Hindawi Publishing Corporation Boundary Value Problems Volume 2009, Article ID 231802, 13 pages doi:10.1155/2009/231802 Research Article Cauchy-Neumann Problem for Second-Order General Schrödinger Equations in Cylinders with Nonsmooth Bases Nguyen Manh Hung,1 Tran Xuan Tiep,2 and Nguyen Thi Kim Son1 1 2 Department of Mathematics, Hanoi University of Education, Hanoi, Vietnam Faculty of Applied Mathematics and Informatics, Hanoi University of Technology, Hanoi, Vietnam Correspondence should be addressed to Nguyen Thi Kim Son, mt02 02@yahoo.com Received 26 February 2009; Accepted 18 June 2009 Recommended by Gary Lieberman The main goal of this paper is to obtain the regularity of weak solutions of Cauchy-Neumann problems for the second-order general Schrödinger equations in domains with conical points on the boundary of the bases. Copyright q 2009 Nguyen Manh Hung et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. 1. Introduction and Notations Cauchy-Dirichlet problem for general Schrödinger systems in domains containing conical points has been investigated in 1, 2. Cauchy-Neumann problems have been dealt with for hyperbolic systems in 3 and for parabolic equations in 4–6. In this paper we consider the Cauchy-Neumann problem for the second-order general Schrödinger equations in infinite cylinders with nonsmooth bases. The solvability of this problem has been considered in 7. Our main purpose here is to study the regularity of weak solution of the mentioned problem. The paper consists of six sections. In Section 1, we introduce some notations and functional spaces used throughout the text. A weak solution of the problem is defined in Section 2 together with some results of its unique existence and smoothness with the time variable. Our main result, the regularity with respect to both of time and spatial variables of the weak solution of the problem, is stated in Section 3. The proof of this result is given in Section 4 with some auxiliary lemmas. In Section 5 we specify that result for the classical Schrödinger equations in quantum mechanics. Finally, some conclusions of our results are given in Section 6. 2 Boundary Value Problems Let Ω be a bounded domain in Rn , n 2; Ω and ∂Ω denote the closure and the boundary of Ω in Rn . We suppose that Γ ∂Ω \ {0} is an infinitely differentiable surface everywhere except the coordinate origin and Ω coincides with the cone K {x : x/|x| ∈ G} in a neighborhood of the origin point 0, where G is a smooth domain on the unit sphere Sn−1 in Rn . We begin by introducing some notations and functional spaces which are used fluently in the rest. Q∞ , S∞ Γ×0, ∞ , x x1 , . . . , xn ∈ Denote Q∞ Ω×0, ∞ , Q∞ is the closure of Ω, ∂xj ∂/∂xj , uxj ∂xj u, utk ∂k u/∂tk , r |x| x12 · · · xn2 . For each multi-index α α1 , . . . , αn αi ∈ N, i 1, . . . , n , set |α| α1 · · · αn , ∂α ∂αx ∂αx11 · · · ∂αxnn . o In this paper we will use usual functional spaces: C∞ Ω , L2 Ω , H m Ω , where m ∈ N see 1, 2 for the precise definitions . Denote Hβl Ω is a space of all measurable complex functions ux, t that satisfy ⎛ uH l Ω ⎝ β ⎞1/2 |α|l Ω r 2β|α|−l |∂ u| dx⎠ α 2 < ∞. 