18-447 Computer Architecture Lecture 8: Microprogramming and Pipelined Microarchitectures Prof. Onur Mutlu Carnegie Mellon University Spring 2012, 2/13/2012 Reminder: Homeworks Homework 2 Due today ISA concepts, ISA vs. microarchitecture, microcoded machines Homework 3 Will be out tomorrow 2 Homework 1 Grades Number of Students 35 30 25 20 15 10 5 0 50 60 70 80 90 100 110 Grade Average Median Max Min 100 103 110 55 Max Possible Points 110 Total number of students 56 3 Reminder: Lab Assignments Getting your Lab 1 fully correct We will allow resubmission once, just for the purposes of testing the correctness of your revised code (no regrading) Lab Assignment 2 Due Friday, Feb 17, at the end of the lab Individual assignment No collaboration; please respect the honor code Lab Assignment 3 Will be out Wednesday 4 Reminder: Extra Credit for Lab Assignment 2 Complete your normal (single-cycle) implementation first, and get it checked off in lab. Then, implement the MIPS core using a microcoded approach similar to what we are discussing in class. We are not specifying any particular details of the microcode format or the microarchitecture; you should be creative. For the extra credit, the microcoded implementation should execute the same programs that your ordinary implementation does, and you should demo it by the normal lab deadline. 5 Readings for Today Pipelining P&H Chapter 4.5-4.8 6 Readings for Next Lecture Required Pipelined LC-3b Microarchitecture Handout Optional Hamacher et al. book, Chapter 6, “Pipelining” 7 Announcement: Discussion Sessions Lab sessions are really discussion sessions TAs will lead recitations Go over past lectures Answer and ask questions Solve problems and homeworks Please attend any session you wish Tue 10:30am-1:20pm (Chris) Thu 1:30-4:20pm (Lavanya) Fri 6:30-9:20pm (Abeer) 8 An Exercise in Microcoding 9 A Simple LC-3b Control and Datapath 10 18, 19 MAR <! PC PC <! PC + 2 33 MDR <! M R R 35 IR <! MDR 32 RTI To 8 1011 BEN<! IR[11] & N + IR[10] & Z + IR[9] & P To 11 1010 [IR[15:12]] ADD To 10 BR AND DR<! SR1+OP2* set CC 1 0 XOR JMP TRAP To 18 DR<! SR1&OP2* set CC [BEN] JSR SHF LEA LDB STW LDW STB 1 PC<! PC+LSHF(off9,1) 12 DR<! SR1 XOR OP2* set CC 15 4 MAR<! LSHF(ZEXT[IR[7:0]],1) To 18 [IR[11]] 0 R To 18 PC<! BaseR To 18 MDR<! M[MAR] R7<! PC 22 5 9 To 18 0 28 1 20 R7<! PC PC<! BaseR R 21 30 PC<! MDR To 18 To 18 R7<! PC PC<! PC+LSHF(off11,1) 13 DR<! SHF(SR,A,D,amt4) set CC To 18 14 2 DR<! PC+LSHF(off9, 1) set CC To 18 MAR<! B+off6 6 7 MAR<! B+LSHF(off6,1) 3 MAR<! B+LSHF(off6,1) MAR<! B+off6 To 18 29 MDR<! M[MAR[15:1]’0] NOTES B+off6 : Base + SEXT[offset6] PC+off9 : PC + SEXT[offset9] *OP2 may be SR2 or SEXT[imm5] ** [15:8] or [7:0] depending on MAR[0] R 31 R DR<! SEXT[BYTE.DATA] set CC MDR<! SR MDR<! M[MAR] 27 R R MDR<! SR[7:0] 16 DR<! MDR set CC M[MAR]<! MDR To 18 To 18 R To 18 24 23 25 17 M[MAR]<! MDR** R R To 19 R State Machine for LDW 10APPENDIX C. THE MICROARCHITECTURE OF THE LC-3B, BASIC MACHINE Microsequencer COND1 BEN R J[4] J[3] J[2] IR[11] Ready Branch J[5] COND0 J[1] Addr. Mode J[0] 0,0,IR[15:12] 6 IRD 6 Address of Next State Figure C.5: The microsequencer of the LC-3b base machine State 18 (010010) State 33 (100001) State 35 (100011) State 32 (100000) State 6 (000110) State 25 (011001) State 27 (011011) unused opcodes, the microarchitecture would execute a sequence of microinstructions, starting at state 10 or state 11, depending on which illegal opcode was being decoded. In both cases, the sequence of microinstructions would respond to the fact that an instruction with an illegal opcode had been fetched. Several signals necessary to control the data path and the microsequencer are not among those listed in Tables C.1 and C.2. They are DR, SR1, BEN, and R. Figure C.6 shows the additional logic needed to generate DR, SR1, and BEN. The remaining signal, R, is a signal generated by the memory in order to allow the C.4. THE CONTROL STRUCTURE 11 IR[11:9] IR[11:9] DR SR1 111 IR[8:6] DRMUX SR1MUX (b) (a) IR[11:9] N Z P Logic BEN (c) Figure C.6: Additional logic required to provide control signals R IR[15:11] BEN Microsequencer 6 Control Store 2 6 x 35 35 Microinstruction 9 (J, COND, IRD) 26 10APPENDIX C. THE MICROARCHITECTURE OF THE