J. of Inequal. & Appl., 1997, Vol. 1, pp. 301-310 Reprints available directly from the publisher Photocopying permitted by license only (C) 1997 OPA (Overseas Publishers Association) Amsterdam B.V. Published in The Netherlands under license by Gordon and Breach Science Publishers Printed in Malaysia Discrete Inequalities of Wirtinger’s Type for Higher Differences GRADIMIR V. MILOVANOVI and IGOR :. MILOVANOVI_, Faculty of Electronic Engineering, Department of Mathematics, P. O. Box 73, 18001 Ni, Yugoslavia e-mail: grade @ gauss.elfak.ni.ac, yu (Received 28 July 1996) Discrete version of Wirtinger’s type inequality for higher differences, An,m x k= where lm [m/2], Um n 2< (Amxk)2 nn,m x k= k=Im [m/2] and mmxk (--1) Xk+m_i i=0 is considered. Under some conditions, the best constants An,m and Bn,m e deteined. Keywords: Discrete inequality; difference of higher order; eigenvalue; eigenvector. AMS 1991 Subject classifications: Primary 26D 15; Secondary 41 A44. 1 INTRODUCTION AND PRELIMINARIES In 1 (see also [2]) we presented a general method for finding the best possible constants An and Bn in inequalities of the form An px <_ k=l rlc(xlk=0 < px, Bn (1.1) k=l This work was supported in part by the Serbian Scientific Foundation, grant number 04M03. 301 G.V. MILOVANOVI( and I.. MILOVANOVI( 302 where p (pk) and r (rk) are given weight sequences and e (x) is an arbitrary sequence of the real numbers. The basic discrete inequalities of the 1 were given by K. Fan, O. Taussky, and J. Todd form (1.1) for p r [3]. Here, we mention some references in this direction [4-8]. The first results for the second difference were proved by Fan, Taussky and Todd [3]: THEOREM 1.1 numbers, then - If XO(-" 0), n-1 (Xk 2Xk+l Xk+2) 2 >__ k=0 THEOREI 1.2 XO Xl, Xn+ If XO, Xl Xn, Xn+l are n 7 16 sin4 A sin with equality in (1.2) if and only if x A is an arbitrary constant. ("- O) are given real Xn, Xn+l XI,X2 2(n + 1) kTr (1.2) k=l n, where 1 2, k n+l x:,2 given real numbers such that Xn and n x (1.3) 0, k=l then (Xk 2Xk+l + Xk+2 >_ 16 sin4 k=0 nn x:. (1.4) k=l The equality in (1.4) is attained if and only if xk A cos (2k 2n k-- 1,2 n, where A is an arbitrary constant. A converse inequality of (1.2) was proved by Lunter [9], Yin [10] and Chen [11] (see also Agarwal [8]). /f X0(= 0), Xl,X2 Xn, xn+l n-1 (x 2x+ + x+e) e _< 16cos4 k=0 with equality in (1.5) if and only if x: Chen [11 also proved the following result: n zr 2(n + 1) A(-1) sin where A is an arbitrary constant. (= 0) are given real kr n-I- 1 i" k 2 xc’ 1 2 (1.5) n, DISCRETE INEQUALITIES OF WIRTINGER’S TYPE THEOREM 1.4 /f xo x and Xn+ Xn, Xn/ X0, Xl 303 are given real numbers such that then Xn, n-1 n 2X+l -F x+2) 2 <_ 16cos4 (x k=O n x, k=l with equality holding if and only if x A(-1) sin (2k- 1)re 1,2,... ,n, k where A is an arbitrary constant. In this case, the n n symmetric matrix corresponding to the quadratic form n-1 F2 __,(Xk 2Xk+l + Xk+2) 2 (Hn,2, ,) k=O 2 -3 1 1 6 -4 -3 6 -4 1 -4 1 "’. "’. "’. "’. "’. 