Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2013, Article ID 769257, 9 pages http://dx.doi.org/10.1155/2013/769257 Research Article Asymptotic Stability of Fractional Stochastic Neutral Differential Equations with Infinite Delays R. Sakthivel,1 P. Revathi,2 and N. I. Mahmudov3 1 Department of Mathematics, Sungkyunkwan University, Suwon 440-746, Republic of Korea Department of Mathematics, Anna University of Technology, Coimbatore 641 047, India 3 Department of Mathematics, Eastern Mediterranean University, Gazimagusa, Mersin 10, Turkey 2 Correspondence should be addressed to R. Sakthivel; krsakthivel@yahoo.com Received 11 September 2012; Accepted 8 November 2012 Academic Editor: Elena Braverman Copyright © 2013 R. Sakthivel et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We study the existence and asymptotic stability in pth moment of a mild solution to a class of nonlinear fractional neutral stochastic differential equations with infinite delays in Hilbert spaces. A set of novel sufficient conditions are derived with the help of semigroup theory and fixed point technique for achieving the required result. The uniqueness of the solution of the considered problem is also studied under suitable conditions. Finally, an example is given to illustrate the obtained theory. 1. Introduction The stochastic differential equations have been widely applied in science, engineering, biology, mathematical finance and in almost all applied sciences. In the present literature, there are many papers on the existence and uniqueness of solutions to stochastic differential equations (see [1–4] and references therein). More recently, Chang et al. [5] investigated the existence of square-mean almost automorphic mild solutions to nonautonomous stochastic differential equations in Hilbert spaces by using semigroup theory and fixed point approach. Fu and Liu [2] discussed the existence and uniqueness of square-mean almost automorphic solutions to some linear and nonlinear stochastic differential equations and in which they studied the asymptotic stability of the unique squaremean almost automorphic solution in the square-mean sense. On the other hand, recently fractional differential equations have found numerous applications in various fields of science and engineering [6]. The existence and uniqueness results for abstract stochastic delay differential equation driven by fractional Brownian motions have been studied in [7]. In particular the stability investigation of stochastic differential equations has been investigated by several authors [8–15]. Let πΎ and π» be two real separable Hilbert spaces with inner products β¨⋅, ⋅β©πΎ and β¨⋅, ⋅β©π», respectively. We denote their norms by | ⋅ |πΎ and | ⋅ |π». To avoid confusion we just use β¨⋅, ⋅β© for the inner product and | ⋅ | for the norm. Let {ππ }∞ π=1 be an orthonormal basis of πΎ. Throughout the paper, we assume that (Ω, F, π; F) (F = {Fπ‘ }π‘≥0 ) is a complete filtered probability space satisfying that F0 contains all πnull sets of F. Suppose {π(π‘) : π‘ ≥ 