Chapter 15 Principles of Metabolic Regulation Required assignment at end of chapter A good chapter that shows the interplay in regulation needed to make an organism work. Unfortunately I think we need to skip many of the nifty details and just focus on a few of the high points as they apply to glycolysis and gluconeogenesis 15.1 Regulation of metabolic pathways Cells and Organisms Maintain a Dynamic Steady State In Chemistry so far we have two ways of thinking about the chemical reaction A6B We can talk about this reaction assuming it is static and does not change In this case we have come to equilibrium and get equations like: K =[B]/[A] and ÄG=-RTlnK Or we can talk this reaction using kinetics and study how fast things change and come up with equations like : rate =k[A] And I would try to emphasize that you can’t mix kinetics and equilibria because they are two very different things Biological systems present a challenge to this way of thinking. If we look at a living organism we have a constant flow of food in and waste out, and as long as nothing changes the organism lives. Thus we have a system that does not appear to change. But this is not because it is at equilibrium, but rather because the kinetics of food in and waste out are matched, so we have a kinetic system, that seems to mimic equilibrium. So it looks like kinetics and equilibria are getting mixed together. This is called the Dynamic Steady State. A system where the concentrations of individual chemical do not change, not because we are at equilibrium, but because [the flux (rate of metabolite flow) of chemicals in = the flux of chemicals out] This is homeostasis on a molecular level. This is the key to understanding metabolism. We have to understand both how an organism keeps the flux of chemical through a given pathway constant, and how it can make that flux change in response to changes in its environment. The flux through an enzyme catalyzed reaction can be changes in two ways : we can change the number of enzyme molecules present, or we can change the catalytic activity of that enzyme. We change the number of enzymes present through various genetic controls that we don’t discuss till chapters 24, 25, and 26, so I will skip those discussions till later. We can change the catalytic activity of enzyme through various control mechanisms you learned back in Chapter 6, so that is what I will emphasize in this chapter. 2 Bottom line I am picking and choosing what I want to take out of this Chapter Pick 1. Page 592 The difference between metabolic regulation - processes that maintain homeostasis or keep things constant -vsmetabolic control - processes that lead to change in response to outside signal The distinction between these two is not always clear cut, but it is useful Pick 2. Also page 574 I had you memorize the ÄG0 for each reaction in the glycolytic pathway because reactions with large - ÄG’s are frequently control points, and I wanted you to recognize this. Here is the explanation and a few more details. Figure 15-6 Here are three reactions. Reaction 1 has a forward rate constant of 10.01/sec and a reverse rate constant of .01/second The net rate of the reaction is 10.01-.01 = 10 If this first order reaction, rate forward = [A]*10.01 And rate backward = [B]*.01 To be at equilibrium rate forward = rate backward so [A]*10.01 = [B]*.01 And [B]\[A] = 10.01/.01 = 1001 [B]/[A] also = K, so K = 1001. A favorable reaction with a large negative ÄG So of the three reactions, #1 has the largest K and most negative delta G while 2 and 3 are much closer to K=1 and ÄG being just slightly negative, yet all three have the same flow or flux = 10 So here we have our first case where we have to think of flux in a dynamic system rather than K’s in an equilibrium system, and you can see they are different. What makes 1 a better control point Rather than math, let’s try to use analogy. Think of water behind a dam. We can punch a hole in the dam at three different levels. Reaction 1 has the most energy so it has the hole punched in the dam at the lowest level. Reaction 3 is closest to equilibrium so it has the hole punched through at the highest level. Now first, we want the water flowing out of the hole (the flux) to be the same. So the lowest hole will have to be the narrowest because the water is coming out the fastest. The upper hole will have to 3 be the widest because the water will come out the slowest. Lets say the lowest hole has a size of 1 unit, and the upper hole has the larger size of 10 units. Now we want to change the flux, or rate of water coming out of the hole. Let’s change the size of the hole by 1 unit. The size of the lower hole is now 1+1=2, so this will double