6 -4 1 -4 1 6 -3 1 -4 2_ 1 -3 n matrix This matrix is the square of the n 1 -1 1 2 -1 -1 2 -1 -1 (1.6) 2 -1 -1 1 The eigenvalues of Hn are .v v(Hn) 4cos 2 (n v + 1)zr 2n v=l and therefore, the largest eigenvalue of Hn is )n(Hn) 4cos 2 nn > ,kn-1 (Hn). n, G.V. MILOVANOVI( and I.;. MILOVANOVI0 304 The corresponding eigenvector is a n (-1) sin Xn (2v 1 v--- 1,2 2n where Xnn Xln X2n n. Thus, the largest eigenvalue of Hn,2 is n(Hn,2)-- 16cos4 nn > ,n-l(Hn,2), and the associated eigenvector is x n Notice that the minimal eigenvalue of the matrix Hn (and also Hn,2) is 0. Therefore, the condition (1.3) must be included in Theorem 1.2 (see X Agarwal [8, Ch. 11]) and the best constant is the square of the relevant eigenvalue re (n- 1)re 4 sin 2 2 4 COS 2 2n 2n For any n-dimensional vector a [xl x2 Xn ]r, Pfeffer [12] introduced a periodically extended n-vector by setting Xi+rn xi for n and r 6 N, and used the rnth difference of a given by 1, 2 (m) Amxn ]T, where Amxl Amx2 m (--1) m-r Amxi r---O () r l<i<n, Xi-[m/2]+r, in order to prove the following result: THEOREM 1.5 If a is a periodically extended n-vector and (1.3) holds, then (X(rn) x(rn)) > with equality case (4sin 2 if and only if a is the periodic extension of a vector of the form Clu + Czv, where U Ul Un U2 T and vk sin v Vl 132 k 1 Vn ]T have the following components uk cos 2krc , g/ 2krc , n and C1 and C2 are arbitrary real constants. n, DISCRETE INEQUALITIES OF WIRTINGER’S TYPE 305 2 MAIN RESULTS In this paper we consider inequalities of the form xk2 An,m k= where Im 1 (Amxk) 2 < Bn,m < [m/2] and n (--1) AmXk (2.1) k= k--Im [m/2], Um 2 xk, Xk+m-i. i=0 /m (AmXk) 2 for m The quadratic form Fm x Vl n-I n-1 2xkxk+l 2x + xn2 -Jr- 1 reduces to k=l k=2 with corresponding tridiagonal symmetric matrix Itn Hn, given by (1.6). We consider inequalities (2.1) under conditions Xs Xl-s, Xn+l-s and define Xn+s (lm < S < 0) (2.2) AJxl-[j/2] AJ x2-[j/2] x (j) (2.3) AJXn-[j/2] The quadratic form Fm can be expressed then in the following form Um Fm_ Fro(x,)_ (Amxk) 2 ((m), x,(m)), where (0) Xl x2 Xn At the begining we prove three auxiliary results: (2.4) G.V. MILOVANOVI( and I.. MILOVANOVI( 306 LEMMA 2.1 If j is an even integer, under conditions (2.2), we have that AJ+lx-[j/2] Proof Let q 0 or q A J+ Xq-[j/2] A2p+lxq-p zxJ+lxn-[j/2] and 0 O. (2.5) 2p we have n. Putting j 2p+l +1 E (-1)i (2p \ , i=0 Xq+p+l-i 2p+l ,(_i x//_i + i=0 P E(--1) (2p+l) Xq+p+l-i E(--1) i--0 2p + 1 x//_ Xq-p+i i=0 E(_I)i i=0 t (- i=p+l ( +) 2p 1 (Xq+p+ l_i Xq-p+i 0 because of the conditions (2.2). LEMMA 2.2 If j is an even integer, under