Volume 15, 2011 35 λ-CENTRAL BMO ESTIMATES FOR MULTILINEAR COMMUTATORS OF LITTLEWOOD-PALEY OPERATOR ON CENTRAL MORREY SPACES Ying Shen, Liu Lanzhe College of Mathematics Changsha University of Science and Technology Changsha, 410077 P.R.of China E-mail: lanzheliu@163.com Abstract: In this paper, we establish λ-central BMO estimates for the multilinear commutator related to the Littlewood-Paley operator in central Morrey spaces, and so does the multilinear commutator of the fractional maximal operator. Key words: λ-central space; Multilinear commutator; Littlewood-Paley operator; Central Morrey spaces. MSC 2010: 42B20, 42B35. 1. Introduction Let b ∈ BM O(Rn ) and T be the Calderón-Zygmund operator, the commutator [b, T ] generated by b and T is defined by [b, T ](f ) = bT (f ) − T (bf ). A classical result of Coifman, Rochberb and Weiss (see [2]) proved that the commutator [b, T ] is bounded on Lp (Rn ), (1 < p < ∞). Since BM O ⊂ ∩ q q q>1 CBM O (see [3]), if we only assume b ∈ CBM O , or more generally b ∈ CBM Oq,λ with q > 1, then [b, T ] may not be a bounded operator on Lp (Rn ). However, it has some boundedness properties on other spaces. As a matter of fact, Grafakos, Li and Yang (see [4]) considered the commutator with b ∈ CBM Oq on Herz spaces for the first time. Alvarez, GuzmánPartida and Lakey (see [1]) and Komori (see [6]) have obtained the λ-central BMO estimates for the commutators of a class of singular integral operators on central Morrey spaces. Motivated by these results, in this paper, we will establish λ-central BMO estimates for the multilinear commutator related to the Littlewood-Paley operator in central Morrey spaces. And the multilinear commutator of the fractional maximal operator is also discussed. 2. Preliminaries and Theorem First, let us introduce some notations. Let Mδ be the fractional maximal operator, which is ∫ δ/n−1 Mδ (f )(x) = sup |B| |f (y)|dy, 0 < δ/n < 1, (1) B∋x B 36 Bulletin of TICMI ⃗ and Mδb be the multilinear commutator of the fractional maximal operator which is defined as follows: ∫ ∏ m ⃗b δ/n−1 Mδ (f )(x) = sup |B| | (bj (x) − bj (y))f (y)|dy. (2) x∈B B j=1 For bj ∈ CBM Opj+1 ,λj+1 (Rn )(j = 1, · · · , m), set ||⃗b||CBM Op⃗,⃗λ = m ∏ ||bj ||CBM Opj+1 ,λj+1 . j=1 Given a positive integer m and 1 ≤ j ≤ m, we denote by Cjm the family of all finite subsets σ = {σ(1), · · ·, σ(j)} of {1, · · ·, m} of j different elements. For σ ∈ Cjm , set σ c = {1, · · ·, m} \ σ. For ⃗b = (b1 , · · ·, bm ) and σ = {σ(1), · · ·, σ(j)} ∈ Cjm , set ⃗bσ = (bσ(1) , · · ·, bσ(j) ), bσ = bσ(1) · · · bσ(j) and ||⃗bσ ||CBM Op⃗,⃗λ = ||bσ(1) ||CBM Op2 ,λ2 · · · ||bσ(j) ||CBM Opj+1 ,λj+1 . Definition 1. Let 0 < λ < δ/n, 0 < δ < n and 1 < q < ∞. A function f ∈ Lqloc (Rn ) is said to belong to the λ-central bounded mean oscillation space CBM Oq,λ (Rn ) if ( ||f ||CBM Oq,λ = sup r>0 1 |B(0, r)|1+λq )1/q ∫ |f (x) − fB(0,r) | dx < ∞. q (3) B(0,r) where, B = B(0, r) = {x ∈ Rn : |x| < r} and fB(0,r) is the mean value of f on B(0, r). Remark 1. If two functions which differ by a constant are regarded as a function in the space CBM Oq,λ becomes a Banach space. The space CBM Oq,λ (Rn ) when λ = 0 is just the space CBM O(Rn ) defined as follows: ( ||f ||CBM Oq = sup r>0 1 |B(0, r)| )1/q |f (x) − fB(0,r) | dx < ∞. ∫ q B(0,r) Apparently, (3) is equivalent to the following condition (see [6]): ( ||f ||CBM Oq,λ = sup inf r>0 c∈C )1/q ∫ 1 |B(0, r)|1+λq |f (x) − c| dx q < ∞. B(0,r) Definition 2. Let λ ∈ R and 1 < q < ∞. The central Morrey space Ḃ (Rn ) is defined by q,λ ( ||f ||Ḃ q,λ = sup r>0 1 |B(0, r)|1+λq ∫ )1/q < ∞. |f (x)| dx q (4) B(0,r) Remark 2. It follows from (3) and (4) that Ḃ q,λ (Rn ) is a Banach space continuously included in CBM Oq,λ (Rn ). We denote by CM Oq,λ (Rn ) and Volume 15, 2011 37 B q,λ (Rn ) the inhomogeneous versions of the λ-central bounded mean oscillation space and the central Morrey space by taking the supremum over r ≥ 1 in Definition 1 and Definition 2 instead of r > 0 there. Obviously, CBM Oq,λ (Rn ) ⊂ CM Oq,λ (Rn ) for λ < δ/n and 1 < q < ∞, and Ḃ q,λ (Rn ) ⊂ B q,λ (Rn ) for λ ∈ R and 1 < q < ∞. Remark 3. When λ1 < λ2 , it follows from the property of monotone functions that B q,λ1 (Rn ) ⊂ B q,λ2 (Rn ) and CM Oq,λ1 (Rn ) ⊂ CM Oq,λ2 (Rn ) for 1 < q < ∞. If 1 < q1 < q2 < ∞, then by Hölder’s