1.1 H m,l e−γt , Q∞ γ > 0 —a space of all measurable complex functions ux, t that have generalized derivatives up to order m with respect to x and up to order l with respect to t with the norm ⎛ uH m,l e−γt ,Q∞ ⎝ ⎡ ⎣ Q∞ |α|m ⎞1/2 ⎤ l |∂α u|2 |utj |2 ⎦e−2γt dx dt⎠ < ∞. 1.2 j1 Hβl,k e−γt , Q∞ —a space of all measurable complex functions ux, t with the norm ⎛ uH l,k e−γt ,Q∞ ⎝ β ⎡ ⎣ Q∞ r 2β|α|−l 2 |∂ u| α |α|l k ⎤ |utj | 2 ⎦ −2γt e ⎞1/2 dx dt⎠ < ∞. 1.3 j1 Hβl e−γt , Q∞ —a weighted space with the norm ⎛ uH l e−γt ,Q∞ ⎝ β |α|jl Q∞ ⎞1/2 r 2β|α|j−l |∂α utj |2 e−2γt dx dt⎠ < ∞. 1.4 Let X be a Banach space. Denote by L∞ 0, ∞; X a space of all measurable functions u : 0, ∞ → X, t → ut with the norm uL∞ 0,∞;X ess sup0<t<∞ ut X < ∞. 1.5 Boundary Value Problems 3 2. Formulation of the Problem and Obvious Results In this paper we consider following problem: iLu − ut f 2.1 in Q∞ , ux, 0 0 on Ω, Nu 0 2.2 2.3 on S∞ , where L is a formal self-adjoint differential operator of second-order defined in Q∞ : Lu Lx, t, ∂ u n ∂u ∂ ajk x, t ax, t u, ∂xj ∂xk j,k1 2.4 ajk x, t akj x, t for all j, k 1, 2, . . . , n; ax, t ax, t , for all x, t ∈ Q∞ , and n Nu Nx, t, ∂ u ajk x, t j,k1 ∂u cos xj , ν ∂xk 2.5 is the conormal derivative on S∞ , ν is the unit exterior normal to S∞ , f is a given function. Set ⎛ ⎞ ∂u ∂v ⎝ Bt, u, v ajk x, t − ax, t uv⎠dx. ∂xk ∂xj Ω j,k1 n 2.6 Throughout this paper, we assume that the coefficients of L are infinitely differentiable and bounded in Q∞ together with all their derivatives. Moreover, suppose that ajk are continuous in x ∈ Ω uniformly with respect to t ∈ 0, ∞ for all j, k 1, . . . , n. In addition, assume that Bt, ·, · is H 1 Ω —coercive uniformly with respect to t ∈ 0, ∞ , that is, Bt, u, u μ0 u2H 1 Ω ∀u ∈ H 1 Ω , t ∈ 0, ∞ , 2.7 where μ0 is a positive constant independent of u and t. The function ux, t is called a weak solution in the space H 1,0 e−γt , Q∞ of the problem 2.1 –2.3 if ux, t ∈ H 1,0 e−γt , Q∞ , satisfying for each T ∈ 0, ∞ n j,k1 Q∞ ajk ∂u ∂η dx dt − ∂xk ∂xj auη dx dt i Q∞ uηt dx dt i Q∞ fη dx dt, 2.8 Q∞ for all test functions ηx, t ∈ H 1,1 e−γt , Q∞ , ηx, t 0 for all t ∈ T, ∞ . Now we derive here some our obvious results of the unique existence and smoothness with respect to time variable of the weak solution of the problem 2.1 –2.3 as lemmas of main results. 4 Boundary Value Problems Lemma 2.1. The solvability of the problem, (see [7, Theorems 3.1, 3.2]). There exists a positive number γ0 such that if f, ft ∈ L∞ 0, ∞, L2 Ω then for every γ > γ0 , the Cauchy-Neumann problem 2.1 – 2.3 has exactly one weak solution ux, t in H 1,0 e−γt , Q∞ , that satisfies 2 2 u2H 1,0 e−γt ,Q∞ C f L∞ 0,∞,L2 Ω ft L∞ 0,∞,L2 Ω , 2.9 where the constant C does not depend on u, f. The constant γ0 depends only on the operator L and the dimension of the space n. Lemma 2.2. The regularity with respect to time variable of the weak solution (see [7, Theorem 4.1]).Let