55 Acta Math. Univ. Comenianae Vol. LXXIII, 1(2004), pp. 55–67 WEIGHTED ENDPOINT ESTIMATES FOR MULTILINEAR LITTLEWOOD-PALEY OPERATORS LIU LANZHE Abstract. In this paper, we prove weighted endpoint estimates for multilinear Littlewood-Paley operators. 1. Introduction and Results Let ψ be a fixed function on Rn which satisfies the following properties: R (1) ψ(x)dx = 0, (2) |ψ(x)| ≤ C(1 + |x|)−(n+1) , (3) |ψ(x + y) − ψ(x)| ≤ C|y|(1 + |x|)−(n+2) when 2|y| < |x|; Let m be a positive integer and A be a function on Rn . The multilinear LittlewoodPaley operator is defined by "Z Z #1/2 nµ t dydt gµA (f )(x) = |FtA (f )(x, y)|2 n+1 , µ > 1, n+1 t + |x − y| t R+ where Z Rm+1 (A; x, z) ψt (y − z)f (z)dz, |x − z|m Rn X 1 Rm+1 (A; x, y) = A(x) − Dα A(y)(x − y)α , α! FtA (f )(x, y) = |α|≤m and ψt (x) = t define −n ψ(x/t) for t > 0. We denote by Ft (f )(y) = f ∗ ψt (y). We also Z Z gµ (f )(x) = n+1 R+ t t + |x − y| nµ dydt |Ft (f )(y)|2 n+1 t !1/2 , which is the Littlewood-Paley operator (see [17]). Received June 11, 2003. 2000 Mathematics Subject Classification. Primary 42B20, 42B25. Key words and phrases. Multilinear operator, Littlewood-Paley operator, Hardy space, BMO space. Supported by the NNSF (Grant: 10271071). 56 LIU LANZHE Let H be the Hilbert space H = R R 1/2 2 n+1 h : ||h|| = <∞ . n+1 |h(t)| dydt/t R + n Then for each fixed x ∈ R , to H, and it is clear that gµA (f )(x) gµ (f )(x) FtA (f )(x, y) may be viewed as a mapping from (0, +∞) nµ/2 t FtA (f )(x, y) , = t + |x − y| nµ/2 t = Ft (f )(y) . t + |x − y| We also consider the variant of gµA , which is defined by "Z Z #1/2 nµ t A A 2 dydt g̃µ (f )(x) = |F̃t (f )(x, y)| n+1 , n+1 t + |x − y| t R+ µ > 1, where F̃tA (f )(x, y) = Z Rn Qm+1 (A; x, z) ψt (y − z)f (z)dz |x − z|m and Qm+1 (A; x, z) = Rm (A; x, z) − X Dα A(x)(x − z)α . |α|=m gµA Note that when m = 0, is just the commutator of Littlewood-Paley operator (see [1], [14], [15]). It is well known that multilinear operators, as an extension of commutators, are of great interest in harmonic analysis and have been widely studied by many authors (see [4] – [8], [12], [13]). In [11], [16], the endpoint boundedness properties of commutators generated by the CalderonZygmund operator and BMO functions are obtained. The main purpose of this paper is to study the weighted endpoint boundedness of the multilinear LittlewoodPaley operators. Throughout this paper, M (f ) will