LC-3B, BASIC MACHINE COND1 BEN R J[4] J[3] J[2] IR[11] Ready Branch J[5] COND0 J[1] 0,0,IR[15:12] 6 IRD 6 Address of Next State Figure C.5: The microsequencer of the LC-3b base machine Addr. Mode J[0] .M LD A R .M LD D R . IR LD . BE LD N . RE LD G . CC LD .PC Ga t eP Ga C t eM Ga DR t eA Ga L U t eM Ga ARM t eS HF UX PC MU X DR MU SR X 1M AD U X DR 1M UX AD DR 2M UX MA RM UX AL UK MI O. E R. W N DA TA LS .SIZ HF E 1 J nd D Co IR LD 000000 (State 0) 000001 (State 1) 000010 (State 2) 000011 (State 3) 000100 (State 4) 000101 (State 5) 000110 (State 6) 000111 (State 7) 001000 (State 8) 001001 (State 9) 001010 (State 10) 001011 (State 11) 001100 (State 12) 001101 (State 13) 001110 (State 14) 001111 (State 15) 010000 (State 16) 010001 (State 17) 010010 (State 18) 010011 (State 19) 010100 (State 20) 010101 (State 21) 010110 (State 22) 010111 (State 23) 011000 (State 24) 011001 (State 25) 011010 (State 26) 011011 (State 27) 011100 (State 28) 011101 (State 29) 011110 (State 30) 011111 (State 31) 100000 (State 32) 100001 (State 33) 100010 (State 34) 100011 (State 35) 100100 (State 36) 100101 (State 37) 100110 (State 38) 100111 (State 39) 101000 (State 40) 101001 (State 41) 101010 (State 42) 101011 (State 43) 101100 (State 44) 101101 (State 45) 101110 (State 46) 101111 (State 47) 110000 (State 48) 110001 (State 49) 110010 (State 50) 110011 (State 51) 110100 (State 52) 110101 (State 53) 110110 (State 54) 110111 (State 55) 111000 (State 56) 111001 (State 57) 111010 (State 58) 111011 (State 59) 111100 (State 60) 111101 (State 61) 111110 (State 62) 111111 (State 63) 10APPENDIX C. THE MICROARCHITECTURE OF THE LC-3B, BASIC MACHINE COND1 BEN R J[4] J[3] J[2] IR[11] Ready Branch J[5] COND0 J[1] 0,0,IR[15:12] 6 IRD 6 Address of Next State Figure C.5: The microsequencer of the LC-3b base machine Addr. Mode J[0] The Microsequencer: Some Questions When is the IRD signal asserted? What happens if an illegal instruction is decoded? What are condition (COND) bits for? How is variable latency memory handled? How do you do the state encoding? Minimize number of state variables Start with the 16-way branch Then determine constraint tables and states dependent on COND 20 The Control Store: Some Questions What control signals can be stored in the control store? vs. What control signals have to be generated in hardwired logic? i.e., what signal cannot be available without processing in the datapath? 21 Variable-Latency Memory The ready signal (R) enables memory read/write to execute correctly Example: transition from state 33 to state 35 is controlled by the R bit asserted by memory when memory data is available Could we have done this in a single-cycle microarchitecture? 22 The Microsequencer: Advanced Questions What happens if the machine is interrupted? What if an instruction generates an exception? How can you implement a complex instruction using this control structure? Think REP MOVS 23 The Power of Abstraction The concept of a control store of microinstructions enables the hardware designer with a new abstraction: microprogramming The designer can translate any desired operation to a sequence microinstructions All the designer needs to provide is The sequence of microinstructions needed to implement the desired operation The ability for the control logic to correctly sequence through the microinstructions Any additional datapath control signals needed (no need if the operation can be “translated” into existing control signals) 24 Let’s Do Some Microprogramming Implement REP MOVS in the LC-3b microarchitecture What changes, if any, do you make to the state machine? datapath? control store? microsequencer? Show all changes and microinstructions Coming up in Homework 3 25 Aside: Alignment Correction in Memory Remember unaligned accesses LC-3b has byte load and byte store instructions that move data not aligned at the word-address boundary Convenience to the programmer/compiler How does the hardware ensure this works correctly? Take a look at state 29 for LDB State 17 for STB Additional logic to handle unaligned accesses 26 Aside: Memory Mapped I/O Address control logic determines whether the specified address of LDx and STx are to memory or I/O devices Correspondingly enables memory or I/O devices