Hindawi Publishing Corporation Journal of Applied Mathematics Volume 2013, Article ID 683205, 11 pages http://dx.doi.org/10.1155/2013/683205 Research Article A Novel Characteristic Expanded Mixed Method for Reaction-Convection-Diffusion Problems Yang Liu, Hong Li, Wei Gao, Siriguleng He, and Zhichao Fang School of Mathematical Sciences, Inner Mongolia University, Hohhot 010021, China Correspondence should be addressed to Yang Liu; mathliuyang@yahoo.cn and Hong Li; smslh@imu.edu.cn Received 3 November 2012; Revised 24 February 2013; Accepted 10 March 2013 Academic Editor: Alexander Timokha Copyright © 2013 Yang Liu et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. A novel characteristic expanded mixed finite element method is proposed and analyzed for reaction-convection-diffusion problems. The diffusion term ∇ ⋅ (π(x, π‘)∇π’) is discretized by the novel expanded mixed method, whose gradient belongs to the square integrable space instead of the classical H(div; Ω) space and the hyperbolic part π(x)(ππ’/ππ‘) + c(x, π‘) ⋅ ∇π’ is handled by the characteristic method. For a priori error estimates, some important lemmas based on the novel expanded mixed projection are introduced. The fully discrete error estimates based on backward Euler scheme are obtained. Moreover, the optimal a priori error estimates in πΏ2 - and π»1 -norms for the scalar unknown π’ and a priori error estimates in (πΏ2 )2 -norm for its gradient π and its flux π (the coefficients times the negative gradient) are derived. Finally, a numerical example is provided to verify our theoretical results. and the bounded vector c(x, π‘) = (π1 (x, π‘), π2 (x, π‘)) satisfies 1. Introduction In this paper, we consider the following reaction-convectiondiffusion problems: π (x) ππ’ + c (x, π‘) ⋅ ∇π’ − ∇ ⋅ (π (x, π‘) ∇π’) + π (x, π‘) π’ ππ‘ = π (x, π‘) , (x, π‘) ∈ Ω × π½, π’ (x, π‘) = 0, (1) (x, π‘) ∈ πΩ × π½, π’ (x, 0) = π’0 (x) , x ∈ Ω, where Ω is a bounded convex polygonal domain in R2 with πΏπππ πβππ‘π§ continuous boundary πΩ and π½ = (0, π] is the time interval with 0 < π < ∞. The initial value π’0 (x) and the source term π(x, π‘) are given functions. Throughout this paper, we assume that the accumulation, diffusion, and reaction coefficients, π = π(x), π = π(x, π‘), and π = π (x, π‘), satisfy H1 : 0 < π0 ≤ π (x) ≤ π1 < +∞, H2 : 0 < π0 ≤ π (x, π‘) ≤ π1 < +∞, H3 : 0 ≤ π 0 ≤ π (x, π‘) ≤ π 1 < +∞, σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ππ‘ (x, π‘)σ΅¨σ΅¨σ΅¨ ≤ π1 , σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨π π‘ (x, π‘)σ΅¨σ΅¨σ΅¨ ≤ π 1 , (2) H4 : 0 < π0 ≤ 2 ( ∑ ππ2 π=1 1/2 (x, π‘)) ≤ π1 < +∞. (3) Reaction-convection-diffusion equations are a class of important evolution partial differential equations and have a lot of applications in many physical problems, such as the infiltration of liquid, the proliferation of gas, the conduction of heat, and the spread of impurities in semiconductor materials. In recent years, a lot of numerical methods, such as mixed finite element methods [1–3], Pod methods [4, 5], characteristic-mixed covolume methods [6], spacetime discontinuous Galerkin methods [7, 8], least-squares finite element methods [9, 10], nonconforming finite element method [11], conforming rectangular element method [12], and two-grid expanded mixed methods [13–16], have been studied for reaction-convection-diffusion equations. In 1994, Chen [17, 18] proposed an expanded mixed finite element method for second-order linear elliptic equation. Compared to standard mixed element methods, the expanded mixed method can approximate three variables simultaneously, namely, the scalar unknown, its gradient, and its flux (the tensor coefficient times the negative gradient). From then on, the expanded mixed method was applied 2 Journal of Applied Mathematics to many evolution equations [2, 19, 20], and some new numerical methods based on the Chen’s expanded mixed method were proposed, for example, expanded mixed covolume method [21], expanded mixed hybrid methods [22], positive definite expanded mixed method [23], and so on. From the above literature on the study of expanded mixed method, we can find that all papers were studied based on Chen’s