Solution of ECE 315 Test 3 F06 ( )

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1.

Solution of ECE 315 Test 3 F06

Below is graphed exactly one period of a periodic function harmonic function

X k

(with

T F

= T

0

) can be written as x t

( )

. Its

X k = A g

( ) e jck

.

What is the name of the function g

( )

?

g is

2

What are the numerical values of A , b and c ?

A = b = c =

( ) tri

( )

( ) tri

( )

6 tri

( )

20

T

0

( )

FS f

0 sinc 2

0

20

( )

FS

(

1 / 20

) sinc 2

(

6 k / 20

)

( )

FS

( ) sinc 2

(

3 k / 10

)

6 tri

( ( )

/ 6

)

6 tri

( ( )

/ 6

) x

( )

= 6 tri

( t 2 / 6

)

20

20

( )

FS

( ) sinc 2

(

3 k / 10

) e j 2 k 2 / 20

20

( )

FS

( ) sinc 2

(

3 k / 10

) e j k /5

10 x( t )

10 t

-10

-10

2.

Below is graphed exactly one period of a periodic function harmonic function X k (with

N

F

= N

0 x n

. Its

) can be written in the form

X k =

( jbk e jck + De jdk

)

Find the numerical values of the constants.

A = B = b = , c =

D = d = x n = 6

20 n + 8 2

20 n 1 + 8

20 n 9

Using

N

F n FS 1 / N

F

and x n n

0

FS X k e j 2 n

0 k / N

F

X k =

( ) e j 16 k / 20 2 1 / 20

) e j 2 k / 20 +

( ) e j 18 k / 20

X k =

( ) (

3 e j 4 k /5 e j k /10 + 4 e j 9 k /10

)

2

0

-2

-4

-6

-8

-10

-10

10

8

6

4

-8 -6 -4 -2 0 n

2 4 6 8 10

3.

2

1

0

-1

-2

-3

0

3

Match the CTFS magnitude graphs to the time functions. (In all cases

T

F

= 4 .)

J C D I G

3 3 3 3

2 t

0

-1

-2

2

1

4

-3

0 2 t

0

-1

-2

2

1

4

-3

0 2 t

0

-1

-2

2

1

4

-3

0 t

2

0

-1

-2

2

1

4

-3

0 t

2 4

A

1

0.8

0.6

0.4

0.2

0

-10 0 k

10

0.8

1

B

0.6

0.4

0.2

0

-10 0 k

10

C

1

0.8

0.6

0.4

0.2

0

-10 0 k

10

D

1

0.8

0.6

0.4

0.2

0

-10 0 k

10

E

1

0.8

0.6

0.4

0.2

0

-10 0 k

10

1

0.8

0.6

0.4

0.2

1

0.8

0.6

0.4

0.2

1

0.8

0.6

0.4

0.2

1

0.8

0.6

0.4

0.2

1

0.8

0.6

0.4

0.2

1.

2.

3.

4.

5.

0

-10 0 k

F

10

0

-10 0 k

G

10

0

-10

H

0 k

10

0

-10

I

0 k

10

0

-10

J

0 k

Second-harmonic sine function. Non-zero impulses only at k

= ± 2

.

One fundamental period of a square wave with an average value of 1.

10

Harmonic function is a sinc function with a non-zero impulse at the fundamental k

= 1 .

Two fundamental periods of a square wave with an average value of 1.

Harmonic function is a sinc function with a zero impulse at the fundamental k

= 1

and a non-zero impulse at k

= 2.

Two fundamental periods of a triangle wave with an average value of 1.

Harmonic function is a sinc squared function with a zero impulse at the fundamental k

= 1

and a non-zero impulse at k

= 2.

The impulses are smaller than for a square wave because of the faster rate of decay of sinc squared compared with sinc.

Fourth-harmonic sine function. Non-zero impulses only at k

= ± 4 .

4.

-1

-2

-3

0

2

1

0

3

Match the DTFS magnitude graphs to the time functions. (In all cases

N

F

= 16

G

.)

D E

3 3 3 3 n

10

-1

-2

-3

0

2

1

0 n

10

-1

-2

-3

0

2

1

0 n

10

-1

-2

-3

0

2

1

0 n

10

-1

-2

-3

0

2

1

0 n

10

1.5

A

1.5

B C

1.5

D

1.5

E

1.5

1 1 1 1 1

1

0.5

0.5

0

0

1.5

k

10

1

0.5

0.5

0

0

1.5

k

10

1

0.5

0.5

0

0

1.5

k

10

1

0.5

0.5

0

0

1.5

k

10

1

0.5

0.5

0

0

1.5

k

10

1.

2.

3.

4.

5.

0

0 k

10

F

0

0 10 k

G

0

0

H k

10

0

0

I k

10

0

0

J k

10

Second-harmonic sine function. Non-zero impulses only at k

= ± 2 repeated periocidally with period 16.

Pulse train with average value of 1/4. Harmonic function has a Dirichlet shape (periodically-repeated sinc functions).

Square wave with an average value of zero and fundamental period equal to representation time. Zero at periodically with period 16.

k

= 0 and non-zero at k

= ± 1 repeated

Pulse train with average value of 1/2. Harmonic function has a Dirichlet shape (periodically-repeated sinc functions) narrower than #2 because the time-domain pulse is twice as wide.

