Hindawi Publishing Corporation Journal of Applied Mathematics Volume 2013, Article ID 353757, 8 pages http://dx.doi.org/10.1155/2013/353757 Research Article Asymptotic Behavior of Solutions to the Damped Nonlinear Hyperbolic Equation Yu-Zhu Wang School of Mathematics and Information Sciences, North China University of Water Resources and Electric Power, Zhengzhou 450011, China Correspondence should be addressed to Yu-Zhu Wang; yuzhu108@163.com Received 17 December 2012; Revised 15 May 2013; Accepted 30 May 2013 Academic Editor: Roberto Natalini Copyright © 2013 Yu-Zhu Wang. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We consider the Cauchy problem for the damped nonlinear hyperbolic equation in n-dimensional space. Under small condition on the initial value, the global existence and asymptotic behavior of the solution in the corresponding Sobolev spaces are obtained by the contraction mapping principle. 1. Introduction We investigate the Cauchy problem for the following damped nonlinear hyperbolic equation: π’π‘π‘ + π1 Δ2 π’ + π2 Δ2 π’π‘ = Δπ (Δπ’) (1) with the initial value π‘ = 0 : π’ = π’0 (π₯) , π’π‘ = π’1 (π₯) . (2) Here π’ = π’(π₯, π‘) is the unknown function of π₯ = (π₯1 , . . . , π₯π ) ∈ Rπ and π‘ > 0, π1 > 0 and π2 > 0 are constants. The nonlinear term π(π’) = π(π’1+π ) and π is a positive integer. Equation (1) is a model in variational form for the neoHookean elastomer rod and describes the motion of a neoHookean elastomer rod with internal damping; for more detailed physical background, we refer to [1]. In [1], the authors have studied a general class of abstract evolution equations π€π‘π‘ + π΄ 1 π€ + π΄ 2 π€π‘ + π∗ π (ππ€) = π, (3) where π΄ 1 , π΄ 2 , π, and π satisfy certain assumptions. For quite general conditions on the nonlinear term, global existence, uniqueness, regularity, and continuous dependence on the initial value of a generalized solution to (3) in a bounded domain of Rπ were obtained. Equation (1) fits the abstract framework of [1]. The local well-posedness for the Cauchy problem for (1), (2) in three-dimensional space was obtained by Chen and Da [2]. More precisely, they proved local existence and uniqueness of weak solutions to (1), (2) under the assumption that π’0 ∈ π»6 (R3 ), π’1 ∈ π»4 (R3 ). Local existence and uniqueness of classical solutions to (1), (2) were also established, provided that π’0 ∈ π»12 (R3 ), π’1 ∈ π»10 (R3 ). Their method is to first establish local-intime well-posedness of a periodic version of (1), (2) and then construc a solution to (1), (2) as a limit of periodic solutions with divergent periods. This paper also arrived at some sufficient conditions for blow-up of the solution in finite time, and an example was given. Song and Yang [3] studied the existence and nonexistence of global solutions to the Cauchy problem for (1) in one-dimensional space. The boundary value problems for (1) are investigated (see [4, 5]). Equation (1) is a fifth-order wave equation. For more higher order wave equations, we refer to [6–8] and references therein. The main purpose of this paper is to establish global existence and asymptotic behavior of solutions to (1), (2) by using the contraction mapping principle. Firstly, we consider the decay property of the following linear equation: π’π‘π‘ + π1 Δ2 π’ + π2 Δ2 π’π‘ = 0. (4) 2 Journal of Applied Mathematics We obtain the following decay estimate of solutions to (4), (2) σ΅© σ΅©σ΅© π σ΅©σ΅©ππ₯ π’ (π‘)σ΅©σ΅©σ΅© 2 ≤ πΆ(1 + π‘)−(π/8+π/4) σ΅©πΏ σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) 1 for (π ≤ π + 4) , σ΅© σ΅©σ΅© π σ΅©σ΅©ππ₯ π’π‘ (π‘)σ΅©σ΅©σ΅© 2 ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) σ΅©πΏ σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) 1 2. Solution Formula for (π ≤ π ) . (5) Based on the above estimates, we define a solution space with time weighted norms, and then global existence and asymptotic behavior of solutions to (1), (2) are obtained by using the contraction mapping principle. More precisely, we prove global existence and the following decay estimate of solution to (1), (2): σ΅© σ΅©σ΅© π σ΅©σ΅©ππ₯ π’ (π‘)σ΅©σ΅©σ΅© 2 ≤ πΆπΈ0 (1 + π‘)−(π/8+π/4) , σ΅©πΏ σ΅© (6) σ΅©σ΅©σ΅©ππ π’ (π‘)σ΅©σ΅©σ΅© ≤ πΆπΈ (1 + π‘)−(π/8+π/4+1/2) σ΅©σ΅© π₯ π‘ σ΅©σ΅©πΏ2 0 for π ≤ π + 4, π ≤ π , and π ≥ [π/2] + 1. Here π’0 ∈ π»π +4 (Rπ ) β πΏ1 (Rπ ), π’1 ∈ π»π (Rπ ) β π»Μ 1−2 (Rπ ), and πΈ0 = βπ’0 βπΏ1 + βπ’1 βπ»Μ 1−2 + βπ’0 βπ»π +4 + βπ’1 βπ»π is assumed to be suitably small. When π = 3, our result allows for the initial data π’0 ∈ π»6 (R3 ), π’1 ∈ π»2 (R3 ). But in [2], the authors proved local existence and uniqueness of weak solutions to (1), (2) under the assumption that π’0 ∈ π»6 (R3 ), π’1 ∈ π»4 (R3 ), so our result improves the regularity of the initial condition for the time derivative. This improvement is due to the strong damping term Δ2 π’π‘ since the strong damping term Δ2 π’π‘ has stronger dissipative effect than the damping π’π‘ . The stronger dissipative effect has been exhibited in the study of the strongly damped wave equation and related problems; see, for instance, [9]. The global existence and asymptotic behavior of solutions to hyperbolic-type equations have been investigated by many authors. We refer to [10–15] for hyperbolic equations, [16–21] for damped wave equation, and [22, 23] for various aspects of dissipation of the plate equation. We give some notations which are used in this paper. Let F[π’] denote the Fourier transform of π’ defined by π’Μ (π) = F [π’] = ∫ π−ππ⋅π₯ π’ (π₯) ππ₯, Rπ Finally, in this paper, we denote every positive constant by the same symbol πΆ or π without confusion. [⋅] is the Gauss symbol. The paper is organized as follows. In Section 2 we derive the solution formula of our semilinear problem. We study the decay property of the solution operators appearing in the solution formula in Section 3. Then, in Section 4, we discuss the linear problem and show the decay estimates. Finally, we prove global existence and asymptotic behavior of solutions for the Cauchy problem (1), (2) in Section 5. (7) and we denote its inverse transform by F−1 . For 1 ≤ π ≤ ∞, πΏπ = πΏπ (Rπ ) denotes the usual Lebesgue space with the norm β ⋅ βπΏπ . The usual Sobolev space of π is defined by π»ππ = (πΌ − Δ)−π /2 πΏπ with the norm βπβπ»ππ = β(πΌ − Δ)π /2 πβπΏπ ; the homogeneous Sobolev space of π is defined by π»Μ ππ = (−Δ)−π /2 πΏπ with the norm βπβπ»ππ = β(−Δ)π /2 πβπΏπ ; especially π»π = π»2π , π»Μ π = π»Μ 2π . Moreover, we know that π»ππ = πΏπ β π»Μ ππ for π ≥ 0. The aim of this section is to derive the solution formula for the problem (1), (2). We first investigate (4). Taking the Fourier transform, we have σ΅¨ σ΅¨4 σ΅¨ σ΅¨4 π’Μπ‘π‘ + π2 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π’Μπ‘ + π1 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π’Μ = 0. (8) The corresponding initial value is given as π‘ = 0 : π’Μ = π’Μ0 (π) , π’Μπ‘ = π’Μ1 (π) . (9) The characteristic equation of (8) is σ΅¨ σ΅¨4 σ΅¨ σ΅¨4 π2 + π2 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ π + π1 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ = 0. (10) Let π = π ± (π) be the corresponding eigenvalues of (10), and we obtain π ± (π) = σ΅¨ σ΅¨4 σ΅¨ σ΅¨2 σ΅¨ σ΅¨4 −π2 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ± σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ √π22 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ − 4π1 2 . (11) The solution to the problem (8)-(9) is given in the form Μ (π, π‘) π’Μ1 (π) + π» Μ (π, π‘) π’Μ0 (π) , π’Μ (π, π‘) = πΊ (12) where Μ (π, π‘) = πΊ Μ (π, π‘) = π» 1 (ππ + (π)π‘ − ππ − (π)π‘ ) , π + (π) − π − (π) (13) 1 (π (π) ππ − (π)π‘ − π − (π) ππ + (π)π‘ ) . π + (π) − π − (π) + (14) Μ π‘)](π₯) We define πΊ(π₯, π‘) and π»(π₯, π‘) by πΊ(π₯, π‘) = F−1 [πΊ(π, −1 Μ and π»(π₯, π‘) = F [π»(π, π‘)](π₯), respectively, where F−1 denotes the inverse Fourier transform. Then, applying F−1 to (12), we obtain π’ (π‘) = πΊ (π‘) ∗ π’1 + π» (π‘) ∗ π’0 . (15) By the Duhamel principle, we obtain the solution formula to (1), (2) π’ (π‘) = πΊ (π‘) ∗ π’1 + π» (π‘) ∗ π’0 π‘ + ∫ πΊ (π‘ − π) ∗ Δπ (Δπ’) (π) ππ. 0 (16) Journal of Applied Mathematics 3 3. Decay Property The aim of this section is to establish decay estimates of the solution operators πΊ(π‘) and π»(π‘) appearing in the solution formula (15). σ΅¨2 σ΅¨ Μ σ΅¨σ΅¨2 σ΅¨ σ΅¨4 σ΅¨ σ΅¨8 σ΅¨ Μ −ππ(π)π‘ , (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ) σ΅¨σ΅¨σ΅¨σ΅¨πΊ (π, π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨σ΅¨πΊ π‘ (π, π‘)σ΅¨σ΅¨σ΅¨ ≤ πΆπ (29) σ΅¨2 σ΅¨ Μ σ΅¨σ΅¨2 σ΅¨σ΅¨ σ΅¨σ΅¨4 σ΅¨σ΅¨ σ΅¨σ΅¨8 −ππ(π)π‘ σ΅¨ σ΅¨4 σ΅¨ σ΅¨8 σ΅¨ Μ (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ) σ΅¨σ΅¨σ΅¨σ΅¨π» (π, π‘)σ΅¨σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨σ΅¨π» π‘ (π, π‘)σ΅¨σ΅¨σ΅¨ ≤ πΆ (σ΅¨σ΅¨πσ΅¨σ΅¨ + σ΅¨σ΅¨πσ΅¨σ΅¨ ) π (30) Lemma 1. The solution of the problem (8), (9) satisfies σ΅¨2 σ΅¨ σ΅¨2 σ΅¨ σ΅¨4 σ΅¨ σ΅¨8 σ΅¨ (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ) σ΅¨σ΅¨σ΅¨π’Μ (π, π‘)σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨π’Μπ‘ (π, π‘)σ΅¨σ΅¨σ΅¨ (17) σ΅¨2 σ΅¨ σ΅¨2 σ΅¨ σ΅¨4 σ΅¨ σ΅¨8 σ΅¨ ≤ πΆπ−ππ(π)π‘ ((σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ) σ΅¨σ΅¨σ΅¨π’Μ0 (π)σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨π’Μ1 (π)σ΅¨σ΅¨σ΅¨ ) for π ∈ Rπ and π‘ ≥ 0, where σ΅¨σ΅¨ σ΅¨σ΅¨4 σ΅¨πσ΅¨ , π (π) = {σ΅¨ σ΅¨ 1, for π ∈ Rπ and π‘ ≥ 0, where σ΅¨σ΅¨ σ΅¨σ΅¨4 σ΅¨πσ΅¨ , π (π) = {σ΅¨ σ΅¨ 1, Μ π‘) and π»(π, Μ π‘) be the fundamental solution Lemma 2. Let πΊ(π, of (4) in the Fourier space, which are given in (13) and (14), respectively. Then one has the estimates σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨πσ΅¨σ΅¨ ≤ π 0 σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨πσ΅¨σ΅¨ ≥ π 0 . (18) Proof. Multiplying (8) by π’Μπ‘ and taking the real part yield 1 π σ΅¨σ΅¨ σ΅¨σ΅¨2 σ΅¨ σ΅¨4 2 σ΅¨ σ΅¨4 σ΅¨ σ΅¨2 {σ΅¨π’Μ σ΅¨ + π2 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ |Μ π’| } + π1 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨π’Μπ‘ σ΅¨σ΅¨σ΅¨ = 0. 2 ππ‘ σ΅¨ π‘ σ΅¨ (19) (31) Proof. If π’Μ0 (π) = 0, from (12), we obtain Μ (π, π‘) π’Μ1 (π) , π’Μ (π, π‘) = πΊ Μπ‘ (π, π‘) π’Μ1 (π) . π’Μπ‘ (π, π‘) = πΊ (32) Substituting the equalities into (17) with π’Μ0 (π) = 0, we get (29). In what follows, we consider π’Μ1 (π) = 0, and it follows from (12) that Multiplying (8) by π’Μ and taking the real part, we obtain 1 π σ΅¨ σ΅¨4 2 σ΅¨ σ΅¨4 2 σ΅¨σ΅¨ Μ σ΅¨σ΅¨2 {π σ΅¨σ΅¨πσ΅¨σ΅¨ |Μ π’π‘ π’Μ)} + π2 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ |Μ π’| + 2 Re (Μ π’| − σ΅¨σ΅¨π’π‘ σ΅¨σ΅¨ = 0. 