0} is cylindrical πΎvalued Brownian motion with a trace class operator π, denote trac π = ∑∞ π=1 π π = π < ∞, which satisfies that πππ = π π ππ . ∞ So, actually, π(π‘) = ∑∞ π=1 √π π ππ (π‘)ππ , where {ππ (π‘)}π=1 are mutually independent one-dimensional standard Brownian motions. Define L(πΎ, π») as the set of all bounded linear operators π΄ : πΎ → π» with the following norm: ∞ σ΅¨ σ΅¨2 |π΄| = (∑σ΅¨σ΅¨σ΅¨π΄ππ σ΅¨σ΅¨σ΅¨ ) 1/2 < ∞. (1) π=1 It is obvious that L(πΎ, π») is a Hilbert space with an inner product induced by the above norm. Let π΄ ∈ L(πΎ, π») be called a Hilbert-Schmidt operator. We further assume that the filtration is generated by the cylindrical Brownian motion π(⋅) and augmented, that is, Fπ‘ = π {π (π ) ; 0 ≤ π ≤ π‘} ∨ N, where N is the π-null sets. (2) 2 Abstract and Applied Analysis The qualitative properties of stochastic fractional differential equations have been considered only in few publications. El-Borai et al. [16] studied the existence uniqueness, and continuity of the solution of a fractional stochastic integral equation. Ahmed [17] derived a set of sufficient conditions for controllability of fractional stochastic delay equations by using a stochastic version of the well-known Banach fixed point theorem and semigroup theory. Moreover, theory of neutral differential equations is of both theoretical and practical interests. For a large class of electrical networks containing lossless transmission lines, the describing equations can be reduced to neutral differential equations. However, to the author’s best knowledge no work has been reported in the present literature regarding the existence, uniqueness, and asymptotic stability of mild solutions for neutral stochastic fractional differential equations with infinite delay in Hilbert spaces. Motivated by this consideration, in this paper we consider the nonlinear fractional neutral stochastic differential equations with infinite delays in the following form: π π·π‘πΌ [π (π‘) + π (π‘, π (π‘ − π (π‘)))] = π΄π (π‘) + π (π‘, π (π‘ − π (π‘))) + π (π‘, π (π‘ − π (π‘))) ππ (π‘) , ππ‘ (3) π‘ ≥ 0, π0 (⋅) = π ∈ BF ([π (0) , 0] , π») , (4) where π΄ is the infinitesimal generator of a strongly continuous semigroup of a bounded linear operator π(π‘), π‘ ≥ 0 in the Hilbert space π», π : π + × π» → π», π : π + × π» → L(πΎ, π») are two Borel measurable mappings, and π : π + × π» → π» is continuous mapping. The fractional derivative π π·π‘πΌ , πΌ ∈ (0, 1) is understood in the Caputo sense. In addition, let π(π‘), π(π‘) ∈ πΆ(π + , π + ) satisfy π‘ − π(π‘) → ∞, π‘ − π(π‘) → ∞ as π‘ → ∞. Let π(0) = max{inf π ≥0 (π − π(π )), inf π ≥0 (π − π(π ))}. Here BF0 ([π(0), 0], π») denote the family of all almost surely bounded, F0 -measurable, continuous random variables π(π‘) : [π(0), 0] → π» with norm |π|B = supπ(0)≤π‘≤0 πΈ|π(π‘)|π». Throughout this paper, we assume that π ≥ 2 is an integer. 