inequality, we know that Ḃ q2 ,λ (Rn ) ⊂ Ḃ q1 ,λ (Rn ) for λ ∈ R and CBM Oq2 ,λ ⊂ CBM Oq1 ,λ , CM Oq2 ,λ (Rn ) ⊂ CM Oq1 ,λ (Rn ) for 0 < λ < δ/n. Definition 3. Let 1 ≤ q < ∞, α ∈ R. The central Campanato space is defined by(see [17]) CLα, q (Rn ) = {f ∈ Lqloc (Rn ) : ||f ||CLα, q < ∞}, where ( −α ||f ||CLα, q = sup |B(0, r)| r>0 1 |B(0, r)| )1/q |f (x) − fB(0,r) | dx . ∫ q B(0,r) Definition 4. Fix δ > 0. Let ψ be a fixed function which satisfies the following ∫ properties: (1) Rn ψ(x)dx = 0; (2)|ψ(x)| ≤ C(1 + |x|)−(n+1−δ) ; (3)|ψ(x + y) − ψ(x)| ≤ C|y|ϵ (1 + |x|)−(n+ϵ−δ) when 2|y| < |x|. n+1 We denote that Γ(x) = {(y, t) ∈ R+ : |x − y| < t} and the characteristic function of Γ(x) by χΓ(x) . The Littlewood-Paley multilinear commutator is defined by [∫ ∫ ]1/2 ⃗b ⃗b 2 dydt |Ft (f )(x, y)| n+1 Sδ (f )(x) = , (5) t Γ(x) where ⃗ Ftb (f )(x, y) ∫ = m ∏ (bj (x) − bj (z))ψt (y − z)f (z)dz, (6) Rn j=1 and ψt (x) = t−n+δ ψ(x/t) for t > 0. We also define that (∫ ∫ |f ∗ Sδ (f )(x) = Γ(x) dydt ψt (y)|2 n+1 t )1/2 , (7) which is the Littlewood-Paley operator(see ∫ ∫[16]). Let H be the space H = h : ||h|| = ( Rn+1 |h(y, t)|2 t(dydt )1/2 < ∞, then, n+1) + ⃗ Rn , Ftb (f )(x, y) for each fixed x ∈ to H, and it is clear that may be viewed as a mapping from [0, +∞) Sδ (f )(x) = ||χΓ(x) Ft (f )(x)|| 38 Bulletin of TICMI and ⃗ ⃗ Sδb (f )(x) = ||χΓ(x) Ftb (f )(x, y)||. ⃗ Note that when b1 = · · · = bm , Sδb is just the commutator of order m. It is well known that commutators are of great interest in harmonic analysis and have been widely studied by many authors(see [5][7-10][12-15]). Our main purpose is to study the boundedness properties for the multilinear commutator on central Morrey spaces. Now we state our theorems as following. Theorem 1. Let 0 < δ < n, 1 < p < n/δ, 1/q = 1/p−δ/n. If λ1 < −δ/n and λ2 = λ1 + δ/n, then Sδ is bounded from Ḃ p,λ1 (Rn ) to Ḃ q,λ2 (Rn ). Theorem 2. Let 0 < δ < n, 1 < p < n/δ, 1/q = 1/p−δ/n. If λ1 < −δ/n and λ2 = λ1 + δ/n, then Mδ is bounded from Ḃ p,λ1 (Rn ) to Ḃ q,λ2 (Rn ). Theorem 3. Let 0 < δ < n, 1 < pu < n/δ(1 ≤ u ≤ m + 1), 1/p1 + 1/p2 + · · · 1/pm+1 < 1 and 1/q = 1/p1 + 1/p2 + · · · + 1/pm+1 − δ/n. Suppose 0 < λi < δ/n(i = 2, 3, · · · , m + 1), λ1 < −λ2 − λ3 − · · · − λm+1 − δ/n and λ = λ1 + λ2 + · · · λm+1 + δ/n. If bj ∈ CBM Opj+1 ,λj+1 (Rn ), for j = 1, · · · , m, ⃗ then Sδb is bounded from Ḃ p1 ,λ1 (Rn ) to Ḃ q,λ (Rn ), and the following inequality holds: ⃗ ||Sδb (f )||Ḃ q,λ ≤ C||⃗b||CBM Op⃗,⃗λ ||f ||Ḃ p1 ,λ1 . Theorem 4. Let 0 < δ < n, 1 < pu < n/δ(1 ≤ u ≤ m + 1), 1/p1 + 1/p2 + · · · 1/pm+1 < 1 and 1/q = 1/p1 + 1/p2 + · · · + 1/pm+1 − δ/n. Suppose 0 < λi < δ/n(i = 2, 3, · · · , m + 1), λ1 < −λ2 − λ3 − · · · − λm+1 − δ/n and λ = λ1 + λ2 + · · · λm+1 + δ/n. If bj ∈ CBM Opj+1 ,λj+1 (Rn ), for j = 1, · · · , m, ⃗ then Mδb is bounded from Ḃ p1 ,λ1 (Rn ) to Ḃ q,λ (Rn ), and the following inequality holds: ⃗ ||Mδb (f )||Ḃ q,λ ≤ C||⃗b||CBM Op⃗,⃗λ ||f ||Ḃ p1 ,λ1 . 3. Proof of Theorems. To prove the theorems, we need the following lemmas. Lemma 1.(see [16]) Let 0 < δ < n, 1 < p < n/δ and 1/q = 1/p − δ/n. Then Sδ is bounded from Lp (Rn ) to Lq (Rn ). Lemma 2.(see [11]) Let 0 < δ < n, 1 < p < n/δ and 1/q = 1/p − δ/n. Then Mδ is bounded from Lp (Rn ) to Lq (Rn ). Lemma 3. Let 0 < δ < n, 1 < p < n/δ, λ > 0. Suppose b ∈ CBM Op,λ (Rn ), then |b2k+1 B − bB | ≤ C||b||CBM Op,λ k|2k+1 B|λ for k ≥ 1 . Proof. |b2k+1 B − bB | ≤ k ∑ j=0 |b2j+1 B − b2j B | ≤ k ∑ j=0 1 j |2 B| ∫ |b(y) − b2j+1 B |dy 2j B Volume 15, 2011 ≤C k ( ∑ j=0 )1/p ∫ 1 |b(y) − b2j+1 B | dy p |2j+1 B| 39 ≤ C||b||CBM Op,λ 2j+1 B ≤ C||b||CBM Op,λ (k + 1)|2 k ∑ |2j+1 B|λ j=0 k+1 B| ≤ C||b||CBM Op,λ k|2 λ k+1 λ B| . Proof of Theorem 1. Let f be a function in Ḃ p,λ1 (Rn ). For fixed r > 0, set B = B(0, r). We consider ( )1/q ∫ 1 q |Sδ (f )(x)| dx |B|1+λ2 q B ( )1/q ( )1/q ∫ ∫ 1 1 q q ≤ |Sδ (f χB )(x)| dx + |Sδ (f χB c )(x)| dx |B|1+λ2 q B |B|1+λ2 q B = I + II. For I, by the boundedness of Sδ from Lp (Rn ) to Lq (Rn ), we have )1/p (∫ −1/q−λ2 p I ≤ C|B| |f (x)| dx −1/q−λ2 B 1/p+λ1 ≤ C|B| |B| ≤ C||f ||Ḃ p,λ1 . ||f ||Ḃ p,λ1 For II, using Minkowski’s inequality, we have )1/2 (∫ ∫ ∫ t1−n Sδ (f χB c )(x) ≤ dydt dz f (z) 2(n+1−δ) Bc Γ(x) (t + |x − z|) )1/2 (∫ ∞ ∫ tdt dz ≤ f (z) (t + |x − z|)2(n+1−δ) c 0 ∫B ≤ f (z)|x − z|−n+δ dz, Bc thus, using Hölder’s inequality