Hindawi Publishing Corporation Journal of Inequalities and Applications Volume 2009, Article ID 852897, 10 pages doi:10.1155/2009/852897 Research Article Rate of Convergence of a New Type Kantorovich Variant of Bleimann-Butzer-Hahn Operators Lingju Chen1 and Xiao-Ming Zeng2 1 2 Department of Mathematics, Minjiang University, Fuzhou 350108, China Department of Mathematics, Xiamen University, Xiamen 361005, China Correspondence should be addressed to Lingju Chen, lingjuchen@126.com and Xiao-Ming Zeng, xmzeng@xmu.edu.cn Received 28 September 2009; Accepted 16 November 2009 Recommended by Vijay Gupta A new type Kantorovich variant of Bleimann-Butzer-Hahn operator Jn is introduced. Furthermore, the approximation properties of the operators Jn are studied. An estimate on the rate of convergence of the operators Jn for functions of bounded variation is obtained. Copyright q 2009 L. Chen and X.-M. Zeng. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. 1. Introduction In 1980, Bleimann et al. 1 introduced a sequence of positive linear Bernstein-type operators Ln abbreviated in the following by BBH operators defined on the infinite interval I 0, ∞ by n n k 1 k x Ln f, x f , n1−k 1 xn k0 k x ∈ I, n ∈ N, 1.1 where N denotes the set of natural numbers. Bleimann et al. 1 proved that Ln f, x → fx as n → ∞ for f ∈ Cb I the space of all bounded continuous functions on I and give an estimate on the rate of convergence of Ln f, x → fx measured with the second modulus of continuity of f. In the present paper, we introduce a new type of Kantorovich variant of BBH operator Jn , also defined on I by Jn f, x n n k0 k k px 1 − px n−k ftdt , dt Ik Ik 1.2 2 Journal of Inequalities and Applications where px x/1 x x ≥ 0, Ik k/n 2 − k, k 1/n 1 − k, and dt is Lebesgue measure. The operator 1.2 is different from another type of Kantorovich variant of BBH operator Kn : k1/n1−k n n ft n2 xk Kn f, x dt, n 1 x k0 k 1 t2 k/n2−k 1.3 which was first considered by Abel and Ivan in 2. The integrand function ft/1 t2 in the operator 1.3 has been replaced with new integrand function ft in the operator 1.2. In this paper we will study the approximation properties of Jn for the functions of bounded variation. The rate of convergence for functions of bounded variation was investigated by many authors such as Bojanić and Vuilleumier 3, Chêng 4, Guo and Khan 5, Zeng and Piriou 6, Gupta et al. 7, involving several different operators. Throughout this paper the class of function Φ is defined as follows: Φ f | f is of bounded variation on every finite subinterval of I 0, ∞ . 1.4 Our main result can be stated as follows. Theorem 1.1. Letf ∈ Φ and let Vab f be the total variation of f on interval a, b. Then, for n sufficiently large, one has 2 n √ 1 xx/ k Jn f, x − fx − fx− ≤ 51√ x fx − fx− 91 x √ V gx O , 2 nx k1 x−x/ k n 2 nx 1.5 where ⎧ ⎪ ft − fx, ⎪ ⎪ ⎨ gx t 0, ⎪ ⎪ ⎪ ⎩ ft − fx−, x < t < ∞, x t, 1.6 0 ≤ t < x. 2. Some Lemmas In order to prove Theorem 1.1, we need the following lemmas for preparation. Lemma 2.1 is the well-known Berry-Esséen bound for the classical central limit theorem of probability theory. Its proof and further discussion can be founded in Feller 8, page 515. Lemma 2.1. Let {ξ}∞ i1 be a sequence of independent and identically distributed random variables. And 0 < Dξ1 < ∞, β3 E|ξ1 − Eξ1 |3 < ∞, then, there holds y