Logic Circuit Synthesis Engineering 43 Bruce Mayer, PE

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Engineering 43
Logic Circuit
Synthesis
Bruce Mayer, PE
Licensed Electrical & Mechanical Engineer
BMayer@ChabotCollege.edu
Engineering-43: Engineering Circuit Analysis
1
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
ReCall the Basic Gates
Engineering-43: Engineering Circuit Analysis
2
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Boolean Logic

The Logical Operators Form The Basis of
BOOLEAN (Two Value, T & F, 1 & 0,
or Hi & Lo) Logic
•

Developed by George Boole (1815-1864)
The Action of the Boolean Operators are
Often Characterized with TRUTH Tables
AND (all high = high, else low)
NOT (inverter)
Input 1
Input 2
Output
Input 1
Input 2
Output
Input = 1 Output = 0
0
0
0
0
0
0
Input = 0 Output = 1
0
1
0
0
1
1
1
0
0
1
0
1
1
1
1
1
1
1
Engineering-43: Engineering Circuit Analysis
3
OR (any high = high, else low)
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Boolean Algebra
 Boolean Logic can be Mathematically
Formalized with the use of Math Operators
 The Math Operators Corresponding to
Boolean Logic Operations:
Operator
Usage
Notation
AND
A AND B
A.B or A·B
OR
NOT
A OR B
NOT A
A+B
~A or A
• A and B can only be TRUE or FALSE
• TRUE represented by 1; FALSE by 0
Engineering-43: Engineering Circuit Analysis
4
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Boolean Algebraic Properties
 Commutative: A.B = B.A and A+B = B+A
 Distributive:
• A.(B+C) = (A.B) + (A.C)
• A+(B.C) = (A+B).(A+C)
 Identity Elements: 1.A = A and 0 + A = A
 Inverse: A.A = 0 and A + A = 1
 Associative:
• A.(B.C) = (A.B).C and A+(B+C) = (A+B)+C
 DeMorgan's Laws:
• A.B = A + B and
• A+B = A.B
Engineering-43: Engineering Circuit Analysis
5
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Prove Distributive Law
 ReCall Bolean
Distributive Law
D
AB  C   AB  AC
 The Circuits at Right
Implement The
Sides of this Identity
 If the Identity is
TRUE, then the
TruthTable for the
two circuits must be
Identical
Engineering-43: Engineering Circuit Analysis
6
D
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Prove Distributive Law
 Constructing a Truth Table that Includes
and Expands [AB+AC] & [A(B+C)]
A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
C B+C AB AC AB+AC A(B+C)
0
0
0
0
0
0
1
1
0
0
0
0
0
1
0
0
0
0
1
1
0
0
0
0
0
0
0
0
0
0
1
1
0
1
1
1
0
1
1
0
1
1
1
1
1
1
1
1
IDENTICAL
Engineering-43: Engineering Circuit Analysis
7
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Prove XOR distributive Law
 A Truth Table AlsoProves
the EXCLUSIVE-OR A(BC) ≡ ABAC
Version of the Dist Law
A B C BC AB AC ABAC A(BC)
0 0 0
0
0
0
0
0
0 0 1
1
0
0
0
0
0 1 0
1
0
0
0
0
0 1 1
0
0
0
0
0
1 0 0
0
0
0
0
0
1 0 1
1
0
1
1
1
1 1 0
1
1
0
1
1
1 1 1
0
1
1
0
0
IDENTICAL
Engineering-43: Engineering Circuit Analysis
8
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
DeMorgan in MATLAB
 DeMorgan → Case-a:  A  B   A  B
?
>> % case-a
>> x = 7
x =
1
1
7
>> a1 = ~((x < 10)&(x >= 6))
a1 =
0
0
0
>> a2 = (~(x < 10))|(~(x >= 6))
a2 =
0
Engineering-43: Engineering Circuit Analysis
9
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
DeMorgan in MATLAB
 DeMorgan → Case-b
A  B  A  B
?