denote the Hardy-Littlewood maximal function of f , Q will denote a cube of Rn with side parallel to the axes. For locally integral function f on Rn ,R we denote that R a cube Q and any R −1 f (Q) = Q f (x)dx, fQ = |Q| f (x)dx and f # (x) = sup |Q|−1 Q |f (y)−fQ |dy. Q x∈Q Moreover, for a weight functions w ∈ A1 (see [10]), f is said to belong BMO(w) if f # ∈ L∞ (w) and define ||f ||BMO(w) = ||f # ||L∞ (w) , if w = 1, we denote that BMO(Rn ) = BMO(w). Also, we give the concepts of atomic and weighted H 1 space. A function a is called a H 1 (w) atom if there exists a cube Q such that R a is supported on Q, ||a||L∞ (w) ≤ w(Q)−1 and a(x)dx = 0. It is well known that, for w ∈ A1 , the weighted Hardy space H 1 (w) has the atomic decomposition characterization (see [2]). We shall prove the following theorems in Section 3. Theorem 1. Let Dα A ∈ BMO(Rn ) for |α| = m and w ∈ A1 . Then gµA is bounded from L∞ (w) to BMO(w). 57 ENDPOINT ESTIMATES FOR LITTLEWOOD-PALEY OPERATORS Theorem 2. Let Dα A ∈ BMO(Rn ) for |α| = m and w ∈ A1 . Then g̃µA is bounded from H 1 (w) to L1 (w). Theorem 3. Let Dα A ∈ BMO(Rn ) for |α| = m and w ∈ A1 . Then gµA is bounded from H 1 (w) to weak L1 (w). Theorem 4. Let Dα A ∈ BMO(Rn ) for |α| = m and w ∈ A1 . (i) If for any H 1 (w)-atom a supported on certain cube Q and u ∈ 3Q \ 2Q, there is nµ/2X Z α Z 1 (x − u) t α w(x)dx ≤ C, ψ (y − z)D A(z)a(z)dz t α! |x − u|m Q (4Q)c t + |x − y| |α|=m then gµA is bounded from H 1 (w) to L1 (w); (ii) If for any cube Q and u ∈ 3Q \ 2Q, there is nµ/2 X Z t 1 1 (Dα A(x) − (Dα A)Q ) w(Q) Q t + |x − y| α! |α|=m Z α (u − z) ψ (y − z)f (z)dz · w(x)dx t m (4Q)c |u − z| ≤ C||f ||L∞ (w) , then g̃µA is bounded from L∞ (w) to BMO(w). Remark. In general, gµA is not bounded from H 1 (w) to L1 (w). 2. Some Lemmas We begin with two preliminary lemmas. Lemma 1. (see [7].) Let A be a function on Rn and Dα A ∈ Lq (Rn ) for |α| = m and some q > n. Then m |Rm (A : x, y)| ≤ C|x − y| X |α|=m 1 |Q̃(x, y)| Z !1/q α q |D A(z)| dz , Q̃(x,y) √ where Q̃(x, y) is the cube centered at x and having side length 5 n|x − y|. Lemma 2. Let w ∈ A1 , 1 < p < ∞ 1 < r ≤ ∞, 1/q = 1/p + 1/r and Dα A ∈ BMO(Rn ) for |α| = m. Then gµA is bounded from Lp (w) to Lq (w), that is ||gµA (f )||Lq (w) ≤ C X |α|=m ||Dα A||BMO ||f ||Lp (w) . 