Available at http://pvamu.edu/aam Appl. Appl. Math. ISSN: 1932-9466 Applications and Applied Mathematics: An International Journal (AAM) Vol. 7, Issue 1 (June 2012), pp. 71 – 98 On Lattice Structure of the Probability Functions on L* Mashaallah Mashinchi and Ghader Khaledi Faculty of Mathematics and Computer Sciences Shahid Bahonar University of Kerman Kerman, Iran mashinchi@mail.uk.ac.ir; gh.khaledi78@gmail.com Received: December 01, 2010; Accepted: January 02, 2012 Abstract: In this paper, the set of all probability functions on L* is studied, where L* is the lattice of bothvalued fuzzy sets or intuitionistic fuzzy sets. It is shown that the set of all probability functions on L* endowed with two appropriate operations has a monoid structure which is also a distributive complete lattice. Also the lattice structure of the set of all probability functions on L* induced by an appropriate function on [0, 1] to itself is studied. Some lattice (dual) isomorphisms are discussed that suggests probabilities on L* could be considered in the framework of theories modeling imprecision. Keywords: Probability, lattice, monoid, complete lattice, fuzzy set, intuitionistic fuzzy set MSC 2010: 06B23, 06D30 1. Introduction Deschrijver and Kerre (2003) have shown that the underlying structure of both interval-valued fuzzy sets and intuitionistic fuzzy sets is an L*-fuzzy set with respect to the lattice L*, in the sense of Goguen (1967). Deschrijver and Kerre (2007) also discussed the position of intuitionistic fuzzy set theory in the framework of theories modeling imprecision, where an overview of interrelationships that exists between intuitionistic fuzzy set theory and other theories modeling imprecision is described. In this direction, the study of intuitionistic 71 72 Mashaallah Mashinchi and Ghader Khaledi balanced operators is studied by Saeb and Mashinchi (2008) which reveals an extension to intuitionistic fuzzy set theory. A complete study of this topic is reported by Saeb (2009). A probability p on L* has been studied by K. Lendelova and Riecan (2006). They found the representation for a probability p on L* with respect to the Lukasiewicz connectives. Recently, Saeb and Mashinchi (2007) followed this trend and extended the notion of a probability on a balanced lattice, which is introduced by Homenda (2006). This topic is also considered from different points of view by M. Rencova (2010), Riecan (2006) and Riecan and Petrovicov (2010). The study of algebraic structures of e-implications and pseudo-e-implications on the lattice L* are considered by Khaledi et al. (2005) and (2007). Inspired by the research on the study of algebraic structures of implications on L*, and the direction of the study of probabilities on the lattice L*, in this paper, the set of all probability functions on L* is considered and it is shown this set endowed with two appropriate operations has a monoid structure which is also a distributive complete lattice with De-Morgan algebra. Then, several other related lattice structures are provided. The results of this paper suggest that probabilities on L* can be considered as the representation of modeling imprecision when viewed from the perspective of Deschrijver et al. (2007). Kaburlasos and Ritter (2007) demonstrated that lattice theory may suggest viable alternatives in practical clustering, classification, pattern analysis and regression applications as worthily noted by Ajmal and Jain (2009) in their recent research. The