h be a nonnegative integer. Suppose that ftk ∈ L∞ 0, ∞, L2 Ω for all k h 1, fx, 0 0 and if h 2 then ftk x, 0 0 for all k h − 1, for all x ∈ Ω. Then for every γ > 2h 1 γ0 , the weak solution ux, t of the problem 2.1 –2.3 has generalized derivatives with respect to time variable up to order h, which belong to H 1,0 e−γt , Q∞ , moreover uts 2H 1,0 e−γt ,Q∞ C h1 ftk 2 ∞ , L 0,∞,L2 Ω ∀s 0, 1, . . . , h, 2.10 k0 where C is a constant independent of u, f. 3. Formulation of the Main Result Let L0 x, t, ∂ be the principal homogenous part of Lx, t, ∂ . We can write L0 0, t, ∂ in the form L0 0, t, ∂ r −2 Lω, t, ∂ω , r∂r , 3.1 where r |x|, ω ω1 , . . . , ωn−1 is an arbitrary local coordinate system on Sn−1 , L is a linear operator with smooth coefficients. Denote λt is an eigenvalue of Neumann problem for following equation: Lω, t, λt , ∂ω vω 0, ω ∈ G. 3.2 It is well known in 8 that for each t ∈ 0, ∞ , the spectrum of this problem is an enumerable set of eigenvalues. Recall that γ0 is the positive real number in Lemma 2.1. Now, let us give the main result of the present paper. Theorem 3.1. Let l be a nonnegative integer. Assume that ux, t is a weak solution in the space H 1,0 e−γt , Q∞ with γ > 2l 5 γ0 of the problem 2.1 –2.3 and ftk ∈ L∞ 0, ∞, H0l Ω if k 3, ftk x, 0 0 if k l 1. In addition, suppose that in the strip 1−ε− n n Imλ l 2 − , 2 2 3.3 Boundary Value Problems 5 where ε > 0 or ε 0 according to n 2 or n > 2, there is no point from the spectrum of the Neumann problem for the equation 3.2 for all t ∈ 0, ∞ . Then we have u ∈ H0l2 e−γt , Q∞ and the following estimate holds u2H l2 e−γt ,Q 0 ∞ C 3 ftk 2 ∞ k0 L 0,∞,H0l Ω , 3.4 where C is a constant independent of u, f. 4. Proof of Theorem 3.1 By using the same arguments as in 1, 2 and Lemmas 2.1, 2.2, we can prove following lemma. Lemma 4.1. Let γ > 3γ0 arbitrary. Assume that ux, t is a weak solution of the problem 2.1 – 2.3 in the space H 1,0 e−γt , Q∞ and f, ft , ftt ∈ L∞ 0, ∞, L2 Ω , fx, 0 0. Then for almost all t ∈ 0, ∞ the equation n k,j1 ∂u ∂χ ajk dx − ∂x k ∂xj Ω Ω auχ dx i Ω ut f χ dx 4.1 holds for all functions χ χx ∈ H 1 Ω . Now we surround the origin by a neighborhood U0 with a sufficiently small diameter such that the intersection of Ω and U0 coincides with the cone K. We begin by proving some auxiliary lemmas. Lemma 4.2. Let ux, t be a weak solution in H 1,0 e−γt , Q∞ γ > 3γ0 of the problem 2.1 –2.3 such that ux, t 0 outside U0 . Moreover, we assume that f, ft , ftt ∈ L∞ 0, ∞, L2 Ω , fx, 0 0. Then for almost all t ∈ 0, ∞ , one has i if n 3 then u ∈ H12 Ω , 2 ii if n 2 then u ∈ H1ε Ω , where ε > 0 arbitrary. Proof. Because f, ft , ftt ∈ L∞ 0, ∞, L2 Ω , fx, 0 0, from Lemma 2.2 we have ut ∈ H 1,0 e−γt , Q∞ or ut ∈ L2 Ω for almost all t ∈ 0, ∞ . Following Lemma 4.1, ux, t is a solution of the Neumann problem for elliptic equation Lu F, 4.2 where F −iut f ∈ L2 Ω for almost all t ∈ 0, ∞ .Denote Ωk {x ∈ Ω : 2−k |x| 2−k1 }, k 1, 2, . . . . Let k0 be large enough such that Ωk0 −1 ⊂ U0 . By choosing a smooth domain Ωk0 