2 ππ‘ 1 σ΅¨ σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨πσ΅¨σ΅¨ ≤ π 0 σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨πσ΅¨σ΅¨ ≥ π 0 . (20) 4 Μ (π, π‘) π’Μ0 (π) , π’Μ (π, π‘) = π» (33) Multiplying both sides of (19) and (20) by 2 and π1 |π| and summing up the resulting equation yield Μπ‘ (π, π‘) π’Μ0 (π) . π’Μπ‘ (π, π‘) = π» π πΈ + πΉ = 0, ππ‘ Substituting the equalities into (17) with π’Μ1 (π) = 0, we get the desired estimate (30). The lemma is proved. (21) where π πΈ + ππ (π) πΈ ≤ 0. ππ‘ (27) πΈ (π, π‘) ≤ π−ππ(π)π‘ πΈ (π, 0) , (28) Lemma 3. Let π and π be nonnegative integer. Then one has σ΅©σ΅© π σ΅© σ΅©σ΅©ππ₯ πΊ (π‘) ∗ πσ΅©σ΅©σ΅© 2 ≤ πΆ(1 + π‘)−(π/8+π/4+π/4−1/2) σ΅© σ΅©πΏ (34) σ΅© σ΅© σ΅© σ΅© × σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©π»Μ −π + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π−4)+ πσ΅©σ΅©σ΅©σ΅©πΏ2 , 1 σ΅©σ΅©σ΅©ππ π» (π‘) ∗ πσ΅©σ΅©σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4+π/4) σ΅©σ΅© π₯ σ΅©σ΅©πΏ2 (35) σ΅© σ΅© σ΅© σ΅© × σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©π»Μ −π + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯π πσ΅©σ΅©σ΅©σ΅©πΏ2 , 1 σ΅©σ΅©σ΅©ππ πΊ (π‘) ∗ πσ΅©σ΅©σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4+π/4) σ΅©σ΅© π₯ π‘ σ΅©σ΅©πΏ2 (36) σ΅© σ΅© σ΅© σ΅© × σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©π»Μ −π + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯π πσ΅©σ΅©σ΅©σ΅©πΏ2 , 1 σ΅©σ΅©σ΅©ππ π» (π‘) ∗ πσ΅©σ΅©σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4+π/4+1/2) σ΅©σ΅© π₯ π‘ σ΅©σ΅©πΏ2 (37) σ΅© σ΅© σ΅© σ΅© × σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©π»Μ −π + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π+4) πσ΅©σ΅©σ΅©σ΅©πΏ2 , 1 σ΅©σ΅©σ΅©ππ πΊ (π‘) ∗ Δπσ΅©σ΅©σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4) σ΅©σ΅© π₯ σ΅©σ΅©πΏ2 (38) σ΅© σ΅© σ΅© σ΅© × σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ1 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ πσ΅©σ΅©σ΅©σ΅©πΏ2 , σ΅©σ΅© π σ΅© σ΅©σ΅©ππ₯ πΊπ‘ (π‘) ∗ Δπσ΅©σ΅©σ΅© 2 ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) σ΅© σ΅©πΏ (39) σ΅© σ΅© σ΅© σ΅© × σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ1 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π+2) πσ΅©σ΅©σ΅©σ΅©πΏ2 . which together with (23) proves the desired estimates (17). Then we have completed the proof of the lemma. Here (π−4)+ = max{0, π−4} in (34) and (π−2)+ = max{0, π−2} in (38). 1 σ΅¨σ΅¨ σ΅¨σ΅¨8 2 σ΅¨ σ΅¨4 π’π‘ π’Μ) , π’| + π1 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ Re (Μ σ΅¨πσ΅¨ |Μ 2σ΅¨ σ΅¨ σ΅¨ σ΅¨8 2 σ΅¨ σ΅¨4 σ΅¨ σ΅¨2 π’| + π1 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨π’Μπ‘ σ΅¨σ΅¨σ΅¨ . πΉ = π1 π2 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ |Μ A simple computation implies that σ΅¨ σ΅¨4 2 σ΅¨ σ΅¨2 πΈ = σ΅¨σ΅¨σ΅¨π’Μπ‘ σ΅¨σ΅¨σ΅¨ + π2 σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ |Μ π’| + (22) πΆπΈ0 ≤ πΈ ≤ πΆπΈ0 , (23) σ΅¨ σ΅¨4 σ΅¨ σ΅¨8 σ΅¨ σ΅¨2 πΈ0 = (σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ) |Μ π’|2 + σ΅¨σ΅¨σ΅¨π’Μπ‘ σ΅¨σ΅¨σ΅¨ . (24) where Note that σ΅¨ σ΅¨2 σ΅¨ σ΅¨4 σ΅¨ σ΅¨4 σ΅¨ σ΅¨8 π’|2 + σ΅¨σ΅¨σ΅¨π’Μπ‘ σ΅¨σ΅¨σ΅¨ ) , {πσ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ((σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ) |Μ πΉ ≥ { σ΅¨ σ΅¨4 σ΅¨ σ΅¨8 σ΅¨ σ΅¨ σ΅¨ σ΅¨ π’|2 + σ΅¨σ΅¨σ΅¨π’Μπ‘ σ΅¨σ΅¨σ΅¨2 ) , σ΅¨ σ΅¨ {π ((σ΅¨σ΅¨πσ΅¨σ΅¨ + σ΅¨σ΅¨πσ΅¨σ΅¨ ) |Μ It follows from (23) that πΉ ≥ ππ (π) πΈ. σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨πσ΅¨σ΅¨ ≤ π 0 σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨πσ΅¨σ΅¨ ≥ π 0 . (25) (26) Using (21) and (26), we get Thus 4 Journal of Applied Mathematics Proof. By the Plancherel theorem and (29), Hausdorff-Young inequality, we obtain σ΅©2 σ΅©σ΅© π σ΅©σ΅©ππ₯ πΊ (π‘) ∗ πσ΅©σ΅©σ΅© 2 σ΅©πΏ σ΅© =∫ |π|≤π 0 |π|≥π 0 ≤∫ |π|≤π 0 σ΅¨σ΅¨ σ΅¨σ΅¨2|π|−4 −π|π|4 π‘ σ΅¨σ΅¨σ΅¨ Μ σ΅¨σ΅¨σ΅¨2 π σ΅¨σ΅¨πσ΅¨σ΅¨ σ΅¨σ΅¨π (π)σ΅¨σ΅¨ ππ |π|≥π 0 |π|≤π 0 + Theorem 4. Assume that π’0 ∈ π»π +4 (Rπ ) β πΏ1 (Rπ ), π’1 ∈ π»π (Rπ ) β π»Μ 1−2 (Rπ )(π ≥ [π/2] + 1). Then the classical solution π’(π₯, π‘) to (4), (2), which is given by the formula (15), satisfies