lattice structures studied in this paper are therefore very useful apparatus in applications as explained by Ajmal, Naseem et al. (2009) that the system of lattice algebra plays a significant role in information theory and can be used within the numerous subfields of computational intelligence. These quotations stress that the results reported in this paper have their potential values both from the theoretical and application points of view in information processing. The organization of this paper is as follows. Following this introduction some preliminaries are discussed in Section 2. Here the structure of the lattice L* and the definition of probability on L*are reviewed. In Section 3, the algebraic structure of the set POL, of all probabilities on L*, is studied. In Section 4, we induce a probability function on L* by a function f : 0,1 0,1 . Then we study the distributive complete lattice structure of the set POL f of all induced probabilities on the lattice L*. This is done based on appropriate lattice operations on L*, when f is a fixed strictly increasing function. Also the lattice structure of the set POL f POL g , is studied, where the fixed functions f and g are strictly increasing. It is proved that this structure is a distributive complete lattice which is isomorphic to □ , where □ is the set [0,1]2 considered as a super lattice of L*. More sub lattices of the lattices □ and L* are obtained. 2. Preliminaries In this section, we review some known definitions and results which will be used later, for more details see Birkhoff (1940), Deschrijver (2004) and Lendelova et al. (2006). Definition 2.1. Let , | , 0,1 and assume AAM: Intern. J., Vol. 7, Issue 1 (June 2012) X x1 , y 1 , Y x2 , y2 73 ▫ . Define , , ▫ , ▫ , , and ▫ Assume, 0 , 0,1 , 1 ▫ | , , . 1,0 and set ▫ 0,1 1, then, we have the following. Theorem 2.2. , is a complete lattice with D as its sub lattice. Definition 2.3. Let , | , 0,1 1, and assume X x1 , y 1 , Y x 2 , y 2 L . Define X L Y Minx1 , x 2 , Max y1 , y 2 X L Y Max x1 , x 2 , Miny1 , y 2 X L Y x1 x 2 and y1 y 2 . Assume, 0 L 0,1 and 1L 1,0 , then we have the following. Lemma 2.4. L , L is a complete lattice. Definition 2.5. Define the binary operations and on L as follows X Y Min x1 x 2 ,1, Max y1 y 2 1,0 74 Mashaallah Mashinchi and Ghader Khaledi X Y Maxx1 x 2 1,0, Miny1 y 2 ,1 , where, X x1 , y 1 and Y x 2 , y 2 . * Definition 2.6. A probability on L is any function p : L [0,1] satisfying the following properties: 1) p(0,1) 0 , p(1,0) 1 2) p X Y p X Y p ( X ) p (Y ) for each X , Y L 3) If X n X , then for each X , X n L , n N , where N is the set of natural numbers. Remark 2.7. The notation X n X , means that X n is an increasing sequence in L and X Xn. n N Theorem 2.8. Let p : L [0,1] be a probability on L . Then there exists p has the following form: p 0,1 such that p x, y p x 1 p 1 y , for all x, y L . Moreover, p is unique. Proof: We only prove the uniqueness of p , since the rest of the proof is given by Lendelova et al. (2006) . Suppose on the contrary that the statement is not true. So, there exist p , p 0,1 , (1) where (p1) (p2) . Also, for all x, y L p x, y p(1) x 1 (p1) 1 y ( 2) AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 75 and px, y (p2) x 1 (p2) 1 y . Let x0 , y0 L \ D . So, we have: (p1) x0 1 (p1) 1 y 0 (p2) x0 1 (p2) 1 y 0 . Hence, But, (1) p (p2) x 0 (p1) (p2) 1 y 0 . (p1) (p2) , therefore, x0 1 y 0 . This is a contradiction. Hence p is unique. ■ The following Lemma is