such that Ωk0 ⊂ Ωk0 ⊂ Ωk0 −1 ∪ Ωk0 ∪ Ωk0 1 , from the theory of the regular of solutions of the boundary value problem for elliptic systems in smooth domains and near the piece smooth 6 Boundary Value Problems boundary of domain see 9 for reference , we have u ∈ H 2 Ωk0 for almost all t ∈ 0, ∞ and the following inequality holds ux, t |2H 2 Ω k0 ux, t 2 , L2 Ωk k0 0 C Fx, t 2L2 Ω 4.3 where C is a positive constant independent of u, F. It follows Ω k0 |∂α ux, t |2 dx C Ωk0 −1 ∪Ωk0 ∪Ωk0 1 |Fx, t |2 |ux, t |2 dx, ∀|α| 2. 4.4 By choosing k1 > k0 and setting x 2k0 /2k1 x , one has Ω k0 α ∂ ux , t 2 dx C ⎡ ⎤ 4 2 2 2k0 ⎣F x , t u x , t ⎦dx , k1 2 Ωk0 −1 ∪Ωk0 ∪Ωk0 1 |α| 2. 4.5 Return to the variable x, we get k0 2 2k1 2|α| ⎡ Ω k1 |∂α ux, t |2 dx C Ωk1 −1 ∪Ωk1 ∪Ωk1 1 ⎣|Fx, t |2 k0 2 2k1 ⎤ 4 |ux, t |2 ⎦dx, 4.6 where the positive constant C is independent of u, f, k1 . Case 1 n 3 . Then −2 Ω 2 r |u| dx C Ω r −n |u|2 dx < ∞. 4.7 It follows from 4.6 that Ω k1 r 2|α|−1 |∂α u|2 dx C Ωk1 −1 ∪Ωk1 ∪Ωk1 1 |F|2 r 2 r −2 |u|2 dx, 4.8 where C does not depend on k1 . Taking sum with respect to k1 > k0 , one has k1 >k0 Ω k1 r 2|α|−1 |∂α u|2 dx C k1 k0 |F|2 r 2 r −2 |u|2 dx. 4.9 |F|2 r 2 r −2 |u|2 dx. 4.10 Ω k1 This implies k>k0 Ωk r 2|α|−1 2 |∂ u| dx C α kk0 Ωk Boundary Value Problems 7 Because in out of a neighborhood of conical point Ω is a smooth domain, so we have Ω r 2|α|−1 |∂ u| dx C |F|2 r 2 r −2 |u|2 dx α 2 Ω 4.11 for all |α| 2, almost all t ∈ 0, ∞ . From 4.7 , 4.11 and F ∈ L2 Ω we receive u ∈ H12 Ω for almost all t ∈ 0, ∞ . 2 Case 2 n 2 . Since u ∈ H 1,0 e−γt , Q∞ so for almost all t ∈ 0, ∞ one has Ω r 0 |∂β u| dx < 2ε β 2 2 ∞, |β| 1. This implies K r |∂ u| dx C K |∂β u| dx < ∞, where ε > 0 arbitrary, C is a positive constant. Because u ≡ 0 outside U0 , so we have Ω 2 2 r 2ε ∂β u dx C ∂β u dx < ∞. Ω 4.12 For all ε > 0 we have 2ε > 0 1 − n/2, so it follows from 8, Lemma 7.1.1, page 268 that Ω r 2ε−1 |u|2 dx C |β|1 Ω 2 2 r 2ε ∂β u dx C ∂β u dx < ∞. |β|1 Ω 4.13 From the inequality 4.6 , for all |α| 2 one gets Ω k1 r 2|α|−1ε 2 |∂ u| dx C α Ωk1 −1 ∪Ωk1 ∪Ωk1 1 |F|2 r 2ε1 r 2ε−1 |u|2 dx, 4.14 where C does not depend on u, f, k1 . By using analogous arguments used in Case 1, from 4.13 , 4.14 we have ⎡ Ω r 21ε|α|−2 |∂α u|2 dx C Ω ⎤ 2 β ⎦ ⎣|F|2 ∂ u dx < ∞, 4.15 |β|1 2 Ω . The lemma is proved. for all |α| 2, almost all t ∈ 0, ∞ . That is u ∈ H1ε Lemma 4.3. Let ftk ∈ L∞ 0, ∞, L2 Ω , k 3, and fx, 0 ft x, 0 0 for x ∈ Ω. Assume that ux, t is a weak solution in H 1,0 e−γt , Q∞ γ > 5γ0 of the problem 2.1 –2.3 such that u ≡ 0 outside U0 . In addition, suppose that the strip 1−ε− n n Imλ 2 − , 2 2 4.16 where ε 0 or ε > 0 according to n 3 or n 2, does not contain any point of the spectrum of the Neumann problem for the equation 3.2 for all t ∈ 0, ∞ . Then u ∈ H02 e−γt , Q∞ . 