and sets up muxes Another instance where the final control signals (e.g., MEM.EN or INMUX/2) cannot be stored in the control store Dependent on address 27 Advantages of Microprogrammed Control Allows a very simple datapath to do powerful computation by controlling the datapath (using a sequencer) Enables easy extensibility of the ISA High-level ISA translated into microcode (sequence of microinstructions) Microcode enables a minimal datapath to emulate an ISA Microinstructions can be thought of a user-invisible ISA Can support a new instruction by changing the ucode Can support complex instructions as a sequence of simple microinstructions If I can sequence an arbitrary instruction then I can sequence an arbitrary “program” as a microprogram sequence will need some new state (e.g. loop counters) in the microcode for sequencing more elaborate programs 28 Update of Machine Behavior The ability to update/patch microcode in the field (after a processor is shipped) enables Ability to add new instructions without changing the processor! Ability to “fix” buggy hardware implementations Examples IBM 370 Model 145: microcode stored in main memory, can be updated after a reboot B1700 microcode can be updated while the processor is running User-microprogrammable machine! 29 Microcoded Multi-Cycle MIPS Design P&H, Appendix D Any ISA can be implemented this way We will not cover this in class However, you can do an extra credit assignment for Lab 2 30 Microcoded Multi-Cycle MIPS Design [Based on original figure from P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] 31 Control Logic for MIPS FSM [Based on original figure from P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] 32 Microprogrammed Control for MIPS FSM [Based on original figure from P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] 33 Microcode storage ALUSrcA IorD Datapath IRWrite control PCWrite outputs PCWriteCond …. Outputs n-bit Input mPC input 1 Microprogram counter k-bit “control” output Horizontal Microcode Sequencing control Adder Address select logic Inputs from instruction register opcode field [Based on original figure from P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] Control Store: 2n k bit (not including sequencing) 34 Vertical Microcode 1-bit signal means do this RT (or combination of RTs) “PC PC+4” “PC ALUOut” Datapath “PC PC[ 31:28 ],IR[ 25:0 ],2’b00” control “IR MEM[ PC ]” outputs “A RF[ IR[ 25:21 ] ]” “B RF[ IR[ 20:16 ] ]” ……. …………. Microcode storage Outputs n-bit mPC input Input m-bit input 1 Microprogram counter Adder Address select logic Inputs from instruction register opcode field ROM k-bit output ALUSrcA IorD IRWrite PCWrite PCWriteCond …. [Based on original figure from P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] Sequencing control If done right (i.e., m<<n, and m<<k), two ROMs together (2nm+2mk bit) should be smaller than horizontal microcode ROM (2nk bit) 35 Nanocode and Millicode Nanocode: a level below mcode Millicode: a level above mcode mprogrammed control for sub-systems (e.g., a complicated floatingpoint module) that acts as a slave in a mcontrolled datapath ISA-level subroutines hardcoded into a ROM that can be called by the mcontroller to handle complicated operations In both cases, we avoid complicating the main mcontroller 36 Nanocode Concept Illustrated a “mcoded” processor implementation ROM mPC processor datapath We refer to this as “nanocode” when a mcoded subsystem is embedded in a mcoded system a “mcoded” FPU implementation ROM mPC arithmetic datapath 37 Multi-Cycle vs. Single-Cycle uArch Advantages Disadvantages You should be very familiar with this right now 38 Microprogrammed vs. Hardwired Control Advantages Disadvantages You should be very familiar with this right now 39 Can We Do Better? What limitations do you see with the multi-cycle design? Limited concurrency Some hardware resources are idle during different phases of instruction processing cycle “Fetch” logic is idle when an instruction is being “decoded” or “executed” Most of the datapath is idle when a memory access is happening 40 Can We Use the Idle Hardware to Improve Concurrency? Goal: Concurrency throughput (more “work” completed in one cycle) Idea: When an instruction