an immediate consequence of a well-known result for sequences in , the fact that the limit in a cartesian product of two metric spaces ( here 0,1 ) is equal to the pair of limits of the components, and the fact that the limit and the supremum of a sequence in a closed subset ( here ) of a metric space is still in that subset. * Lemma 2.9. Let X n xn , y n be an increasing sequence in L . Then, X x, y X n if and only if X lim x n , lim y n . n N n n Theorem 2.10. Let [0,1] , p : L [0,1] , be defined by p X x1 1 1 y1 . Then, p is a probability on . , and 76 Mashaallah Mashinchi and Ghader Khaledi Proof: Obviously is well-defined. We show that p satisfies the conditions of Definition 2.6. 1) p(0,1) 0 , p(1,0) 1 2) Let X x1 , y1 , Y x 2 , y 2 L . We have: X Y Minx1 x 2 ,1, Maxy1 y 2 1,0 X Y Maxx1 x 2 1,0, Miny1 y 2 ,1 . Consider the following four cases: (a) x1 x 2 1 and y1 y 2 1 In this case we have: p X Y x1 x 2 1 1 0 , and p X Y 0 1 1 y1 y 2 . So, p X Y p X Y x1 x 2 1 1 1 y1 1 y 2 x1 1 1 y1 x 2 1 1 y 2 p( X ) p(Y ) . (b) x1 x 2 1 and y1 y 2 1 . In this case we have: p X Y ( x1 x 2 ) 1 1 y1 y 2 1 , and p X Y (0) 1 1 1 . AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 77 So, p X Y p X Y x1 x 2 1 1 y1 1 y 2 x1 1 1 y1 x2 1 1 y 2 p( X ) p(Y ) . (c) x1 x 2 1 and y1 y 2 1 p X Y 1 1 0 1 p X Y ( x1 x 2 1) 1 1 y1 y 2 . So, p X Y p X Y 1 x1 x 2 1 1 y1 1 y 2 x1 1 1 y1 x 2 1 1 y 2 p( X ) p(Y ) . (d) x1 x 2 1 and y1 y 2 1 In this case we have: x1 x 2 y1 y 2 2 . Therefore, x1 y1 x 2 y 2 2 . Hence, x1 y1 1 or x 2 y 2 1 . And, X L or Y L . So case (d) does not occur. Therefore, in all cases the condition 2 of Definition 2.6 does hold. 3) Let X n X , then we have: p X n x n 1 1 y n . is an increasing sequence. Let xn 1 1 y n xn1 1 1 y n1 . , so and .Therefore, Hence, . 78 Mashaallah Mashinchi and Ghader Khaledi Therefore, lim p X n lim x n 1 1 y n n n lim x n 1 1 lim y n n n x 1 1 y (By Lemma 2.9) p( X ) .■ 3. Algebraic Structure of the Set of Probabilities on L * In this section we assume that X x1 , y1 and Y x 2 , y 2 are elements of L , unless clearly stated otherwise. Notation 3.1. Set POL= p p is a probabilit y on L . Definition 3.2. Define and on POL as follows: p q : L [0,1] X Min p , q x1 1 Min p , q 1 y1 , and p q : L [0,1] X Max p , q x1 1 Max p , q 1 y1 . Lemma 3.3. The operations and defined in Definition 3.2 are well-defined, closed and associative on POL. Proof: It is clear that and are well-defined and closed on POL. We show that and are associative on POL. Let p, q, r POL and X L . AAM: Intern. J., Vol. 7, Issue 1 (June 2012) p q r X Min pq 79 , r x1 1 Min p q , r 1 y1 1 y , Min , x 1 Min , Min , 1 y Min , x 1 Min , 1 y Min Min Min p , q , r x1 1 Min Min p , q , r p p q qr r 1 1 p p qr q r 1 1 1 p q r X . Similarly, we can show that, p q r X p q r X .■ The following Lemma follows immediately from Theorem 2.10 by putting 1 and 0 to obtain 1 X and 0 X respectively. Lemma 3.4. Define the mappings 1,0 : L 0,1 in the following: 1 X x1 and 0 X 1 y1 . Then, 1,0 POL . Lemma 3.5. Let p POL . Then: (1) p0 0 p 0 (2) p 1 1 p p (3) p 0 0 p p (4) p 1 1 p 1 . Proof: We shall only prove (1), the other parts are similar. By commutative property of , we have p 0 0 p . Also, p 0 X Min p , 0 x1 1 Min p , 0 1 y1 Min p ,0x1 1 Min p ,01 y1 1 y1 0 X . ■ 80 Mashaallah Mashinchi and Ghader Khaledi Theorem 3.6. , and , are monoids. Proof: It follows from Lemmas 3.3-3.5.