Kuta Software - Infinite Algebra 2
Solve each equation.
1)
4 −2
X =
−7 2
−6
12
Name___________________________________
Date________________ Period____
2)
−1 1
5 −2
4
C =
−26
3)
2 −3
Z =
−5 5
−1
20
4)
1 −9
1 0
Z =
−35
−8
5)
−1 2
−6 10
Z =
6
22
6) 3 X =
12 −12
21 −27
7)
25 13
=
13 9
7 −2
3 −2
X 8)
20 −3
15 −3
=
−6 −5
−5 −4
X
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n 3 3 M D a T d 0 e x T w c i Z t G h e N I M n Y f h i F n 6 i Y t n e 3 5 A Z l R g L e s b U r 0 a H a 2 5 .
S
-1-
Worksheet by Kuta Software LLC

Solve each equation or state if there is no unique solution.
9) Y −
−1
−5
=
8
8
−6
6
−16
0
10)
−1 −1
−8 0
−6 3
X =
−40 −40
11)
0 −4
0 −1
X =
28 0 −20
7 0 −5
9 −15
12)
−21 39
2 −3
=
−7 9
X
13)
−1 −2
B =
2 9
−3 −5 13
21 0 −36
14)
−1 −9
0 −1
C =
11
2
Critical thinking questions:
15) Assuming that a solution exists, what are the dimensions of M ?
1 2 −2 3
3 4
5 6
M = 5 −10
0 1
16) Find one solution to:
0 1
X =
3 5
0 0 0 0
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g J W M t a F d 1 e N k w b i 3 t p h 0 m I c n M f K i X n j i b t v e p c A s l w g y e m b W r l a J 0 2 L .
c
-2-
Worksheet by Kuta Software LLC

Kuta Software - Infinite Algebra 2
Solve each equation.
1)
4 −2
X =
−7 2
−6
12
−2
−1
Name___________________________________
Date________________ Period____
2)
−1 1
5 −2
4
C =
−26
−6
−2
3)
2 −3
Z =
−5 5
−1
20
−11
−7
4)
1 −9
1 0
Z =
−35
−8
−8
3
5)
−1 2
−6 10
Z =
6
22
8
7
6) 3 X =
12 −12
21 −27
4 −4
7 −9
7)
25 13
=
13 9
7 −2
3 −2
X
3 1
−2 −3
8)
20 −3
15 −3
=
−6 −5
−5 −4
X
5 3
−10 −3
© 8 1 2 d 0 I 1 W 2 I 2 K 9 u V t u a l f S X o n f I t B w F a Z r d e c N L 1 L U C L .
A S j A I l d l G a r 4 i s g o h a t O s h B r h e o s c e k r Z v C e u d J .
6 o E M u a L d Z e q 8 w v i g t b h Z V I n n c f a i N n o i 5 t f e b 7 A C l W g m e 9 b q r u a M U 2 c .
C
-1-
Worksheet by Kuta Software LLC

Solve each equation or state if there is no unique solution.
9) Y −
−1
−5
=
8
8
−6
6
−16
0
10)
−1 −1
−8 0
−6 3
X =
−40 −40
5 5
1 −8
−7
1
−8
8
11)
0 −4
0 −1
X =
28 0 −20
7 0 −5
No unique solution
12)
9
−21 39
−6 6
−7 9
−15
=
2 −3
−7 9
X
13)
−1 −2
B =
2 9
−3 −5 13
21 0 −36
−3 9 −9
3 −2 −2
14)
−1 −9
0 −1
C =
11
2
7
−2
Critical thinking questions:
15) Assuming that a solution exists, what are the dimensions of M ?
1 2 −2 3
3 4
5 6
M = 5 −10
0 1
2 × 2
16) Find one solution to:
0 1
0 0
X =
3
0
5
0
Many answers. Ex:
2 2
3 5
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© 8 8 2 t 0 P 1 U 2 H 2 K z u U t C a G q S b o i f r t f w q a r r K e c 3 L S L q C q .
M x h A w l 2 l f U r h i a g s h V t b s a Y r S e K s r e 5 r B v 8 e l d f .
M E r M a a R d 2 e 1 C w c i J t D h k c I g n v f 3 i T n V i a t 2 e 5 v A V l f g G e x b 3 r R a N f 2 6 .
j
-2-
Worksheet by Kuta Software LLC