Research Journal of Applied Sciences, Engineering and Technology 4(10): 1250-1259, 2012 ISSN: 2040-7467 © Maxwell Scientific Organization, 2012 Submitted: November 25, 2011 Accepted: December 27, 2011 Published: May 15, 2012 New Restructure of Transmitted Sequences for CP-based LS Channel Estimation Method in OFDM System Wang-Xing Zhao, Zhang-Xin Chen and Qun Wan Department of EE, University of Electronic Science and Technology of China, Chengdu, China Abstract: This study proceeded to investigate a study and a signal processing on channel estimation problem of OFDM system in wireless communication area. We gave an optimization stretching into total transmitted sequences restructure which aimed to improve Cyclic-prefix Least Square (CPLS) channel estimation method proposed in this paper. By contrast to conventional Training Sequences (TS) methods especially frequency TS, like sub-carriers TS, which directly occupy sub-carrier data sequences, CPLS method can greater the usage of cyclic-prefix thus saves system resources. In detail, we first gave a deduction and Mean Square Error (MSE) compare of both CPLS and Equally Spaced Training Sequences (ESTS) method based on LS principle. Then according to the deduction, we mainly concerned the restructure of total transmitted sequences using optimization tools, the Lagrange resolving, before which an constrain model was established, effects of our restructure were that it largely lower down the channel estimation MSE by using CPLS, while system BER was also improved. In the last part simulations given showed the correctness of our restructure theory. Key words: Channel estimation, constrain model, Cyclic-prefix Least Square (Cpls) method, Equally Spaced Training Sequences (ESTS) method, lagrange resolving, Orthogonal Frequency Division Multiplexing (OFDM), transmitted sequences restructure INTRODUCTION Orthogonal Frequency Division Multiplexing (OFDM) is considered to be a key technical in the next 4G or B3G wireless communication systems. And before this, it has already been used in European Digital Broadcast Audios (DBA) system etc. Superiority of this new technical is its high usage rate of frequency, due to its function that transforms a frequency band with a certain width into orthogonal sub-carriers; sub-carriers carry data symbols and are modulated into OFDM symbols. As a necessary part of OFDM systems, channel estimation can reduce detection Bits Error Rate (BER) in receiver thus gains a large significance of investigation. By now, means or methods of estimation are already abundant. Among them, the most prevalent way is the method that inserts comb pilots and interpolates so as to imitate the fast time-varied channel. This method uses assistant information in frequency and performs well particularly in time-varied channel. In the methods that based on training sequences, in different principles discussed in Wang et al. (2008), like Least-Square (LS), Linear Minimal Mean Square Error (LMMSE), or Maximal Likelihood (ML), computer in both receiver and transmitted training sequences, it can make out result of estimation. Nevertheless, drawbacks of this method are its occupying of valid data sequences. Other sorts of method basically cope with channel as a FIR filter and explicit adaptive signal processing ways to estimate it, that is, do iterations to make closest to real channel value, as mentioned in article Sun et al. (2005), LMS adaptive algorithm, and in paper Way and Yumin (2004), the Kalman filtering method. In the field of blind channel estimation, conventional method is to transform the received signal into high order to generate a new correlation matrix and decompose it into sub-spaces then recover the channel information see Kathryn and Ying (2005). Due to matrix theory, paper Feng (2009) abstracts OFDM system into matrix perturbation model and resolves the model so as to reach the purpose of estimation. Cyclic-prefix only plays a role as to inhibit the symbols and sub-carriers interferences and is seldom used to estimate channel. However, paper Toshiaki and Andreas (2011) deduces the channel time presentation through convex optimum modeling. Paper Christopher and Steger (2004) specifically excavates the relations between