■ Definition 3.7. The ordering relation on POL is defined as follows. For p, q POL : p q p q . Definition 3.8. Define : 0,1 POL by a pa , where pa X ax1 1 a 1 y1 for all X L . The following reveals the relation between the lattices [0,1] and POL. Lemma 3.9. Consider in Definition 3.8, then: (1) is a bijection. (2) Mina, b a b . (3) Maxa, b a b . (4) a b if and only if a b . AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 81 Proof: Straightforward. ■ Corollary 3.10 POL, , , is a distributive complete lattice. Proof: Lemma 3.9 shows that is an isomorphism between the lattices 0,1 and POL. Hence POL, , , is a distributive complete lattice. ■ Definition 3.11. Let p POL . We define p in the following: p : L [0,1] p X 1 p X , where X y 1 , x1 . Lemma 3.12. Let p POL . Then: (i) (ii) (iii) p POL , p 1 p , (a) p p , (b) p , q POL p q q p , (iv) (De-Morgan properties): (i ) p, q POL p q p q , (ii ) p, q POL p q p q (v) 0 1 and 1 0 . 82 Mashaallah Mashinchi and Ghader Khaledi Proof: (i) 1 p0,1 1 p1,0 1 -1 0 p1,0 1 p 0,1 1- 0 1 (2) We show that: X Y Y X and X Y Y X . X Y Maxy1 y 2 1,0,Minx1 x 2 ,1 . On the other hand: Y X Max y1 y 2 1,0,Min x1 x 2 ,1 . Similarly we can show that: X Y Y X . p X Y p X Y 1-p X Y 1 p X Y 1-p Y X 1 p Y X 2- p Y X p Y X 2- p Y p X 2- 1-p Y 1 p X p X p Y . (3) Let X n X . Then: lim p X n lim 1 p X n 1 p X p X . n n AAM: Intern. J., Vol. 7, Issue 1 (June 2012) (ii) 83 p X p x1 1 p 1 y1 1 - p X 1 - p y1 1 x1 p p x1 1 - p x1 p 1 y1 So, p 1 p . (iii) (a) p X 1 p X 1 - 1 - p X p X (b) Let p q , then p q . So, 1 q 1 p . Hence, q p . Hence, q p . (iv) p q X 1 p q X 1-Minα p ,α q y1 1 Minα p ,α q 1 x1 1-Minα p ,α q y1 1 x1 Minα p ,α q Minα p ,α q x1 Minα p ,α q 1-y1 1 Minα p ,α q x1 On the other hand: p q X Max α p ,αq x1 1 Max α p ,αq 1 y1 Max 1 - α p ,1 αq x1 1 Max 1 - α p ,1 αq 1 y1 1 - Min α p ,αq x1 Min α p ,αq 1 y1 . Similarly, we can show that: p q p q . (v) (i) 84 Mashaallah Mashinchi and Ghader Khaledi 0 X 1 0 X 1 - 1 - x1 x1 1 X (ii) 1 X 1 1 X 1-y1 0 X . ■ Theorem 3.13. POL, , , ,0,1 is De-Morgan algebra. Proof: The proof follows from Lemma 3.12.■ 4. f Probability on L In this section we induce a probability function on L by an appropriate function f : 0,1 0,1 . Then we study the distributive complete lattice structure of the set of all induced probabilities on L based on appropriate lattice operations, when f is a fixed strictly increasing function. Definition 4.1. Let f : 0,1 0,1 be any function, p : L 0,1 be a probability on L and p be the unique real number obtained in Theorem 2.8. Define the induced p f : L 0,1 by f in the following: p f X f p x1 1 f p 1 y1 . Lemma 4.2. The induced p f in Definition 4.1 is a probability on L . Proof: It is straightforward.■ In the following we will consider a class of probabilities on L induced by Sugeno negation. AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 85 Example 4.3. Let p : L 0,1 be a probability function on L . Consider the Sugeno negation N : 0,1 0,1 , where N x 1 x , 1, . 1 x Then, 1 p p N X 1 p 1 p x1 1 p is a probability on L , where 1 y1 , 1, p is the unique real number obtained in Theorem 2.8. Lemma 4.4. Let p : L 0,1 be an arbitrary probability function on L and f : 0,1 0,1 be any function. Then p f in Definition 4.1 is onto. Proof: Let y 0,1. Define X y ,1 y . It is clear that X L and p f X y .