>> % case-b
>> y = 3
y =
0
0
3
>> b1 = ~((y == 2)|(y > 5))
b1 =
1
1
1
>> b2 = (~(y == 2))&(~(y >5))
b2 =
1
Engineering-43: Engineering Circuit Analysis
10
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Multiple-Input Gates
 The Flexibility of
Boolean Algebra
permits
straightforward
Extension to Gates
with Many Inputs
Engineering-43: Engineering Circuit Analysis
11
 The Number of
Entries in the TT is
2N, where:
• N ≡ No. of INputs
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Gates  Boolean (WhiteBoard)
 Write the Boolean Expression
Equivalent to the Logic Circuit Analyzed
Last Lecture
Q
A  B D  C D  C  D  Q
Engineering-43: Engineering Circuit Analysis
12
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Boolean  Gates (WhiteBoard)
 Draw the Logic-Gate Circuits to
Implement these Boolean Equations
• Use Multiple-Input Gates as desired
Q1   A  B  C   A  B  C 
Q2  B  C  D  A  C  D  C  D 
Engineering-43: Engineering Circuit Analysis
13
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Principal Boolean Algebra Laws
OR expression
AND expression
0+a=a
1a = a
1+a=1
0a = 0
a+a=a
aa = a
a + a' = 1
aa' = 0
(a')' = a
a+b=b+a
ab = ba
a +(bc) = (a + b)(a + c)
a(b + c) = ab + ac
a + (b + c) = (a + b) + c
a(bc) = (ab)c
a + ab = a
a(a + b) = a
a + a'b = a + b
a(a' + b) = ab
( a + b)' = a' b'
(ab)' = a' + b'
ab + a'c + bc = ab + a'c (a+b)(a'+c)(b+c) = (a+b)(a'+c)
NOTE:
Engineering-43: Engineering Circuit Analysis
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a'  a
b'  b
Law Name
Identity
Idempotency
Complement
Involution
Commutativity
Distributivity
Associativity
Absorption
Simplification
DeMorgan's Law
Consensus Thrm
etc.
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
MinTerms  Sum of Products
 Consider an Example  Function Notation
Boolean function of
• X, Y, Z→ Inputs
three variables by
• Q → Output
Truth Table
 The only non-zero
X Y Z Q
OutPuts are at:
0 0 0 0
FIX:
R(101)=1 0
R(110)=0 0
0
1
1
1
1
0
1
1
0
0
1
1
1
0
1
0
1
0
1
0
1
0
0
1
0
0
Engineering-43: Engineering Circuit Analysis
15
• X = 0, Y = 1, Z = 0
• X = 1, Y = 1, Z = 0
 The Fcn is 1 for
those 2 input-sets
and 0 for all other
input conditions.
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
MinTerms  Sum of Products
 The Function
Operation Requires
• The output to be 1
whenever
– X=0 AND Y=1 AND
Z=0
• OR when
– X=1 AND Y=0 AND
Z=1
 This Description can
written using
Boolean Algebra:
Engineering-43: Engineering Circuit Analysis
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X
0
0
0
0
1
1
1
1
Y
0
0
1
1
0
0
1
1
Z
0
1
0
1
0
1
0
1
Q  X Y  Z  X Y  Z
 Function read as:
(NOT-X AND Y
AND NOT-Z) OR (X
AND NOT-Y AND Z)
 By Way of
• NOT-X = 0
• NOT-Y = 0
• Etc.
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Q
0
0
1
0
0
1
0
0
MinTerms  Sum of Products
 The Ckt Below
Implements Fcn:
Q  X Y  Z  X Y  Z
Q
Engineering-43: Engineering Circuit Analysis
17
 The function is
composed of two
groups of three.
X
0
0
0
0
1
1
1
1
Y
0
0
1
1
0
0
1
1
 Each group of three is
a minterm.
• minterm implies that
each of the groups of
3 in the expression
takes on a value of 1
only for one of the 8
possible combos of X,
Y and Z and their
inverses Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Z
0
1
0
1
0
1
0
1
Q
0
0
1
0
0
1
0
0
MinTerms  Sum of Products
 Important points about minterms include
the following.
1. In a minterm, each variable, X, Y or Z
appears once, either as the variable
itself or as the inverse.
X Y Z Q
0 0 0 0
2. Each minterm corresponds 0 0 1 0
0 1 0 1
to exactly one entry (row!) 0 1 1 0
1 0 0 0
in the truth table.
• The Rows with Output = 1
Engineering-43: Engineering Circuit Analysis
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1
1
1
0
1
1
1
0
1
1
0
0
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Boolean Eqn from TruthTable
 It turns out that ANY Boolean function can be
constructed using minterms
 To build a Boolean fcn from minterms:
1. Examine the truth table for the function.
–
Be sure that all possible combinations of variables and
inverses are accounted for.
2. For each entry of the truth table for which the Function
takes on a value of 1, determine the corresponding
minterm expression (an AND expression)
–
Remember that EVERY variable or its inverse will appear in
EVERY minterm.