the decay estimate σ΅¨2 σ΅¨ σ΅¨2 σ΅¨σ΅¨ σ΅¨σ΅¨2|π| σ΅¨σ΅¨σ΅¨ Μ σ΅¨σ΅¨πσ΅¨σ΅¨ σ΅¨σ΅¨πΊ (π, π‘)σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨σ΅¨πΜ (π)σ΅¨σ΅¨σ΅¨σ΅¨ ππ + πΆπ−ππ‘ ∫ ≤∫ 4. Decay Estimate of Solutions to (4), (2) σ΅¨2 σ΅¨ σ΅¨2 σ΅¨σ΅¨ σ΅¨σ΅¨2|π| σ΅¨σ΅¨σ΅¨ Μ σ΅¨σ΅¨πσ΅¨σ΅¨ σ΅¨σ΅¨πΊ (π, π‘)σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨σ΅¨πΜ (π)σ΅¨σ΅¨σ΅¨σ΅¨ ππ +∫ σ΅© σ΅©σ΅© π σ΅©σ΅©ππ₯ π’ (π‘)σ΅©σ΅©σ΅© 2 ≤ πΆ(1 + π‘)−(π/8+π/4) σ΅©πΏ σ΅© σ΅¨σ΅¨ σ΅¨σ΅¨2π σ΅¨σ΅¨ σ΅¨σ΅¨8 σ΅¨σ΅¨ σ΅¨σ΅¨4 −1 σ΅¨σ΅¨σ΅¨ Μ σ΅¨σ΅¨σ΅¨2 σ΅¨σ΅¨πσ΅¨σ΅¨ (σ΅¨σ΅¨πσ΅¨σ΅¨ + σ΅¨σ΅¨πσ΅¨σ΅¨ ) σ΅¨σ΅¨π (π)σ΅¨σ΅¨ ππ σ΅¨σ΅¨ σ΅¨σ΅¨2π−4+2π −π|π|4 π‘ σ΅¨σ΅¨ σ΅¨σ΅¨−2π σ΅¨σ΅¨σ΅¨ Μ σ΅¨σ΅¨σ΅¨2 π σ΅¨σ΅¨πσ΅¨σ΅¨ σ΅¨σ΅¨πσ΅¨σ΅¨ σ΅¨σ΅¨π (π)σ΅¨σ΅¨ ππ σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) 1 (40) |π|≤π 0 for (π ≤ π + 4) , (42) σ΅© σ΅©2 πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π−4)+ πσ΅©σ΅©σ΅©σ΅©πΏ2 σ΅©2 σ΅©σ΅¨ σ΅¨−π ≤ πΆσ΅©σ΅©σ΅©σ΅©σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ πΜ (π)σ΅©σ΅©σ΅©σ΅©πΏ∞ ∫ where π 0 is a small positive constant in Lemma 1. Thus (38) follows. Similarly, we can prove (39). Thus we have completed the proof of the lemma. σ΅© σ΅©σ΅© π σ΅©σ΅©ππ₯ π’π‘ (π‘)σ΅©σ΅©σ΅© 2 ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) σ΅©πΏ σ΅© σ΅¨σ΅¨ σ΅¨σ΅¨2π−4+2π −π|π|4 π‘ π ππ σ΅¨σ΅¨πσ΅¨σ΅¨ σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) 1 σ΅© σ΅©2 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π−4)+ πσ΅©σ΅©σ΅©σ΅©πΏ2 for (π ≤ π ) , (43) σ΅© σ΅©2 ≤ πΆ(1 + π‘)−(π/4+π/2+π/2−1) σ΅©σ΅©σ΅©σ΅©(−Δ)−π/2 πσ΅©σ΅©σ΅©σ΅©πΏ1 σ΅© σ΅©σ΅© β σ΅©σ΅©ππ₯ π’ (π‘)σ΅©σ΅©σ΅© ∞ ≤ πΆ(1 + π‘)−(π/4+β/4) σ΅©πΏ σ΅© σ΅© σ΅©2 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π−4)+ πσ΅©σ΅©σ΅©σ΅©πΏ2 . σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) 1 Here (π − 4)+ = max{0, π − 4} and π 0 is a small positive constant in Lemma 1. Thus (34) follows. Similarly, using (29) and (30), respectively, we can prove (35)–(37). In what follows, we prove (38). By the Plancherel theorem, (29), and Hausdorff-Young inequality, we have σ΅©2 σ΅©σ΅© π σ΅©σ΅©ππ₯ πΊ (π‘) ∗ Δπσ΅©σ΅©σ΅© 2 σ΅©πΏ σ΅© =∫ |π|≤π 0 +∫ ≤∫ |π|≤π 0 σ΅© σ΅© σ΅© σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4) (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 ) 1 σ΅¨2 σ΅¨ σ΅¨4 σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨2π σ΅¨σ΅¨σ΅¨ Μ σ΅¨2 σ΅¨σ΅¨πσ΅¨σ΅¨ σ΅¨σ΅¨πΊ (π, π‘)σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨πΜ (π)σ΅¨σ΅¨σ΅¨ ππ σ΅¨σ΅¨ σ΅¨σ΅¨2π −π|π|4 π‘ σ΅¨σ΅¨ Μ σ΅¨σ΅¨2 σ΅¨σ΅¨πσ΅¨σ΅¨ π σ΅¨σ΅¨π (π)σ΅¨σ΅¨ ππ + πΆπ−ππ‘ ∫ |π|≥π 0 σ΅©2 σ΅© ≤ πΆσ΅©σ΅©σ΅©πΜ (π)σ΅©σ΅©σ΅©πΏ∞ ∫ σ΅¨2 σ΅¨σ΅¨ σ΅¨σ΅¨2π σ΅¨ σ΅¨4 −1 σ΅¨ σ΅¨σ΅¨πσ΅¨σ΅¨ (1 + σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ ) σ΅¨σ΅¨σ΅¨πΜ (π)σ΅¨σ΅¨σ΅¨ ππ |π|≤π 0 σ΅¨σ΅¨ σ΅¨σ΅¨2π −π|π|4 π‘ ππ σ΅¨σ΅¨πσ΅¨σ΅¨ π σ΅© σ΅©2 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ πσ΅©σ΅©σ΅©σ΅©πΏ2 σ΅© σ΅©2 σ΅© σ΅©2 ≤ πΆ(1 + π‘)−(π/4+π/2) σ΅©σ΅©σ΅©πσ΅©σ΅©σ΅©πΏ1 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ πσ΅©σ΅©σ΅©σ΅©πΏ2 , Proof. Firstly, we prove (42). Using (34) and (35), for π ≤ π +4, we obtain σ΅©σ΅© π σ΅© σ΅©σ΅©ππ₯ π’ (π‘)σ΅©σ΅©σ΅© 2 σ΅© σ΅©πΏ σ΅© σ΅© σ΅© σ΅© ≤ σ΅©σ΅©σ΅©σ΅©ππ₯π πΊ (π‘) ∗ π’1 σ΅©σ΅©σ΅©σ΅©πΏ2 + πΆσ΅©σ΅©σ΅©σ΅©ππ₯π π» (π‘) ∗ π’0 σ΅©σ΅©σ΅©σ΅©πΏ2 σ΅¨2 σ΅¨ σ΅¨4 σ΅¨ σ΅¨2 σ΅¨σ΅¨ σ΅¨σ΅¨2|π| σ΅¨σ΅¨σ΅¨ Μ σ΅¨σ΅¨πσ΅¨σ΅¨ σ΅¨σ΅¨πΊ (π, π‘)σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨πΜ (π)σ΅¨σ΅¨σ΅¨ ππ |π|≥π 0 π for (β ≤ π − [ ] + 3) . 2 (44) σ΅© σ΅© σ΅© σ΅© + πΆπ−ππ‘ (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) (41) ≤ πΆ(1 + π‘)−(π/8+π/4) σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) . 