2. Preliminaries and Basic Properties Let π΄ be the infinitesimal generator of an analytic semigroup π(π‘) in π». Then, (π΄−ππΌ) is invertible and generates a bounded analytic semigroup for π > 0 large enough. Therefore, we can assume that the semigroup π(π‘) is bounded and the generator π΄ is invertible. It follows that (−π΄)π , 0 < π ≤ 1 can be defined as a closed linear invertible operator with its domain π·(−π΄)π being dense in π». We denote by π»π the Banach space π·(−π΄)π endowed with the norm |π₯|π = |(−π΄)π π₯|, which is equivalent to the graph norm of (−π΄)π . For more details about semigroup theory, one can refer [18]. Lemma 1 (see [18]). Suppose that the preceding conditions are satisfied. (a) Let 0 < π ≤ 1, then π»π is a Banach space. (b) If 0 < π ≤ π, then the embedding π»π ⊂ π»π is compact whenever the resolvent operator of π΄ is compact. (c) For every π ∈ (0, 1], there exists a positive constant πΆπ such that βπ΄π π(π‘)β ≤ πΆπ /π‘π , π‘ > 0. Definition 2 (see [19]). The fractional integral of order π with the lower limit 0 for a function π is defined as πΌπΌ π (π‘) = π‘ π (π ) 1 ππ , ∫ Γ (πΌ) 0 (π‘ − π )1−πΌ π‘ > 0, π > 0 (5) provided the righthand side is pointwise defined on [0, ∞), where Γ(⋅) is the gamma function. Definition 3 (see [19]). The Caputo derivative of order πΌ for a function π : [0, ∞) → π can be written as π π‘ π(π) (π ) 1 ππ = πΌπ−πΌ π(π) (π‘) , ∫ Γ (π − πΌ) 0 (π‘ − π )πΌ+1−π (6) π·πΌ π (π‘) = π‘ > 0, 0 ≤ π − 1 < πΌ < π. If π is an abstract function with values in π», then integrals which appear in the above definitions are taken in Bochner’s sense. According to Definitions 2 and 3, it is suitable to rewrite the stochastic fractional equation (3) in the equivalent integral equation π (π‘) = [π (0) + π (0, π)] − π (π‘, π (π‘ − π (π‘))) + π‘ 1 ∫ (π‘ − π )πΌ−1 [π΄π (π ) + π (π , π (π − π (π ))) Γ (πΌ) 0 +π (π , π (π −π (π ))) ππ (π ) ]ππ . ππ (7) In view of [18, Lemma 3.1] and by using Laplace transform, we present the following definition of mild solution of (3). Definition 4. A stochastic process {π(π‘) : π‘ ∈ [0, π]}, 0 ≤ π < ∞ is called a mild solution of (3), if (i) π(π‘) is Fπ‘ -adapted and is measurable, π‘ ≥ 0; (ii) π(π‘) ∈ π» has caΜdlaΜg paths on π‘ ∈ [0, π] almost surely and for each π‘ ∈ [0, π], the function (π‘ − π )πΌ−1 π΄ππΌ (π‘ − π )π(π , π(π − π(π ))) is integrable such that the following integral equation is satisfied: π (π‘) = ππΌ (π‘) [π (0) + π (0, π)] − π (π‘, π (π‘ − π (π‘))) π‘ − ∫ (π‘ − π )πΌ−1 π΄ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ 0 π‘ + ∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ 0 π‘ + ∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ (π ) , 0 (8) Abstract and Applied Analysis 3 π (H4) Θ = [4(π−1) |(−π΄)(−π½) | πππ + 4π−1 πππ πΎ(πΌ, π½)(ππΌπ½ / (iii) π0 (⋅) = π ∈ BF ([π(0), 0], π»), π ∞ ππΌ (π‘) π = ∫ ππΌ (π) π (π‘πΌ π) π ππ, 0 πΏσΈ = ∫0 [ππ‘−π (π‘ − π )πΌ−1 ] ππ . πΌ ππΌ (π‘) π = πΌ ∫ πππΌ (π) π (π‘ π) π ππ 0 In addition, in order to derive the stability of the solution, we further assume that with ππΌ a probability density function defined on (0, ∞). The following properties of ππΌ (π‘) and ππΌ (π‘) [18] are useful. Lemma 5. Under previous assumptions on π(π‘), π‘ ≥ 0 and