expanded mixed method [17, 18]. In 2011, we developed a new expanded mixed finite element method [24] based on the mixed weak formulations [25–27]. In this paper, we develop and analyze a novel characteristic expanded mixed finite element method, which combines the novel expanded mixed method [24] applied to approximating the diffusion term and the characteristic method that handled the hyperbolic part, for reactionconvection-diffusion equations. The gradient for our method belongs to the square integrable space instead of the classical H(div; Ω) space of Chen’s expanded mixed method. We derive a priori error estimates based on backward Euler method. Moreover, we prove the optimal a priori error estimates in πΏ2 - and π»1 -norms for the scalar unknown π’ and a priori error estimates in (πΏ2 )2 -norm for its gradient π and its flux π (the coefficients times the negative gradient). Throughout this paper, πΆ will denote a generic positive constant which does not depend on the spatial mesh parameter β and time discretization parameter Δπ‘. At the same time, we denote the natural inner product in πΏ2 (Ω) or (πΏ2 (Ω))2 by (⋅, ⋅) with the corresponding norm β ⋅ β. The other notations and definitions of Sobolev spaces as in [28] are used. 2. Novel Characteristic Expanded Mixed System Introducing the two auxiliary variables π = ∇π’, π = −(π(x, π‘)∇π’) = −(π(x, π‘)π), we obtain the following first-order system for (1): π ππ’ + c ⋅ ∇π’ + ∇ ⋅ π + π π’ = π (x, π‘) , ππ‘ π − ∇π’ = 0, (4) Using the similar method to the one in [29], the expanded mixed weak formulation for problem (1) is to find {π’, π, π} : [0, π] σ³¨→ π × V × X such that (π ππ’ , V) + (∇ ⋅ π, V) + (π π’, V) = (π, V) , ππ (π, w) + (π’, ∇ ⋅ w) = 0, (π, z) + (ππ, z) = 0, π (x) π c (x) π = ⋅ ∇, + ππ (x) π (x, π‘) ππ‘ π (x, π‘) (π where π(x, π‘) = (π2 (x) + |c(x, π‘)|2 )1/2 . Then the first-order system (4) can be rewritten as π π + ππ = 0. (7c) (π, w) − (∇π’, w) = 0, (π, z) + (ππ, z) = 0, ∀V ∈ π»01 , 2 ∀w ∈ (πΏ2 (Ω)) , 2 ∀z ∈ (πΏ2 (Ω)) . (8a) (8b) (8c) For approximating the solution at time π‘π = πΔπ‘, the characteristic derivative will be approximated by xΜπ = x − Δπ‘ π (x, π‘π ) , π (x) (9) and then we have the following approximation: π (x, π‘π ) π’ (x, π‘π ) − π’ (Μxπ , π‘π−1 ) ππ’ σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ ≈ π (x, π‘π ) ππ σ΅¨σ΅¨π‘π √(x − xΜπ )2 + (Δπ‘)2 (10) π’ (x, π‘π ) − π’ (Μxπ , π‘π−1 ) . Δπ‘ Let (πβ , Wβ ) ⊂ (π»01 , (πΏ2 (Ω))2 ) be defined by the following finite element pair π1 − π02 [25, 26]: πβ = {Vβ ∈ πΆ0 (Ω) ∩ π»01 | Vβ ∈ π1 (πΎ) , ∀πΎ ∈ Kβ } , Wβ ππ’ + ∇ ⋅ π + π π’ = π (x, π‘) , ππ π − ∇π’ = 0, (7b) ∀z ∈ X, ππ’ , V) − (π, ∇V) + (π π’, V) = (π, V) , ππ = π (x) (5) ∀w ∈ V, (7a) where π = πΏ2 (Ω) or π = {π€ ∈ πΏ2 (Ω)|π€|πΩ = 0}, V = H(div; Ω) = {v ∈ (πΏ2 (Ω))2 | ∇⋅v ∈ πΏ2 (Ω)}, and X = (πΏ2 (Ω))2 . In this paper, we propose and discuss a novel characteristic expanded mixed method. The new characteristic expanded mixed weak formulation is to find {π’, π, π} : [0, π] σ³¨→ π»01 × (πΏ2 (Ω))2 × (πΏ2 (Ω))2 such that π + ππ = 0. Let the characteristic direction corresponding to the hyperbolic part πππ’/ππ‘ + c ⋅ ∇π’ be denoted by π = π(x), which is subject to ∀V ∈ π, 2 = {wβ = (π€1β , π€2β ) ∈ (πΏ2 (Ω)) | π€1β , π€2β ∈ π0 (πΎ) , (6) ∀πΎ ∈ Kβ } . (11) Journal of Applied Mathematics 3 Now the novel characteristic expanded mixed finite element procedure for (8a), (8b), and (8c) is to find {π’βπ , ππβ , πβπ } : [0, π] σ³¨→ πβ × Wβ × Wβ satisfying (π Μ π−1 π’βπ − π’ β , Vβ ) − (πβπ , ∇Vβ ) + (π π’βπ , Vβ ) Δπ‘ π = (π , Vβ ) , Lemma 5 (see [24]). There is a constant πΆ independent of β such that σ΅©σ΅© σ΅©σ΅© 2 σ΅©σ΅©πσ΅©σ΅© ≤ πΆβ βπ’βπ»2 , σ΅©σ΅© σ΅©σ΅© 2σ΅© σ΅© σ΅©σ΅©ππ‘ σ΅©σ΅© ≤ πΆβ σ΅©σ΅©σ΅©π’π‘ σ΅©σ΅©σ΅©π»2 , (12a) σ΅©σ΅© σ΅©σ΅© σ΅©σ΅©πσ΅©σ΅©1 ≤ πΆβ (βπ’βπ»2 + βπβ(π»1 (Ω))2 ) . ∀Vβ ∈ πβ , (ππβ , wβ ) − (∇π’βπ , wβ ) = 0, ∀wβ ∈ Wβ , (12b) (πβπ , zβ ) + (ππ ππβ , zβ ) = 0, ∀zβ ∈ Wβ , (12c) Μ π−1 where π’βπ = π’β (π‘π ), π’ β (Δπ‘/π(x))π(x, π‘π ), π‘π−1 ). = π’β (Μxπ , π‘π−1 ) = π’β (x − Remark 1. From [25, 26], we find that (πβ , Wβ ) satisfies the so-called discrete Ladyzhenskaya-Babuska-Brezzi condition. Remark 2. Compared to the scheme (7a), (7b), and (7c) based on Chen’s expanded mixed element method, the gradient in the scheme (8a), (8b), and (8c) belongs to the simple square integrable space instead of the classical H(div; Ω) space. For H(div; Ω) ⊂ (πΏ2 (Ω))2 , we easily find that our method reduces the regularity requirement on the gradient solution π = ∇π’. Remark 3. Based on finite element space (πβ , Wβ ) in (11), the number of total degrees of freedom for our scheme ((12a), (12b), and (12c)) is less than that for the scheme in [29]. By the same discussion as Remark 1 in [30], we can obtain the detailed analysis for degrees of freedom. 