and note that x ∈ B, we get ∞ ∫ ∑ |Sδ (f χB c )(x)| ≤ |x − z|−n+δ |f (z)|dz k+1 B\2k B k=1 2 ∞ ∑ ≤ C k=0 ≤ C ∞ ∑ (∫ |2 B| k )1/p |f (z)| dz δ/n−1 p |2k+1 B|1−1/p 2k+1 B |2k B|δ/n−1 |2k+1 B|1/p+λ1 ||f ||Ḃ p,λ1 |2k+1 B|1−1/p k=0 ≤ C||f ||Ḃ p,λ1 |B|δ/n+λ1 , therefore, we deduce II ≤ C||f ||Ḃ p,λ1 |B|δ/n+λ1 |B|−1/q−λ2 |B|1/q ≤ C||f ||Ḃ p,λ1 . 40 Bulletin of TICMI This completes the proof of Theorem 1. Proof of Theorem 2. Set ∫ Seδ (f )(x) = |x − z|−n+δ |f (z)|dz, Rn it is easy to know the Theorem 1 is also true for the operator Seδ (f )(x). Since Mδ (f )(x) ≤ Seδ (f )(x), thus, Theorem 2 can be easily deduced. We omit the details here. Proof of Theorem 3. Let f be a function in Ḃ p1 ,λ1 (Rn ). When m = 1, ∫ set (b1 )B = |B|−1 B b1 (x)dx and note that Sδb1 (f )(x) = (b1 (x) − (b1 )B )Sδ (f )(x) − Sδ ((b1 − (b1 )B )f )(x). We have ( ( 1 |B|1+λq )1/q ∫ |Sδb1 (f )(x)|q dx B )1/q 1 q ≤ |(b1 (x) − (b1 )B )(Sδ (f χB ))(x)| dx |B|1+λq B ( )1/q ∫ 1 q + |(b1 (x) − (b1 )B )(Sδ (f χ(B)c ))(x)| dx |B|1+λq B )1/q ( ∫ 1 q |Sδ ((b1 − (b1 )B )f χB )(x)| dx + |B|1+λq B ( )1/q ∫ 1 q + |Sδ ((b1 − (b1 )B )f χ(B)c )(x)| dx |B|1+λq B = J1 + J2 + J3 + J4 . ∫ For J1 , taking 1 < p1 < n/δ and t such that 1/t = 1/p1 − δ/n, choosing 1/q = 1/p2 + 1/t, by Hölder’s inequality and the boundedness of Sδ from Lp1 (Rn ) to Lt (Rn ), we know (∫ )1/p2 (∫ )1/t −1/q−λ p2 t J1 ≤ |B| |b1 (x) − (b1 )B | dx |Sδ (f χB )(x)| B −1/q−λ ≤ C|B| −1/q−λ (∫ |B| 1/p2 +λ2 ||b1 ||CBM Op2 ,λ2 ≤ C|B| |B| ||b1 ||CBM Op2 ,λ2 |B| ≤ C||b1 ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 . 1/p2 +λ2 B )1/p1 |f (x)| dx p1 B 1/p1 +λ1 ||f ||Ḃ p1 ,λ1 For J2 , using the fact |Sδ (f χB c )(x)| ≤ C||f ||Ḃ p,λ1 |B|δ+λ1 from the proof of Theorem 1 and by Hölder’ inequality, we get (∫ )1/p2 −1/q−λ δ/n+λ1 p2 J2 ≤ C|B| |B| ||f ||Ḃ p,λ1 |b1 (x) − (b1 )B | dx |B|1/q−1/p2 B Volume 15, 2011 41 ≤ C|B|−1/q−λ |B|δ/n+λ1 ||f ||Ḃ p,λ1 |B|1/p2 +λ2 ||b1 ||CBM Op2 ,λ2 |B|1/q−1/p2 ≤ C||b1 ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 . For J3 , taking 1 < l < n/δ and q such that 1/q = 1/l − δ/n, choosing 1/l = 1/p1 + 1/p2 , by the boundedness of Sδ from Ll to Lq and Hölder’s inequality, we