cyclic-prefix and channel in time domain. Paper Borching (2008) concludes how the completeness of cyclic-prefix influents channels estimation and data recovery in receiver. However, unlike the methods based on cyclic-prefix above, the paper reuse cyclic-prefix in a simple way, that is, transform both received cyclic-prefix and transmitted cyclic-prefix in frequency sequences and directly do LS estimation, we call it Cyclic-prefix LS (CPLS), as shown in Fig. 1. Corresponding Author: Wang-Xing Zhao, Department of EE, University of Electronic Science and Technology of China, Chengdu, China 1250 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 LS channel estimator and input condition: In OFDM system, according to paper ¤LKER (2005), combine (2) channel estimator based on frequency LS principle can be presented as: Y H ls X Fig. 1: A simplified CPLS channel estimation model Method of CPLS is easy to accomplish and for OFDM system, it only need to transform CP into frequency domain and do LS estimation. Thus this method can greatly increase the usage effectiveness of cyclicprefix and save extra cost. However, compare to the conventional TS or the most optimized Equally Spaced TS (ESTS), MSE performance of CPLS is not always better. Paper Wang-xing and Fang (2011) gives a proof that in LS frame, whatever transmitted sequences are, it can always find a certain number of training sequences whose performances are better than CPLS. Actually in this paper we compare deeply the MSE of same point equally spaced TS and CPLS method under same transmitted sequences. Under this background, this paper proposes a transmitted sequence restructure method that make CPLS and ESTS as close as possible or in MSE even better, moreover, in constrain model constraints are made aiming to better CPLS under LS frame. We repeatedly use Lagrange resolving mathematical tool to resolve our models, that is, use the tool for two times. In the first, a subtle way is introduced to resolve the result as we wanted, while in the second resolving process we proposed a resolving algorithm by which we escape large amount of computing complexity and obtain final result. At last, simulations given verify our theories respectively. Moreover, before restructure, we deduce the MSE of LS frame and deduce the characteristic representation of ESTS as follows. These are roots for our restructure theory. In (3), Y is received frequency sequences, X means transmitted frequency sequences, the action is to do a division in the corresponding sides, then according to the definition of MSE: H N N E H H H H X X N H N N H N E X X X X N 2 X 2 (4) 1 SNR Equation (4) means that when MSE of noise vector is stationed, MSE of LS channel estimation only depends on the signal power. Besides, (4) shows MSE of LS estimator only relates to transmitted symbols. Actually, selections of transmitted sequences can be arbitrary in LS estimator, if and only if they are linearly combined from all transmitted sequences. Consider attach CP frequency sequences to transmitted sequences, we have: 1 1 X p Fp * * 1 N 1 1 e j e 2 *( N p 1) N j 2 *( N p 2 ) N ... 2 * N j e N ... ... ... ... 2 *( N p 1)( N 1) N 2 *( N p 2 )( N 1) j N e ... 2 *( N 1) j N e e j (5) * X N Fp N * X N General channel transmitted model of OFDM system: (1) In formulation (1), y indicates receiver time domain symbols, s, the transmitted time domain symbols; h indicates channel, n, Gauss white noise, H presents convolution calculation. Particularly, when transmitted symbols are continuous, according to cyclic convolution property, in frequency domain, (1) can be presented as: Y = HS + N M SE ls E ( H ls H ) H ( H ls H ) LS ESTIMATOR y=sqh+n (3) (2) In Eq. (5), N presents number of transmitted symbols or number of sub-carriers, p is the length of cyclic prefix, Xp equals to left side of (5) and presents the cyclic prefix frequency sequences, XN, total transmitted sequences, F p×N is a linear transformation matrix. Therefore, Eq.