3. Some Lemmas and Error Estimates 3.1. Novel Expanded Mixed Projection and Lemmas. We first introduce the novel expanded mixed elliptic projection [24] associated with our equations to derive a priori error estimates for the proposed method. Μ ,π Let (Μ π’β , π β Μ β ) : [0, π] → πβ × Wβ × Wβ be given by the following mixed relations: Μ β , ∇Vβ ) = 0, (π − π ∀Vβ ∈ πβ , (13a) Μ , w ) − (∇ (π’ − π’ Μ β ) , wβ ) = 0, (π − π β β ∀wβ ∈ Wβ , (13b) Μ ) , z ) = 0, Μ β , zβ ) + (π (π − π (π − π β β ∀zβ ∈ Wβ . (13c) In the following discussion, we will give some important lemmas based on the novel expanded mixed projection. Lemma 4 (see [24]). There is a constant πΆ independent of β such that βπΏβ ≤ πΆβ (βπβ(π»1 (Ω))2 + βπ’βπ»2 ) , σ΅©σ΅© σ΅©σ΅© σ΅©σ΅©πσ΅©σ΅© ≤ πΆβ (βπ’βπ»2 + βπβ(π»1 (Ω))2 + βπβ(π»1 (Ω))2 ) , σ΅©σ΅© σ΅©σ΅© σ΅©σ΅©∇πσ΅©σ΅© ≤ πΆβ (βπ’βπ»2 + βπβ(π»1 (Ω))2 ) , Μ , and π = π − π Μβ. Μβ , πΏ = π − π where π = π’ − π’ β (14) (15) (16) (17) Lemma 6 (see [6]). For each π one has (πΜV, ΜV) − (πV, V) ≤ πΆΔπ‘ (πV, V) , ∀V ∈ πΏ2 (Ω) , (18) where ΜV = V(x − c(x, π‘π )Δπ‘/π(x)). Remark 7. For proving Lemmas 4 and 5, we introduce two linear operators [25, 26] Πβ : (πΏ2 (Ω))2 → Wβ and πβ : π»01 (Ω) → πβ and consider the following auxiliary elliptic problem: −∇ ⋅ (π∇π) = π, π = 0, in Ω, (19) on πΩ. The detailed proofs for Lemmas 4 and 5 are shown in [24]. 3.2. A Priori Error Estimates. In the following discussion, we will derive a priori error estimates based on fully discrete backward Euler method. Let 0 = π‘0 < π‘1 < π‘2 < ⋅ ⋅ ⋅ < π‘π = π be a given partition of the time interval [0, π] with step length Δπ‘ = π/π and nodes π‘π = πΔπ‘, for some positive integer π. For a smooth function π on [0, π], define ππ = π(π‘π ). In order to derive a priori error estimates, we now write Μ πβ ) + (Μ π’πβ − π’βπ ) = ππ + ππ , π’ (π‘π ) − π’βπ = (π’ (π‘π ) − π’ Μ π ) + (π Μ π − ππ ) = πΏπ + ππ , π (π‘π ) − ππβ = (π (π‘π ) − π β β β (20) Μ πβ ) + (Μ ππβ − πβπ ) = ππ + ππ . π (π‘π ) − πβπ = (π (π‘π ) − π Combining (8a), (8b), and (8c), (12a), (12b), and (12c) and (13a), (13b), and (13c) at π‘ = π‘π , we get the error equations (π ππ − Μππ−1 , Vβ ) − (ππ , ∇Vβ ) + (π ππ , Vβ ) Δπ‘ = (ππ Μ π−1 ππ’π π’π − π’ −π , Vβ ) ππ Δπ‘ − (π ππ − πΜπ−1 , Vβ ) − (π ππ , Vβ ) , Δπ‘ ∀Vβ ∈ πβ , (21a) (ππ , wβ ) − (∇ππ , wβ ) = 0, ∀wβ ∈ Wβ , (21b) (ππ , zβ ) + (ππ ππ , zβ ) = 0, ∀zβ ∈ Wβ . (21c) Based on the error equations (21a), (21b), and (21c), we obtain the following theorem for the fully discrete error estimates. 4 Journal of Applied Mathematics Μ β (0); then there exist some Theorem 8. Assume that π’β0 = π’ positive constants independent of β = π(Δπ‘) such that σ΅© σ΅¨σ΅© σ΅©σ΅¨ σ΅©σ΅© σ΅©σ΅©π’ (π‘π½ ) − π’βπ½ σ΅©σ΅©σ΅© ≤ πΆ (π0 , π1 ) σ΅¨σ΅¨σ΅¨σ΅©σ΅©σ΅©π (β2 , Δπ‘)σ΅©σ΅©σ΅©σ΅¨σ΅¨σ΅¨ σ΅© σ΅¨σ΅© σ΅©σ΅¨ σ΅© σ΅©σ΅© 1/2 π σ΅©σ΅©2 σ΅©σ΅© 1/2 π−1 σ΅©σ΅©2 σ΅©σ΅©π π σ΅©σ΅© − σ΅©σ΅©π Μπ σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© + π σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅©2 + σ΅©σ΅©σ΅©σ΅©(π π )1/2 ππ σ΅©σ΅©σ΅©σ΅©2 0σ΅© σ΅© σ΅©σ΅© σ΅©σ΅© 2Δπ‘ σ΅©σ΅© 1/2 π σ΅©σ΅©2 σ΅©σ΅© 1/2 π−1 σ΅©σ΅©2 σ΅©σ΅© 1/2 π π−1 σ΅©σ΅©2 σ΅©σ΅©π π σ΅©σ΅© − σ΅©σ΅©π Μπ σ΅©σ΅© + σ΅©σ΅©π (π − Μπ )σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© ≤σ΅© 2Δπ‘ σ΅©σ΅© 1/2 σ΅© 1/2 σ΅© σ΅©2 σ΅©σ΅© σ΅©2 + σ΅©σ΅©σ΅©(ππ ) ππ σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) ππ σ΅©σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© + πΆ (π0 , π1 , π 1 ) β2 βπ’βπΏ∞ (π»2 ) , σ΅©σ΅© σ΅© σ΅¨σ΅© σ΅©σ΅¨ σ΅©σ΅©π’ (π‘π½ ) − π’βπ½ σ΅©σ΅©σ΅© ≤ πΆ (π0 , π1 ) σ΅¨σ΅¨σ΅¨σ΅©σ΅©σ΅©π (β1 , Δπ‘)σ΅©σ΅©σ΅©σ΅¨σ΅¨σ΅¨ σ΅© σ΅©1 σ΅¨σ΅© σ΅©σ΅¨ + β [πΆ (π0 , π1 , π 1 ) βπ’βπΏ∞ (π»2 ) + πΆβπβπΏ∞ ((π»1 )2 ) ] , σ΅©σ΅© σ΅© σ΅¨σ΅© σ΅©σ΅¨ σ΅©σ΅©π (π‘π½ ) − ππ½β σ΅©σ΅©σ΅© ≤ πΆ (π0 , π1 , π 1 ) σ΅¨σ΅¨σ΅¨σ΅©σ΅©σ΅©π (β1 , Δπ‘)σ΅©σ΅©σ΅©σ΅¨σ΅¨σ΅¨ σ΅© σ΅© σ΅¨σ΅© σ΅©σ΅¨ Noting that −πΜππ−1 ππ /Δπ‘ = (||π1/2 (ππ −Μππ−1 )||2 −(||π1/2Μππ−1 ||2 + ||π1/2 ππ ||2 ))/2Δπ‘, (24) may be written as = (ππ (22) + β [πΆ (π0 , π1 , π 1 , π 1 ) βπ’βπΏ∞ (π»2 ) σ΅©σ΅© σ΅© σ΅¨σ΅© σ΅©σ΅¨ σ΅©σ΅©π (π‘π½ ) − πβπ½ σ΅©σ΅©σ΅© ≤ πΆ (π0 , π1 , π 1 ) σ΅¨σ΅¨σ΅¨σ΅©σ΅©σ΅©π (β1 , Δπ‘)σ΅©σ΅©σ΅©σ΅¨σ΅¨σ΅¨ σ΅© σ΅© σ΅¨σ΅© σ΅©σ΅¨ (ππ + πΆ (π0 , π1 , π 1 , π 1 ) βπ’βπΏ∞ (π»2 ) ] , where |βπ(β2−π , Δπ‘)β| = β2−π (||π’||πΏ∞ (π»2 ) + ||π’π‘ ||πΏ2 (π»2 ) ) + Δπ‘||π’π‘π‘ ||πΏ2 (πΏ2 ) , π = 0, 1. Proof. Set Vβ = ππ in (21a), wβ = ππ in (21b), and zβ = ππ in (21c) to obtain ππ − Μππ−1 π , π ) − (ππ , ∇ππ ) + (π π ππ , ππ ) Δπ‘ = (ππ Μ π−1 π ππ’π π’π − π’ −π ,π ) ππ Δπ‘ − (π (23a) ππ − πΜπ−1 π , π ) − (π π ππ , ππ ) , Δπ‘ (∇ππ , ππ ) − (ππ , ππ ) = 0, (23b) σ΅©σ΅© 1/2 σ΅© σ΅©2 (ππ , ππ ) + σ΅©σ΅©σ΅©(ππ ) ππ σ΅©σ΅©σ΅© = 0. σ΅© σ΅© (23c) Μ π−1 π ππ’π π’π − π’ −π ,π ) ππ Δπ‘ − (π π π−1 π − πΜ Δπ‘ , ππ ) − (π π ππ , ππ ) . = (ππ Μ π−1 π ππ’π π’π − π’ −π ,π ) ππ Δπ‘ − (π ππ − ππ−1 + ππ−1 − πΜπ−1 π , π ) − (π π ππ , ππ ) Δπ‘ σ΅©σ΅© σ΅© σ΅© σ΅© Μ π−1 σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ − ππ−1 σ΅©σ΅©σ΅© π’π − π’ σ΅© ππ’π σ΅©σ΅© + σ΅©σ΅©π σ΅©σ΅© ≤ (σ΅©σ΅©σ΅©σ΅©ππ −π Δπ‘ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© Δπ‘ σ΅©σ΅©σ΅© σ΅©σ΅© ππ σ΅©σ΅© π−1 Μπ−1 σ΅©σ΅© σ΅© π − π σ΅©σ΅© σ΅©σ΅© π π σ΅©σ΅© σ΅©σ΅© π σ΅©σ΅© σ΅©σ΅© + σ΅©σ΅©π π σ΅©σ΅©) σ΅©σ΅©π σ΅©σ΅© + σ΅©σ΅©σ΅©σ΅©π σ΅©σ΅© Δπ‘ σ΅©σ΅© σ΅© σ΅©2 π‘π σ΅© 1 π‘π σ΅©σ΅©σ΅©σ΅© ππ σ΅©σ΅©σ΅©σ΅©2 σ΅©σ΅© π2 π’ σ΅©σ΅© σ΅© σ΅©2 ≤ πΆ (π1 ) [Δπ‘ ∫ σ΅©σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅©σ΅© ππ + ∫ σ΅©σ΅© σ΅©σ΅© ππ + σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅© ] σ΅© σ΅© ππ Δπ‘ ππ σ΅© π‘π−1 σ΅© π‘ σ΅© σ΅© π−1 σ΅© σ΅© σ΅©σ΅© π−1 Μπ−1 σ΅©σ΅© σ΅©2 σ΅© π − π σ΅©σ΅©σ΅© σ΅©σ΅© π σ΅©σ΅© σ΅© + σ΅©σ΅©σ΅©π π ππ σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©σ΅©π σ΅©σ΅©σ΅© σ΅©σ΅©π σ΅©σ΅© . Δπ‘ σ΅©σ΅© σ΅© (26) σ΅©σ΅© π−1 Μπ−1 σ΅©σ΅© β + Δπ‘ σ΅©σ΅© π−1 σ΅©σ΅© σ΅©σ΅© π σ΅©σ΅© σ΅©σ΅© π − π σ΅©σ΅© σ΅©σ΅© π σ΅©σ΅© σ΅©σ΅©π σ΅©σ΅© σ΅©σ΅©π σ΅©σ΅© ≤ πΆ ( ) σ΅©σ΅©σ΅©π σ΅©σ΅©σ΅© σ΅©σ΅©π σ΅©σ΅© σ΅©σ΅© σ΅© Δπ‘ Δπ‘ σ΅©σ΅© σ΅© π σ΅© σ΅©2 ≤ πΆ (π0 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) + 0 βπβ2 . 2 σ΅©σ΅© ππ − Μππ−1 π 1/2 σ΅© 1/2 σ΅© σ΅©2 σ΅©σ΅© σ΅©2 , π ) + σ΅©σ΅©σ΅©(ππ ) ππ σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) ππ σ΅©σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© Δπ‘ = (ππ ππ − πΜπ−1 π Μ π−1 π ππ’π π’π − π’ −π , π ) − (π , π ) − (π π ππ , ππ ) ππ Δπ‘ Δπ‘ Using the assumption β = π(Δπ‘), we obtain Adding the above three equations, we obtain (π ππ − πΜπ−1 π , π ) − (π π ππ , ππ ) . Δπ‘ Using the same analysis as that in [31], the right-hand side of (25) can be rewritten as + β [πΆ (βπβπΏ∞ ((π»1 )2 ) + βπβπΏ∞ ((π»1 )2 ) ) (π Μ π−1 π ππ’π π’π − π’ −π ,π ) ππ Δπ‘ − (π + πΆβπβπΏ∞ ((π»1 )2 ) ] , (25) (24) (27) By Lemma 6, we have σ΅©σ΅© 1/2 π−1 σ΅©σ΅©2 σ΅©σ΅© 1/2 π−1 σ΅©σ΅©2 σ΅©2 σ΅© σ΅©σ΅©π π σ΅©σ΅© − σ΅©σ΅©π Μπ σ΅©σ΅© ≥ −πΆΔπ‘σ΅©σ΅©σ΅©π1/2 ππ−1 σ΅©σ΅©σ΅© . σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© (28) Journal of Applied Mathematics 5 Choose wβ = ππ in (32), Vβ = (ππ − ππ−1 )/Δπ‘ in (21a), and zβ = (ππ − ππ−1 )/Δπ‘ in (21c) to obtain Using (28), we obtain σ΅©σ΅© 1/2 π σ΅©σ΅©2 σ΅©σ΅© 1/2 π−1 σ΅©σ΅©2 σ΅©σ΅©π π σ΅©σ΅© − σ΅©σ΅©π Μπ σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© + π σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅©2 + σ΅©σ΅©σ΅©σ΅©(π π )1/2 ππ σ΅©σ΅©σ΅©σ΅©2 0σ΅© σ΅© σ΅©σ΅© σ΅©σ΅© 2Δπ‘ σ΅©σ΅© 1/2 π σ΅©σ΅©2 σ΅©2 σ΅© σ΅©σ΅©π π σ΅©σ΅© − (1 + πΆΔπ‘) σ΅©σ΅©σ΅©π1/2 ππ−1 σ΅©σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© ≥ 2Δπ‘ 1/2 σ΅© σ΅©2 σ΅© σ΅©2 σ΅©σ΅© + π0 σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) ππ σ΅©σ΅©σ΅© σ΅© σ΅© σ΅©σ΅© 1/2 π σ΅©σ΅©2 σ΅©σ΅© 1/2 π−1 σ΅©σ΅©2 σ΅©2 σ΅© σ΅©σ΅©π π σ΅©σ΅© − σ΅©σ΅©π π σ΅©σ΅© − πΆΔπ‘σ΅©σ΅©σ΅©π1/2 ππ−1 σ΅©σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© = 2Δπ‘ 1/2 