8 Boundary Value Problems Proof. We can rewrite 2.1 in the form t −i ut f L0 0, t, ∂ − Lx, t, ∂ u. L0 0, t, ∂ u Fx, 4.17 If n 3 then by applying Lemma 4.2 we have u ∈ H12 Ω . In another way, because ajk are continuous in x ∈ Ω uniformly with respect to t ∈ 0, ∞ for all j, k 1, . . . , n then |ajk x, t − ajk 0, t | C|x|, for all t ∈ 0, ∞ and C is a constant independent of t. Therefore, from the hypotheses of this lemma one gets F ∈ L2 Ω for almost all t ∈ 0, ∞ . Since in the strip 1 − n/2 Imλ 2 − n/2 there is no spectral point of the Neumann problem for the equation 3.2 for all t ∈ 0, ∞ , then following results of the work 9, one gets u ∈ H02 Ω and satisfies 2 u2H 2 Ω C F L2 Ω 0 u2H 2 Ω , 1 4.18 for almost all t ∈ 0, ∞ , where C is a positive constant. Using the same arguments in the proof of Lemma 4.2, we have 2 u2H 2 Ω C ut 2L2 Ω f L2 Ω u2H 1 Ω , 0 4.19 for almost all t ∈ 0, ∞ . Multiplying this inequality with e−2γt , then integrating with respect to t from 0 to ∞, from Lemma 2.2 one gets u2H 2,0 e−γt ,Q ∞ 0 C 3 ftk 2 ∞ L 0,∞,L2 Ω k0 < ∞. 4.20 Then u is a function in the space H02,0 e−γt , Q∞ . 2 Ω for almost all t ∈ 0, ∞ . If n 2 then following Lemma 4.2 we have u ∈ H1ε This and the property of the functions ajk continuous in x ∈ Ω uniformly with respect to t ∈ 0, ∞ follows F ∈ H10 Ω . Because the strip 1 − ε − n/2 Imλ 1 − n/2 does not contain any spectral point of the Neumann problem for 3.2 , so from results of the work 9 we have u ∈ H12 Ω satisfying 2 u2H 2 Ω C F 1 H10 Ω u2H 2 1ε . 4.21 Repeating the proof in the case n 3 we achieve u ∈ H02,0 e−γt , Q∞ , too. Now differentiating 2.1 with respect to t, we have Lv F1 −i vt ft Lt u, 4.22 where v ut , Lt nj,k1 ∂/∂xj ajk t ∂/∂xk a t . From the hypotheses of the operator L and Lemma 2.2 we have F1 ∈ L2 Ω for almost all t ∈ 0, ∞ . Repeating arguments used for function u we receive v ∈ H02,0 e−γt , Q∞ or ut ∈ H02,0 e−γt , Q∞ . Boundary Value Problems 9 In another way, it follows from Lemma 2.2 that Q∞ |ut2 |2 e−2γt dx dt < ∞. 4.23 From 4.23 and the assertion that both u and ut are in the space H02,0 e−γt , Q∞ we have u ∈ H02 e−γt , Q∞ . This lemma is proved. Lemma 4.4. Let l be a nonnegative integer number, γ be a real number satisfying γ > 2l 5 γ0 , ux, t be a weak solution in H 1,0 e−γt , Q∞ of the problem 2.1 –2.3 such that u ≡ 0 outside U0 . Assume that ftk ∈ L∞ 0, ∞, H0l Ω , k 3, and ftk x, 0 0 for k l 1, x ∈ Ω. Moreover, suppose that the strip 1−ε− n n Imλ l 2 − 2 2 4.24 does not contain any point of the spectrum of the Neumann problem for the equation 3.2 for all t ∈ 0, ∞ , where ε 0 or ε > 0 according to n 3 or n 2. Then u ∈ H0l2 e−γt , Q∞ , satisfying u2H l2 e−γt ,Q 0 ∞ C 3 ftk 2 ∞ L 0,∞,H0l Ω k0 , 4.25 where the constant C is independent of u, f. Proof. We use the induction by l. For l 0 then we had Lemma 4.3 with noting that H00 Ω ≡ L2 Ω . Assume that lemma’s assertion holds up to l − 1, we need to prove this holds up to l. It means that we have to prove following inequality: utj 2 l2−j −γt e ,Q∞ H0 C 3 ftk 2 ∞ , L 0,∞,H l Ω 0 k0 4.26 for j l, l − 1, . . . , 0, where C is a positive constant. Since ftk ∈ L∞ 0, ∞, H0l Ω for k 3, so ftk ∈ L∞ 0, ∞, L2 Ω for k l 3. In another way, ftk x, 0 0 for k l 1. Then from Lemma 2.2 we have utl1 ∈ H 