58 LIU LANZHE Proof. By Minkowski inequality and the condition of ψ, we have gµA (f )(x) !1/2 nµ Z Z |f (z)||Rm+1 (A; x, z)| t dydt ≤ |ψt (y − z)|2 dz n+1 |x − z|m t + |x − y| t1+n Rn R+ Z ∞ Z Z |f (z)||Rm+1 (A; x, z)| t−2n ≤ C 2n+2 |x − z|m Rn 0 Rn (1 + |y − z|/t) nµ 1/2 dydt t · dz t + |x − y| t1+n Z ∞ nµ Z Z |f (z)||Rm+1 (A; x, z)| t −n ≤ C t |x − z|m t + |x − y| Rn 0 Rn 1/2 dy · tdt dz, (t + |y − z|)2n+2 noting that nµ dy t t t + |x − y| (t + |y − z|)2n+2 n R 1 1 (x) ≤ C ≤ CM (t + | · −z|)2n+2 (t + |x − z|)2n+2 −n Z and Z 0 ∞ tdt = C|x − z|−2n , (t + |x − z|)2n+2 we obtain gµA (f )(x) Z ≤ C Rn Z = C Rn |f (z)| |Rm+1 (A; x, z)| |x − z|m |f (z)||Rm+1 (A; x, z)| dz, |x − z|m+n Z ∞ 0 thus, the lemma follows from [8] [9]. tdt (t + |x − z|)2n+2 1/2 dz 3. Proof of Theorems Proof of Theorem 1. It is only to prove that there exists a constant CQ such that Z 1 |g A (f )(x) − CQ |w(x)dx ≤ C||f ||L∞ (w) w(Q) Q µ √ holds for any cube Q. Fix a cube Q = Q(x0 , l). Let Q̃ = 5 nQ and P 1 α α α Ã(x) = A(x) − α! (D A)Q̃ x , then Rm (A; x, y) = Rm (Ã; x, y) and D Ã = |α|=m Dα A − (Dα A)Q̃ for |α| = m. We write FtA (f ) = FtA (f1 ) + FtA (f2 ) for f1 = f χQ̃ ENDPOINT ESTIMATES FOR LITTLEWOOD-PALEY OPERATORS 59 and f2 = f χRn \Q̃ , then 1 w(Q) = Z |gµA (f )(x) − gµA (f2 )(x0 )|w(x)dx Z 1 t nµ/2 A ||( ) Ft (f )(x, y)|| w(Q) Q t + |x − y| Q − ||( ≤ 1 w(Q) t )nµ/2 FtA (f2 )(x0 , y)|| w(x)dx t + |x0 − y| Z gµA (f1 )(x)w(x)dx nµ/2 Z t 1 FtA (f2 )(x, y) + w(Q) Q t + |x − y| nµ/2 t − FtA (f2 )(x0 , y) w(x)dx t + |x0 − y| Q := I(x) + II(x). Now, let us estimate I and II. First, by the L∞ boundedness of gµA (Lemma 2), we gain I ≤ ||gµA (f1 )||L∞ (w) ≤ C||f ||L∞ (w) . To estimate II, we write nµ/2 FtA (f2 )(x, y) nµ/2 t − FtA (f2 )(x0 , y) t + |x0 − y| 1 − ψt (y − z)Rm (Ã; x, z)f2 (z)dz |x0 − z|m nµ/2 Z t 1 t + |x − y| |x − z|m nµ/2 Z t ψt (y − z)f2 (z) + [Rm (Ã; x, z) − Rm (Ã; x0 , z)]dz t + |x − y| |x0 − z|m nµ/2 nµ/2 # Z " t t ψt (y − z)Rm (Ã; x0 , z)f2 (z) + − dz t + |x − y| t + |x0 − y| |x0 − z|m X 1 Z t (x − z)α − ( )nµ/2 α! t + |x − y| |x − z|m |α|=m nµ/2 t (x0 − z)α − ψt (y − z)Dα Ã(z)f2 (z)dz t + |x0 − y| |x0 − z|m = t t + |x − y| := II1t (x) + II2t (x) + II3t (x) + II4t (x), 60 LIU LANZHE Note that |x − z| ∼ |x0 − z| for x ∈ Q̃ and z ∈ Rn \ Q̃, similar to the proof of Lemma 2 and by Lemma 1, we have Z 1 ||II1t (x)||w(x)dx w(Q) Q ! Z Z C |x − x0 ||f (z)| ≤ |Rm (Ã; x, z)|dz w(x)dx n+m+1 w(Q) Q Rn \Q̃ |x − z| ! Z ∞ Z X C |x − x0 ||f (z)| ≤ |Rm (Ã; x, z)|dz w(x)dx n+m+1 w(Q) Q k+1 Q̃\2k Q̃ |x − z| k=0 2 Z ∞ X kl(2k l)m X α ≤ C ||D A|| ( |f (z)|dz) BMO (2k l)n+m+1 2k+1 Q̃ |α|=m k=0 X ≤ C ∞ X ||Dα A||BMO ||f ||L∞ (w) |α|=m X ≤ C k2−k k=0 α ||D A||BMO ||f ||L∞ (w) ; |α|=m For II2t (x), by the formula (see [7]): Rm (Ã; x, z)−Rm (Ã; x0 , z) = Rm (Ã; x, x0 )+ X 0<|β|<m 1 Rm−|β| (Dβ Ã; x0 , z)(x−x0 )β β! and Lemma 1, we get |Rm (Ã; x, z) − Rm (Ã; x0 , z)| X ≤ C ||Dα A||BMO (|x − x0 |m + |α|=m X |x0 − z|m−|β| |x − x0 ||β| ), 0<|β|<m thus, for x ∈ Q, ||II2t (x)|| Z ≤ C |f2 (z)| |Rm (Ã; x, z) − Rm (Ã; x0 , z)|dz |x − z|m+n Rn Z |x − x |m + P m−|β| X |x − x0 ||β| 0 0<|β|<m |x0 − z| α ≤ C |D A||BMO |f2 (z)|dz |x0 − z|m+n Rn |α|=m ≤ C X |α|=m ≤ C X |α|=m ≤ C X |α|=m kDα A||BMO ∞ X k=0 klm k (2 l)m+n ||Dα A||BMO ||f ||L∞ (w) ∞ X k=1 ||Dα A||BMO ||f ||L∞ (w) ; Z |f (z)|dz 2k+1 Q̃ k2−km ENDPOINT ESTIMATES FOR LITTLEWOOD-PALEY OPERATORS 61 For II3t (x), by the inequality: a1/2 − b1/2 ≤ (a − b)1/2 for a ≥ b > 0, we obtain, similar to the estimate of Lemma 2 and II1 , ||II3t (x)|| Z ≤ C n+1 R+ Rn Z ≤ C Rn Z ≤ C Rn Z !1/2 2 tnµ/2 |x − x0 |1/2 |ψt (y − z)||f2 (z)| dydt |Rm (Ã; x0 , z)| dz tn+1 (t + |x − y|)(nµ+1)/2 |x0 − z|m |f2 (z)||x − x0 |1/2 |Rm (Ã; x0 , z)| |x0 − z|m !1/2 nµ+1 Z Z t t−n dydt · dz n+1 t + |x − y| (t + |y − z|)2n+2 R+ Z ∞ 1/2 dt |f2 (z)||x − x0 |1/2 |Rm (Ã; x0 , z)| dz |x0 − z|m (t + |x − z|)2n+2 0 |f2 (z)||x − x0 |1/2 |Rm (Ã; x0 , z)| dz |x0 − z|m+n+1/2 Rn Z ∞ X kl1/2 (2k l)m X α ≤ C ||D A|| ( |f (z)|dz) BMO (2k l)n+m+1/2 2k+1 Q̃ k=0 Z ≤ C |α|=m ≤ C X ||Dα A||BMO ||f ||L∞ (w) |α|=m ≤ C X ∞ X k2−k/2 k=0 α ||D A||BMO ||f ||L∞ (w) ; |α|=m For II4t (x), similar to the estimates of II1t (x) and II3t (x), we have ||II4t (x)|| Z ≤ C Rn \Q̃ ≤ C X |x − x0 | |x − x0 |1/2 + |x − z|n+1 |x − z|n+1/2 ||Dα A||BMO ||f ||L∞ (w) |α|=m ≤ C X ∞ X X |Dα Ã(z)||f (z)|dz |α|=m k(2−k + 2−k/2 ) k=0 α ||D A||BMO ||f ||L∞ (w) . |α|=m Combining these estimates, we complete the proof of Theorem 1. Proof of Theorem 2. It suffices to show that there exists a constant C > 0 such that for every H 1 (w)-atom R a (that is that a satisfies: supp a ⊂ Q = Q(x0 , r), ||a||L∞ (w) ≤ w(Q)−1 and a(y)dy = 0 (see [8])), we have ||g̃µA (a)||L1 (w) ≤ C. 62 LIU LANZHE We write Z Rn g̃µA (a)(x)w(x)dx "Z Z = + |x−x0 |≤2r # g̃µA (a)(x)w(x)dx := J + JJ. |x−x0 |>2r For J, by the following equality Qm+1 (A; x, y) = Rm+1 (A; x, y) − X 1 (x − y)α (Dα A(x) − Dα A(y)), α! |α|=m we have, similar to the proof of Lemma 2, g̃µA (a)(x) ≤ gµA (a)(x) X Z |Dα A(x) − Dα A(y)| +C |a(y)|dy, |x − y|n |α|=m thus, g̃µA is L∞ -bounded by Lemma 2 and [3]. We see that J ≤ C||g̃µA (a)||L∞ (w) w(2Q) ≤ C||a||L∞ (w) w(Q) ≤ C. P 1 To obtain the estimate of JJ, we denote that Ã(x) = A(x)− |α|=m α! (Dα A)2B xα . Then Qm (A; x, y) = Qm (Ã; x, y). by the vanishing moment of a and P We write, 1 Qm+1 (A; x, y) = Rm (A; x, y) − |α|=m α! (x − y)α Dα A(x), for x ∈ (2Q)c , F̃tA (a)(x, y) Z X 1 Z ψt (y − z)Dα Ã(z)(x − z)α ψt (y − z)Rm (Ã; x, z) a(z)dz − a(z)dz = |x − z|m α! |x − z|m |α|=m # Z " ψt (y − z)Rm (Ã; x, z) ψt (y − x0 )Rm (Ã; x, x0 ) = − a(z)dz |x − z|m |x − x0 |m X 1 Z ψt (y − z)(x − z)α ψt (y − x0 )(x − x0 )α − − Dα Ã(x)a(z)dz, α! |x − z|m |x − x0 |m |α|=m thus, similar to the proof of II in Theorem 1, we obtain ||F̃tA (a)(x, y)|| ≤ C |Q|1+1/n X ( ||Dα A||BMO |x − x0 |−n−1 + |x − x0 |−n−1 |Dα Ã(x)|), w(Q) |α|=m 2 ) |Q1 | note that if w ∈ A1 , then w(Q |Q2 | w(Q1 ) ≤ C for all cubes Q1 , Q2 with Q1 ⊂ Q2 . Thus, by Holder’ inequality and the reverse of Holder’ inequality for w ∈ A1 , ENDPOINT ESTIMATES FOR LITTLEWOOD-PALEY OPERATORS 63 taking p > 1 and 1/p + 1/p0 = 1, we obtain JJ ≤ C X α ||D A||BMO |α|=m +C ∞ X −k 2 k=1 ∞ X X |α|=m k=1 2−k |Q| w(Q) |Q| w(2k+1 Q) w(Q) |2k+1 Q| Z 1 |2k+1 Q| · 1 1/p |Dα Ã(x)|p dx 2k+1 Q Z 1/p0 w(x) dx p0 |2k+1 Q| 2k+1 Q ∞ X X w(2k+1 Q) |Q| ≤ C, ≤ C ||Dα A||BMO k2−k |2k+1 Q| w(Q) |α|=m k=1 which together with the estimate for J yields the desired result. This finishes the proof of Theorem 2. Proof of Theorem 3. By the equality Rm+1 (A; x, y) = Qm+1 (A; x, y) + X 1 (x − y)α (Dα A(x) − Dα A(y)) α! |α|=m and similar to the proof of Lemma 2, we get gµA (f )(x) ≤ g̃µA (f )(x) X Z |Dα A(x) − Dα A(y)| |f (y)|dy, +C |x − y|n |α|=m by Theorem 1 and 2 with [3], we obtain w({x ∈ Rn : gµA (f )(x) > λ}) ≤ w({x ∈ Rn : g̃µA (f )(x) > λ/2}) X Z |Dα A(x) − Dα A(y)| + w({x ∈ Rn : |f (y)|dy > Cλ}) |x − y|n |α|=m ≤ C||f ||H 1 (w) /λ. This completes the proof of Theorem 3. Proof of Theorem 4. (i) It suffices to show that there exists a constant C > 0 such that for every H 1 (w)-atom a with suppa ⊂ Q = Q(x0 , d), there is ||gµA (a)||L1 (w) ≤ C. 64 LIU LANZHE P Let Ã(x) = A(x) − |α|=m 1 α α α! (D A)Q̃ x . We write, by the vanishing moment of a and for u ∈ 3Q \ 2Q, FtA (a)(x, y) = χ4Q (x)FtA (a)(x, y) # Z " Rm (Ã; x, z)ψt (y − z) Rm (Ã; x, u)ψt (y − u) − a(z)dz + χ(4Q)c (x) |x − z|m |x − u|m