(5) indicates that CP frequency sequences can be linearly combined by transmitted sequences, it satisfies input conditions of LS estimator. Consistency condition of LS estimator: From the LS estimators using conventional training sequences in 1251 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 frequency domain we find that it must satify an consistency condition, that is, training sequences for LS division of both receiver and transimtted part must be conresponding to each other, otherwise, it may not comform to the purpose of what we want. So here we have to analysis the consitence condition satification of CPLS. From the property of eccess of OFDM system, what we need to prove is the receiver cyclic-prefix also equals to the last part of time domain OFDM symbols of receiver. Now we prove based on transimtted model in time channel model. We set receive time domain OFDM symbol with cyclic-prefix as: yN+p = (y(0), y(1), … , y(N+p-1)) (6) then cyclic-prefix of receiver can be presented as: yCP = (y(0), y(1), … , y(p-1)) (7) Meanwhile the last P point of time symbols y N+p is: yp = (y(N-1) , y (N) , … , y(N+p-1)) (8) Then, Y CP = Fp* yCP meanwhile: F p × N* YN = Fp *yp (9) So we only need to compare to prove yCP = yP .Actually in OFDM time domain transmitted model it is not hard to prove. First consider cyclic-prefix of the transmitted side xg OFDM time domain symbols without cyclic-prefix is x, then: x ( N p n) , 0 n p 1 xg (n) x ( n p) , p n N p 1 y N + p (m) = y N+P (m+N-1), m = 0,…, p-1, p > l So yCP = yp which means receiver side also satisfies the cyclic-prefix added trait. Therefore this proof of consistence conditions of CPLS provides that CPLS can be totally feasible to compare with the conventional training sequences like ESTS. CHARACTERISTICS SEQUENCES As mentioned above, here define two characteristic sequences, all of them can do LS estimation; they are Equally Spaced Training Sequences (Ests) and Cyclic Prefix Frequency Sequences (CPFS), as shown in Fig. 2 where transmitted sequences named in this paper are actually sub-carriers symbols in OFDM system. First, we deduce their expression and make a compare of both sequences. Set length of IDFT M which equals to number of subcarriers, as P<M, thus, we can always selected P training sequences from M transmitted sequences in equal space. Each adjacent training sequences space in length, Q = [M/P], [•] presents Gauss ceiling. To easily deduce, we set M = P*Q, in reality we just need to adjust the length of P so that it is large than the length of paths number of multi-paths channel. Let Xi, i = 1, 2, …, M presents total transmitted sequences, then, ESTS can be presented as: X m+(i-1)*Q, 1# m # Q, I = 1, 2,…, P (13) M presents originate position of the sequences P means the block number, Q is space. Generally, for arbitrary m, use DFT: X m X m Q X m( P 1)Q (10) m*0 W M ( mQ )*0 W M ... M ( p 1)*Q *0 W M Therefore time domain transmitted model can be presented as: l 1 y g (n) h(i ) * x g (n i ) w(n) (12) (11) m*( M 1) WM x1 x 2 ... ... ... ... [ m( P 1)*Q ]*( M 1) x M ... W M ... (14) ( mQ )*( M 1) WM i0 Length of yg is N+p+l-1, in general, take the sequences from l to N+p+l-1, that is , y N + p (n) = yg (n+l1) n = 0,…, N+p-1.Therefore according to (10) and (11) where cyclic-prefixes are added in transmitted side, if p > l there must be: WMi*k e j *2 *i *k M Equation (14) means xQ = F xM. xM. is time domain transmitted OFDM symbols. Consider separate xM into pieces, that is: 1252 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 Fig. 2: Two characteristic sequences to be compared f 0 x 1 f1 x M x2 ... ... f x Q2 M f Q 1 WMm*0 0 0 0 m*1 0 0 0 W M F0 FP FPW 0 0 0 ... 0 0 WMm*( P 1) 0 (15) Meanwhile, it is not hard to find out that property as: In Eq. (15), f Q-1 = x CP, means the cyclic prefix. f 0,…, f Q-2 are non-CP part. Therefore x M is divided into Q pieces, the last one is cyclic prefix. Do the same separations to F, that is, block F into Q blocks: F = [F0 F1 … FQ-2 FQ-1] W Mm*0 ... ( m Q)*0 W M ... F0 ... ... W [ M ( p 1)*Q]*0 ... M W M( m Q)*( P 2 ) ... [ m ( P 1)*Q*( P 2 )] WM m* P WM 0 F1 F0 0 0 0 0 m* P WM 0 0 ... 