σ΅© σ΅©2 σ΅© σ΅©2 σ΅©σ΅© + π0 σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) ππ σ΅©σ΅©σ΅© . σ΅© σ΅© (π ∇ππ − ∇ππ−1 ππ − Μππ−1 ππ − ππ−1 , ) − (ππ , ) Δπ‘ Δπ‘ Δπ‘ = (ππ Multiplying by 2Δπ‘, summing (29) from π = 1 to π½, and using (25)–(29), the resulting inequality becomes ( π½ σ΅© σ΅©2 1/2 σ΅© σ΅©2 σ΅© σ΅©2 σ΅©σ΅© π0 σ΅©σ΅©σ΅©σ΅©ππ½ σ΅©σ΅©σ΅©σ΅© + Δπ‘ ∑ (π0 σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) ππ σ΅©σ΅©σ΅© ) σ΅© σ΅© π=1 π½ σ΅© σ΅©2 σ΅© σ΅©2 + πΆ (π0 , π1 , π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) + πΆ (π1 ) Δπ‘ ∑ σ΅©σ΅©σ΅©σ΅©ππ−1 σ΅©σ΅©σ΅©σ΅© σ΅© σ΅©2 = π1 σ΅©σ΅©σ΅©σ΅©π0 σ΅©σ΅©σ΅©σ΅© + πΆ (π0 , π1 ) π‘π½ σ΅© π‘π½ σ΅© σ΅©σ΅© π2 π’ σ΅©σ΅©σ΅©2 σ΅©σ΅© ππ σ΅©σ΅©σ΅©2 × [(Δπ‘)2 ∫ σ΅©σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅©σ΅© ππ + ∫ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ ] π‘0 σ΅© π‘0 σ΅© σ΅© ππ σ΅©σ΅© σ΅© ππ σ΅©σ΅© (33b) ππ − ππ−1 ππ − ππ−1 ) + (ππ ππ , ) = 0. Δπ‘ Δπ‘ (33c) Adding the three equations and using Cauchy-Schwarz inequality and Young inequality, we obtain (π ππ − Μππ−1 ππ − ππ−1 ππ − ππ−1 , ) + (ππ ππ , ) Δπ‘ Δπ‘ Δπ‘ + (π π ππ , π½ σ΅© σ΅©2 σ΅© σ΅©2 + πΆ (π0 , π1 , π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) + πΆ (π1 ) Δπ‘ ∑ σ΅©σ΅©σ΅©σ΅©ππ−1 σ΅©σ΅©σ΅©σ΅© . = (ππ π=1 (30) π½ σ΅© σ΅©2 1/2 σ΅© σ΅©2 σ΅© σ΅©2 σ΅©σ΅© π0 σ΅©σ΅©σ΅©σ΅©ππ½ σ΅©σ΅©σ΅©σ΅© + Δπ‘ ∑ (π0 σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) ππ σ΅©σ΅©σ΅© ) σ΅© σ΅© π=1 π‘π½ σ΅© π‘π½ σ΅© σ΅©σ΅© π2 π’ σ΅©σ΅©σ΅©2 σ΅©σ΅© ππ σ΅©σ΅©σ΅©2 (31) ≤ πΆ (π0 , π1 ) [(Δπ‘)2 ∫ σ΅©σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅©σ΅© ππ + ∫ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ ] σ΅© σ΅© ππ ππ σ΅© π‘0 σ΅© π‘ σ΅© σ΅© 0 σ΅© σ΅© σ΅© σ΅©2 + πΆ (π0 , π1 , π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) . ππ − ππ−1 ) Δπ‘ Μ π−1 ππ − ππ−1 ππ’π π’π − π’ −π , ) ππ Δπ‘ Δπ‘ − (π Using Gronwall lemma, we have ππ − πΜπ−1 ππ − ππ−1 ππ − ππ−1 , ) − (π π ππ , ) Δπ‘ Δπ‘ Δπ‘ σ΅©σ΅© σ΅© σ΅© σ΅© Μ π−1 σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ − ππ−1 σ΅©σ΅©σ΅© π’π − π’ σ΅© ππ’π σ΅©σ΅© + σ΅©σ΅©π σ΅©σ΅© ≤ ( σ΅©σ΅©σ΅©σ΅©ππ −π Δπ‘ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© Δπ‘ σ΅©σ΅©σ΅© σ΅©σ΅© ππ σ΅©σ΅© π−1 Μπ−1 σ΅©σ΅© σ΅© σ΅© σ΅© π − π σ΅©σ΅© σ΅©σ΅© π π σ΅©σ΅© σ΅©σ΅©σ΅© ππ − ππ−1 σ΅©σ΅©σ΅© σ΅©σ΅© + σ΅©σ΅©π π σ΅©σ΅©) σ΅©σ΅© σ΅© + σ΅©σ΅©σ΅©σ΅©π σ΅©σ΅© Δπ‘ σ΅©σ΅©σ΅© σ΅©σ΅© Δπ‘ σ΅©σ΅© σ΅© σ΅© σ΅© σ΅©σ΅© 2 σ΅©σ΅©2 πΆ (π1 ) π‘π σ΅©σ΅©σ΅©σ΅© ππ σ΅©σ΅©σ΅©σ΅©2 σ΅©σ΅© π π’ σ΅©σ΅© σ΅©σ΅© 2 σ΅©σ΅© ππ + ∫ σ΅©σ΅© σ΅©σ΅© ππ σ΅© ππ σ΅©σ΅© Δπ‘ π‘π−1 σ΅© π‘π−1 σ΅© σ΅© ππ σ΅©σ΅© σ΅© σ΅© π‘π ≤ πΆ (π1 ) Δπ‘ ∫ From (21b), we get ππ − ππ−1 ∇ππ − ∇ππ−1 , wβ ) − ( , wβ ) = 0. Δπ‘ Δπ‘ ππ − πΜπ−1 ππ − ππ−1 ππ − ππ−1 , ) − (π π ππ , ), Δπ‘ Δπ‘ Δπ‘ (33a) ππ − ππ−1 π ∇ππ − ∇ππ−1 π ,π ) − ( , π ) = 0, Δπ‘ Δπ‘ (ππ , π=1 ( Μ π−1 ππ − ππ−1 ππ’π π’π − π’ −π , ) ππ Δπ‘ Δπ‘ − (π σ΅© σ΅©2 ≤ π1 σ΅©σ΅©σ΅©σ΅©π0 σ΅©σ΅©σ΅©σ΅© + πΆ (π0 , π1 ) π½ π‘π σ΅© σ΅©σ΅© π2 π’ σ΅©σ΅©σ΅©2 1 π‘π σ΅©σ΅©σ΅©σ΅© ππ σ΅©σ΅©σ΅©σ΅©2 × [Δπ‘ ∑ (Δπ‘ ∫ σ΅©σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅©σ΅© ππ + ∫ σ΅© σ΅© ππ )] Δπ‘ π‘π−1 σ΅©σ΅©σ΅© ππ σ΅©σ΅©σ΅© π‘π−1 σ΅© σ΅© ππ σ΅©σ΅© π=1 ππ − ππ−1 ) Δπ‘ + (π π ππ , (29) (32) σ΅© σ΅©2 + πΆ (π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) + σ΅© σ΅©2 1 σ΅©σ΅©σ΅© ππ − ππ−1 σ΅©σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© . 2 σ΅©σ΅©σ΅© Δπ‘ σ΅©σ΅©σ΅© (34) 6 Journal of Applied Mathematics Summing (36) from π = 1 to π½, the resulting inequality becomes The left-hand side of (34) can be written as (π ππ − Μππ−1 ππ − ππ−1 ππ − ππ−1 , ) + (ππ ππ , ) Δπ‘ Δπ‘ Δπ‘ + (π π ππ , π π −π Δπ‘ π−1 σ΅©2 π½ σ΅© σ΅©σ΅© ππ − ππ−1 σ΅©σ΅©σ΅© σ΅©σ΅© Δπ‘ ∑ σ΅©σ΅©σ΅©σ΅©π1/2 Δπ‘ σ΅©σ΅©σ΅© σ΅© π = 1σ΅© ) σ΅©2 σ΅©σ΅© ππ − ππ−1 σ΅©σ΅©σ΅© ππ−1 − Μππ−1 ππ − ππ−1 σ΅© σ΅©σ΅© + (π , ) = σ΅©σ΅©σ΅©σ΅©π1/2 Δπ‘ σ΅©σ΅©σ΅© Δπ‘ Δπ‘ σ΅©σ΅© σ΅©σ΅© π 1/2 π σ΅©2 σ΅©σ΅©(π ) (π − ππ−1 )σ΅©σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© + 2Δπ‘ σ΅©σ΅© π 1/2 π σ΅©σ΅©2 σ΅©σ΅©σ΅© π−1 1/2 π−1 σ΅©σ΅©σ΅©2 σ΅©σ΅©(π ) π σ΅©σ΅© − σ΅©σ΅©(π ) π σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© + 2Δπ‘ σ΅©σ΅© π 1/2 π π−1 σ΅©σ΅©2 σ΅©σ΅©(π ) (π − π )σ΅©σ΅© σ΅© σ΅©σ΅© ππ − ππ−1 π−1 π−1 −( π ,π ) + σ΅© 