§5.6 Roadmap I I I I Notes §5.6 Examples §5.4, 5.5 Homework Questions Exam Review Problems §6.1 Volunteer to solve board problems. (Math 1010) M 1010 §5.6 1/8 §5.6 Assignment Notes For Wednesday: 1. Exercises from 5.6 2. Next Exam: October 30 - Chapter 4 & 5, and Cumulative Portion Study guide: Chapter 4 Test, p 294, # 1 - 5. Chapter 5 Test, p 367 # 1 - 19. Cumulative: Chapter 1 - 4, p 295, # 1 - 8, 11 - 20. (Math 1010) M 1010 §5.6 2/8 §5.6 Notes Today’s lesson is using factoring to solve a polynomial equation. The steps are 1. ”Solve the equation for zero,” or set all terms on one side and zero on the other. 2. Simplify the equation. 3. Factor the polynomial into smaller factors. 4. Solve each factor equal to zero. 5. Check the solutions in the original equation. (Math 1010) M 1010 §5.6 3/8 §5.6 Solving Linear Equations Notes We will often need to solve linear equations (§2.1) in later steps. Here are some examples to try: (A) x + 1 = 0 (B) 2y − 7 = 0 (C) 6 − s = 0 7 Answers: (A) x = −1, (B) y = , (C) s = 6 2 M 1010 §5.6 (Math 1010) 4/8 §5.6 Factoring Review Notes Factoring will also be a required step. Here are the three basic techniques: Factoring monomials Find the largest common coefficient and largest power of the unknown. 6x 4 y 3 + 12x 2 y − 2x 5 y 2 = 2x 2 y (3x 2 y 2 + 6 − x 3 y ) Grouping Factor out common monomials from pairs of terms. 2y 2 (y 2 + 6) + 7(y 2 + 6) Factoring Trinomials This method uses guessing-and-checking. (Math 1010) 2 4x 2 + 5x − 6 M=1010 4x§5.6 − 3x + 8x − 6 5/8 §5.6 Zero-Factor Property Notes If a · b = 0, then either a = 0 or b = 0. This also applies to three or more factors. Example: Solve x(x − 4) = 0 Either x or (x − 4) must be zero. Setting the second equal to zero gives x −4=0 x = 4 Add 4 to both sides The equation x(x − 4) = 0 has exactly two solutions. Check: x = 0: 0(0 − 4) = 0. x = 4: 4(4 − 4) = 4(0) = 0. (Math 1010) M 1010 §5.6 6/8 §5.6 Examples - Quadratic Equations Notes Solve: (A) Example 1 x 2 − x − 6 = 0 (B) Example 2 2x 2 + 5x = 12 (C) Example 3 x 2 − 2x + 16 = 6x (D) # 25 x 2 − 3x − 10 = 0 (E) #47 x(x − 5) = 36 (F) #57 (t − 2)2 = 16 (Math 1010) M 1010 §5.6 7/8 §5.6 Examples - Higher-Degree Polynomials Notes Look for common monomial factors. Look for pairs for grouping. Solve: (A) Example 5 3x 3 = 15x 2 + 18x (B) Example 6 x 4 + x 3 − 4x 2 − 4x = 0 (C) #65 x 3 − 19x 2 + 84x = 0 (D) #69 z 2 (z + 2) − 4(z + 2) = 0 (Math 1010) M 1010 §5.6 8/8 Notes