1,0 e−γt , Q∞ , uts ∈ H 1,0 e−γt , Q∞ for all s l. Hence, by using similar arguments in the proof of Lemma 4.3 we get utl ∈ H02 e−γt , Q∞ . This means that 4.26 holds for j l. Assume that 4.26 holds for j l, l − 1, . . . , s 1. By putting v uts ∈ H0l−s1 e−γt , Q∞ by inductive hypothesis and differentiating 2.1 s-times with respect to t, we have s p Lv −i vt fts Cs Ltp uts−p , 4.27 p1 where Ltp nj,k1 ∂/∂xj ajk tp ∂/∂xk a tp . Following the assumptions of the induction of s and the hypotheses of the function f one has vt ∈ H0l−s1 e−γt , Q∞ , fts ∈ H0l−s e−γt , Q∞ . p It follows Fs −ivt fts sp1 Cs Ltp uts−p ∈ H0l−s e−γt , Q∞ . In another way since 10 Boundary Value Problems l−s−1,0 −γt l−s−1 −γt e , Q∞ , so we have Fs ∈ H−1 e , Q∞ for almost all t ∈ H0l−s e−γt , Q∞ ⊆ H−1 0, ∞ . Because the strip l 1 − s − n/2 Imλ l 2 − s − n/2 does not contain any point of the spectrum of the Neumann problem for 3.2 for all t ∈ 0, ∞ , then following l1−s,0 −γt l1−s Ω . This implies v ∈ H−1 e , Q∞ . Note results of the work 9, one gets v ∈ H−1 that Fs ∈ H0l−s,0 e−γt , Q∞ then by applying 8, Theorem 7.3.2 one gets v ∈ H0l2−s,0 e−γt , Q∞ satisfying v2H l2−s,0 e−γt ,Q ∞ 0 C Fs 2H l−s,0 e−γt ,Q ∞ 0 v2H l1−s,0 e−γt ,Q , 4.28 uts 2H l2−s,0 e−γt ,Q . 4.29 ∞ −1 where C is a positive constant. In another way, it is easy to see that uts 2H l2−s e−γt ,Q ∞ 0 uts1 2H l2−s−1 e−γt ,Q ∞ 0 0 ∞ Hence from the inductive assumptions we receive uts 2H l2−s e−γt ,Q ∞ 0 C 3 ftk 2 ∞ , L 0,∞,H l Ω 0 k0 4.30 where C is a constant independent of u, f. It means that 4.26 is proved. Finally we only need to fix j 0 in 4.26 to complete the proof of this lemma. Now let us prove Theorem 3.1. o Proof. Denote u0 ϕ0 u, where ϕ0 ∈ C∞ U0 and ϕ0 ≡ 1 in a neighborhood of coordinate origin. The function u0 satisfies iLu0 − u0 t ϕ0 f L1 u, 4.31 where L1 u is a linear differential operator order 1. Coefficients of this operator depend on the choice of the function ϕ0 and equal to 0 outside U0 . Denote u1 ϕ1 u 1−ϕ0 u. It is easy to see that u1 is equal to 0 in a neighborhood of conical point. Therefore we can apply the theorem on the smoothness of a solution of elliptic problem in a smooth domain to this function to conclude that u1 ϕ1 u ∈ H0l2 Ω for almost all t ∈ 0, ∞ . By applying Lemma 2.2 we receive u1 ∈ H0l2 e−γt , Q∞ and u1 2H l2 e−γt ,Q 0 ∞ C 3 ftk 2 ∞ , L 0,∞,H l Ω k0 0 C const > 0. 4.32 Now, let us prove Theorem 3.1 by induction by l. When l 0 then functions u0 , f ϕ0 f L1 u satisfy the hypotheses of Lemma 4.3. So u0 ∈ H02 e−γt , Q∞ . It follows that u u0 u1 is in H02 e−γt , Q∞ . Assume that the theorem holds up to l − 1 then we have u ∈ H0l1 e−γt , Q∞ . By using analogous arguments in the proof of Lemma 4.4, with note that fts ∈ H0l−s e−γt , Q∞ from the hypothesis of induction , we can prove that u0 ∈ H0l2 e−γt , Q∞ . So Boundary Value Problems 11 u ∈ H0l2 e−γt , Q∞ . The inequality in Theorem 3.1 can derive from inequality 4.25 for u0 and inequality 4.32 . The theorem is proved completely. 