α + 0.4
0.1α + 5 0.2α + 0.1
And calculating B−1 , C−1 in the below:
B
−1
=
20α+10
2 +2α−499
๏ฟฝ2α−10α−500
2α2 +2α−499
−40α−100
2α2 +2α−499
30α+10 ๏ฟฝ,
2α2 +2α−499
C
−1
=
−50α+400
300α−1900
2
+1835α−9820
๏ฟฝ45α 200α−5400
45α2 +1835α−9820
๏ฟฝ
−300α+900
45α2 +1835α−9820
45α2 +1835α−9820
Answer Calculation of equation X = A−1 Y or:
−1
X
๏ฟฝ ๏ฟฝ = ๏ฟฝB
0
X
0 ๏ฟฝ=Y
C−1
20α+10
−40α−100
2
2
x1 โŽก2α +2α−499 2α +2α−499
−10α−500
30α+10
x2 โŽข2α2 +2α−499 2α2 +2α−499
โŽข
๏ฟฝx ๏ฟฝ=
1
โŽข
0 0
x2 โŽข
0 0
โŽฃ
And finally:
x1 =
x2 =
x1 =
x2 =
0
0
−50α+400
45α2 +1835α−9820
200α−5400
45α2 +1835α−9820
0
โŽค
1
โŽฅ
0
โŽฅ × ๏ฟฝ0.5๏ฟฝ
300α−1900
1
โŽฅ
45α2 +1835α−9820
0.5
โŽฅ
−300α+900
45α2 +1835α−9820 โŽฆ
−40α−100
2α2 +2α−499
−20α−495
2α2 +2α−499
100α−550
45α2 +1835α−9820
−350α−4950
45α2 +1835α−9820
392
Res. J. Environ. Earth Sci., 6(7): 389-393, 2014
and WALL2 are illustrated in Fig. 1. The calculation of
the values of the anteriority index between F and G
gives Centr (F) = 0.95 and Centr (G) = 0.05. So, as
defined in Sect. 3, F is rather anterior to G, thus
WALL1 was rather anterior to WALL2. So this result
suggests that WALL1 was built first and was destroyed
before the construction of WALL2.
AN APPLICATION
The SIGRem project is an archaeological GIS
dedicated to the Roman period of Reims. The main goal
of the project is to help experts in their decision
processes. In this section, we use the anteriority index
in the decision processes for simulation and data
visualization. Dates in archaeological excavation data
can be represented by the possibility theory using fuzzy
numbers as “near 1330 A.D.” or “Middle Ages”. To
give the archaeologists some predictive maps, we want
to use the comparison decisions for spatial inference.
The anteriority index helps us to resolve some spatial
and architectural contradictions of excavation maps. On
the “Galeries Remoises” site, there are two walls
(WALL1 and WALL2) built during the first century,
showing an architectural contradiction as one overlaps
the other. Our goal is to design a new map to simulate
the archaeological hypothesis on dating. The index
proposes a weighed indication on the question “Was
WALL1 built before WALL2?”. The two building dates
are represented by fuzzy numbers F (date of WALL1)
and G (date of WALL2). The membership function f
(resp. g) of F (resp. G) is defined as a trapezoidal
where:
•
•
•
CONCLUSION
In the present study the authors want to investing
the ways for solving the fuzzy linear systems that the
coefficient is a fuzzy number, which is equals a classic
number and our aim is to show the fact that whether the
answer can be fuzzy systems or not and at the end
complete the discussion by a numerical example.
REFERENCES
Ezzati, R., 2008. A method for solving fuzzy general
linear systems. Appl. Comput. Math, 2: 881-889.
Ezzati, R., 2011. Solving fuzzy linear systems. Soft
Comput., 15: 193-197.
Friedman, M., M. Ming and A. Kandel, 1998. Fuzzy
linear systems. Fuzzy Set. Syst., 96: 201-209.
Friedman, M., M. Ming and A. Kandel, 2000. Duality
in fuzzy linear system. Fuzzy Set. Syst., 109:
55-58.
Ma, M., M. Friedman, M. Ming and A. Kandel, 1999.
Perturbation analysis for a class of fuzzy linear
system. J. Comput. Appl. Math, 224: 54-65.
Wu, C.X. and M. Ma, 1991. Embedding problem of
fuzzy number spsce: Part I. Fuzzy Set. Syst., 44(1):
33-38.
Support (f) = [(t1 - 0.2 (t2 - t1), (t2 - 0.2 (t2 - t1)]
Kernel (f) = [(t1 - 0.2 (t2 - t1), (t2 0.2 (t2 t1)]
t1 and t2 are respectively the beginning and the end
of the period
For WALL1, t1 is equal to 0 and t2 to 100. For
WALL2, t2 is equal to 50 and t2 to 100. So F = (-20,
20, 80, 120, 1) and G = (40, 60, 90, 110). Membership
functions of the fuzzy numbers associated to WALL1
393
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