3. OR (add)Together all the minterms from step-2
Engineering-43: Engineering Circuit Analysis
19
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
MinTerms & SOP Sumarized
 We can sum up the MinTerm
Construiction with the following:
 A truth table gives a unique
sum-of-products function
that follows directly from
expanding the ones in the
truth table as minterms.
Engineering-43: Engineering Circuit Analysis
20
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
MinTerms Example
 Construct Fcn for
A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
V
0
0
0
1
0
1
1
1
 ID the Rows with
ONES for minterms
Engineering-43: Engineering Circuit Analysis
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A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
V
0
0
0
1
0
1
1
1
 Thus This Fuction
has a Total of FOUR
MinTerms
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
MinTerms Example
 T1 product is the
First MinTerm by
Multiplication
T1  A  B  C
 Similarly Construct
Terms 2-4 by
Multiplication
T2  A  B  C
T4  A  B  C
22
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
V
0
0
0
1
0
1
1
1
 To Write the V(ABC)
Function Simply OR
(add) the MinTerms
V
A  B  C    A  B  C  
A  B  C    A  B  C 
T3  A  B  C
Engineering-43: Engineering Circuit Analysis
A
0
0
0
0
1
1
1
1
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
A
0
0
0
0
1
1
1
1
MinTerms Example
 The Ckt Fragment
for the 1st minterm
T1  A  B  C
 The Ckts for the
other Three
minterms:
Engineering-43: Engineering Circuit Analysis
23
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
V
0
0
0
1
0
1
1
1
MinTerm Example
 OR-ing the
MinTerms
Completes the
Function:
V
V
A  B  C    A  B  C  
A  B  C    A  B  C 
 This amounts to
Connecting the
4 ckt-fragments
to an OR gate
Engineering-43: Engineering Circuit Analysis
24
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Sum-of-Products Summarized
 One or more AND gates feeding a
single OR gate at the output
 Example:
AB '  CD' E  AC ' E '
A
B'
C
D'
E
A
C'
E'
Engineering-43: Engineering Circuit Analysis
25
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
PRODUCT of SUMS summarized
 One or more OR gates feeding a single
AND gate at the output
• The DUAL of Sum of Products
( A  B ' )(C  D'  E )( A  C '  E ' )
A
B'
C
D'
E
A
C'
E'
Engineering-43: Engineering Circuit Analysis
26
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Prod-of-Sums  MaxTerms
 Use MaxTerms to
Write the Boolean
Equation for
A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
Q
1
0
1
0
0
0
1
1
Engineering-43: Engineering Circuit Analysis
27
 ID rows with OutPut
of ZERO
A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
Q
1
0
1
0
0
0
1
1
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Prod-of-Sums  MaxTerms
A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
 Note for a SUM (OR)
All elements MUST
Be Zero
A  B  C   0  0  0  0
 Examine the 2nd row
A  B  C   0  0  0  0
A  B  C   0  0  0  0
A  B  C   0  0  0  0
A
0
0
0
B
0
0
1
C
0
1
0
Q
1
0
1
 For A, B, & C to Add
to ZERO Need
Engineering-43: Engineering Circuit Analysis
28
 Similarly for the
other ZERO Rows
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
C
0
1
0
1
0
1
0
1
Q
1
0
1
0
0
0
1
1
Prod-of-Sums  MaxTerms
 Thus ANDing (multiplying) the
MaxTerms ENSURES that Q will Zero if
any one of the MaxTerms is Zero.
