Calculus II: Volumes of Revolution: Shell vs. Disk Method Revised by Learning Center Revolution about the y axis Revolution about the y axis Shell Method: Create differential area parallel to axis of revolution Find the radius of the shell Find the height of the shell. It may be necessary to subtract two functions Find the limits of integration Integrate: Disk Method: Create differential area perpendicular to axis of revolution Find the radius of the disk If the revolution has a hole, subtract the volume of the inner volume by finding the radius of the inner disk. Find the limits of integration Integrate: b V 2 shell radius shell height dx b V Rdisk dy 2 a a Find the volume of the shape made by the revolution of y x and y x 2 about the y axis using the shell method. Find the volume of the shape made by the revolution of y x and y x 2 about the y axis using the disk method. b V 2 Rshell H shell dx a 1 V 2 x x x 2 dx 0 V 6 b b V Rdisk1 dy R disk2 dy 2 a 1 V 0 V 2 a y dy y dy 2 1 2 0 6 Made for the Learning Center: by Lon Farr and Phillip Flanders ©2005 Calculus II: Volumes of Revolution: Shell vs. Disk Method Revised by Learning Center Revolution about the x axis Revolution about the y axis Find the volume of the shape made by the revolution of y x and y x 2 about the x axis using the shell method. Find the volume of the shape made by the revolution of y x and y x 2 about the x axis using the disk method. b V 2 Rshell H shell dy a 1 b b a V 2 y y y 2 dy 0 V R disk1 dx R disk2 dx 2 1 V 0 2 a x dx x dx 2 1 2 2 0 3 V 10 3 V 10 Remember Make sure your height, radius and differential are all in terms of the same variable, but look for the simplest combination, don’t solve if you don’t have to. You may need to subtract two functions to find the height. Set limits of integration that come from the area you’re integrating over, (often, you’ll have to calculate an intersection.) Remember Make sure to have the radius of the disk in terms of the same variable as your differential. You may need to subtract two disks to find a volume with an internal void Set limits of integration that come from the area you’re integrating over, (often, you’ll have to calculate an intersection.) Made for the Learning Center: by Lon Farr and Phillip Flanders ©2005