0 0 0 F0 0 m* P WM 0 In the same way, F i F i-1N , i = 1,…, Q , thus, combine Eq. (16) and (19), we subtly get the relation that: ( m Q )*( P 1) WM ... [ m ( P 1)*Q ]*( P 1) WM W Mm*( P 1) F = F p W [I p, N , …, N Q-1] (17) X Q FPWf 0 FP W f 1 ... FPW Q 1 f Q 1 FP W[ I , ,..., Q 1 ] X M WM[ m (i 1)*Q ]*( j 1) W (22) while according to the definition of cyclic prefix: Unit expression of elements in F0 is, WM [m+(i-1)*Q]*(j-1) , = 1, 2, …, P m*( j 1) M (21) Therefore, combine Eq. (14) and (15) ultimately we get deduction of presentation for ESTS as following: XCP = Fp f Q-1 = FP [0, 0,…, I] XM WMm*( j 1)WM( j 1)*(11)*Q (20) (16) In Eq. (16), F0corresponds to multiply f0 in detail: W Mm*( P 2 ) (19) (18) ( j 1)*( i 1) P W Set Fp be P points DFT matrix, combine (18) we can tear F0 as: (23) Then in Appendix A we give a proof of MSE of LS estimation for XQ and XCP in detail, the proof shows that MSE of CPLS is not always larger than ESTS method except that under our following restructure we force the MSE of former smaller than the latter. Simulation will show the correctness. While in Appendix B we give a optimization concerned proof that under same number of TS selected, ESTS can make MSE of LS smallest, therefore we need not find other TS from transmitted sequences. These can be the origins and roots for our restructure in the next part of article. 1253 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 Therefore combine Eq. (4) and (5), we can establish constrains as following: NEW RESTRUCTURE OF TRANSMITTED SEQUENCES Restructure method analysis: Deduction in appendix shows that under same condition MSE of ESTS and CPLS are not certain while in the selection of direct TS (training sequences) ESTS is the optimized. Therefore, here we consider restructure a formation of new transmitted sequences using convex optimization. We need to set up a principle function, as well as constrains, all of them composed an optimized model. First, our target function, we need to restructure transmitted sequences that make representation of CPFS is as similar as possible to ESTS or in MSE the former even better than the latter. So our participation goes like this: a first target function make both method as close as possible in formation, and a second target function we aim to make CPLS surpass the other in MSE performance. Then, for constrains, according to LS estimator property, especially the MSE of LS we deduced before, we aim to make CPLS of new transmitted sequences not larger than ESTS in MSE. Meanwhile, remain structure of the new restructured sequence the same as before so that BER can be controlled. Combine the first target function and constrains we can compose an initial optimizing models. Then Lagrange resolving method tool is introduced to resolve our constrain model respectively. Restrictions model: Let new transmitted sequences be x, for the description of method, combine Eq. (5) and (22), new x must satisfy: Fp1 F p N X AX x op arg min 1 X W F N X (26) " maps time domain transmitted sequences into sequences with cyclic prefix, * is a constant assured by input sequences. FN1 X / FN1 X N Presents the ratio of time domain power of new transmitted and original sequences which is also the ratio of variances of noise because when signal-to-noise ratio is stationed the value of latter is directly related to the former. W FN1 X N Is the original power of original ESTS. Therefore combine Eq. (24) (25) and (26), a constrained model is set up as following respectively: min AX X st . X X N and MX NX (27) Lagrange resolving: To make out the result of (27), here we first restructure Lagrange function where the method Lagrange resolving is a common method to solve convex problem: 2 ( X X N ( MX 2 NX 2 2 2) 2 2 ) (28) Here 8, : are Lagrange factor, , is one increment element, introduced by the second inequality formulation. Now according to the essence of Lagrange resolving extremism, grade the (28) by X and differential (28) by 8 and :, we have: A H AX X X N M H MX 2 N H NX 0 .....( a ) 2 2 ......(b) X XN .....(c) MX 2 2 NX 2 2 (25) õ is a small real positive number. Further, in order to make MSE of CPLS smaller than that of ESTS method, according to deduction of MSE for LS, it is determined by two factors: time domain power of input sequences of LS and variance of noise. FN1 X N N FN1 , (24) This goal function makes both sequences closer to each other. Our goal is to restructure the transmitted sequences under which the two sequences ESTS and CPFS mentioned will be close toN each other. Second, keep the total structure as similar as original: FN 1 X * W FN1 X N NX f ( X , , ) AX 5 5Means the second norm of vector, N [N 0 , … , NQ-1]. 