π΄, (i) ππΌ (π‘) and ππΌ (π‘) are strongly continuous; π΄ππΌ (π‘) π = π΄1−π½ ππΌ (π‘) π΄π½ π, π‘ ∈ [0, π] . (10) Definition 6. Let π ≥ 2 be an integer. Equation (8) is said to be stable in πth moment if for arbitrarily given π > 0 there exists a πΏ > 0 such that πΈ (sup|π (π‘)|π ) < π, π‘≥0 σ΅¨ σ΅¨ when σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨B < πΏ. (11) Definition 7. Let π ≥ 2 be an integer. Equation (8) is said to be asymptotically stable in πth moment if it is stable in πth moment and, for any π ∈ BF ([π(0, 0)], π»), it holds lim πΈ (sup|π (π‘)|π ) = 0. π→∞ π‘≥π (12) 3. Main Result In this section, we prove the existence, uniqueness, and stability of the solution to fractional stochastic equation (3) by using the Banach fixed point approach. In order to obtain the existence and stability of the solution to (3), we impose the following assumptions on (3). (H1) There exist constants π ≥ 1 and π > 0 such that |π(π‘)| ≤ ππ−ππ‘ . (H2) There exists a positive constant πΏ 1 , for every π‘ ≥ 0 and π₯, π¦ ∈ π», such that σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨π (π‘, π₯) − π (π‘, π¦)σ΅¨σ΅¨σ΅¨ ≤ πΏ 1 σ΅¨σ΅¨σ΅¨π₯ − π¦σ΅¨σ΅¨σ΅¨ , (13) σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨σ΅¨π (π‘, π₯) − π (π‘, π¦)σ΅¨σ΅¨σ΅¨ ≤ πΏ 1 σ΅¨σ΅¨σ΅¨π₯ − π¦σ΅¨σ΅¨σ΅¨ . (H3) There exist 0 < π½ < 1 such that π is π»π½ -valued, (−π΄)π½ π is continuous and there exists a positive constant ππ such that σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨(−π΄)π½ π (π‘, π₯) − (−π΄)π½ π (π‘, π¦)σ΅¨σ΅¨σ΅¨ ≤ ππ σ΅¨σ΅¨σ΅¨σ΅¨π₯ − π¦σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ for every π‘ ≥ 0 and π₯, π¦ ∈ π». (H5) π (π‘, 0) = 0, π (π‘, 0) = 0, π (π‘, 0) = 0. (15) It is obvious that (3) has a trivial solution when π = 0 under the assumption (H5). (ii) for any π ∈ π», π½ ∈ (0, 1) and π ∈ (0, 1] one has Γ (2 − π) σ΅¨ πΌπΆπ σ΅¨σ΅¨ π σ΅¨σ΅¨π΄ ππΌ (π‘)σ΅¨σ΅¨σ΅¨ ≤ , σ΅¨ σ΅¨ π‘πΌπ Γ (1 + πΌ (1 − π)) 2 π (9) ∞ π πΌπ½)π + 4π−1 πΌπ ππ πΏ 1 πΏπ + 4π−1 πΆπ πΌπ ππ πΏ 1 πΏσΈ (π/2) ] < = (π(π − 1))/2π/2 , ππ‘ = 1, where πΆπ πΌπ π‘ π πΌ−1 −ππ‘ ∫0 πππΌ (π)π ππ, πΏ = ∫0 π(π‘−π ) (π‘ − π ) ππ and where (14) Lemma 8. Let π ≥ 2, π‘ > 0 and let Φ be an L(πΎ, π»)-valued, π‘ π predictable process such that πΈ ∫0 |Φ(π )|L ππ < ∞. Then, σ΅¨σ΅¨ π σ΅¨σ΅¨σ΅¨π σ΅¨ sup πΈσ΅¨σ΅¨σ΅¨∫ Φ (π’) ππ (π’)σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ 0≤π ≤π‘ σ΅¨σ΅¨ 0 π/2 π (π − 1) ≤( ) 2 π‘ (16) π/2 σ΅¨ π σ΅¨ 2/π (∫ (πΈ σ΅¨σ΅¨σ΅¨σ΅¨Φ(π )L σ΅¨σ΅¨σ΅¨σ΅¨) ) 0 . Theorem 9. Let π ≥ 2 be an integer. Assume that the conditions (H1)–(H4) hold, then the nonlinear fractional neutral stochastic differential equation (3) is asymptotically stable in the πth moment. Proof. Denote by B the space of all F0 -adapted process π(π‘, π€) : [π(0), 0] × Ω → π , which is almost surely continuous in π‘ for fixed π€ ∈ Ω and satisfies π(π‘, π€) = π(π‘) for π‘ ∈ [π(0), 0] and πΈ|π(π‘, π€)|π → 0 as π‘ → 0. It is then routine to check that B is a Banach space when it is equipped with a π norm defined by |π|B = supπ‘≥0 πΈ|π(π‘)|π». Define the nonlinear operator Ψ : B → B such that (Ψπ)(π‘) = π(π‘), π‘ ∈ [π(0), 0] and, for π‘ ≥ 0, (Ψπ) (π‘) = ππΌ (π‘) [π (0) + π (0, π)] − π (π‘, π (π‘ − π (π‘))) π‘ − ∫ (π‘ − π )πΌ−1 π΄ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ 0 π‘ + ∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ 0 π‘ +∫ (π‘−π )πΌ−1 ππΌ (π‘−π ) π (π , π (π −π (π ))) ππ (π ) . 