Rn X 1 Z (x − z)α (x − u)α −χ(4Q)c (x) − ψt (y − z)Dα A(z)a(z)dz α! Rn |x − z|m |x − u|m |α|=m X 1 Z (x − u)α −χ(4Q)c (x) ψt (y − z)Dα A(z)a(z)dz, α! Rn |x − u|m |α|=m then gµA (a)(x) nµ/2 t A = Ft (a)(x, y) t + |x − y| nµ/2 t A ≤ χ4Q (x) Ft (a)(x, y) t + |x − y| " Z nµ/2 t Rm (Ã; x, z)ψt (y − z) + χ(4Q)c (x) t + |x − y| |x − z|m Rn # Rm (Ã; x, u)ψt (y − u) a(z)dz − |x − u|m nµ/2 X Z t 1 (x − z)α (x − u)α c + χ(4Q) (x) − α! Rn |x − z|m |x − u|m t + |x − y| |α|=m · ψt (y − z)Dα A(z)a(z)dz|| nµ/2 X Z α t 1 (x − u) + χ(4Q)c (x) ψt (y − z)a(z)dz m α! Rn |x − u| t + |x − y| |α|=m = L1 (x) + L2 (x) + L3 (x, u) + L4 (x, u). By the L∞ (w)-boundedness of gµA , we get Z Z L1 (x)w(x)dx = gµA (a)(x)w(x)dx ≤ ||gµA (a)||L∞ (w) w(4Q) Rn 4Q ≤ C||a||L∞ (w) w(Q) ≤ C; ENDPOINT ESTIMATES FOR LITTLEWOOD-PALEY OPERATORS 65 Similar to the proof of Theorem 1, we obtain Z L2 (x)w(x)dx ≤ C Rn and Z L3 (x, u)w(x)dx ≤ C. Rn Thus, using the condition of L4 (x, u), we obtain Z Rn gµA (a)(x)w(x)dx ≤ C. P (ii) For any cube Q = Q(x0 , d), let Ã(x) = A(x) − |α|=m 1 α α α! (D A)Q̃ x . We write, for f = f χ4Q + f χ(4Q)c = f1 + f2 and u ∈ 3Q \ 2Q, F̃tA (f )(x, y) Z Rm (Ã; x, z) ψt (y − z)f2 (z)dz |x − z|m Z X 1 (x − z)α (u − z)α − (Dα A(x) − (Dα A)Q ) − ψt (y − z)f2 (z)dz m α! |u − z|m Rn |x − z| |α|=m Z X 1 (u − z)α α α − (D A(x) − (D A)Q ) ψ (y − z)f2 (z)dz, m t α! Rn |u − z| = F̃tA (f1 )(x, y) + Rn |α|=m then ! Rm (Ã; x0 , ·) A f (x ) g̃µ (f )(x) − gµ 2 0 |x0 − ·|m nµ/2 t A = F̃t (f )(x, y) t + |x − y| ! nµ/2 t Rm (Ã; x0 , ·) − Ft f2 (x0 ) m t + |x0 − y| |x0 − ·| nµ/2 t ≤ F̃tA (f )(x, y) t + |x − y| ! nµ/2 t Rm (Ã; x0 , ·) − Ft f2 (x0 ) m t + |x0 − y| |x0 − ·| 66 LIU LANZHE nµ/2 t A ≤ F̃t (f1 )(x, y) t + |x − y| Z " nµ/2 Rm (Ã; x, z) t ψt (y − z) + R n t + |x − y| |x − z|m # nµ/2 Rm (Ã; x0 , z) t ψt (x0 − z) f2 (z)dz − m t + |x0 − y| |x0 − z| nµ/2 t + t + |x − y| Z α α X 1 (y − z) (u − z) · (Dα A(x)−(Dα A)Q ) − ψ (y − z)f (z)dz t 2 m m α! |u − z| Rn |y − z| |α|=m nµ/2 t + t + |x − y| Z α X 1 (u − z) α α · (D A(x) − (D A)Q ) ψ (y − z)f (z)dz t 2 m α! Rn |u − z| |α|=m = M1 (x) + M2 (x) + M3 (x, u) + M4 (x, u). By the L∞ (w)-boundedness of g̃µA , we get Z 1 M1 (x)w(x)dx ≤ ||g̃µA (f1 )||L∞ (w) ≤ C||f ||L∞ (w) ; w(Q) Q Similar to the proof of Theorem 1, we obtain Z 1 M2 (x)w(x)dx ≤ C||f ||L∞ (w) w(Q) Q and 1 w(Q) Z M3 (x, u)w(x)dx ≤ C||f ||L∞ (w) . 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