1 For π ≤ π , it follows from (36) and (37) that σ΅© σ΅©σ΅© π σ΅©σ΅©ππ₯ π’π‘ (π‘)σ΅©σ΅©σ΅© 2 σ΅©πΏ σ΅© σ΅© σ΅© σ΅©σ΅© π σ΅© ≤ σ΅©σ΅©σ΅©ππ₯ πΊπ‘ (π‘) ∗ π’1 σ΅©σ΅©σ΅©σ΅©πΏ2 + πΆσ΅©σ΅©σ΅©σ΅©ππ₯π π»π‘ (π‘) ∗ π’0 σ΅©σ΅©σ΅©σ΅©πΏ2 (45) Journal of Applied Mathematics 5 σ΅© σ΅© σ΅© σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 ) 1 where σ΅© σ΅© σ΅© σ΅© + πΆπ−ππ‘ (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) σ΅© σ΅© βπ’βπ = sup { ∑ (1 + π‘)π/8+π/4 σ΅©σ΅©σ΅©σ΅©ππ₯π π’ (π‘)σ΅©σ΅©σ΅©σ΅©πΏ2 π‘≥0 ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) (46) Equation (44) follows from (42) and Gagliardo-Nirenberg inequality. The lemma is proved. 5. Global Existence and Asymptotic Behavior The purpose of this section is to prove global existence and asymptotic behavior of solutions to the Cauchy problem (1), (2). We need the following lemma, which comes from [24] (see also [25]). Lemma 5. Let π and π be positive integers, πΏ > 0, π, π, π ∈ [1, ∞] satisfy 1/π = 1/π + 1/π, and let π ∈ {0, 1, 2, . . . , π }. Assume that πΉ(V) is class of πΆπ and satisfies σ΅¨σ΅¨σ΅¨ππ πΉ (V)σ΅¨σ΅¨σ΅¨ ≤ πΆ |V|π+1−π , |V| ≤ πΏ, 0 ≤ π ≤ π , π < π + 1, σ΅¨σ΅¨ σ΅¨σ΅¨ V π,πΏ σ΅¨σ΅¨ π σ΅¨ σ΅¨σ΅¨πV πΉ (V)σ΅¨σ΅¨σ΅¨ ≤ πΆπ,πΏ , |V| ≤ πΏ, π ≤ π , π + 1 ≤ π. σ΅¨ σ΅¨ (47) If V ∈ πΏπ β ππ,π β πΏ∞ and βVβπΏ∞ ≤ πΏ, then for |πΌ| ≤ π one has σ΅© σ΅© πΌ σ΅© σ΅©σ΅© πΌ π−1 σ΅©σ΅©ππ₯ πΉ (V)σ΅©σ΅©σ΅©πΏπ ≤ πΆπ,πΏ σ΅©σ΅©σ΅©ππ₯ Vσ΅©σ΅©σ΅©πΏπ βVβπΏπ βVβπΏ∞ . (48) Lemma 6. Let π and π be positive integers, let πΏ > 0, π, π, π ∈ [1, ∞] satisfy 1/π = 1/π + 1/π, and let π ∈ {0, 1, 2, . . . , π }. Let πΉ(V) be a function that satisfies the assumptions of Lemma 5. Moreover, assume that σ΅¨ σ΅¨σ΅¨ π π σ΅¨σ΅¨πV πΉ (V1 ) − πV πΉ (V2 )σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ max{π−π ,π} σ΅¨σ΅¨ (49) ≤ πΆπΏ (σ΅¨σ΅¨σ΅¨V1 σ΅¨σ΅¨σ΅¨ + σ΅¨σ΅¨σ΅¨V2 σ΅¨σ΅¨σ΅¨) σ΅¨σ΅¨V1 − V2 σ΅¨σ΅¨σ΅¨ , σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨V1 σ΅¨σ΅¨ ≤ πΏ, σ΅¨σ΅¨σ΅¨V2 σ΅¨σ΅¨σ΅¨ ≤ πΏ. If V1 , V2 ∈ πΏπ β ππ,π β πΏ∞ and βV1 βπΏ∞ ≤ πΏ, βV2 βπΏ∞ ≤ πΏ, then for |πΌ| ≤ π, one has σ΅©σ΅© πΌ σ΅© σ΅©σ΅©ππ₯ (πΉ (V1 ) − πΉ (V2 ))σ΅©σ΅©σ΅©πΏπ σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© ≤ πΆπ,πΏ {(σ΅©σ΅©σ΅©ππ₯πΌ V1 σ΅©σ΅©σ΅©πΏπ + σ΅©σ΅©σ΅©ππ₯πΌ V2 σ΅©σ΅©σ΅©πΏπ ) σ΅©σ΅©σ΅©V1 − V2 σ΅©σ΅©σ΅©πΏπ (50) σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© + (σ΅©σ΅©σ΅©V1 σ΅©σ΅©σ΅©πΏπ + σ΅©σ΅©σ΅©V2 σ΅©σ΅©σ΅©πΏπ ) σ΅©σ΅©σ΅©ππ₯πΌ (V1 − V2 )σ΅©σ΅©σ΅©πΏπ } σ΅© σ΅© π−1 σ΅© σ΅© × (σ΅©σ΅©σ΅©V1 σ΅©σ΅©σ΅©πΏ∞ + σ΅©σ΅©σ΅©V2 σ΅©σ΅©σ΅©πΏ∞ ) . Based on the estimates (42)–(44) of solutions to the linear problem (4), (2), one defines the following solution space: π = {π’ ∈ πΆ ([0, ∞) ; π»π +4 (Rπ )) 1 π π β πΆ ([0, ∞) ; π» (R )) : βπ’βπ < ∞} , (52) σ΅© σ΅© +∑(1 + π‘)π/8+π/4+1/2 σ΅©σ΅©σ΅©σ΅©ππ₯π π’π‘ (π‘)σ΅©σ΅©σ΅©σ΅©πΏ2 } . σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) . 1 βπΉ (V)βππ,π ≤ πΆπ,πΏ βVβππ,π βVβπΏπ βVβπ−1 πΏ∞ , π≤π +4 (51) π≤π For π > 0, one defines ππ = {π’ ∈ π : βπ’βπ ≤ π } , (53) where π depends on the initial value, which is chosen in the proof of main result. For β ≤ π −[π/2]+3, using Gagliardo-Nirenberg inequality, one obtains σ΅© σ΅©σ΅© β σ΅©σ΅©ππ₯ π’ (π‘)σ΅©σ΅©σ΅© ∞ ≤ πΆ(1 + π‘)−(π/4+β/4) βπ’βπ . σ΅©πΏ σ΅© (54) Theorem 7. Assume that π’0 ∈ π»π +4 (Rπ ) β πΏ1 (Rπ ), π’1 ∈ π π»π (Rπ ) β π»Μ 1−2 (Rπ ) (π ≥ [ ] + 1), and integer π ≥ 1. π(π’) 2 satisfies the assumptions of Lemmas 5 and 6. Put σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© πΈ0 = σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π . 