5. Cauchy-Neumann Problem For Classical Schrödinger Equation In Quantum Mechanics In this section we apply the previous result to the Cauchy-Neumann problem for classical Schrödinger equations in quantum mechanics. It is shown that the smoothness of the weak solution of this problem depends on the structure of the boundary of the domain, the right hand side and the dimension n of the space Rn . The classical Schrödinger equation in quantum mechanics has the form iΔux, t − ut x, t fx, t , 5.1 where Δ is the Laplace operator. Now we consider the Cauchy-Neumann problem for 5.1 in infinite cylinder Q∞ with the initial condition ux, 0 0 on Ω, 5.2 n ∂u ∂u cosxk , ν 0 on S∞ , ∂ν k1 ∂xk 5.3 and the boundary condition where ν is the unit exterior normal to S∞ . The Laplace operator in polar coordinate r, ω in Rn can be written in the form Δur, ω 1 ∂ n−1 ∂ r ur, ω 2 Δω ur, ω , ∂r r r n−1 ∂r 1 5.4 where Δω is the Laplace-Beltrami operator on the unit sphere Sn−1 . Therefore, the corresponding spectral problem for 3.2 is the Neumann problem for following equation: Δω v iλ 2 i2 − n λ v 0, ω ∈ G. 5.5 The regularity of the weak solution of the problem 5.1 –5.3 can be stayed as follows. Theorem 5.1. Let n > 4, u be a weak solution in the space H 1,0 e−γt , Q∞ γ > 5γ0 of the CauchyNeumann problem 5.1 –5.3 and ftk ∈ L∞ 0, ∞, L2 Ω if k 3, fx, 0 ft x, 0 0. Then u ∈ H02 e−γt , Q∞ . Proof. Note k be nonnegative eigenvalues of the Neumann problem for equation Δω v kv 0, ω ∈ G. 5.6 12 Boundary Value Problems Then λ i2 − n /2 ± n − 2 /2 2 k are eigenvalues of the Neumann problem for 5.5 . It is easy to see that when n > 4 the strip 1− n n Imλ 2 − 2 2 5.7 does not contain any eigenvalue of the Neumann problem for 5.5 . By applying Theorem 3.1 we have u ∈ H02 e−γt , Q∞ . The theorem is proved. 6. Conclusions The Schrödinger equation has received a great deal of attention from mathematicians, in particular because of its application to quantum mechanics and optics. It is therefore important to research boundary value problems for it. Such problems have been previously proposed and analyzed for Schrödinger equations whose coefficients are independent of the time variable and in finite cylinders QT T < ∞ see, e.g., 10 . In infinite cylinder Q∞ , the first initial boundary value problem for this kind of equation with coefficients depend on both of time and spatial variables has been considered see 1, 2 . In this paper, for a general Schrödinger equation in infinite cylinder Q∞ with conical points in the boundary of base, we proved regularity property of solution of second initial boundary value problem. As a special application of these new results, we received the regularity of solution of a classical Schrödinger equation in quantum mechanics when the dimension of space n > 4. The similar questions for the case n 4 can be answered after researching the asymptotic of solution in the case the strip 1 − n/2 Imλ 2 l − n/2 contains eigenvalues of the associated spectral problem. 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