2Δπ‘ 2Δπ‘ π½ σ΅©σ΅© σ΅©σ΅©2 σ΅©σ΅© σ΅©σ΅©2 1/2 1/2 + ∑ (σ΅©σ΅©σ΅©(ππ ) (ππ − ππ−1 )σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) (ππ − ππ−1 )σ΅©σ΅©σ΅© ) σ΅© σ΅© σ΅© σ΅© π=1 σ΅©σ΅© 1/2 σ΅© 1/2 σ΅© σ΅©2 σ΅©σ΅© σ΅©2 + σ΅©σ΅©σ΅©σ΅©(ππ½ ) ππ½ σ΅©σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©σ΅©(π π½ ) ππ½ σ΅©σ΅©σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© π‘π½ σ΅© σ΅©σ΅© π2 π’ σ΅©σ΅©σ΅©2 σ΅©σ΅© 1/2 σ΅© σ΅©2 ≤ σ΅©σ΅©σ΅©σ΅©(π0 ) π0 σ΅©σ΅©σ΅©σ΅© + πΆ (π1 ) ((Δπ‘)2 ∫ σ΅©σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅©σ΅© ππ σ΅© σ΅© π‘0 σ΅© σ΅© ππ σ΅©σ΅© π‘π½ σ΅© σ΅©σ΅© ππ σ΅©σ΅©σ΅©2 + ∫ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ ) π‘0 σ΅© σ΅© ππ σ΅©σ΅© π½−1 σ΅© σ΅©2 σ΅© σ΅©2 + πΆ (π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) + πΆ (π1 ) Δπ‘ ∑ σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅© σ΅©σ΅© π 1/2 π σ΅©σ΅©2 σ΅©σ΅©σ΅© π−1 1/2 π−1 σ΅©σ΅©σ΅©2 σ΅©σ΅©(π ) π σ΅©σ΅© − σ΅©σ΅©(π ) π σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© + 2Δπ‘ −( π=0 π½−1 σ΅© σ΅©2 + πΆ (π 1 ) Δπ‘ ∑ σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅© π π − π π−1 π−1 π−1 π ,π ). 2Δπ‘ π=0 π½ (35) − Δπ‘ ∑ (π π=1 Substitute (35) into (34) and multiply by 2Δπ‘ to get (37) σ΅©σ΅© σ΅©2 σ΅©2 ππ − ππ−1 σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© π 1/2 π σ΅© σ΅©σ΅© + σ΅©σ΅©(π ) (π − ππ−1 )σ΅©σ΅©σ΅©σ΅© Δπ‘σ΅©σ΅©σ΅©σ΅©π1/2 σ΅© σ΅© σ΅© Δπ‘ σ΅©σ΅© σ΅©σ΅© σ΅©σ΅©2 1/2 σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) (ππ − ππ−1 )σ΅©σ΅©σ΅© σ΅© σ΅© σ΅©σ΅©2 σ΅©σ΅© 1/2 1/2 σ΅© σ΅©2 σ΅©σ΅© + (σ΅©σ΅©σ΅©(ππ ) ππ σ΅©σ΅©σ΅© − σ΅©σ΅©σ΅©σ΅©(ππ−1 ) ππ−1 σ΅©σ΅©σ΅©σ΅© ) σ΅© σ΅© σ΅© σ΅© Using the same analysis as that in [29], we obtain π½ Δπ‘ ∑ (π π=1 σ΅©σ΅© 2 σ΅© σ΅©σ΅© π π’ σ΅©σ΅© σ΅©σ΅© 2 σ΅©σ΅© ππ σ΅© ππ σ΅©σ΅© π‘π−1 σ΅© σ΅© σ΅© 2 σ΅© ππ σ΅©σ΅© π‘π σ΅© σ΅© σ΅© σ΅© σ΅©2 + πΆ (π1 ) ∫ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ + πΆ (π 1 ) Δπ‘σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) σ΅© ππ π‘π−1 σ΅© σ΅© σ΅© ππ−1 − Μππ−1 ππ − ππ−1 , ) Δπ‘ Δπ‘ π½ σ΅©σ΅©2 σ΅©σ΅© 1/2 1/2 σ΅© σ΅©2 σ΅©σ΅© + (σ΅©σ΅©σ΅©(π π ) ππ σ΅©σ΅©σ΅© − σ΅©σ΅©σ΅©σ΅©(π π−1 ) ππ−1 σ΅©σ΅©σ΅©σ΅© ) σ΅© σ΅© σ΅© σ΅© ≤ πΆ (π1 ) (Δπ‘)2 ∫ = Δπ‘ ∑ (π π=1 σ΅©2 π‘π ππ−1 − Μππ−1 ππ − ππ−1 − Δπ‘ (π , ) Δπ‘ Δπ‘ + Δπ‘ ( π−1 2Δπ‘ π½ π=1 (36) π½ = Δπ‘ ∑ (π π=1 π½ π=1 π−1 π π−1 ,π ) π½ ∫π‘ π π π‘ ππ − Δπ‘ ∑ (π π=1 π−1 2Δπ‘ ππ−1 , ππ−1 ) . π½ = Δπ‘ ∑ (π π=1 ππ−1 − Μππ−1 ππ−1 , ) Δπ‘ Δπ‘ ππ−1 − ππ − Μππ−1 + Μππ ππ , ) Δπ‘ Δπ‘ + Δπ‘ ∑ (π π‘ − Δπ‘ ( ππ−1 − Μππ−1 ππ , ) Δπ‘ Δπ‘ − Δπ‘ ∑ (π π‘ ∫π‘ π ππ‘ ππ ππ−1 − Μππ−1 ππ − ππ−1 , ). Δπ‘ Δπ‘ ππ − Μππ ππ , ) Δπ‘ Δπ‘ ππ−1 − Μππ−1 ππ−1 , ) Δπ‘ Δπ‘ ππ−1 − ππ − Μππ−1 + Μππ ππ ππ½ − Μππ½ π½ , ) + (π ,π ) Δπ‘ Δπ‘ Δπ‘ Journal of Applied Mathematics 7 π½ σ΅© π½ π½ σ΅©σ΅© ππ−1 − ππ − Μππ−1 + Μππ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© πππ σ΅©σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© + (π π − Μπ , ππ½ ) ≤ Δπ‘ ∑ σ΅©σ΅©σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅© Δπ‘ Δπ‘ σ΅©σ΅© σ΅© Δπ‘ σ΅©σ΅© σ΅© π=1 σ΅© π½ σ΅© π½ σ΅©σ΅© ππ−1 − ππ σ΅©σ΅©σ΅©2 σ΅©σ΅© + πΆ (π) Δπ‘ ∑ σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅©2 + πΆ (π ) σ΅©σ΅©σ΅©ππ½ σ΅©σ΅©σ΅©2 . ≤ πΔπ‘ ∑ σ΅©σ΅©σ΅©σ΅© σ΅©σ΅© 1 σ΅© σ΅© σ΅© σ΅© σ΅©σ΅© σ΅© Δπ‘ σ΅©σ΅© π = 1σ΅© π=1 (38) Combining (14)–(16), (31), (40), (43), (42), and the triangle inequality, we complete the proof. Remark 9. Compared to the results in [29], we can obtain the optimal a priori error estimates in π»1 -norm for the scalar unknown π’ in Theorem 8. 4. Numerical Experiment Substitute (31) and (38) into (37) to obtain π½ σ΅© σ΅©σ΅© ππ − ππ−1 σ΅©σ΅©σ΅©2 σ΅©σ΅© (π0 − π) Δπ‘ ∑ σ΅©σ΅©σ΅©σ΅© σ΅©σ΅© σ΅© Δπ‘ σ΅©σ΅© π = 1σ΅© In this section, in order to confirm our theoretical results for the novel characteristic expanded mixed finite element method, we consider the following test problem: π½ σ΅©σ΅© σ΅©σ΅©2 σ΅©σ΅© σ΅©σ΅©2 1/2 1/2 + ∑ (σ΅©σ΅©σ΅©(ππ ) (ππ − ππ−1 )σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©(π π ) (ππ − ππ−1 )σ΅©σ΅©σ΅© ) σ΅© σ΅© σ΅© σ΅© π=1 (x, π‘) ∈ πΩ × π½, (45) π’ (x, 0) = π₯1 π₯2 (π₯1 − 1) (π₯2 − 1) (2π₯2 − 1) , x ∈ Ω, (46) and initial condition π=0 (39) Using Gronwall lemma, we have π½ σ΅© σ΅©σ΅© ππ − ππ−1 σ΅©σ΅©σ΅©2 σ΅© π½ σ΅©2 σ΅©σ΅© π½ 1/2 π½ σ΅©σ΅©2 σ΅©σ΅© + σ΅©σ΅©π σ΅©σ΅© + σ΅©σ΅©(π ) π σ΅©σ΅© Δπ‘ ∑ σ΅©σ΅©σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© σ΅©σ΅© Δπ‘ σ΅© σ΅© σ΅© σ΅©σ΅© π =1σ΅© where Ω = [0, 1] × [0, 1], x = (π₯1 , π₯2 ), π½ = (0, 1], π(x, π‘) = 1 + 2π₯12 + π₯22 , c(x, π‘) = (1 + π₯12 + π₯22 + π‘2 , 1 + π₯12 + π₯22 + π‘2 ), π (x, π‘) = 1 + π₯12 + 2π₯22 , and π(x) = 1 and π(x, π‘) is chosen so that the exact solution for the scalar unknown function is π’ (x, π‘) = π−π‘ π₯1 π₯2 (π₯1 − 1) (π₯2 − 1) (2π₯2 − 1) . σ΅©2 π‘π½ σ΅© π‘π½ σ΅© σ΅©σ΅© π2 π’ σ΅©σ΅© σ΅©σ΅© ππ σ΅©σ΅©σ΅©2 ≤ πΆ (π0 , π1 , π 1 ) ((Δπ‘)2 ∫ σ΅©σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅©σ΅© ππ + ∫ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ ) π‘0 σ΅© π‘0 σ΅© σ΅© ππ σ΅©σ΅© σ΅© ππ σ΅©σ΅© (40) π Taking zβ = π in (21a), (21b), and (21c), we get (47) The corresponding exact gradient function is π₯2 (2π₯1 − 1) (π₯2 − 1) (2π₯2 − 1) ], π₯1 (π₯1 − 1) (6π₯22 − 6π₯2 + 1) π = ∇π’ = π−π‘ [ (48) and its exact flux function is π = − π∇π’ (41) Substitute (40) into (41) to get π‘π½ σ΅© π‘π½ σ΅© σ΅©σ΅© π2 π’ σ΅©σ΅©σ΅©2 σ΅© ππ σ΅©σ΅©2 σ΅©σ΅© π½ σ΅©σ΅©2 σ΅©σ΅©π σ΅©σ΅© ≤ πΆ (π0 , π1 , π 1 ) ((Δπ‘)2 ∫ σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅© ππ + ∫ σ΅©σ΅©σ΅©σ΅© σ΅©σ΅©σ΅©σ΅© ππ ) σ΅© σ΅© σ΅©σ΅© ππ σ΅©σ΅© π‘0 σ΅© π‘0 σ΅© σ΅© ππ σ΅©σ΅© σ΅© (42) Taking wβ = ∇ππ in (21b), we have σ΅©σ΅© π σ΅©σ΅©2 σ΅©σ΅© π σ΅©σ΅©2 σ΅©σ΅©∇π σ΅©σ΅© ≤ σ΅©σ΅©π σ΅©σ΅© π‘π½ σ΅© π‘π½ σ΅© σ΅©σ΅© π2 π’ σ΅©σ΅©σ΅©2 σ΅©σ΅© ππ σ΅©σ΅©σ΅©2 ≤ πΆ (π0 , π1 , π 1 ) ((Δπ‘)2 ∫ σ΅©σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅©σ΅© ππ + ∫ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ ) π‘0 σ΅© π‘0 σ΅© σ΅© ππ σ΅©σ΅© σ΅© ππ σ΅©σ΅© σ΅© σ΅©2 + πΆ (π0 , π1 , π 1 , π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) . (x, π‘) ∈ Ω × π½, π’ (x, π‘) = 0, σ΅© σ΅©2 σ΅© σ΅©2 + πΆ (π0 , π1 , π 1 , π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) + πΆ (π1 ) Δπ‘ ∑ σ΅©σ΅©σ΅©ππ σ΅©σ΅©σ΅© . σ΅© σ΅©2 + πΆ (π0 , π1 , π 1 , π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) . (44) with boundary condition π½−1 σ΅©σ΅© π σ΅©σ΅©2 σ΅© π σ΅©2 σ΅©σ΅©π σ΅©σ΅© ≤ πΆσ΅©σ΅©σ΅©π σ΅©σ΅©σ΅© . ππ’ + c (x, π‘) ⋅ ∇π’ − ∇ ⋅ (π (x, π‘) ∇π’) + π (x, π‘) π’ ππ‘ = π (x, π‘) , σ΅©σ΅© 1/2 σ΅© 1/2 σ΅© σ΅©2 σ΅©σ΅© σ΅©2 + σ΅©σ΅©σ΅©σ΅©(ππ½ ) ππ½ σ΅©σ΅©σ΅©σ΅© + σ΅©σ΅©σ΅©σ΅©(π π½ ) ππ½ σ΅©σ΅©σ΅©σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© 2 σ΅©σ΅©2 π‘π½ σ΅© π‘π½ σ΅© σ΅©σ΅© ππ σ΅©σ΅©σ΅©2 σ΅©π π’σ΅© ≤ πΆ (π0 , π1 , π 1 ) ((Δπ‘)2 ∫ σ΅©σ΅©σ΅©σ΅© 2 σ΅©σ΅©σ΅©σ΅© ππ + ∫ σ΅©σ΅©σ΅© σ΅©σ΅©σ΅© ππ ) π‘0 σ΅© π‘0 σ΅© σ΅© ππ σ΅©σ΅© σ΅© ππ σ΅©σ΅© σ΅© σ΅©2 + πΆ (π0 , π1 , π 1 , π 1 ) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ∞ (πΏ2 ) . π (x) (43) π₯2 (2π₯1 − 1) (π₯2 − 1) (2π₯2 − 1) ]. π₯1 (π₯1 − 1) (6π₯22 − 6π₯2 + 1) (49) = − π−π‘ (1 + 2π₯12 + π₯22 ) [ We divide the domain Ω = [0, 1] × [0, 1] into the triangulations of spatial mesh parameter β uniformly and use the backward Euler procedure with uniform time discretization parameter Δπ‘. We consider the piecewise linear space πβ with index π = 1 and the corresponding piecewise constant space Wβ with index π = 0. In Table 1, we get the optimal a priori error estimate in πΏ2 -norm for the scalar unknown π’ with β = 2√2Δπ‘ = √2/16, √2/32, √2/64. At the same time, we also obtain the optimal a priori error estimate in π»1 -norm for the scalar unknown π’. In Table 2, we obtain some convergence results in (πΏ2 (Ω))2 -norm for the gradient π with β = 2√2Δπ‘ = √2/16, √2/32, √2/64 in Table 2. The similar results are obtained for the flux π in Table 2. From the data obtained in Table 2, we can 8 Journal of Applied Mathematics Table 1: The errors and convergence rate for π’. (β, Δπ‘) (√2/8, 1/16) (√2/16, 1/32) βπ’ − π’β βπΏ∞ (πΏ2 (Ω)) 1.3622π − 003 Rate βπ’ − π’β βπΏ∞ (π»1 (Ω)) 2.6286π − 002 Rate 4.1958π − 004 1.6989 1.3583π − 002 0.9525 (√2/32, 1/64) 1.3172π − 004 1.6715 6.8843π − 003 0.9804 Table 2: The errors and convergence rate for π and π. (β, Δπ‘) (√2/8, 1/16) (√2/16, 1/32) βπ − π β βπΏ∞ ((πΏ2 (Ω))2 ) 2.6251π − 002 Rate βπ − πβ βπΏ∞ ((πΏ2 (Ω))2 ) 5.4313π − 002 Rate 1.3576π − 002 0.9513 2.9081π − 002 0.9013 (√2/32, 1/64) 6.8830π − 