the size of the lower hole, so there will double the flux. If we change the size of the upper hole 1 unit, 10+1=11, so we only make a 10% change in the flux. Thus it makes sense to use a control point where the energy drop is the greatest because small changes will have the most dramatic effect. Another thing we talked about last semester was the ÄG0' was not the only thing we need to look at. We found that the actual concentrations of reactants and products can change the actual ÄG dramatically. Look at table 15-3. In this table we have ÄG0', concentrations, and ÄG. Notice how the ÄG’s of the reactions shift, sometime quite dramatically (aldolase from quite unfavorable to slightly favorable) The table has arbitrarily drawn the line at ÄG being +/-6 kJ as being at equilibrium and not great control points, So we will focus on the 4 reactions in this table (and fructose 1,6bisphosphate which is not given) for our analysis of control. 15.2 Analysis of Metabolic controls An interesting section. But it starts using partial derivatives and ratios of partial derivatives, and I have the feeling that to do this section justice, you probably need a week or two plus Calc II or Calc III, so this is a skip. One interesting factoid to come out of this however. Back in kinetics you were taught to focus on the rate limiting reaction. I stated then that the everything slows down to match the slow step. The new thought that comes out of this more complex analysis is that focusing on the rate limiting step is NOT CORRECT in biological flux type systems. The bottom line is that it may work for simple chemical kinetics, but not complex biological systems. 4 15.3 Coordinated regulation of glycolysis and gluconeogenesis The above analysis on reactions that are far from equilibrium focuses us on 4 main reactions for control: Hexokinase PFK-1 Pyruvate Kinase Pyruvate carboxylase and PEP carboxykinase We will also see Fructose 1,6-bisphosphatase as a control point but is it not on the table Pick these reaction out on (Figure 15-13) (Show figure on projector then highlight these reaction and names on board) Glycolysis Reaction Gluconeogenesis Glucose W Glucose 6-phosphate Hexokinase Glucose-6-phosphatase Fructose-6-P WFructose 1,6 biphosphate Phosphofructokinase-1 Fructose 1,6-bisphosphatase (PFK-1) (FBPase-l) PEPWPyruvate pyruvate kinase Pyruvate carboxylase & PEP carboxykinase Need to keep from running continuously Any pair of reactions, if going full bore would chew up ATP - called a futile cycle More recently have found that do to a small amount of cycling for control purposes In this case called a substrate cycle Analogy, like idling your car? A. Hexokinase Isozymes & tissue specific control Liver is designed to make glucose, muscle is designed to use So Hexokinase (RXN1 lysis side) is different in different tissues Four isozyme (I-IV) coded on 4 different genes Muscle forms (predominately Hexokinase II, high affinity glucose, ½ saturated at 0.l mM ) Blood level 4-5 mM so saturated, going flat out under normal conditions Muscle also has hexokinase I but not as much Both Hexokinase II and I allosterically inhibited by product (Glucose-6-P) so 5 enzyme shuts down if G-6-P rises above normal levels Liver is designed to maintain blood glucose by consuming or producing so want reverse reaction to go and this to be shut down Predominate form hexokinase IV (glucokinase) Differs from Hexkinase II in three ways 1. ½ saturated @ 10 mM, only fractionally turned on Figure 15-14 Essentially only kicks in when blood glucose is high, GLUT2 transporter lets glucose into cell, and therefor take glucose out of blood by changing to Glu-6-P which keeps it in cell At low blood glucose levels (<10 mM) enzyme is not very reactive, so Glucose levels build up in cell, and GLUT2 transport glucose out of cell and into blood 2.Not down regulated by G-6-P so will continue to make G-6-P even when building up in cell 3. Additional regulation by a binding protein that physically takes enzyme out of cytosol and into nucleus Figure 15-15. This is regulated by Fructose 6-P (further down pathway). When Fruct-6-P is high want to slow down production so cell can get back into balance, so takes enzyme out of circulation When Glucose is high, have plenty of raw material so put enzyme back into cytosol so can break glucose down. Additional control for this and reverse reaction (Glucose-6-phosphatase) via transcriptional regulation- here is thumbnail sketch If cell has low ATP, high AMP or high glucose consumption Will make more mRNA for Hexokinase IV gene If cell need more glucose to be produced, will make more mRNA for Glucose-6-phosphatase B. Phosphofructokinase 1 (PFK1) and Fructose 