■ p : L 0,1 be an arbitrary probability function on L and f : 0,1 0,1 be any function. Then p f in Definition 4.1 is not 1-1. Remark 4.5. Let Define X 1 f and , f , where p p 0,0 . It is clear that , p is the unique real number obtained in Theorem 2.8 and X Y . Also, p f X p f Y 1 f . p Notation 4.6. Let f : 0,1 0,1 be any function. Set: POL f p f p POL. Definition 4.7. Let POL f be as in Notation 4.6. Define the operations and on POL f as follows: p f q f : L 0,1 X Minf α p ,f α q x1 1 Minf α p ,f α q 1 y1 , 86 Mashaallah Mashinchi and Ghader Khaledi and p f q f : L 0,1 X Maxf α p ,f α q x1 1 Maxf α p ,f α q 1 y1 . Definition 4.8. For a fixed f : 0,1 0,1 , define the ordering relation f on POL f as follows: p f f q f f p f q , for all p f , q f POL f . Lemma 4.9. Let f : 0,1 0,1 be a strictly increasing (strictly decreasing) function and p, q POL . Then: (1) (2) . Proof: (1) Let X L and f : 0,1 0,1 be a strictly increasing function, then: ( p q) f X f p q x1 1 f p q 1 y1 f Min p , q x1 1 f Min p , q 1 y1 Minf p , f q x1 1 Minf p , f q 1 y1 ( p f q f ) X . Let X L and f : 0,1 0,1 be a strictly decreasing function then: ( p q) f X f pq x1 1 f pq 1 y1 f Min p , q x1 1 f Min p , q 1 y1 Maxf p , f q x1 1 Maxf p , f q 1 y1 AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 87 ( p f q f ) X . (2) The proof is similar to part (1). ■ Definition 4.10. Let f : 0,1 0,1 be a function. Define : POL POL f as p p f . Lemma 4.11. Let f : 0,1 0,1 be a function, p, q POL and be as in Definition 4.10, then: (1) is well-defined. If f : 0,1 0,1 is strictly increasing (strictly decreasing) function then: (2) is a bijection, (3) p q p q ( p q p q ), (4) p q p q ( p q p q ), (5) p q if and only if p f q ( p q if and only if q f p ). Proof: It is similar to the proof of Lemma 4.9. ■ Now the following fact is immediate. Corollary 4.12. Let f : 0,1 0,1 be a function. (1) If f is a strictly increasing function, then POL f , , , f is a distributive complete lattice. (2) If f is a strictly decreasing function, then in Definition 4.10 is a dual isomorphism. 88 Mashaallah Mashinchi and Ghader Khaledi Example 4.13. (1) Consider : 0,1 0,1 , where , where 1 1 Hence, POL f , , , f (2) Consider and : 0,1 , where 1 Hence, . Then is a strictly increasing function and . is a distributive complete lattice. 0,1 , where 1 1 . Then is a strictly decreasing function . is a dual isomorphism. Remark 4.14. As Birkhoff, G. (1940) mentioned, the product of two lattices is also a lattice. Let f , g : 0,1 0,1 be two strictly increasing functions, then POL f POL g is also a distributive complete lattice. Lemma 4.15. Let f : 0,1 0,1 be onto. Then POL POL f . Proof: It is clear that POL f POL . Let p POL . We show that p POL f . Since p POL , we have: p X p x1 1 p 1 y1 and p 0,1 . f is onto, so there exist 0,1 such that f p . Define q X x1 1 1 y1 . By Theorem 2.10, q POL and q f X f x1 1 f 1 y1 . Therefore q f X p x1 1 p 1 y1 p X . Hence, p POL f . Therefore, POL POL f .■ AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 89 Corollary 4.16. Let N be the Sugeno negation as in Example 4.3, then POL POL N . Definition 4.17. Let f , g : 0,1 0,1 be two functions. Define : ▫ by , p f , q g , where, for all p f X f x1 1 f 1 y1 , and q g X g x1 1 g 1 y1 . Definition 4.18. Let f , g : 0,1 0,1 be two functions and assume p f , q g , r f , s g POL f POL g . Define (1) , ▫ , rf , qg s g , (2) , ▫ , rf , qg s g , (3) , , ▫ if and only if p f f r f and q g g sg , Theorem 4.19. Let f , g : 0,1 0,1 be two functions and be as in Definition 4.17. Then: (1) is well-defined. If f , g : 0,1 0,1 be two strictly increasing (strictly decreasing) functions then: (2) is a bijection. (3) ( (4) ( , ▫ , , ▫ , , ▫ , , ▫ , , ▫ , , ▫ , , ▫ , , ▫ , 90 Mashaallah Mashinchi and Ghader Khaledi , (5) , ▫ , ▫ if and only if , if and only if , , ▫ , ▫ . , .) Proof: , Let , and X L . Define p f , q g , r f and s g as follows: , p f X f x1 1 f 1 y1 , q g X g x1 1 g 1 y1 , r f X f x1 1 f 1 y1 , and s g X g x1 1 g 1 y1 . It is clear that p f , q g and r f , s g POL f POL g . (1) Let So p f , , , therefore and . Hence f f and g g . r f and q g s g . Therefore, , , . We only prove the Lemma in the case that f, g are strictly increasing functions. The proof of the case that f, g are strictly decreasing functions is similar. , , . Hence p f , q g r f , s g . Therefore, p f r f and q g s g . So f f and g g . Hence, and . Therefore, , , . (2) Let Let u f , v g POL f POL g , such that: u f X f u x1 1 f u 1 y1 and v g X g v x1 1 g v 1 y1 . AAM: Intern. J., Vol. 7, Issue 1 (June 2012) , It is clear that (3) 91 u , v u f , v g . and , L , Min , , Max , m f , n g , where, , 1 , 1 and n g X g Max , x1 1 g Max , 1 y1 . Therefore, 1 , , 1 , and ng X Max g , g x1 1 Max g , g 1 y1 . So, m f X p f r f X and n X q g g s g X . Hence, , L , p f r f , q g s g , ▫ , ▫ , , . (4) It is similar to the part (3). (5) Let , ▫ , . Hence, and . So, f f and g g . Therefore, p f f r f and q g It is similar to the above part. ■ g s g . Hence, , ▫ , . 92 Mashaallah Mashinchi and Ghader Khaledi Corollary 4.20. Let f , g : 0,1 0,1 be two functions. (1) If f and g are two strictly increasing functions, then POL f POL g is a distributive . complete lattice which is isomorphic to (2) If f and g are two strictly decreasing functions, then in Definition 4.17 is a dual isomorphism. Example 4.21. (1) Consider , : 0,1 functions and 0,1 , where , 1 1 1 1 , , . Then , are strictly increasing , where and . Hence, POL f POL g is a distributive complete lattice which is isomorphic to L . (2) Consider , : 0,1 decreasing functions and 0,1 , where 1 , , where , 1 1 1 1 , and Then . is a dual isomorphism. Notation 4.22. Let f , g : 0,1 0,1 be two functions. Define L POL f POL g POL f POL g as follows: L POL f POL g p f , q g p, q POL and p q 1. 1 . Then , are strictly AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 93 Definition 4.23. Let f , g : 0,1 0,1 be two functions. Define : L L POL f POL g by , p f , q g , where p f X f x1 1 f 1 y1 and q g X g x1 1 g 1 y1 , for all X L . Definition 4.24. Let f , g : 0,1 0,1 be two functions and assume p , q g , r f , s g L POL f POL g . f Define: (1) p f , q g L r f , s g p f r f , q g s g (2) p f , q g L r f , s g p f r f , q g s g (3) p f , q g L r f , s g if and only if p f f r f and q g g sg . Theorem 4.25. Let f , g : 0,1 0,1 be two functions and be as in Definition 4.23. Then: (1) is well-defined. If f , g : 0,1 0,1 are strictly increasing (strictly decreasing) functions then: (2) is a bijection. (3) , L , , L , , , , , L (4) , L L , , L , , , , , L L 94 Mashaallah Mashinchi and Ghader Khaledi (5) , L , if and only if , L , . , , if and only if , , . L L Proof: It is similar to the proof of Theorem 4.19. ■ Corollary 4.26 Let f , g : 0,1 0,1 be two functions. (1) If f and g are two strictly increasing functions, then L POL f POL g is a distributive complete lattice which is isomorphic to L . (2) If f and g are two strictly decreasing functions, then in Definition 4.23 is a dual isomorphism. Example 4.27. (1) Consider , in Example 4.21 part (1). Then L POL f POL g p f , q g p, q POL and p q 1, where 1 1 1 1 and . Hence, L POL f POL g is a distributive complete lattice which is