Fourth-harmonic sine function. Non-zero impulses only at k

= ± 4 repeated periodically with period 16.

1.

Solution of ECE 315 Test 3 F06

Below is graphed exactly one period of a periodic function harmonic function

X k

(with

T

F

= T

0

) can be written as x t

( )

. Its

X k = A g

( ) e jck

.

What is the name of the function g

( )

?

What are the numerical values of A , b and c ?

A = b = c = x

( )

= 8tri

( t 2 / 4

)

( ) tri

( )

( ) tri

( )

T

0

( )

FS f

0 sinc 2

0

20

( )

FS

(

1 / 20

) sinc 2

(

4 k / 20

)

8tri

( )

20

( )

FS

( ) sinc 2

( )

8tri

( ( )

/ 4

)

8tri

( ( )

/ 4

)

20

20

( )

FS

( ) sinc 2

( ) e j 2 k 2 / 20

20

( )

FS

( ) sinc 2

( ) e j k /5

10 x( t )

10 t

-10

-10

2.

Below is graphed exactly one period of a periodic function harmonic function X k (with

N

F

= N

0 x n

. Its

) can be written in the form

X k =

( jbk + Ce jck + De jdk

)

Find the numerical values of the constants.

A = b = , C = -3 , c =

D = d = x n = 2

20 n + 7 6

20 n 1 + 8

20 n 5

Using

N

F n FS 1 / N

F

and x n n

0

FS X k e j 2 n

0 k / N

F

X k =

( ) e j 14 k / 20 6 1 / 20

) e j 2 k / 20 +

( ) e j 10 k / 20

X k =

( ) ( e j 7 k /10 3 e j k /10 + 4 e j k / 2

)

2

0

-2

-4

-6

-8

-10

-10

10

8

6

4

-8 -6 -4 -2 0 n

2 4 6 8 10

3.

2

1

0

-1

-2

-3

0

3

Match the CTFS magnitude graphs to the time functions. (In all cases

T

F

= 4 .)

I

3 3 3 3

2 t

0

-1

-2

2

1

4

-3

0 2 t

0

-1

-2

2

1

4

-3

0 2 t

0

-1

-2

2

1

4

-3

0 t

2

0

-1

-2

2

1

4

-3

0 t

2 4

A

1

0.8

0.6

0.4

0.2

0

-10 0 k

10

0.8

1

B

0.6

0.4

0.2

0

-10 0 k

10

C

1

0.8

0.6

0.4

0.2

0

-10 0 k

10

D

1

0.8

0.6

0.4

0.2

0

-10 0 k

10

E

1

0.8

0.6

0.4

0.2

0

-10 0 k

10

1

0.8

0.6

0.4

0.2

1

0.8

0.6

0.4

0.2

1

0.8

0.6

0.4

0.2

1

0.8

0.6

0.4

0.2

1

0.8

0.6

0.4

0.2

1.

2.

3.

4.

5.

0

-10 0 k

F

10

0

-10 0 k

G

10

0

-10

H

0 k

10

0

-10

I

0 k

10

0

-10

J

0 k

Second-harmonic sine function. Non-zero impulses only at k

= ± 2

.

One fundamental period of a square wave with an average value of 1.

Harmonic function is a sinc function with a non-zero impulse at the fundamental k

= 1 .

Two fundamental periods of a square wave with an average value of 1.

Harmonic function is a sinc function with a zero impulse at the fundamental k

= 1

and a non-zero impulse at k

= 2.

Two fundamental periods of a triangle wave with an average value of 1.

Harmonic function is a sinc squared function with a zero impulse at the fundamental k

= 1

and a non-zero impulse at k

= 2.

The impulses are smaller than for a square wave because of the faster rate of decay of sinc squared compared with sinc.

Fourth-harmonic sine function. Non-zero impulses only at k

= ± 4 .

10

4.

-1

-2

-3

0

2

1

0

3

Match the DTFS magnitude graphs to the time functions. (In all cases

N

F

= 16

E

.)

A

3 3 3 3 n

10

-1

-2

-3

0

2

1

0 n

10

-1

-2

-3

0

2

1

0 n

10

-1

-2

-3

0

2

1

0 n

10

-1

-2

-3

0

2

1

0 n

10

1.5

A

1.5

B C

1.5

D

1.5

E

1.5

1 1 1 1 1

1

0.5

0.5

0

0

1.5

k

10

1

0.5

0.5

0

0

1.5

k

10

1

0.5

0.5

0

0

1.5

k

10

1

0.5

0.5

0

0

1.5

k

10

1

0.5

0.5

0

0

1.5

k

10

1.

2.

3.

4.

5.

0

0 k

10

F

0

0 10 k

G

0

0

H k

10

0

0

I k

10

0

0

J k

10

Second-harmonic sine function. Non-zero impulses only at k

= ± 2 repeated periocidally with period 16.

Pulse train with average value of 1/4. Harmonic function has a Dirichlet shape (periodically-repeated sinc functions).

Square wave with an average value of zero and fundamental period equal to representation time. Zero at periodically with period 16.

k

= 0 and non-zero at k

= ± 1 repeated

Pulse train with average value of 1/2. Harmonic function has a Dirichlet shape (periodically-repeated sinc functions) narrower than #2 because the time-domain pulse is twice as wide.

Fourth-harmonic sine function. Non-zero impulses only at k

= ± 4 repeated periodically with period 16.

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