n c β3 1 1 −t2 /2 maxP e dt < √ , 2.1 ξk − a1 ≤ y − √ √ y∈R n b1 3 b1 n k1 2π −∞ √ where a1 Eξ1 , b1 2 Dξ1 Eξ1 − Eξ1 2 , 1/ 2π ≤ c ≤ 0.82. Journal of Inequalities and Applications 3 In addition, let {ξ}ni1 be the random variables with two-point distribution Pξ i ⎧ ⎨x, ξi 1 2.2 ⎩1 − x, ξ 0, i where i 1, 2, . . . , n. Then we can easily obtain that Let ηn β3 E|ξ1 − Eξ1 |3 ≤ x1 − x 2x2 − 2x 1 . b1 2 Dξ1 x1 − x, a1 Eξ1 x, n i1 ξi , 2.3 then we also have P ηn k n k xk 1 − xn−k , k 0, 1, . . . , n. 2.4 On the other hand, Jn f, x can be written by following integral form: n x I ftdt ∞ k pn,k ftHn x, tdt, Jn f, x 1x dt 0 k0 Ik 2.5 where n x 1 , χk t pn,k Hn x, t 1 x dt k0 I χk t k ⎧ ⎨1, t ∈ Ik , ⎩0, t/ ∈ Ik , Ik k/n2−k, k1/n1−k, k 0, 1, 2, . . . , n. It is easy to verify that 2.6 ∞ 0 Hn x, udu 1. Lemma 2.2. If x ∈ 0, ∞ is fixed and n is sufficiently large, then a for 0 ≤ y < x, there holds y 0 2x1 x2 2 n 1 , x−y 2.7 2x1 x2 . z − x2 n 1 2.8 Hn x, tdt ≤ 1 b for x < z < ∞, there holds ∞ Hn x, tdt ≤ z 1 Proof. We first prove a. Since 0 ≤ y < x, t ∈ 0, y, then x − t/x − y ≥ 1. Hence, we have y 0 Hn x, tdt ≤ y 1 x − t2 2 2 Hn x, tdt ≤ 2 Jn x − t , x . 0 x−y x−y 2.9 4 Journal of Inequalities and Applications Direct calculation gives x1 x2 1 x4 1 x4 4x 1 o n−4 . Jn x − t2 , x n1 3n 1n 2 3n 1n 2n 3 Hence 2.10 y Hn x, tdt ≤ 1/x − y2 2x1 x2 /n 1, for n sufficiently large. The proof of b is similar. 0 Lemma 2.3 see 9, Theorem 1 or, cf. 10. For every x ∈ 0, 1, there holds pn,k x Cnk xk 1 − xn−k ≤ 1 2enx1 − x . 2.11 3. Proof of Theorem 1.1 Let f ∈ Φ, and x ∈ I, Bojanic-Cheng decomposition yields ft fx − fx− fx − fx− fx − fx− gx t sgnt − x δx t fx − , 2 2 2 3.1 where gx t is defined as in 1.6 and δx t ⎧ ⎨1, t x, ⎩0, t/ x. 3.2 Obviously, Jn δx t, x 0. Thus it follows from 3.1 that Jn f, x − fx − fx− ≤ Jn gx , x Jn sgnt − x, x fx − fx− . 2 2 3.3 First of all, we estimate |Jn sgnt − x, x| Jn sgnt − x, x n n 1 − kn 2 − k k0 n2 where Ik k/n 2 − k, k 1/n 1 − k. x pn,k sgnt − xdt, 1 x Ik 3.4 Journal of Inequalities and Applications 5 Assuming that x ∈ k /n 2 − k , k 1/n 1 − k , for some k 0 ≤ k ≤ n, then we have Jn sgnt − x, x pn,k k/n2−k>x x x − pn,k x1 x1 k1/n1−k<x k 1/n1−k x n 1 − k n 2 − k pn,k n2 1x 1−2 k/n2−k≤x 2 pn,k dt − x x k /n2−k dt x x1 k 1/n1−k x n 1 − k n 2 − k pn,k n2 1x dt. x 3.5 Thus x x 2pn,k Jn sgnt − x, x ≤ 1 − 2 . p n,k x 1 1x k/n2−k≤x 3.6 By Lemma 2.3 combining some direct computations, we can easily obtain 2pn,k x 2 1x ≤ ≤ √ . 1x nx 2enx/1 x · 1/1 x Set y x/1 x < 1, then by 2.4 and using Lemma 2.1, we have x 1 − 2 pn,k x 1 k/n2−k≤x 1 1 − 2 pn,k y 2 − P ηn ≤ n 2y 2 k≤n2y ⎛ ⎞ 1 2y ⎜ ηn − ny ⎟ 2 − P ⎝ ≤ ⎠ 2 ny 1 − y ny 1 − y ⎛ ⎞ 2y−1/√ny1−y 2y 1 2 ⎟ ⎜ ηn − ny 2P ⎝ e−t /2 dt ≤ ⎠ − √2π −∞ ny 1 − y ny 1 − y 1 √ 2π 2y−1/√ny1−y 0 2 e−t /2 dt 3.7 6 Journal of Inequalities and Applications ⎛ ⎞ 2y−1/√ny1−y η − ny 2y 1 2 n ⎟ ⎜ −t /2 ≤ e dt ≤ 2P ⎝ − √ ⎠ 2π −∞ ny 1 − y ny 1 − y 2 √ 2π 2y/√ny1−y e−t /2 dt 2 0 2y/√ny1−y 2cβ3 2 2 e−t /2 dt ≤√ 3√ 2π 0 nb1 2 × 0.82 × y 1 − y 2y2 − 2y 1 2y 2 ≤ √ 2π ny 1 − y y 1 − y ny 1 − y ≤ 4 41 x √nx . ny 1 − y 3.8 Thus, by 3.7, 3.8 we have x 1 x 51 x Jn sgnt − x, x ≤ 41 √ √ . √ nx nx nx 3.9 Finally, we estimate Jn gx , x. First, interval I 0, ∞ can be decomposed into four parts as x D1 0, x − √ , n x x D2 x − √ , x √ , n n x D3 x √ , 2x , n D4 2x, ∞. 