have (∫ )1/l −1/q−λ l J3 ≤ C|B| |(b1 (x) − (b1 )B f (x)| dx B −1/q−λ (∫ ≤ C|B| )1/p2 (∫ )1/p1 p1 |b1 (x) − (b1 )B | dx |f (x)| dx p2 B 1/p2 +λ2 −1/q−λ B ≤ C|B| |B| ||b1 ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 |B|1/p1 +λ1 ≤ C||b1 ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 . For J4 , note that x ∈ B, using Hölder’s inequality, Lemma 3, noticing that λ2 > 0 and λ1 < −λ2 − δ/n, we have |Sδ ((b1 − (b1 )B )f χ(B)c )(x)| )1/p2 (∫ ∞ ∑ p2 k δ/n−1 |b1 (z) − (b1 )B | dz ≤ C |2 B| 2k+1 B k=0 )1/p1 (∫ |f (z)|p1 dz × 2k+1 B ≤ C||f ||Ḃ p1 ,λ1 [( ∫ × ∞ ∑ |2k+1 B|1−1/p1 −1/p2 |2k B|δ/n−1 |2k+1 B|1/p1 +λ1 |2k+1 B|1−1/p1 −1/p2 k=0 |b1 (z) − (b1 )2k+1 B |p2 dz 2k+1 B ≤ C||b1 ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 ∞ ∑ )1/p2 ] k2kn(λ1 +λ2 +δ/n) |B|λ1 +λ2 +δ/n k=0 λ1 +λ2 +δ/n ≤ C||b1 ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 |B| + |(b1 )2k+1 B − (b1 )B ||2k+1 B|1/p2 , thus, we get J4 ≤ C||b1 ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 |B|λ1 +λ2 +δ/n |B|−1/q−λ |B|1/q ≤ C||b1 ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 . This completes the proof of the case m = 1. ∫ When m > 1, set ⃗bB = ((b1 )B , · · · , (bm )B ), where (bj )B = |B|−1 B |bj (x)|dx, 1 ≤ j ≤ m, we have ⃗ Ftb (f )(x, y) = m ∑ ∑ j=0 σ∈Cjm (−1)m−j (b(x) − (b)B )σ 42 Bulletin of TICMI ∫ × (b(z) − (b)B )σc ψt (y − z)f (z)dz Rn m ∏ m ∏ (bj (x) − (bj )B )Ft (f )(y) + (−1) Ft ( (bj − (bj )B ))f )(y) = m j=1 + j=1 ∫ m−1 ∑ ∑ j=1 σ∈Cjm (−1)m−j (b(x) − (b)B )σ (b(z) − b(x))σc ψt (y − z)f (z)dz Rn m m ∏ ∏ m = (bj (x) − (bj )B )Ft (f )(y) + (−1) Ft ( (bj − (bj )B ))f )(y) j=1 j=1 m−1 ∑ + ∑ ⃗ (b(x) − (b)B )σ Ftbσc (f )(x, y), j=1 σ∈Cjm thus, ⃗ ⃗ Sδb (f )(x) = ||χΓ(x) Ftb (f )(x)|| m ∏ ≤ ||χΓ(x) (bj (x) − (bj )B )Ft (f )(x)|| j=1 + m−1 ∑ ∑ ⃗ ||χΓ(x) (b(x) − (b)B )σ Ftbσc (f )(x)|| j=1 σ∈Cjm m ∏ +||χΓ(x) Ft ( (bj − (bj )B )f )(x)|| j=1 ≤ m ∏ m ∏ (bj (x) − (bj )B )Sδ (f )(x) + (−1) Sδ ( (bj − (bj )B ))B )f )(x) m j=1 + m−1 ∑ j=1 ∑ (−1)m−j (b(x) − bB )σ Sδ ((b − bB )σc f )(x). j=1 σ∈Cjm We consider ( ( ≤ 1 |B|1+λq )1/q ∫ ⃗ |Sδb (f )(x)|q dx B ∫ m ∏ )1/q 1 | (bj (x) − (bj )B )(Sδ (f χB ))(x)|q dx 1+λq |B| B j=1 ( )1/q ∫ ∏ m 1 q + | (bj (x) − (bj )B )(Sδ (f χB c ))(x)| dx |B|1+λq B j=1 ( )1/q ∫ m ∏ 1 + |Sδ ( (bj − (bj )B )f χB )(x)|q dx |B|1+λq B j=1 Volume 15, 2011 ( + 1 |B|1+λq + 1 |B|1+λq + 1 |B|1+λq ∫ 43 m ∏ |Sδ ( (bj − (bj )B )f χB c )(x)|q dx B )1/q j=1 1/q ∫ m−1 ∑ ∑ q (b(x) − bB )σ Sδ ((b − bB )σc f χB )(x) dx B j=1 σ∈Cjm 1/q ∫ m−1 q ∑ ∑ (b(x) − bB )σ Sδ ((b − bB )σc f χB c )(x) dx B j=1 σ∈Cjm = ν1 + ν2 + ν3 + ν4 + ν5 + ν6 . For ν1 , taking 1 < p1 < n/δ and t such that 1/t = 1/p1 − δ/n, choosing 1/q = 1/p2 + · · · + 1/pm+1 + 1/t, by Hölder’s inequality and the boundedness of Sδ from Lp1 (Rn ) to Lt (Rn ), we have −1/q−λ ν1 ≤ |B| m (∫ ∏ j=1 m ∏ −1/q−λ ≤ C|B| ≤ C|B|−1/q−λ j=1 m ∏ |bj (x) − (bj )B | pj+1 )1/t )1/pj+1 (∫ t |(Sδ (f χB ))(x)| dx dx B B (∫ |B| 1/pj+1 +λj+1 ||bj ||CBM Opj+1 ,λj+1 )1/p1 |f (x)| dx p1 B |B|1/pj+1 +λj+1 ||bj ||CBM Opj+1 ,λj+1 |B|1/p1 +λ1 ||f ||Ḃ p1 ,λ1 j=1 ≤ C||⃗b||CBM Op⃗,⃗λ ||f ||Ḃ p1 ,λ1 . For ν2 , using the fact |Sδ (f χ(B)c )(x)| ≤ C||f ||Ḃ p,λ1 |B|δ/n+λ1 from the proof of Theorem 1 and the Hölder’s inequality, we get )1/pi+1 m (∫ ∏ −1/q−λ pi+1 δ/n+λ1 ν2 ≤ C|B| ||f ||Ḃ p1 ,λ1 |B| |bi (x) − (bi )B | dx i=1 × |B|1/q−1/p2 −···−1/pm+1 −1/q−λ ≤ C|B| ||f ||Ḃ p1 ,λ1 |B| δ/n+λ1 m ∏ B |B|1/pi+1 +λi+1 ||bi ||CBM Opi+1 ,λi+1 i=1 1/q−1/p2 −···−1/pm+1 × |B| ≤ C||⃗b|| CBM O p⃗,⃗λ ||f ||Ḃ p1 ,λ1 . For ν3 , taking 1 < p1 < n/δ and q such that 1/q = 1/l − δ/n, choosing 1/l = 1/p1 + · · · + 1/pm+1 , by the boundedness of Sδ from Ll to Lq and Hölder’s inequality, we have (∫ )1/l m ∏ ν3 ≤ C|B|−1/q−λ | (bj (x) − (bj )B )f (x)|l dx B j=1 44 Bulletin of TICMI −1/q−λ ≤ C|B| ≤ C|B|−1/q−λ m (∫ ∏ j=1 m ∏ |bj (x) − (bj )B | pj+1 )1/pj+1 (∫ )1/p1 p1 dx |f (x)| dx B B |B|1/pj+1 +λj+1 ||bi ||CBM Opj+1 ,λj+1 |B|1/p1 +λ1 ||f ||Ḃ p1 ,λ1 j=1 ≤ C||⃗b||CBM Op⃗,⃗λ ||f ||Ḃ p1 ,λ1 . For ν4 , note that x ∈ B, by Hölder’s inequality, Lemma 3 and noticing that λj > 0(2 ≤ j ≤ m + 1), λ1 < −λ2 − · · · − λm+1 < δ/n, we have m ∏ |Sδ ( (bj − (bj )B )f χ(B)c )(x)| ≤ j=1 ∫ ∞ ∑ | 2k+1 B\2k B ≤ k=0 ∞ ∑ C m ∏ j=1 |b1 (z) − (b1 )B | dz |2 B| p2 δ/n−1 2k+1 B (∫ |bm (z) − (bm )B | ··· pm+1 (∫ 2k+1 B )1/p1 |f (z)| dz × p1 2k+1 B × ≤ )1/p2 (∫ k