is using some resources in its processing phase, process other instructions on idle resources not needed by that instruction E.g., when an instruction is being decoded, fetch the next instruction E.g., when an instruction is being executed, decode another instruction E.g., when an instruction is accessing data memory (ld/st), execute the next instruction E.g., when an instruction is writing its result into the register file, access data memory for the next instruction 41 Pipelining: Basic Idea More systematically: Pipeline the execution of multiple instructions Analogy: “Assembly line processing” of instructions Idea: Divide the instruction processing cycle into distinct “stages” of processing Ensure there are enough hardware resources to process one instruction in each stage Process a different instruction in each stage Instructions consecutive in program order are processed in consecutive stages Benefit: Increases instruction processing throughput (1/CPI) Downside: Start thinking about this… 42 Example: Execution of Four Independent ADDs Multi-cycle: 4 cycles per instruction F D E W F D E W F D E W F D E W Time Pipelined: 4 cycles per 4 instructions (steady state) F D E W F D E W F D E W F D E W Time 43 The Laundry Analogy Time 6 PM 7 8 9 10 11 12 1 2 AM Task order A B C D “place one dirty load of clothes in the washer” “when the washer is finished, place the wet load in the dryer” 1 6 PM 8 9 10 11 dry 12 2 AM “when the dryer is7 finished, take out the load and fold” Time “when folding is finished, ask your roommate (??) to put the clothes Task away” order A B C - steps to do a load are sequentially dependent - no dependence between different loads - different steps do not share resources D Based on original figure from [P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] 44 Pipelining Multiple Loads of Laundry 6 PM 7 8 9 10 11 12 1 2 AM 6 PM TimeA 7 8 9 10 11 12 1 2 AM 7 8 9 10 11 12 1 2 AM 7 8 9 10 11 12 1 2 AM Time Task order Task B order A C D B C D 6 PM Time Task order 6 PM Time A Task order B A C B D C D Based on original figure from [P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] - 4 loads of laundry in parallel - no additional resources - throughput increased by 4 - latency per load is the same 45 Pipelining Multiple Loads of Laundry: In Practice Time 6 PM 7 8 9 10 11 12 1 2 AM 6 PM 7 8 9 10 11 12 1 2 AM 6 PM 7 8 9 10 11 12 1 2 AM 6 PM 7 8 9 10 11 12 1 2 AM Task order A Time B Task order C A D B C D Time Task order TimeA Task B order C A D B C the slowest step decides throughput D Based on original figure from [P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] 46 Pipelining Multiple Loads of Laundry: In Practice 6 PM 7 8 9 10 11 12 1 2 AM A 6 PM Time 7 8 9 10 11 12 1 2 AM 6 PM 7 8 9 10 11 12 1 2 AM Task order 6 PM Time A 7 8 9 10 11 12 1 2 AM Time Task order Task B order C A D B C D Time Task B order C A B D A B A B C D Throughput restored (2 loads per hour) using 2 dryers Based on original figure from [P&H CO&D, COPYRIGHT 2004 Elsevier. ALL RIGHTS RESERVED.] 47 We did not cover the following slides in lecture. These are for your preparation for the next lecture. An Ideal Pipeline Goal: Increase throughput with little increase in cost (hardware cost, in case of instruction processing) Repetition of identical operations Repetition of independent operations No dependencies between repeated operations Uniformly partitionable suboperations The same operation is repeated on a large number of different inputs Processing an be evenly divided into uniform-latency suboperations (that do not share resources) Good examples: automobile assembly line, doing laundry What about instruction processing pipeline? 49 Ideal Pipelining combinational logic (F,D,E,M,W) T psec T/2 ps (F,D,E) T/3 ps (F,D) BW=~(1/T) BW=~(2/T) T/2 ps (M,W) T/3 ps (E,M) T/3 ps (M,W) BW=~(3/T) 50 More Realistic Pipeline: Throughput Nonpipelined version with delay T BW = 1/(T+S) where S = latch delay T ps k-stage pipelined version BWk-stage = 1 / (T/k +S ) BWmax = 1 / (1 gate delay + S ) T/k ps T/k ps 51 More Realistic Pipeline: Cost Nonpipelined version with combinational cost G Cost = G+L where L = latch cost G gates k-stage pipelined version Costk-stage = G + Lk G/k G/K 52