5.3 Transforming Quadratic Functions The “Parent” Function of the Quadratic: f ( x) x 2 5 We can transform the quadratic the same way we did with the absolute value function. f(x) = a(x –h)2 +k 4 3 2 1 -5 -4 -3 -2 -1 1 2 3 4 5 -1 -2 a, h, and k do the same things as before -3 -4 -5 Notice how it increases. Up 1 over 1. Up 3 over 1. Up 5 over 1. Describe, in order, the sequence of transformations of each function and then graph the function by hand. 2 1) f ( x) 2 x 4 2) f ( x) 1 x 2 2 5 3) f ( x) 1 x 12 2 3 2 Down 4 Right 2 Left 1 Goes up twice as fast. Down 5 for vertex. ½ as tall. Might be best to plug in some points, then use symmetry. Up 2 for vertex Reflected. 1/3 as tall. Again, plug in some points 5 5 5 4 4 4 3 3 3 2 2 2 1 1 1 -5 -4 -3 -2 -1 1 2 3 4 5 -5 -4 -3 -2 -1 1 2 3 4 5 -5 -4 -3 -2 -1 1 -1 -1 -1 -2 -2 -2 -3 -3 -3 -4 -4 -4 -5 -5 -5 2 3 4 5 Write a function for the graph below. Right 3 Up 4 8 6 So then f(x) = a(x -3)2 + 4 Now you have to see whether there is an ‘a’ or not. So pick an (x,y) point, plug in-8 and check. I picked (2, 3) 3 = a(2 – 3)2 + 4 -1 = a(-1)2 So a = -1 4 2 -6 -4 -2 2 -2 -4 -6 -8 4 6 8 Write a function for the graph below. 8 Left 2 Down 2 So f(x) = a(x + 2)2 -2 6 4 Point (-1, 0) 2 0 = a( -1 + 2)2 – 2 2 = a(1)2 a=2 f(x) = 2(x +2)2 -2 -8 -6 -4 -2 2 -2 -4 -6 -8 4 6 8 Write a function for the graph below. Left 4 Up 7 f(x) = a(x +4)2 +7 8 6 Point (-2, 5) 4 5 = a(-2 + 4)2 + 7 2 -2 = a(2)2 -8 -6 -4 -2 2 a = -2/4 = -1/2 -2 f(x) = -1/2(x + 4)2 + 7 -4 -6 -8 4 6 8 5.3 Problems to do: Pg. 255 #13-31 odd, 42, 43, 45, 47, 51 This is an important section so make sure you know what you are doing. Tutoring every M, W, T after school San Juan. Midterm Take home due Thursday morning. Work together, but no freeloaders! Fear is the main source of superstition, and one of the main sources of cruelty. To conquer fear is the beginning of wisdom.