3.10 So Jn gx , x can be divided into four parts J n gx , x ∞ gx tHn x, tdt Δ1,n gx Δ2,n gx Δ3,n gx Δ4,n gx , 3.11 0 where Δj,n gx Dj gx tHn x, tdt. Noticing gx x 0 and for t ∈ D2 , we have gx t gx t − gx x. Thus Δ2,n gx ≤ xx/√n n √ √ gx t − gx xHn x, tdt ≤ V xx/√ n gx ≤ 1 V xx/√ k gx . x−x/ n √ n k1 x−x/ k x−x/ n t √ Next, let y x − x/ n, λn x, t 0 Hn x, udu. 3.12 Journal of Inequalities and Applications 7 Now, we recall the Lebesgue-Stieltjes integral representation, and by using partial Lebesgue-Stieltjes integration, we get y Δ1,n gx gx tdt λn x, t 0 y gx y λn x, y − λn x, tdt gx t 0 y gx y − gx x λn x, y − λn x, tdt gx t − gx x ≤ Vyx gx λn x, y y 0 3.13 0 λn x, tdt −Vtx gx . An application of a in Lemma 2.2 yields 2 2x1 x2 Δ1,n gx ≤ Vyx gx 2x1 x 2 n 1 x − y n 1 y 0 1 2 x − t dt −Vtx gx . 3.14 Furthermore, since y 0 1 x − t d −Vtx 2 t gx y x −Vyx gx V0x gx Vt gx 2 dt, 2 2 3 x 0 x − t x−y 3.15 we have x−x/√n x Vt gx 2x1 x2 V0x gx Δ1,n gx ≤ 2 dt . n1 x2 x − t3 0 3.16 √ Putting t x − x/ u in the last integral, we have x−x/√n x n Vt gx 1 n x 1 x √ gx . dt Vx−x/√u gx du ≤ 2 Vx−x/ 2 3 2 k x 1 x k1 x − t 0 3.17 It follows from 3.16 and 3.17 that 2 Δ1,n gx ≤ 2x1 x n 1x2 V0x gx n k1 x √ Vx−x/ k gx ≤ n 41 x2 x √ gx . Vx−x/ k n 1x k1 3.18 8 Journal of Inequalities and Applications By a similar method and using Lemma 2.2b, we obtain 2 n √ Δ3,n gx ≤ 81 x Vxxx/ k gx . n 1x k1 3.19 Now, the remainder of our work is to estimate Δ4,n gx . For fx satisfying the growth condition ft 0tr for some positive integer r as t → ∞, we obviously have Δ4,n gx ≤ x pn,k 1x k/n2−k>2x dt g Ik x t . dt Ik 3.20 Thus, for n sufficiently large, there exists a M > 0, such that the following inequalities hold: x I tr dt k pn,k 1 x dt k/n2−k>2x Ik r Ik t dt M pn,k y dt k/n2−k>2y/1−y Ik Δ4,n gx ≤ M ≤M pn,k y k/n2−k>2y/1−y k1 n1−k 3.21 r , where y x/1 x. By the definition of the Stirling numbers Sr, s of the second kind, we readily have ar r Sr, saa − 1 · · · a − s 1, r ∈ N, 3.22 s1 where the Stirling numbers Sr, s satisfy Sn, 0 ⎧ ⎨1 n 0, ⎩0 n ∈ N. 3.23 Thus we can write k/n2−k>2y/1−y k1 n1−k r r pn,k y Sr, sAs , s1 3.24 Journal of Inequalities and Applications 9 where As k 1k · · · k − s 2 pn,k y r n 1 − k k/n2−k>2y/1−y n−k 1 n!k 1 . yk 1 − y r · − s 1!n − k! k 1 − k n k/n2−k>2y/1−y 3.25 From k/n 2 − k > 2x, x/1 x y, we can easily find k > 2n 4y/1 y. For a fixed x > 0, when n > 2r r/x, we have k 1/k 1 − s < 2. Thus there holds n−k 1 n! yk 1 − y . r · n 1 − k k − s!n − k! k>2n4y/1y As ≤ 2 3.26 Now using the similar method as that in the proof of Lemma 4 of 11, we deduce that r−s2 24r!n!ys−1 1 y As ≤ , n r − s!n r − s 2 for n > 2r r . x 3.27 From 3.21, 3.24, and 3.27, we obtain Δ4,n gx ≤ M pn,k y k/n2−k>2y/1−y k1 n1−k r 1 . M Sr, sAs O n s1 r 3.28 Finally, by combining 3.12, 3.18, 3.19, and 3.28, we deduce that Jn gx t, x ≤ Δ1,n gx Δ2,n gx Δ3,n gx Δ4,n gx n n √ 1 xx/√k 81 x2 41 x2 1 x xx/ k √ √ ≤ V V gx Vx−x/ k gx gx O n n n 1x k1 x−x/ k n 1x k1 x ≤ n √ 1 xx/√k 81 x2 1 xx/ k √ Vx−x/√k gx Vx−x/ g O x k n n n 1x k1 ≤ n √ 1 91 x2 xx/ k √ . Vx−x/ g O x k nx k1 n Theorem 1.1 now follows from 3.3, 3.9, and 3.29. 3.29 10 Journal of Inequalities and Applications Acknowledgments This work is supported by the National Natural Science Foundation of China and the Fujian Provincial Science Foundation of China. 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