[SHIVOK SP212] February 3, 2016 CH 25 Capacitance I. Capacitance A. Figurebelowshowsthebasicelementsofanycapacitor–two isolatedconductorsofanyshapewithaninsulatingmaterial betweenthem.Theinsulatingmaterialcanbeair.Thetwoconductors nomatterwhattheirgeometryarecalledPlates. B. Whenacapacitorischarged,itsplateshavechargesofequal magnitudesbutoppositesigns:q+andq‐.However,werefertothe chargeofacapacitorasjustbeingq,theabsolutevalueofthese chargesontheplates. Page1 [SHIVOK SP212] February 3, 2016 C. ThechargeqandthepotentialdifferenceVforacapacitorare proportionaltoeachother: D. TheproportionalityconstantCiscalledthe___________________________ ofthecapacitor.Itsvaluedependsonlyonthegeometryoftheplates andnotontheirchargeorpotentialdifference. E. TheSIunitiscalledthefarad(F): II. ChargingaCapacitor A. ThecircuitshownbelowisincompletebecauseswitchSisopen; thatis,theswitchdoesnotelectricallyconnectthewiresattachedto it.Whentheswitchisclosed,electricallyconnectingthosewires,the circuitiscompleteandchargecanthenflowthroughtheswitchand thewires. B. Astheplatesbecomeoppositelycharged,thatpotentialdifference increasesuntilitequalsthepotentialdifferenceVbetweenthe terminalsofthebattery.Withtheelectricfieldzero,thereisno furtherdriveofelectrons.Thecapacitoristhensaidtobefully charged,withapotentialdifferenceVandchargeq. Page2 [SHIVOK SP212] February 3, 2016 III. CalculatingtheCapacitance A. TorelatetheelectricfieldEbetweentheplatesofacapacitorto thechargeqoneitherplate,weuseGauss’law: B. HereqisthechargeenclosedbyaGaussiansurfaceand isthenetelectricfluxthroughthatsurface.Inourspecial caseinthefigure, inwhichAistheareaofthatpartoftheGaussiansurfacethrough whichthereisaflux. C. Thepotentialdifferencebetweentheplatesofacapacitoris relatedtothefieldEby 1. IfVisthedifferenceVf‐Vi, where, Page3 [SHIVOK SP212] February 3, 2016 D. ACylindricalCapacitor(proofisinthebook) 1. Wherebistheouterplateradiusanda istheinnerplateradius. 2. Listheheight(length)ofthecylinder. E. ASphericalCapacitor(proofisinthebook) 1. Wherebistheouterradius, 2. Andaistheinnerradiusasshown. Page4 [SHIVOK SP212] February 3, 2016 F. CalculatingtheCapacitance:AnIsolatedSphere: 1. Wecanassignacapacitancetoasingleisolatedsphericalconductorof radiusRbyassumingthatthe“missingplate”isaconductingsphereofinfinite radius. 2. Thefieldlinesthatleavethesurfaceofapositivelychargedisolated conductormustendsomewhere;thewallsoftheroominwhichtheconductor ishousedcanserveeffectivelyasoursphereofinfiniteradius. 3. Tofindthecapacitanceoftheconductor,wefirstrewritethe capacitanceas: 4. Nowlettingb→∞,andsubstitutingRfora, G. SampleProblems: 1. (a)Findthecapacitanceofanair‐filledparallel‐platecapacitorwith squareplatesofedgelengths0.80cmandplateseparationd=0.30mm.(Later inthechapter,capacitorsmightbefilledwithadielectricmaterial,buthere we'lluseonlyair.) (b)Whatischargeonthiscapacitorifweconnectedittoyourcar battery(12V)? Page5 [SHIVOK SP212] February 3, 2016 2. Theplatesofasphericalcapacitorhaveradii r1 38.0 mm and r2 40.0 mm . a) Calculatethecapacitance. b) Whatmustbetheplateareaofaparallel‐platecapacitorwiththe sameplateseparationandcapacitance? Page6 [SHIVOK SP212] February 3, 2016 IV. CapacitorsinParallel A. WhenapotentialdifferenceVisappliedacrossseveralcapacitors connectedinparallel,thatpotentialdifferenceVisappliedacross eachcapacitor.Thetotalchargeqstoredonthecapacitorsisthesum ofthechargesstoredonallthecapacitors. B. Capacitorsconnectedinparallelcanbereplacedwithan equivalentcapacitorthathasthesametotalchargeqandthesame potentialdifferenceVastheactualcapacitors. Page7 [SHIVOK SP212] February 3, 2016 V. CapacitorsinSeries A. WhenapotentialdifferenceVisappliedacrossseveralcapacitors