1 (55) If πΈ0 is suitably small, the Cauchy problem (1)-(2) has a unique global classical solution π’(π₯, π‘) satisfying π’ ∈ πΆ ([0, ∞) ; π»π +4 (Rπ )) , π’π‘ ∈ πΆ ([0, ∞) ; π»π (Rπ )) . (56) Moreover, the solution satisfies the decay estimate σ΅© σ΅©σ΅© π σ΅©σ΅©ππ₯ π’ (π‘)σ΅©σ΅©σ΅© 2 ≤ πΆπΈ0 (1 + π‘)−(π/8+π/4) , σ΅©πΏ σ΅© σ΅©σ΅© π σ΅©σ΅© σ΅©σ΅©ππ₯ π’π‘ (π‘)σ΅©σ΅© 2 ≤ πΆπΈ0 (1 + π‘)−(π/8+π/4+1/2) σ΅© σ΅©πΏ (57) for π ≤ π + 4 and π ≤ π . Proof. Define the mapping T (π’) = πΊ (π‘) ∗ π’1 + π» (π‘) ∗ π’0 π‘ + ∫ πΊ (π‘ − π) ∗ Δπ (Δπ’ (π)) ππ. (58) 0 Using (34)-(35), (38), Lemma 5, and (54), for π ≤ π + 4, we obtain σ΅©σ΅© π σ΅© σ΅©σ΅©ππ₯ T (π’)σ΅©σ΅©σ΅© 2 σ΅© σ΅©πΏ σ΅© σ΅© σ΅© σ΅© ≤ πΆσ΅©σ΅©σ΅©σ΅©ππ₯π πΊ (π‘) ∗ π’1 σ΅©σ΅©σ΅©σ΅©πΏ2 + πΆσ΅©σ΅©σ΅©σ΅©ππ₯π π» (π‘) ∗ π’0 σ΅©σ΅©σ΅©σ΅©πΏ2 π‘ σ΅© σ΅© + πΆ ∫ σ΅©σ΅©σ΅©σ΅©ππ₯π πΊ (π‘ − π) ∗ Δπ (Δπ’ (π))σ΅©σ΅©σ΅©σ΅©πΏ2 ππ 0 6 Journal of Applied Mathematics σ΅© σ΅© σ΅© σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4) σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯(π−4)+ π’1 σ΅©σ΅©σ΅©σ΅©πΏ2 It follows from (58) that 1 σ΅© σ΅© σ΅© σ΅© + πΆ(1 + π‘)−(π/8+π/4) σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯π π’0 σ΅©σ΅©σ΅©σ΅©πΏ2 + πΆ∫ π‘/2 0 T(π’)π‘ = πΊπ‘ (π‘) ∗ π’1 + π»π‘ (π‘) ∗ π’0 π‘ σ΅© σ΅© (1 + π‘ − π)−(π/8+π/4) σ΅©σ΅©σ΅©π (Δπ’)σ΅©σ΅©σ΅©πΏ1 ππ + ∫ πΊπ‘ (π‘ − π) ∗ Δπ (Δπ’ (π)) ππ. 0 π‘ σ΅© σ΅© + πΆ ∫ (1 + π‘ − π)−π/8 σ΅©σ΅©σ΅©σ΅©ππ₯π π (Δπ’)σ΅©σ΅©σ΅©σ΅©πΏ1 ππ Using (36)-(37), (39), Lemma 5, and (54), for π ≤ π , we have π‘/2 π‘ σ΅© σ΅© + πΆ ∫ π−π(π‘−π) σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ π (Δπ’)σ΅©σ΅©σ΅©σ΅©πΏ2 ππ σ΅©σ΅© π σ΅© σ΅©σ΅©ππ₯ T(π’)π‘ σ΅©σ΅©σ΅© 2 σ΅© σ΅©πΏ σ΅© σ΅© σ΅© σ΅© ≤ πΆσ΅©σ΅©σ΅©σ΅©ππ₯π πΊπ‘ (π‘) ∗ π’1 σ΅©σ΅©σ΅©σ΅©πΏ2 + πΆσ΅©σ΅©σ΅©σ΅©ππ₯π π»π‘ (π‘) ∗ π’0 σ΅©σ΅©σ΅©σ΅©πΏ2 0 σ΅© σ΅© σ΅© σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4) (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 ) 1 π‘ σ΅© σ΅© + πΆ ∫ σ΅©σ΅©σ΅©σ΅©ππ₯π πΊπ‘ (π‘ − π) ∗ Δπ (Δπ’ (π))σ΅©σ΅©σ΅©σ΅©πΏ2 ππ 0 σ΅© σ΅© σ΅© σ΅© + πΆπ−ππ‘ (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) + πΆ∫ π‘/2 0 σ΅© σ΅© σ΅© σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ₯π π’1 σ΅©σ΅©σ΅©σ΅©πΏ2 1 (1 + π‘ − π)−(π/8+π/4) βΔπ’β2πΏ2 βΔπ’βπ−1 πΏ∞ ππ σ΅© σ΅© σ΅© σ΅© + πΆ(1 + π‘)−(π/8+π/4+1/2) σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + πΆπ−ππ‘ σ΅©σ΅©σ΅©σ΅©ππ+4 π’0 σ΅©σ΅©σ΅©σ΅©πΏ2 π‘ + πΆ ∫ (1 + π‘ − π)−π/8−1/2 βΔπ’βπΏ2 π‘/2 π‘/2 + πΆ∫ σ΅© σ΅© × σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ Δπ’σ΅©σ΅©σ΅©σ΅©πΏ2 βΔπ’βπ−1 πΏ∞ ππ 0 σ΅© σ΅© + πΆ ∫ π−π(π‘−π) σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ Δπ’σ΅©σ΅©σ΅©σ΅©πΏ2 βΔπ’βππΏ∞ ππ π‘/2 π‘ σ΅© σ΅© + πΆ ∫ π−π(π‘−π) σ΅©σ΅©σ΅©σ΅©ππ₯π+2 π (Δπ’)σ΅©σ΅©σ΅©σ΅©πΏ2 ππ 0 σ΅© σ΅© σ΅© σ΅© ≤ πΆ(1 + π‘)−(π/8+π/4) (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 ) 1 + πΆπ 0 ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) σ΅© σ΅© σ΅© σ΅© (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) + πΆπ π+1 ∫ π‘/2 0 σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) 1 (1 + π‘ − π)−(π/8+π/4) (1 + π)−(π/4+1) π‘/2 + πΆ∫ 0 × (1 + π)−(π/4+1/2)(π−1) ππ π‘/2 + πΆπ π+1 ∫ (1 + π‘ − π)−π/8−1/2 (1 + π)−(π/4+π/4) π‘/2 π‘ σ΅© σ΅© + πΆ ∫ π−π(π‘−π) σ΅©σ΅©σ΅©σ΅©ππ₯π+4 π’σ΅©σ΅©σ΅©σ΅©πΏ2 βΔπ’βππΏ∞ ππ × (1 + π)−(π/4+1/2)(π−1) ππ + πΆπ π‘ −π(π‘−π) ∫ π 0 0 ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) −(π/8+((π−2)+ +2)/4) (1 + π) σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × (σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) 1 × (1 + π)−(π/4+1/2)π ππ ≤ πΆ(1 + π‘) (1 + π‘ − π)−(π/8+π/4+1/2) βΔπ’β2πΏ2 βΔπ’βπ−1 πΏ∞ ππ π‘ σ΅© σ΅©2 + πΆ ∫ (1 + π‘ − π)−(π/8+1/2) σ΅©σ΅©σ΅©σ΅©ππ₯π Δπ’σ΅©σ΅©σ΅©σ΅©πΏ2 βΔπ’βπ−1 πΏ∞ ππ π‘ π+1 σ΅© σ΅© (1 + π‘ − π)−(π/8+π/4+1/2) σ΅©σ΅©σ΅©π (Δπ’)σ΅©σ΅©σ΅©πΏ1 ππ π‘ σ΅© σ΅© + πΆ ∫ (1 + π‘ − π)−(π/8+1/2) σ΅©σ΅©σ΅©σ΅©ππ₯π π (Δπ’)σ΅©σ΅©σ΅©σ΅©πΏ1 ππ π‘ −ππ‘ (61) + πΆπ π+1 ∫ −(π/8+π/4) π‘/2 0 σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × {(σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) + π π+1 } . 