Engineering 45 Dislocations & Strengthening (1) Bruce Mayer, PE Licensed Electrical & Mechanical Engineer BMayer@ChabotCollege.edu Engineering-45: Materials of Engineering 1 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Learning Goals Understand Why DISLOCATIONS are observed primarily in METALS and ALLOYS Determine How Strength and Dislocation-Motion are Related Techniques to Increase Strength Understand How HEATING and/or Cooling can change Strength and other Properties Engineering-45: Materials of Engineering 2 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Theoretical Strength of Crystals The ideal or theoretical strength of a “perfect” crystal is E/10 • For Steel, E = 200 GPa – Thus the theoretical strength 20 GPa • 2,000 MPa is the practical limit for steel and this is an ORDER of MAGNITUDE Less than 20,000 MPa • Most commercial steels have a strength 500 MPa - Why is there such differences? Engineering-45: Materials of Engineering 3 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Role of Crystal Imperfections Crystal imperfections explain why metals are weak (relative to the Theoretical) and why they are so ductile • In most applications we need ductility as well as strength - so there is a plus side to the presence of imperfections • The main task in deciding what strengthening process to use in metal alloys is to chose a method which minimizes the loss of ductility Engineering-45: Materials of Engineering 4 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Edge Dislocations Recall from Chp.4 The Crystal Imperfection of an Extra ½-Plane of Atoms Extra ½-Plane of Atoms • Called an EDGE DISLOCATION These imperfections are the Source of PLASTIC Deformation in Xtals Engineering-45: Materials of Engineering 5 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Dislocations vs. Metals Dislocation Motion is RELATIVELY Easier in Metals Due to • NON-Directional Atomic Bonding • Close-Packed Crystal Planes allow “sliding” of the Planes relative to each other Ion Cores Electron Sea Dislocations & Slip (Deformation) – Called SLIP Engineering-45: Materials of Engineering 6 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Disloc vs. Covalent Ceramics For CoValent Ceramics Dislocation Motion is RELATIVELY more Difficult Due to • Directional (angular) and Powerful Atomic Bonding Strong, Directional Bonds Dislocations & Slip (Deformation) Examples • Diamond Carbon • Silicon Engineering-45: Materials of Engineering 7 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Disloc vs. Ionic Ceramics For Ionic Ceramics Dislocation Motion is RELATIVELY more Difficult Due to • Coulombic Attraction and/or Repulsion • Slip Will Encounter ++ & -- Charged nearest neighbors Engineering-45: Materials of Engineering 8 + Ion Cores − Ion Cores Dislocations & Slip (Deformation) Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Dislocations vs Matl Type Metals Allow Xtal Planes to Slip Relative to Each other • Relatively Low Onset of Plastic Deformation (Yield Strength, σy) • Relatively High Ductility: The amount of Plastic deformation Prior to Breaking Ceramics Tend to Prevent Disloc. Slip • Allow for little Plastic Deformation • Failure by Brittle-Fracture (cracking) Engineering-45: Materials of Engineering 9 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Dislocation Motion Produces Plastic Deformation In Crystals Proceeds by Incremental, Step-by-Step Breaking & Remaking of Xtal Bonds WithOut Dislocation motion Plastic (Ductile) Deformation Does NOT Occur Engineering-45: Materials of Engineering 10 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Screw Dislocations In the EDGE configuration The axis of is Parallel (||) to the Applied Shear Stress EDGE Dislocation SHEARING Motion A SCREW dislocation is Perpendicular to the Applied Force SCREW Dislocation TEARING Motion Engineering-45: Materials of Engineering 11 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Role of Imperfections in Plastic Deformation No edge dislocation present Dislocation present (a) Compression stress field Bond Broken All bonds broken in the one plane CRSS very high Dislocation present (b) Tension stress field Dislocation present (c) Bond reattached Bond broken Plastic Flow occurs by Dislocation Movement Engineering-45: Materials of Engineering 12 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Dislocation Motion Analogies Caterpillar LoCoMotion Carpet-Layer LoCoMotion Engineering-45: Materials of Engineering 13 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Stress and Dislocation Motion Crystals slip due to a resolved shear stress, R Applied TENSION can Produce This -Stress Resolved shear stress: R =Fs /As Applied tensile stress: s = F/A F A slip plane R normal, ns As Fs F R Relation between sand R R =Fs /As Fcos l F l Fs R F Acos l cos s cos l cos Engineering-45: Materials of Engineering 14 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt A/cos ns A As Resolved Shear Stress, R (in detail) Consider a single crystal of crosssectional area A under compression force F • angle between the slip plane normal and the compression (or Tension) axis • l angle between the slip direction and the tensile axis. Engineering-45: Materials of Engineering 15 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Resolved Shear Stress, R cont.1 F projected on Slip Direction: Fs F cos l As Fcosλ The Slip Direction Slant Area, As, Relative to the Compression Area, A A = Ascos Engineering-45: Materials of Engineering 16 A As cos Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Resolved Shear Stress, R cont.2 Thus the Resolved Shear Stress F cos l R Fs As A cos As F cos l cos A But F/A = σ; the Compression (or Fcosλ Tension) Stress - So A = Ascos Engineering-45: Materials of Engineering 17 R s cos l cos Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Critical Resolved Shear Stress Condition for Dislocation Motion: R>CRSS • CRSS CRITICAL Resolved Shear Stress Xtal Orientation Can Facilitate Dicloc. Motion R s cos l cos s s R = 0 l = 90° HARD to Slip Engineering-45: Materials of Engineering 18 R = s/2 l = 