5X!XN5#0 Fp 1 F p N X MX (29) Next we will utilize a subtle way to resolve these relations in (29), the deduction of result X op is as following: First, (29) (a) is meant to: 1254 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 X N X A H A M M H 2 NH N X BX However, this condition is somewhat off to our optimizing goals, our goal is to let CPLS surpass ESTS method under LS. So here we have to introduce a more direct and strong target function as (39): (30) Then substitute (30) into (29) (b): X H B H BX 2 (31) X op Fold (29) (c): X H (M H M 2 N H N) X 2 (32) arg min x (39) Then, a repeated Lagrange resolving model can be: Therefore compare (31) and (32), we discover that: g ( x ) A X b BH B 2 (M H M 2 N H N) F 1 F p N X p A `X b W FN1 X N 2 2 X H X N X H X X H zX (40) (33) We grade both sizes by x, Important analysis: N= " F N is (N+P)×N matrix with rank N, so MHM - *2 NHN must be a full rank matrix with rank N, thus, we certainly find a matrix z which satisfy MHM - *2 NHN z2 N×N, here z is full rank matrix also with rank N. Meanwhile, according to (30), BHB is a symmetric matrix, thus, (33) is: -1 B 2 z (35) A H A M H M 2 N H N with XH in the left side and X in right side, according to (32): Till now, multiply X H A H AX 2 X H zX X H A H AX 2 X H XN X H X C C (36) (41) 2X H A H A X 2 X H A H b (42) X H XN set g0 = 0.0001; X(0)op = ones (N, 1), F(0) = 1; While g (X(k)op) > g0 do ( k 1) ( k ) X op I ( k ) z A H A 1 (k ) X N A H b 2 (37) H 2 X ( k ) A H A X ( k 1) Therefore combine (36) and (37) we get the relation which is rather important: X H X N X H X X H zX 1 Nevertheless, it seems we have no ways to solve the final result. But actually, thanks to computer simulations tool, here we need not to get the mathematical presentation and avoid the complex calculations that are required, what we need is to design an approximate algorithm to make out the drawing near result as follows, which exists equal to what we want: Meanwhile according to (29) (a), multiply XH in the left side, we resolute: I z A `H A Here F is a Lagrange constraint factor: (34) z op X N A `H b 2 2 Because B is also a full matrix, thus respectively, (34) is meant to: B X C 2 X ( k ) H A H b X (k ) H X N k = k + 1, If (k ) g ( X op ) 0 stop (43) (38) Definitely (38) have multitude resolutions of x. And the mission of (38) is done to make the CPLS as close as possible to ESTS under same transmitted sequences. Though algorithm (43), we get our final resolution, X op , out . Then in next part, we will give simulations to verify the algorithms (43) to see whether it is conform to our aims or not. 1255 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 Table 1: Simulation conditions 1 Front modulation 2 Number of sub-carriers 3 Insert pilots or not 4 Length of cyclic prefix 5 Length of equal space 6 Channel type 7 Number of channel paths 8 Signal distribution 9 Maximum SNR 10 Space of SNR 11 Channel interpolations CPLS after restructure Equally spaced TS after restructure CPLS before restructure Equally spaced TS before restructure 100 -1 BER 10 -2 10 final result. Whatever, only four methods are compared in our simulations, they are: CPLS and ESTS method before and after restructuring. -3 10 5 0 10 15 20 25 SNR 30 35 40 Fig. 3: BER compare of methods before or after restructure for basic simulation CPLS after restructure Equally spaced TS after restructure CPLS before restructure Equally spaced TS before restructure 101 0 10 MSE -1 10 -2 10 -3 10 -4 10 0 5 10 15 20 25 SNR 30 35 40 Fig. 4: MSE compare of methods before or after restructure for basic simulation CPLS after restructure Equally spaced TS after restructure CPLS before restructure Equally spaced TS before restructure 101 0 MSE -1 10 -2 10 -3 10 -4 10 5 10 15 20 25 SNR 30 VARIED CONDITIONS AND THE SIMULATION RESULTS Basic stationed simulation conditions: We find that the total restructure resolution contains some parameters that need to be assured, but unfortunately we have seldom found the principles. Here we just give some analysis in that not only under stationed conditions but also under varied conditions our total performance compare should be the same. Actually, from