 Thus the Function Q
A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
Q  A  B  C  A  B  C  A  B  C  A  B  C 
 A (different)
P.O.S. Ckt
Fragment
Engineering-43: Engineering Circuit Analysis
29
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
C
0
1
0
1
0
1
0
1
Q
1
0
1
0
0
0
1
1
A
0
0
0
0
1
1
1
1
Prod-of-Sums  MaxTerms
 The Logic Circuit for the Example
Q
Engineering-43: Engineering Circuit Analysis
30
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
Q
1
0
1
0
0
0
1
1
SOP & MINterms ShortHand
Row
 Consider the Fcn
0
1
 Written in SOP
2
Form
3
Q  A B C  A BC  ABC
4
 Notice the function 5
6
consists of
7
minterms from
rows 0, 2, and 6
 Thus the ShortHand
Q  m0  m2  m6
Engineering-43: Engineering Circuit Analysis
31
A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
minterm
Q
1 → A’∙B’∙C’
0
1 → A’∙B∙C’
0
0
0
→ A∙B∙C’
1
0
 In Even ShorterHand
Q   m0,2,6
• Quickly ID the
minterms
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
POS & MAXTerms ShortHand
Row
 Consider the Fcn
0
1
 Written POS
2
Form
3




Q  A B C A  B C A  B C
4
 Notice the function 5
6
consists of
7
maxterms from
rows 3, 4, and 7
 Thus the ShortHand
Q  M3  M4  M7
Engineering-43: Engineering Circuit Analysis
32
A
0
0
0
0
1
1
1
1
B
0
0
1
1
0
0
1
1
C
0
1
0
1
0
1
0
1
maxterm
Q
1
1
1
0 → A+B’+C’
→ A’+B+C
0
1
1
0 → A’+B’+C’
 In Even ShorterHand
Q   M 3,4,7
• Quickly ID the
maxterms
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
SOP & POS Summarized
 Sum-of-Products (SOP)
• first the product (AND) terms are formed
then these are summed (OR)
• e.g.: A∙B∙C + D∙E∙F + G∙H∙I
 Product-of-Sums (POS)
• first the sum (OR) terms are formed then the
products are taken (AND)
• e.g.:(A+B+C)∙(D+E+F)∙(G+H+I)
 Convert Between forms using DeMorgan
Engineering-43: Engineering Circuit Analysis
33
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Canonical Form
 Canonical form is not usually an
efficient description of a Boolean fcn but
it is sometimes useful in analysis and
design
 In an expression in canonical form,
every variable appears in every Term
(for SOP) or Factor (for POS), e.g.:
f SOP  A, B, C , D   A B C D  A BC D  ABCD
f POS  A, B, C , D   A  B  C  D  A  B  C  D   A  B  C  D 
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
SOP  Canonical
 Any SOP expression can be forced into
canonical form by ANDing the
incomplete terms with terms of the Form
(X+X’) where X is the name of the
missing variable, e.g.:
Q A, B, C  



AB  BC
ABC  C   A  A BC
ABC  ABC  ABC  A BC
ABC  ABC  A BC
 This operation produce the minterms
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
MINIMUM: SOP & POS
 The minimum sum of products (MSOP) of a function, f, is a SOP
representation of f that contains the fewest number of product terms
and fewest number of literals (Variable-Instances) of any SOP
representation of f.
 Example -- f(a,b,c,d) = m(3,7,11,12,13,14,15)
= ab + acd + acd
= ab + cd
 The minimum product of sums (MPOS) of a function, f, is a POS
representation of f that contains the fewest number of sum terms
and the fewest number of literals of any POS representation of f.
 Example -- f(a,b,c,d) = M(0,1,2,4,5,6,8,9,10)
= (a + c)(a + d)(a + b + d)(b + c + d)
= (a +c)(a + d)(b + c)(b + d)
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Maps
 Karnaugh maps (K-maps) -- convenient
tool for representing switching functions
of up to six variables.
 K-maps form the basis of useful
heuristics (algorithms) for finding MSOP
and MPOS representations.
 An n-variable K-map has 2n cells with
each cell corresponding to a row of an
n-variable truth table.
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Maps
 K-map cells are labeled with the
corresponding truth-table row.
 K-map cells are arranged such that
adjacent cells correspond to truth rows
that differ in only one bit position (logical
adjacency, or GRAY-code form)
 Switching functions are mapped (or
plotted) by placing the function’s value
(0,1,d) in each cell of the map.
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Map Example
 An Example of a 4
Variable Karnaugh
Map
AB\CD 00
01
11
00
01
A  B C  D
 The Square Marked
▼ represents
A  B C  D
▲
▼
11
01
Engineering-43: Engineering Circuit Analysis
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01
 The Square Marked
▲ represents
 Note the two
marked Squares
differ only the C
Variable
• The GRAY format
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
What is GRAY code sequence?
 Gray code sequence only changes one
bit as we go from one number to the
next in the sequence, unlike binary.
 Adjacent cells vary
by only one bit
because a Gray
code sequence
varies by only
one bit.