connectedinseries,thecapacitorshaveidenticalchargeq.Thesumof thepotentialdifferencesacrossallthecapacitorsisequaltothe appliedpotentialdifferenceV. B. Capacitorsthatareconnectedinseriescanbereplacedwithan equivalentcapacitorthathasthesamechargeqandthesametotal potentialdifferenceVastheactualseriescapacitors. Page8 [SHIVOK SP212] February 3, 2016 VI. CapacitorsinParallelandinSeries A. Sampleproblems: 1. FindtheequivalentCapacitanceforthebelowcircuitassumingall capacitorsare12µF. 2. FindVoltageonCapacitorC2iftheBatteryisa12voltscarbattery. 3. FindchargeonC1 Page9 [SHIVOK SP212] February 3, 2016 B. Inthecircuitshown,whatisthevoltagefeltacrossthe9.0μF capacitorandthechargeonthe3.0 μFcapacitor? 9µF 5µF 150.0 V Show all work: Page 10 [SHIVOK SP212] February 3, 2016 VII. EnergyStoredinanElectricField: A. Thepotentialenergyofachargedcapacitormaybeviewedas beingstoredintheElectricFieldbetweenitsplates. B. Supposethat,atagiveninstant,achargeq’hasbeentransferred fromoneplateofacapacitortotheother.ThepotentialdifferenceV’ betweentheplatesatthatinstantwillbeq’/C.Ifanextraincrementof chargedq’isthentransferred,theincrementofworkrequiredwillbe, C. Theworkrequiredtobringthetotalcapacitorchargeuptoafinal valueqis D. ThisworkisstoredaspotentialenergyUinthecapacitor,sothat, E. Thiscanalsobeexpressedas: Page 11 [SHIVOK SP212] February 3, 2016 VIII. EnergyDensity: A. Inaparallel‐platecapacitor,neglectingfringing,theelectricfield hasthesamevalueatallpointsbetweentheplates.Thus,theenergy densityu—thatis,thepotentialenergyperunitvolumebetweenthe plates—shouldalsobeuniform. B. Wecanfindubydividingthetotalpotentialenergybythevolume Adofthespacebetweentheplates. 1. Butsince(C= A/d),thisresultbecomes 0 C. However,(E=‐V/s),V/dequalstheelectricfieldmagnitudeE. Therefore. Page 12 [SHIVOK SP212] February 3, 2016 IX. EnergySampleproblem: A. Theparallelplatesinacapacitor,withaplateareaof8.50cm2and anair‐filledseparationof3.00mm,arechargedbya6.00Vbattery. Theyarethendisconnectedfromthebatteryandpulledapart (withoutdischarge)toaseparationof8.00mm.Neglectingfringing, find(a)thepotentialdifferencebetweentheplates,(b)theinitial storedenergy,(c)thefinalstoredenergy,and(d)theworkrequired toseparatetheplates. Page 13 [SHIVOK SP212] February 3, 2016 X. CapacitorwithaDielectric: A. Adielectric,isaninsulatingmaterialsuchasmineraloilorplastic, andischaracterizedbyanumericalfactor,calledthedielectric constantofthematerial. 1. Somedielectrics,suchasstrontiumtitanate,canincreasethe capacitancebymorethantwoordersofmagnitude. B. Inaregioncompletelyfilledbyadielectricmaterialofdielectric constant,allelectrostaticequationscontainingpermittivity constante0aretobemodifiedbyreplacinge0withe0 C. Theintroductionofadielectricalsolimitsthepotentialdifference thatcanbeappliedbetweentheplatestoacertainvalueVmax,called thebreakdownpotential.Everydielectricmaterialhasacharacteristic dielectricstrength,whichisthemaximumvalueoftheelectricfield thatitcantoleratewithoutbreakdown. Page 14 [SHIVOK SP212] February 3, 2016 D. SampleproblemswithDielectric 1. Aparallel‐platecapacitorhastwosquaremetalplates.Thesidesof eachplateare3.0cmlongandtheplatesareseparatedby5.0mm.Thespace betweentheplatesisfilledwithTeflon,whichhasadielectricconstant= 2.1. Thecapacitanceofthiscapacitorisclosestto: A. 1.6 pF B. 33 pF C. 14 pF D. 2.1 pF E. 3.3 pF Show all work: Page 15 [SHIVOK SP212] February 3, 2016 2. InFig.below,howmuchchargeisstoredontheparallel‐plate capacitorsbythe12.0Vbattery?Oneisfilledwithair,andtheotherisfilled withadielectricforwhichκ=3.00;bothcapacitorshaveaplateareaof 5.00×10‐3m2andaplateseparationof2.00mm. Show all work: Page 16