algorithms (43), definitely 0, g should be certain first, they are what we called varied parameters. we know that they are both small positive number, and the ratio 0/g directly determine the effects and strengths of matrix z in final resolution. So here we set them under two conditions: C C 0 = 0.01, g = 0.01 0 = 0.0001, g = 0.1 Besides, from the final restructure result while other stationed results are stationed, no other parameters should be certain and it seems that only the final simulation should be done. Nevertheless, there is one noticing which should be highlighted. That is, for the BER compare, we only need to consider the BER performance of restructure sequences without reduction in receiver although in transmitted side transmitted sequences have been restructured. 10 0 16-QAM 256 no P = 16 Q = 16 Rayleigh H = 16 random 40db Space of SNR DFT-based 35 40 Fig. 5: MSE compare of methods before or after restructure for extension simulation Simulations: To verify the theory of our restructure method, we give simulations. First set simulation conditions. Table 1, we unify in the article some conditions are stationed therefore need not be discussed while other conditions are varied which may influent the Basic simulation: In this simulation we set 0 = 0.01, g = 0.01 as the varied conditions. Judge the MSE and BER of both CPLS of new transmitted sequences and ESTS of old ones based on our stationed conditions as followings. From Fig. 3, definitely, BER of CPLS of new transmitted sequences is better than that of ESTS (Equally spaced TS) method of original transmitted sequences. This means after restructure if in receiver we deal with some reduction inversely BER of OFDM system can be more optimized, however here we do not discuss the reduction algorithms. 1256 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 on it, we established a serials of constrain model; used Lagrange resolving method to get the resolution. Simulation shows that for CPLS in new transmitted sequences performance is much better than the conventional LS methods under original transmitted sequences in both MSE and BER. Furthermore this method can increase utilization of cyclic prefix and save and balance OFDM resources although it requires some complexity for restructuring process. Therefore this new method our paper discussed must be a good choice to fulfill the requirement of channel estimation. Fig. 6: A new simplified OFDM scheme after transmitted sequences restructured Furthermore, from Fig. 4, MSE of CPLS after new transmitted sequences restructured is indeed smaller than that of ESTS method, this means CPLS can also estimate channel more accurately. Figure 4 also proved that under different transmitted sequences (before or after restructure), CPLS is not always larger than ESTS method except after restructure by which we force it to be smaller, though it approach our purpose kindly. This verified conclusion from the deduction of Appendix A. Extension simulation: Unlike the conditions of basic simulation analysis, here we set 0 = 0.01, g = 0.01 while keep other conditions stationed in Table 1. Then we do our simulation. Gladly we find that CPLS after restructure is the optimized among the totals although compare to the former, superiority is not that obvious. An system model: Conclude Fig. 3 and 4, 5, and combine Fig. 6, the structure of new OFDM system, we gladly discover its value for system model. Figure 6 where ' means our restructure process and Rd., the reduction part. It can be expected that if Rd. process does not make impact to total system BER, the performance is mainly determined by CPLS as discussed above. Therefore, it can be predicted that total system BER will be lower down. Appendix A: From deduction of equally spaced training sequences presentation, according to MSE of LS estimator, when transmitted sequences are certain, MSE of LS only determined by input sequences power. According to Parseval theory, power in time domain relates to frequency domain as: xT T 2 1 P XF 2 F So we only need compare the power of XQ XCP. Consider following transformation: |XQ |2- |XCP| 2 =(XQ – X CP)H (XQ + X CP)-(HHQ XCP - XHCP XQ) Calculate each part. Because f --and W are diagnosis matrix, therefore f H