isomorphic to L . (2) Consider , 1 1 1 1 and Then, in Example 4.21 part (2). Then , p f , q g , where is a dual isomorphism. . AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 95 Definition 4.28. Let f , g : 0,1 0,1 be two functions. Define D POL f POL g p f , q g p, q POL and p q 1. Lemma 4.29. Let f , g : 0,1 0,1 be two functions. Then D POL f POLg p f , pg p POL. Proof: Let p f , q g D POL f POL g . So, p q 1 . Hence, q 1 p . By Lemma 3.12, we have q p . Therefore, q g p g . Hence, p POL. Let p , pg p f , pg f p p POL . f , q g p f , p g . So, By Lemma p p p 1 p 1 . Therefore, p f , p g D POL f 3.12, POL g p f , q g p f , pg p 1 p , so .■ Definition 4.30. Let f , g : 0,1 0,1 be two functions. Define : D D POL f POL g , by ,1 p f , p g , where p X x1 1 1 y1 for all X L . Theorem 4.31. Let f , g : 0,1 0,1 be two functions and be as in Definition 4.30. Then: (1) is well-defined. If f , g : 0,1 0,1 are two strictly increasing (strictly decreasing) functions, then: (2) is a bijection. (3) ,1 ,1 ,1 L L ,1 ,1 ,1 L (4) ,1 ,1 ,1 L ,1 L ,1 L ,1 96 Mashaallah Mashinchi and Ghader Khaledi ,1 ,1 ,1 L (5) ,1 L ,1 L ,1 if and only if ,1 L ,1 ,1 if and only if ,1 L ,1 . L ,1 . Proof: The proof is similar to the proof of Theorem 4.19. ■ Corollary 4.32 Let f , g : 0,1 0,1 be two functions. (1) If f and g are two strictly increasing functions, then D POL f POL g is a distributive complete lattice which is isomorphic to D . (2) If f and g are two strictly decreasing functions, then in Definition 4.30 is a dual isomorphism. Example 4.33. (1) Consider , in Example 4.21 part (1). Then D POL f POLg p f , pg p POL, where 1 1 and ́ 1 1 1 . 1 Hence, D POL f POL g is a distributive complete lattice which is isomorphic to D . (2) Consider , 1 1 and ́ 1 in Example 4.21 part (2).Then ,1 p f , p g , where 1 1 1 . AAM: Intern. J., Vol. 7, Issue 1 (June 2012) 97 is a dual isomorphism. Remark 4.34. Note that the results given in Corollary 4.26 show that a probability on the lattice L POL f POL g (as an isomorphism of L ) could be viewed as a representation of modeling imprecision, if it is seen from the perspective of Figure 1 in the paper of Ajmal, Naseem et al. (2009) , where it is proved that different models of imprecision such as grey sets, vague sets, intuitionistic [0,1]-fuzzy sets, L - fuzzy sets, intuitionistic fuzzy sets and interval-valued fuzzy sets are equivalent up to isomorphism. 5. Conclusion In this paper, POL, the set of all probability functions on L* is studied. It is shown that this set is sufficiently large by constructing many examples using Sugeno’s negation. Two operations are defined to endow this set as monoid structure which is a distributive complete lattice and also De-Morgan algebra. Then, POL f , the set of all f probabilities on L*, induced by a fixed strictly increasing function on [0,1] to itself is studied and it is proved that this set is a distributive complete lattice when endowed with appropriate lattice operations. It is shown that the product lattice POL f POL g , when f and g are strictly increasing functions, is a distributive complete lattice isomorphic to , where is the set [0,1]2 considered as a super and L*are obtained. Some lattices (dual) isomorphism lattice of L*. Then more sub lattices of studied in this paper actually reveal that probabilities on the lattice L*could be considered as a representation of modeling imprecision as explained in Remark 4.34. 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