conditions (2.2), we have that _x(j+2), Hnx(j) where the matrix Hn is given by (1.6). Proof We have AJ xI_[j/2] A j x2-[j/2] --AJ+2xI_[j/2 Un x (J) (2.6) AJ+2xn 2 -[j/2] A J Xn- 1-[j/2] "1- A J Xn-[j/2] Since AJ+2x_[j/2] AJ+lxl_[j/2] AJ+lx_[j/2] and AJ+2xn_l_[j/2] AJ+lxn_[j/2] AJ+lxn_l_[j/2], DISCRETE INEQUALITIES OF WIRTINGER’S TYPE 307 because of Lemma 2.1, we conclude that AJ+2x_[j/2]- AJ+IxI_[j/2] and AJ+2xn_l_[j/2] -"--AJ+lxn_l_[j/2], respectively. Therefore, AJ xI-[j/2] AJ x2-[j/2] AJ+lxl [j/2] _AJ +2x-[j/2] and --AJ Xn-l-[j/2] + Aj xn-[j/2] AJ+I Xn-l-[j/2] AJ+2xn -1-[j/2]. Then (2.6) becomes AJ+2xI-[(j+2)/2] AJ+2x2-[(j+2)/2] AJ+2x_[j/2 AJ+2xl_[j/2] _x(J+2). Hnx(J) A j +2x n_ 1-[(j +2)/21 A]+2xn-2-[j/2] AJ+2Xn-l-[j/2] AJ+2xn-[(j+2)/2] LEMMA 2.3 If j is an even integer, under conditions (2.2), we have that (x(j), x(j+2)) _((j+l), (j+l)). Proof Let j is an even integer. Using (2.3) we have n (X (j) X (j+2)) E Ajxk-[j/2] AJ+2xk -1-[j/21 k=l E AJxk-[J/z](AJxk-l-[j/2] E AJxk-[j/2](AJxk+l-[j/2] 2AJxk-[j/2] + AJXk+l-[j/2]) k=l n AJxk-[j/2]) k=l }2 k=l AJ Xk-[j/2]AJ+lxk-[j/2] k=l n E Ajxk-[j/2lAj+lxk-[j/2l k=l E Aj Xk-[j/2]AJ+l E AJxk+l-[j/2lAJ+lxk-[j/2]" Xk-l-[j/2] k=l n-1 k=O G.V. MILOVANOVI( and I.. MILOVANOVI( 308 Because of (2.5) we can write (X (j), x(J+2))-- -AJxk-[j/2]AJ+" 1Xk_[j/2] AJxk+I_[j/2]A j+l Xk-[j/2] k=l k=l n 2 1Xk-[j k=l Since j is an even integer we have that (Aj + lxk-[(j+l)/2] )2 (x(j) x(j+2)) _(x(J+I), x(J+l)). k--1 Now, we give the main result: THEOREM 2.4 If Xl, X2 Xn are given real numbers and conditions (2.2) are satisfied, then n bl (AmXk) 2 <_ 4m COS 2m k=lm where lm 1 if and only if [m/2] and Um A(-1) sin Xk (2.7) Xk’ k=l n (2k [m/2]. The equality in (2.7) is attained 1)re k-- 1,2 n, where A is an arbitrary constant. Proof We will prove that the corresponding matrix of the quadratic form (2.4) is exactly the mth power of the matrix Hn Hn,1 so that the best constant in the right inequality (2.1), i.e., (2.7), is given by Bn,m Evidently, An,m 4m cs2m 7g 2n O. Let m be an even integer. Then, using Lemma 2.2, we find Fm (x,(m), x, (m)) (Un3(m-2), Unx,(m-2)), DISCRETE INEQUALITIES OF WIRTINGER’S TYPE 309 <>, Hnm/’ <>) em Similarly, for an odd m, using Lemmas 2.3 and 2.4, we obtain Frn (x (m), x(m)) _((m--1), (m+l)) ((m-1), nn(m-1)). Now, using Lemma 2.2 again, we find (nn(m-1)/2x (0), nn(m+l)/2 (0)) (anm, ). Frn By restriction (1.3), we can obtain the following result: TI-IEORM 2.5 If xl, X2 Xn are given real numbers and conditions (2.2) and (1.3) are satisfied, then 4m sinZm where lm 1 if and only if 7z" 2-- [m/2] and Um xk Acos 2 [m /2]. The equality in (2.8) is attained 1)Tr (2k 2n (2.8) k--Im k=l n (Amxl) 2 < k 1,2 n, where A is an arbitrary constant. 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