H 1 , WH =W-1, besides, f has a period of Q below: NQ-1 = WMmP(Q-i) = WMmP(-i) = N Q-1 Therefore, using property above: (XQ!XCP)H (XQ+XCP) H XM [ I , ,..., Q 1 W 1 ]H W H FPH FPW [ I , ,..., Q 1 W 1] X M H XM [ I , ,..., Q 1 W 1 ]H P[ I , ,..., Q 1 W 1] X M H PX M [ I , 1,..., 1 Q W ]T [ I , ,..., Q 1 W 1] m H PX M AX M and H X QH X CP X M [ I , ,..., Q 1 ] H W H FPH FP [0,0,..., I ] X M H XM [ I , 1 ,..., 1Q ]T W 1 P H [0,0,..., I ]x M Px M Bx M Therefore, CONCLUSION This study proposed a new restructuring method that improves the performance of cyclic prefix based channel estimation. We first introduced the cyclic prefix LS method and then deduce the equally spaced training sequences presentation to get the relation with it, then gave a proof of comparing MSE of both methods. Based H H H X CP X Q ( X QH X CP ) H PX M B XM Thus, |XQ |2!|XCP |2 = PXHM (A!B+BH)xM = PxHM CxM In detail, calculate, 1257 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 I 1 1 I ... ... 1Q W 2Q W Q 1 QL×L. Pp×L is a matrix whose rank must be smaller than p, thus, QL×L = PH p×L Pp×L has properties as: QL×L = Q HL×L , diag (QL×L) = p Rank (QL×L)# Rank (Pp×L ) # p 1 W Q 2 1 1 W ... 1 1 W W ... ... ... ... which means it was a hermit matrix, dialogize elements are all p and the rank is smaller than p.Consider do Eigen value decomposition to QL×L as follows: 1 0 0 QL L q L L s 0 0 0 0 ... W 1 1 1 0 0 ... W B ... ... ... ... 1Q 1 W 0 0 ... C A B B H I 1 ... 1Q q L L q LH L , s p I ... 2 Q ... Q 1 ... Q 2 ... ... 0 ... Among, qL×L is unitary matrix and because Pp×L is complex matrix, thus Eigen values of QL×L must be complexes. Meanwhile, the summary of Eigen value equal to all summary of diagnosis elements. Define the size of one matrix in the spectrum norm; we get the restriction relations: imax ( QL L max i ) 2 s st . i L * p i 1 Then, we see that under same x M , the result only determined by the matrix C, whether it is positive or negative. According the traits of matrix C, we reform it as: I 1 C ... 1Q I ... 2 Q ... Q 1 I ... Q 2 0 ... ... ... 0 0 ... ... Q 1 0 ... ... ... 0 ... Appendix B: We select number p training sequences from number L total transmitted sequences composing assemble {k1,k2,..., kp}, then: X p ( X k 1 , X k 1 ,..., X kp ) 1 1 1 * L 1 2 *k 1*1 j L e 2 *k 2*1 j L e 2 *kp*1 j L e 1 L Definitely, if QL×L has only one Eigen value, all power will decline to the Eigen value which make the spectrum norm the biggest. Then rank of QL×L is one, according to the definition, it means rank of Pp×L must be one. Return to find the presentation of Pp×L , its rank is one, we must let: 0 D ... I We find that C and D is equal in their Eigen value, because D has negative Eigen values -1, therefore it is not positive, therefore C is also not positive. Above proved that the result is not always positive, therefore we get the conclusion that under LS frame MSE of CPLS is not always smaller nor larger than that of ESTS method although the latter is the optimized. T 0 0 H q L L 0 e 2 * k 1 *j L e 2 *k 2 *j L ... e 2 *kp *j L j 1,..., L 1 ki 0 {0, 1, ..., L!1} ]ki = k1 + L / p!1 * (i!1) , i = 1,..., p This means we have to select the training sequences equally-spaced. Then, we subtly prove our theory. ACKNOWLEDGEMENT * Pp L * x L We gratefully thank lecturer Zhang-xin Chen of Department of EE, University of Electronic Science and Technology of China, for his Fundamental Research Funds for the Central Universities (No. ZYGX2011J016) 2 *k 1*( L 1) j L e 2 *k 2*( L 1) j L e 2 *kp*( L 1) j L e REFERENCES Here |Xp |2 can be represent as: H |Xp |2 = XHp = 1/L * XHL PH p×L Pp×L xL = 1/L * x L QL×L xL From above, whatever x L is, the result |Xp |2 is only determined by Borching, S., 2008. Blind Channel Estimation using Redundant Recoding: New Algorithms, Analysis and Theory [D]. Institute of Technology Pasadena, California, pp: 1-80. Christopher, B.S, 2004. Wireless Downlink Schemes in a class of Frequency Selective Channels with uncertain Channel State Information [D]. Rice University, Houston, pp: 1-80. 1258 Res. J. Appl. Sci. Eng. Technol., 4(10): 1250-1259, 2012 Feng, W., 2009. Signal-Perturbation-Free semi-Blind Channel Estimation for MIMO-OFDM Systems [D]. 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