1,6-bisphosphatase are Reciprocally Regulated Middle reaction Glu-6-P can be used several different ways: glycolysis, glycogen synthesis, pentose phosphate pathway The PFK-1 reaction is commit step to glycolysis (saw earlier that is essentially irreversible so this makes sense) Use complex allosteric regulation ATP is both a substrate and a regulator High ATP shuts down (cell has plenty of E) Binding actually lowers affinity for Fructose-6-P Figure 15-16b,c Can be relieved with AMP or ADP (only build up is cell is low in E) 6 Citrate (intermediate in TCA cycle - If conc. is high, then TCA must be shut down because cell has plenty of E) Enhances ATP effect further Fructose 2,6- bisphosphate - activates see why later Now for the reciprocal control in the other direction Fructose bisphosphatate (FBPase-1) Figure 15-17 Strongly inhibited by AMP (so inhibited if cell is low in E) So this Allosteric control is the opposite of what we saw for the glycolytic counterpart - so coordinated reciprocally C. Both PFK-1 and FBPase-1 have additional allosteric effector 2,6-Bisphosphate (Show structure on board page 605, right hand column) Skipped over earlier, now let’s examine Part of hormonal control Glucagon hormone signals to liver to release more Glucose for blood has two ways to do this degrade more glycogen into glucose make more glucose through gluconeogenesis Fructose 2,6 bisphophate is key allosteric effector here Figure 15-18 a,b,&c PFK1 (Reaction 1 lysis) Increases affinity for substrate (lowers Km curve (a) shifts left) Decrease affinity for ATP and citrate so can't inhibit So turns on In fact, under normal conditions this enzyme is turned off unless F-2,6-is present! FBPase-1 (Reaction on genesis) Inhibited by F-2,6P (binding decreased, Km increased, curve shifts right) F-26-P Is not product of either lysis or genesis, so this is not a direct feedback control Figure 15-19 Formed by Phophofructkinase-2 (PFK-2)and broken down by Fructokinase 2,6-biphosphatase (FBPase-2) distinct different enzymes from PFK-1 and FBPase-1 Actually 2 distinct activities that are combined in a single bifunctional protein! Balance is controlled by insulin and glucagon Glucagon (signal for more glucose)- releases cAMP- that makes a kinase phosphorylate this enzyme PhosphorylationFBP-2 activity increases PFK-2 decreases Net - 2,6 level goes down 7 Glycolysis goes down Insulin (signal that blood sugar shouldn't go higher) Stimulates a phosphoprotein phosphatase Removes P from phosphoproteins FBP-2 decreases PFK-2 increases 2,6 goes up Glycolysis up, Neogensis down D. Xylulose 5-phosphate is key regulator of carbohydrate and Fat metabolism The above level of F 2,6- bisphosphate is also regulated by xylulose 5-P , a product of the pentose phosphate pathway (figure 14-23?) Just talked about the PFK-2/FBPase-2 enzyme that Raises F26BP when de-phosphorylated indirectly by insulin And Lower F26BP when phosphorylated indirectly by glucagon Xylulose 5-phosphate activates the protein ‘phosphoprotein phosphatase 2A ‘ Which also dephosphoylates F26BP leading to 8F26BP 8Glycolysis 9gluconeogenesis Increased glycolysis increases amount of Acetyl CoA in TCA cycle And increased flow of sugars through pentose pathway Resulting in increased generation of NADPH Increased NADPH and acetyl CoA results in Fatty acid synthesis E. Pyruvate kinase Reaction 3 on lysis side 3 isozymes also allosteric control ATP, acetyl CoA, long chain FA's all inhibit Liver isozyme (L) further controlled by attaching a phosphate (Figure 15-21) Low blood glucose - releases hormone glucagon - release cAMP in cell Kinase is phophorylated and this inhibits, so burning of glucose in liver is slowed so concentration of glucose can rise In Muscle cAMP had a different trigger and response Epinephrine (Fight or Flight hormone) releases cAMP in Muscle But here cAMP activates glycogen breakdown and glycolysis F. Gluconeogenic Conversion of Pyruvate to PEP Figure 15-22 starting with pyruvate had two choices further degradation in TCA for more E (Pyruvate dehydrogenase is next enzyme in this direction, see 8 next chapter) Turn back into glucose through gluconeogeneiss If liver has lots of Fatty acid to burn (and this give more E than glucose) then have high level of acetyl-CoA Acetyl Co A will stimulate pyruvate carboxylase (gluconeogeneisis) And inhibit pyruvate dehydrogenase (first step to start TCA Note controls are not absolute there is a low level of substrate cycling G. This section deals with control by changing the amount of enzyme present by changing transcription and translation. I don’t want to start this until we have done chapters 2426, so we will take a pass for now. Will also skip the rest of this chapter.