003 0.9800 1.5018π − 002 0.9534 The exact solution π’ at π‘ = 1 The numerical solution π’β at π‘ = 1 0.01 0.01 0.005 0.005 0 0 −0.005 −0.01 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 1 0.5 0 Figure 1: The surface for the exact solution π’. find that the numerical results confirm the theoretical results of Theorem 8. Figure 1 shows the surface for the exact solution π’ at π‘ = 1, and Figure 2 describes the corresponding surface for the numerical solution π’β with β = 2√2Δπ‘ = √2/16 at π‘ = 1. In Figures 1 and 2, we can find easily that the exact solution π’ is approximated very well by the numerical solution π’β . Figures 3 and 4 show the surface of the exact gradient function π and the surface of the numerical gradient function π β with β = 2√2Δπ‘ = √2/16 at π‘, respectively. A similar comparison between the surface of the exact flux function π and the surface of the numerical flux function πβ in Figures 5 and 6 also is made. From the convergence results for βπ’ − π’β βπΏ∞ (πΏ2 (Ω)) , βπ’ − π’β βπΏ∞ (π»1 (Ω)) , βπ − π β βπΏ∞ ((πΏ2 (Ω))2 ) , and βπ − πβ βπΏ∞ ((πΏ2 (Ω))2 ) in Tables 1 and 2 and Figures 1 and 2, we find that the numerical results confirm our theoretical analysis. 5. Concluding Remarks In this paper, we propose and study a novel characteristic expanded mixed finite element method, which combines the novel expanded mixed method [24] applied to approximating the diffusion term and the characteristic method that handled the hyperbolic part, for reaction-convection-diffusion equations. Compared to Chen’s expanded mixed method, the −0.005 1 −0.01 1 0.5 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0 0 Figure 2: The surface for the numerical solution π’β . gradient for our method belongs to the square integrable space instead of the classical H(div; Ω) space. We derive a priori error estimates based on backward Euler method. Moreover, we prove the optimal a priori error estimates in πΏ2 - and π»1 -norms for the scalar unknown π’ and a priori error estimates in (πΏ2 )2 -norm for its gradient π and its flux π. Finally, we choose a test problem to confirm our theoretical results. In the near future, the proposed characteristic expanded mixed scheme will be applied to other linear/nonlinear evolution equations, such as nonlinear reaction-diffusion equations, linear/nonlinear convection-dominated Sobolev equations, and time-dependent convection-diffusion optimal control problems. Acknowledgments The authors thank the anonymous referees and editors for their helpful comments and suggestions, which greatly improve the paper. This work is supported by the National Natural Science Fund (11061021), Natural Science Fund of Inner Mongolia Autonomous Region (2012MS0108, 2012MS0106, and 2011BS0102), Scientific Research Projection of Higher Schools of Inner Mongolia (NJZZ12011, NJ10006, NJ10016, and NJZY13199), Key Project of Chinese Ministry of Education (12024), and the Program of Higher-Level Journal of Applied Mathematics 9 The exact solution π 2 at π‘ = 1 The exact solution π 1 at π‘ = 1 0.04 0.1 0.02 0.05 0 0 1 −0.02 0.8 −0.04 1 1 −0.05 0.8 −0.1 1 0.6 0.6 0.4 0.5 0.4 0.5 0.2 0.2 0 0 0 (a) 0 (b) Figure 3: The surface for the exact solution π = (π 1 , π 2 ). The numerical solution π 1β at π‘ = 1 The numerical solution π 2β at π‘ = 1 0.04 0.1 0.02 0.05 0 0 1 −0.02 0.8 −0.04 1 0.6 1 −0.05 0.8 −0.1 1 0.6 0.4 0.4 0.5 0.2 0.5 0.2 0 0 (a) 0 (b) Figure 4: The surface for the numerical solution π β = (π 1β , π 2β ). 0 10 Journal of Applied Mathematics The exact solution π1 at π‘ = 1 The exact solution π2 at π‘ = 1 0.2 0.3 0.1 0.2 0 0.1 1 −0.1 0.8 −0.2 1 1 0 0.8 −0.1 1 0.6 0.6 0.4 0.5 0.4 0.5 0.2 0 0.2 0 0 (a) 0 (b) Figure 5: The surface for the exact solution π = (π1 , π2 ). The numerical solution π1β at π‘ = 1 The numerical solution π2β at π‘ = 1 0.15 0.3 0.1 0.2 0.05 0.1 0 1 −0.05 0.8 −0.1 1 0.6 1 0 0.8 −0.1 1 0.6 0.4 0.5 0.2 0.4 0.5 0.2 0 0 (a) 0 0 (b) Figure 6: The surface for the numerical solution πβ = (π1β , π2β ). Journal of Applied Mathematics Talents of Inner Mongolia University (125119, Z200901004, and 30105-125132). References [1] C. Johnson and V. 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