1 (59) (1 + π‘ − π)−(π/8+π/4+1/2) (1 + π)−(π/4+1) × (1 + π)−(π/4+1/2)(π−1) ππ π‘ + πΆπ π+1 ∫ (1 + π‘ − π)−(π/8+1/2) (1 + π)−(π/4+π/2+1) π‘/2 × (1 + π)−(π/4+1/2)(π−1) ππ Thus σ΅© σ΅© (1 + π‘)π/8+π/4 σ΅©σ΅©σ΅©σ΅©ππ₯π T (π’)σ΅©σ΅©σ΅©σ΅©πΏ2 ≤ πΆπΈ0 + πΆπ π+1 . π‘ (60) + πΆπ π+1 ∫ π−π(π‘−π) (1 + π)−(π/8+(π+4)/4) 0 Journal of Applied Mathematics 7 π−1 × (1 + π)−(π/4+1/2)π ππ × (βΔΜ π’βπΏ∞ + βΔπ’βπΏ∞ ) ππ π‘ ≤ πΆ(1 + π‘)−(π/8+π/4+1/2) σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© σ΅© × {(σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©πΏ1 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»Μ −2 + σ΅©σ΅©σ΅©π’0 σ΅©σ΅©σ΅©π»π +4 + σ΅©σ΅©σ΅©π’1 σ΅©σ΅©σ΅©π»π ) + π π+1 } . 1 (62) + πΆ ∫ π−π(π‘−π) 0 σ΅© σ΅© σ΅© σ΅© × {(σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ ΔΜ π’σ΅©σ΅©σ΅©σ΅©πΏ2 + σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ ΔΜ π’σ΅©σ΅©σ΅©σ΅©πΏ2 ) × βΔ (Μ π’ − π’)βπΏ∞ + (βΔΜ π’βπΏ∞ + βΔπ’βπΏ∞ ) σ΅© σ΅© × σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ Δ (Μ π’ − π’)σ΅©σ΅©σ΅©σ΅©πΏ2 } Thus π−1 σ΅© σ΅© (1 + π‘)π/8+π/4+1/2 σ΅©σ΅©σ΅©σ΅©ππ₯π T(π’)π‘ σ΅©σ΅©σ΅©σ΅©πΏ2 ≤ πΆπΈ0 + πΆπ π+1 . × (βΔΜ π’βπΏ∞ + βΔπ’βπΏ∞ ) (63) ≤ πΆπ π βΜ π’ − π’βπ ∫ π‘/2 (1 + π‘ − π)−(π/8+π/4) 0 Combining (60), (63) and taking π = 2πΆπΈ0 and πΈ0 suitably small yield ππ × (1 + π)−(π/4+1+(π/4+1/2)(π−1)) ππ π‘ + πΆπ π βΜ π’ − π’βπ ∫ (1 + π‘ − π)−π/8−1/2 π‘/2 βT (π’)βπ ≤ 2πΆπΈ0 . (64) −(π/4+π/4+1/2+(π/4+1/2)(π−1)) × (1 + π) ππ π‘ + πΆπ π βΜ π’ − π’βπ ∫ π−π(π‘−π) For π’Μ, π’ ∈ ππ , by using (58), we have 0 × (1 + π)−(π/8+((π−2)+ +2)/4+(π/4+1/2)π) ππ π‘ T (Μ π’) − π (Δπ’)] ππ. (65) π’) − T (π’) = ∫ πΊ (π‘ − π) ∗ Δ [π (ΔΜ 0 (66) Exploiting (65), (38) Lemma 6, and (54), for π ≤ π + 4, we obtain σ΅© σ΅©σ΅© π σ΅©σ΅©ππ₯ (T (Μ π’) − T (π’))σ΅©σ΅©σ΅©σ΅©πΏ2 σ΅© σ΅© σ΅© ≤ ∫ σ΅©σ΅©σ΅©σ΅©ππ₯π πΊ (π‘ − π) ∗ Δ [π (ΔΜ π’) − π (Δπ’)]σ΅©σ΅©σ΅©σ΅©πΏ2 ππ 0 π‘/2 σ΅© σ΅© π’) − π (Δπ’))σ΅©σ΅©σ΅©πΏ1 ππ (1 + π‘ − π)−(π/8+π/4) σ΅©σ΅©σ΅©(π (ΔΜ 0 π‘ σ΅© σ΅© + πΆ ∫ (1 + π‘ − π)−π/8 σ΅©σ΅©σ΅©σ΅©ππ₯π (π (ΔΜ π’) − π (Δπ’))σ΅©σ΅©σ΅©σ΅©πΏ1 ππ π‘/2 π‘ σ΅© σ΅© π’) − π (Δπ’))σ΅©σ΅©σ΅©σ΅©πΏ2 ππ + πΆ ∫ π−π(π‘−π) σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ (π (ΔΜ 0 ≤ πΆ∫ π‘/2 0 π’βπΏ2 + βΔπ’βπΏ2 ) (1 + π‘ − π)−(π/8+π/4) (βΔΜ π−1 π’βπΏ∞ + βΔπ’βπΏ∞ ) × βΔ (Μ π’ − π’)βπΏ2 (βΔΜ π‘ which implies σ΅© σ΅© π’) − T (π’))σ΅©σ΅©σ΅©σ΅©πΏ2 ≤ πΆπ π βΜ π’ − π’βπ . (1 + π‘)π/8+π/4 σ΅©σ΅©σ΅©σ΅©ππ₯π (T (Μ (67) Similarly for π ≤ π , from (61), (39), and (54), we have π‘ ≤ πΆ∫ ≤ πΆπ π (1 + π‘)−(π/8+π/4) βΜ π’ − π’βπ , ππ σ΅©σ΅© π σ΅© σ΅©σ΅©ππ₯ (T (Μ π’) − T (π’))π‘ σ΅©σ΅©σ΅©σ΅©πΏ2 σ΅© π‘ σ΅© σ΅© π’) − π (Δπ’)]σ΅©σ΅©σ΅©σ΅©πΏ2 ππ ≤ ∫ σ΅©σ΅©σ΅©σ΅©ππ₯π πΊπ‘ (π‘ − π) ∗ Δ [π (ΔΜ 0 π‘/2 σ΅© σ΅© π’)−π (Δπ’))σ΅©σ΅©σ΅©πΏ1 ππ ≤ πΆ ∫ (1+π‘ − π)−(π/8+π/4+1/2) σ΅©σ΅©σ΅©(π (ΔΜ 0 π‘ σ΅© σ΅© + πΆ ∫ (1+π‘ − π)−(π/8+1/2) σ΅©σ΅©σ΅©σ΅©ππ₯π (π (ΔΜ π’)−π (Δπ’))σ΅©σ΅©σ΅©σ΅©πΏ1 ππ π‘/2 π‘ σ΅© σ΅© + πΆ ∫ π−π(π‘−π) σ΅©σ΅©σ΅©σ΅©ππ₯π+2 (π (ΔΜ π’) − π (Δπ’))σ΅©σ΅©σ΅©σ΅©πΏ2 ππ 0 π ≤ πΆπ (1 + π‘)−(π/8+π/4+1/2) βΜ π’ − π’βπ , (68) −π/8−1/2 + πΆ ∫ (1 + π‘ − π) π‘/2 σ΅© σ΅© σ΅© σ΅© × {(σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ ΔΜ π’σ΅©σ΅©σ΅©σ΅©πΏ2 + σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ ΔΜ π’σ΅©σ΅©σ΅©σ΅©πΏ2 ) βΔ (Μ π’ − π’)βπΏ2 σ΅© σ΅© + (βΔΜ π’βπΏ2 + βΔπ’βπΏ2 ) σ΅©σ΅©σ΅©σ΅©ππ₯(π−2)+ Δ (Μ π’ − π’)σ΅©σ΅©σ΅©σ΅©πΏ2 } which implies σ΅© σ΅© π’) − T (π’))π‘ σ΅©σ΅©σ΅©σ΅©πΏ2 ≤ πΆπ π βΜ π’ − π’βπ . 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