45° = 45° EASY to Slip s R = 0 = 90° HARD to Slip Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Yield Stress, sy An Xtal Plastically Deforms When R ,max CRSS and R ,max s cos cos l To Get Yield Strength, Need sminimum → (cos cosl)max cos cos l max Thus sy = 2CRSS Plastically stretched zinc single crystal. cos 45 cos 45 1 2 Engineering-45: Materials of Engineering 19 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt PolyXtal Disloc Motion Slip planes & directions (l, ) change from one crystal to another R varies from one crystal, or Grain, to another 300 mm Engineering-45: Materials of Engineering 20 The Xtal/Grain with the LARGEST R Yields FIRST Other (less favorably oriented) crystals Yield LATER Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Summary Edge Dislocations Plastic flow can occur in a crystal by the breaking and reattachment of atomic bonds one at a time • This dramatically reduces the required shear stress – Consider how a caterpillar gets from A to B A similar mechanism applies to screw dislocations Screw & Edge dislocations often occur together Engineering-45: Materials of Engineering 21 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt 1-Phase Metal Strengthening Basic Concept Plastic Deformation in Metals is CAUSED by DISLOCATION MOVEMENT Strengthening Strategy RESTRICT or HINDER Dislocation Movement Strengthening Tactics 1. Grain Size Reduction 2. Solid Solution Alloying Engineering-45: Materials of Engineering 22 3. Strain Hardening 4. Precipitation (2nd-ph) Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Strengthen-1 G.S. Reduction Grain boundaries are barriers to slip due to Discontinuity of the Slip Plane Barrier "Strength“ Increases with Grain MisOrientation Smaller grain size → more Barriers to slip Hall-Petch Reln → Engineering-45: Materials of Engineering 23 slip plane grain A s y s 0 k y d • Where – s0 “BaseLine” Yield Strength (MPa) – ky Matl Dependent Const (MPa•m) – d Grain Size (m) Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Example GS Reduction Calc The Hall-Petch Slope, ky, for 70Cu-30Zn (C2600, or Cartridge) Brass k y s y d s y 1 2 Find the ’s d 1 2 d 1 2 12 4 8 mm1 2 s y 180 70 110 MPa Then the Slope Engineering-45: Materials of Engineering 24 k y 110MPa 8mm 1 2 k y 435 kPa m Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Strengthen-2 Solid Solution Impurity Atoms distort the Lattice & Generate Stress Stress Can produce a Barrier to Dislocation Motion • Smaller substitutional impurity • Larger substitutional impurity A C B • Impurity generates local shear at A and B that opposes dislocation motion to the right. Engineering-45: Materials of Engineering 25 D • Impurity generates local shear at C & D that opposes dislocation motion to the right. Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Example Ni-Cu Solid-Soln Tensile (Ultimate) Strength, σu, and & Yield Strength, σy, increase with wt% Ni in Cu Empirical Relation: σy ~ C½ Basic Result: Alloying increases σy & σu Engineering-45: Materials of Engineering 26 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Strengthen-3 Strain Harden COLD WORK Room Temp Deformation Common forming operations Change The Cross-Sectional Area: -Forging force die Ao blank -Drawing die Ao die Ad force Ad -Extrusion tensile force Ao Ad %CW x100 Ao Engineering-45: Materials of Engineering 27 -Rolling Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Dislocations During Cold Work ColdWorked Ti Alloy • Dislocations entangle with one another during COLD WORK • Dislocation motion becomes more difficult 0.9 mm Engineering-45: Materials of Engineering 28 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt ColdWorking Consequences Dislocation linear density, ρd, increases: • Carefully prepared sample: ρd ~ 103 mm/mm3 • Heavily deformed sample: ρd ~ 1010 mm/mm3 Measuring Dislocation Density 40mm Volume, V length, l 1 length, l 2 length, l 3 r l1 l2 l3 d V σy Increases as ρd increases: Engineering-45: Materials of Engineering 29 Area , A dislocation pit OR r N d A N dislocation pits (revealed by etching) Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Typical Dislocation Densities (Total Length of Dislocation Line/unit Volume) 0 - 103 Very Pure Crystals (whiskers) Annealed Single Crystals 105 - 106 Annealed Polycrystals 107 - 108 Highly Cold Worked Metals Engineering-45: Materials of Engineering 30 mm/mm3 1011 - 1012 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt CW Strengthening Mechanism Strain Hardening Explained by Dislocation-Dislocation InterAction Cold Work INCREASES ρd • Thus the Average - Separation-Distance DECREASES with Cold Work Recall - interactions are, in general, REPULSIVE Thus Increased ρd IMPEDES -Motion Engineering-45: Materials of Engineering 31 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Simulation – DisLo Generator Tensile loading (horizontal dir.) of a FCC metal with notches in the top and bottom surface Over 1 billion atoms modeled in 3D block. Note the large increase in Dislocation Density Engineering-45: Materials of Engineering 32 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt -Motion Impedance Dislocations Generate Stress • This Generates -Traps Reddislocation generates shear at pts Aand Bthat opposes motion of green disl. from left to right. Engineering-45: Materials of Engineering 33 A B Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt ColdWork Results-Trends As Cold Work Increases • Yield Strength, sy, INcreases • Ultimate Strength, su, INcreases • Ductility (%EL or %RA) DEcreases Engineering-45: Materials of Engineering 34 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt Cold Work Example What is the Tensile Strength & Ductility After Cold Working? %CW ro2 rd2 ro2 x100 35.6% yield strength (MPa) 700 500 300 300MPa 100 0 20 Cu 40 % Cold Work sy=300MPa 60 Engineering-45: Materials of Engineering 35 Post-Work Ductility is HAMMERED Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt WhiteBoard Work Engineering-45: Materials of Engineering 36 Bruce Mayer, PE BMayer@ChabotCollege.edu • ENGR-45_Lec-17_DisLoc_Strength-1.ppt