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Map MiniMization
 Write the Boolean expression in SOP
form
 For each product term, write a 1 in all
the squares which are included in the
term, 0 elsewhere
• canonical form: one square
• one term missing: two adjacent squares
• two terms missing: 4 adjacent squares
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Map MiniMization
 Example: Q  A BC  AB C  ABC  ABC
 Then the
A\BC 00 01 11 10
K-map
0 0
0
1
0
1
 What the
1’s mean
Engineering-43: Engineering Circuit Analysis
42
0
1
1
1
A\BC 00
01
11
10
0
0
0
A’BC
0
1
0
AB’C
ABC
ABC’
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Map MiniMization
 Minimization is done by recognizing patterns of
1's and 0's
 Simple theorems are then used to simplify the
Boolean description of the patterns
 Pairs of adjacent 1's
• remember that adjacent squares differ by only one
variable
• hence the combination of
P A A
2 adjacent squares has the form

• this can be simplified just P as
P∙(0+1) = P∙(1+0) = P by Boolean Algebra
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx

Karnaugh Map Example
 The Previous K-map
A\CD
A/BC 00
01
11
10
0
0
0
1
0
1
0
1
1
1
 Note ADJACENT
Sqs at “11”
• Boxing In the
Vertical Adjecancy
Engineering-43: Engineering Circuit Analysis
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 The adjacent Sqs
A’∙B∙C and
A ∙B ∙C differ
ONLY in A
• hence they can be
combined into just BC
• normally indicated by
grouping the adjacent
squares subject to
combination
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Adjacent Pairs
 Again: Q  A BC  AB C  ABC  ABC
 “Cover” all the 1’s A\BC 00 01 11 10
0 0
0
1
0
with maximum
Varies Only
grouping:
1
1
1
by “A” 1 0
 The simplified (BC group)
Eqn is one that Varies Only
Varies Only
by “B”
by “C”
Sums All Terms
(AC group)
(AB group)
corresponding to
each of the groups: Q  AB  AC  BC
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Wrap-Around Adjacency
 The Top/Bot and Left/Right Edges of
the K-maps are Adjacent as well
• Think of Map being “Rolled Up”
Only C’ does not change
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Map Simplification
 The K-Map uses the following rules for
simplification of expressions by
grouping together adjacent cells
containing ones
1. Groups may not include any cell
containing a zero
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Rules
2. Groups may be horizontal or vertical,
but not diagonal
3. Groups must contain 1, 2, 4, 8, or in
general 2n cells (need “Square Boxes”)
•
That is if n = 1, a group will contain two
1's since 21 = 2. If n = 2, a group will
contain four 1's since 22 = 4.
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Grouping ProtoCol
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Rules
4. Each group should be as large as
possible
5. Each cell
containing
a one must
be in at least
one group
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Rules
6. Groups May
OverLap
7. Groups May
“Wrap-Around”
•
Top↔Bot
•
Left↔Right
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Rules
8. There should be as few groups as
possible, as long as this does not
contradict any of the previous rules.
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Karnaugh Rule Summary
1. No zeros allowed.
2. No diagonals.
3. Only power-of-2 number of cells in each
group.
4. Groups should be as large as possible.
5. Every ONE must be in at least one group.
6. OverLapping allowed.
7. Wrap-Around allowed.
8. Fewest number of groups possible
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
4-Var K-Map Examples
C&D Change,
A&B Change,
A&C Change, D Changes, ABC
AB Same → AB C’D Same → C’D BD’ Same → BD’ Same → ABC
Q  AB  C D
Engineering-43: Engineering Circuit Analysis
54
Q  ABC  BD
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Even More
Complicated
Examples
 Eliminate the
letters that
CHANGE
Across the
Group (if the
group is >1)
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
“don’t care” Conditions
 In certain cases some of the minterms may
never occur or it may not matter what
happens if they do
 In such cases we fill in the Karnaugh map
with an X (or d) to mean “don't care”
 When minimizing an X is like a "joker“
• X can be 0 or 1; Which Ever Helps Minimization
A\BC 00 01 10 11
 e.g. this
00
0
• With d=1
Simplifies to Q = B 01 0
Engineering-43: Engineering Circuit Analysis
56
0
1
d
0
1
1
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Don’t Care Examples
 “Don’t care” conditions should be
changed to either 0 or 1 to produce
K-map Grouping that yields the simplest
expression.
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
All Done for Today
Maurice
Karnaugh
& a Map
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
Engineering 43
Appendix
NAND
Bruce Mayer, PE
Licensed Electrical & Mechanical Engineer
BMayer@ChabotCollege.edu
Engineering-43: Engineering Circuit Analysis
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Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
what
Engineering-43: Engineering Circuit Analysis
60
Bruce Mayer, PE
BMayer@ChabotCollege.edu • ENGR-43_Lec-06a_Fourier_XferFcn.pptx
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