k=0 ≤ (bj (z) − (bj )B )||x − z|−n+δ |f (z)|dz C||f ||Ḃ p1 ,λ1 k+1 ∞ ∑ k=0 1/p2 +λ2 k|2 B| C||⃗b|| CBM O p⃗,⃗λ )1/pm+1 dz |2k+1 B|1−1/p1 −1/p2 ···−1/pm+1 |2k B|δ/n−1 |2k+1 B|1/p1 +λ1 |2k+1 B|1−1/p1 −1/p2 −···1/pm+1 ||b1 ||CBM Op2 ,λ2 · · · k|2k+1 B|1/pm+1 +λm+1 ||bm ||CBM Opm+1 ,λm+1 ||f ||Ḃ p1 ,λ1 |B|λ1 +λ2 +···+λm+1 +δ/n , thus, we obtain ν4 ≤ C||⃗b||CBM Op⃗,⃗λ ||f ||Ḃ p1 ,λ1 |B|λ1 +λ2 +···+λm+1 +δ/n |B|−1/q−λ |B|1/q ≤ C||⃗b||CBM Op⃗,⃗λ ||f ||Ḃ p1 ,λ1 . For ν5 , taking 1 < s < n/δ and t such that 1/t = 1/s − δ/n, choosing 1/q = 1/p3 + 1/t, 1/s = 1/p1 + 1/p2 , by the boundedness of Sδ from Lt to Ls and Hölder’s inequality, we have −1/q−λ ν5 ≤ C|B| (∫ × m−1 ∑ ∑ (∫ j=1 σ∈Cjm )1/p3 |(b(x) − bB )σ | dx p3 B )1/t |Sδ ((b − bB )σc f χB )(x)| dx t B Volume 15, 2011 −1/q−λ ≤ C|B| (∫ × ≤ C m−1 ∑ ∑ (∫ j=1 σ∈Cjm 45 )1/p3 |(b(x) − bB )σ | dx p3 B )1/p2 (∫ )1/p1 p1 |(b − bB )σc | dx |f (x)| dx p2 B m−1 ∑ ∑ B |B|−1/q−λ |B|1/p3 +λ3 ||⃗bσ ||CBM Op3 ,λ3 |B|1/p2 +λ2 j=1 σ∈Cjm ×||⃗bσc ||CBM Op2 ,λ2 |B|1/p1 +λ1 ||f ||Ḃ p1 ,λ1 ≤ C||⃗b||CBM Op⃗,⃗λ ||f ||Ḃ p1 ,λ1 . For ν6 , note that x ∈ B, by Hölder’s inequality , Lemma 3 and noticing that λj > 0(2 ≤ j ≤ m + 1), λ1 < −λ2 − δ/n, we have |Sδ ((b − bB )σc f χB c )(x)| (∫ )1/p2 ∞ ∑ k δ/n−1 p2 ≤ C |2 B| |(b(z) − bB )σc | dz 2k+1 B k=0 )1/p1 (∫ |f (z)| dz × p1 2k+1 B ≤ C||⃗bσc ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 |2k+1 B|1−1/p1 −1/p2 ∞ ∑ |2k B|δ/n−1 |2k+1 B|1/p1 +λ1 k m |2k+1 B|1/p2 +λ2 k=1 ×|2 k+1 B| 1−1/p1 −1/p2 ≤ C||⃗bσc ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 |B|λ1 +λ2 +δ/n , thus, we get ν6 ≤ C m−1 ∑ ∑ |B|−1/q−λ ||⃗bσc ||CBM Op2 ,λ2 ||f ||Ḃ p1 ,λ1 |B|λ1 +λ2 +δ/n j=1 σ∈Cjm (∫ × )1/p3 |(b(x) − bB )σ | dx |B|1/q−1/p3 p3 B ≤ C||⃗b||CBM Op⃗,⃗λ ||f ||Ḃ p1 ,λ1 . This completes the total proof of the Theorem 3. Proof of Theorem 4. Set ∫ m ∏ f⃗b −n+δ Sδ (f )(x) = |x − z| | (bj (x) − bj (z))f (z)|dz, Rn j=1 f⃗ it is easy to know the Theorem 3 is also true for the commutator Sδb (f )(x). Since ⃗ f⃗ Mδb (f )(x) ≤ Sδb (f )(x), 46 Bulletin of TICMI thus, Theorem 4 can be easily deduced. We omit the details here. 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