0 (17) As mentioned in Luo [20], to prove the asymptotic stability it is enough to show that the operator Ψ has a fixed point in π». To prove this result, we use the contraction mapping principle. To apply the contraction mapping principle, first we verify the mean square continuity of Ψ on [0, ∞). Let 4 Abstract and Applied Analysis π ∈ B, π‘1 ≥ 0 and let |β| be sufficiently small, and observe that π‘1 πΌ−1 + 3π−1 πΈ (∫ [(π‘1 + β − π ) 0 πΌ−1 − (π‘1 − π ) ] σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)1−π½ ππΌ (π‘1 + β − π )σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨π σ΅¨ πΈσ΅¨σ΅¨σ΅¨(Ψπ) (π‘1 + β) − (Ψπ) (π‘1 )σ΅¨σ΅¨σ΅¨ π σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)π½ π (π , π (π − π (π )))σ΅¨σ΅¨σ΅¨σ΅¨ ππ ) (18) 5 σ΅¨ σ΅¨π ≤ 5π−1 ∑πΈσ΅¨σ΅¨σ΅¨πΉπ (π‘1 + β) − πΉπ (π‘1 )σ΅¨σ΅¨σ΅¨ . π=1 π‘1 + 3π−1 πΈ (∫ (π‘1 − π ) πΌ−1 0 Note that σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨(−π΄)1−π½ σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨ππΌ (π‘1 + β − π ) − ππΌ (π‘1 − π )σ΅¨σ΅¨σ΅¨ σ΅¨π σ΅¨ πΈσ΅¨σ΅¨σ΅¨πΉ1 (π‘1 + β) − πΉ1 (π‘1 )σ΅¨σ΅¨σ΅¨ π σ΅¨ σ΅¨π = πΈσ΅¨σ΅¨σ΅¨(ππΌ (π‘1 + β) − ππΌ (π‘1 )) [π (0) − π (0, π)]σ΅¨σ΅¨σ΅¨ . × (19) The strong continuity of ππΌ (π‘) [18] implies that the right hand of (19) goes to 0 as |β| → 0. In view of Lemma 5 and the Holder’s inequality, the third term of (18) becomes ≤ 3π−1 πΎ (πΌ, π½) πππ (∫ σ΅¨σ΅¨ π‘1 +β σ΅¨ πΌ−1 = πΈ σ΅¨σ΅¨σ΅¨σ΅¨∫ (π‘1 + β − π ) (−π΄) ππΌ (π‘1 + β − π ) π σ΅¨σ΅¨ 0 πΌ−1 − ∫ (π‘1 − π ) ×∫ π‘1 ×∫ (−π΄) ππΌ (π‘1 − π ) π πΌπ½−1 (π‘1 + β − π ) π−1 ππ ) πΈ|π (π − π (π ))|π ππ πΌ−1 ππ ) πΌ(π½−1) (π‘1 + β − π ) πΌ−1 (π‘1 + β − π ) π−1 πΌ−1 − (π‘1 − π ) πΌ−1 − (π‘1 − π ) πΌ(π½−1) (π‘1 + β − π ) πΈ|π (π − π (π ))|π ππ π−1 0 π‘1 × ∫ (π‘1 − π ) πΌ−1 0 π−1 ≤3 ×∫ πΈ|π (π − π (π ))|π ππ πΌπ½ π−1 π β πΎ (πΌ, π½) ππ ( ) πΌπ½ π‘1 +β π‘1 πΌπ½−1 (π‘1 + β − π ) πΈ|π (π − π (π ))|π ππ + 3π−1 πΎ (πΌ, π½) πππ × (∫ π‘1 0 ×∫ π‘1 0 (π‘1 + β − π ) πΌ−1 πΌ(π½−1) (π‘1 + β − π ) πΌ−1 (π‘1 + β − π ) π πΌ−1 − (π‘1 − π ) πΌ(π½−1) (π‘1 + β − π ) σ΅¨ σ΅¨π π‘ + 3π−1 ππ πππ σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)1−π½ σ΅¨σ΅¨σ΅¨σ΅¨ ( 1 ) πΌ π‘1 × ∫ (π‘1 − π ) 0 πΌ−1 π−1 πΌ−1 − (π‘1 − π ) πΌ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨(−π΄)1−π½ ππΌ (π‘1 + β − π )σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)π½ π (π , π (π − π (π )))σ΅¨σ΅¨σ΅¨σ΅¨ ππ ) π‘1 πΌ−1 σ΅¨ σ΅¨π π‘1 πΌ−1 + 3π−1 ππ πππ σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)1−π½ σ΅¨σ΅¨σ΅¨σ΅¨ (∫ (π‘1 − π ) ππ ) σ΅¨σ΅¨π σ΅¨ × (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ (π‘1 + β − π ) (π‘1 + β − π ) 0 × [ππΌ (π‘1 + β − π ) − ππΌ (π‘1 − π )] π π‘1 π‘1 0 σ΅¨σ΅¨ π‘1 +β σ΅¨ πΌ−1 ≤ 3π−1 πΈ σ΅¨σ΅¨σ΅¨σ΅¨∫ (π‘1 + β − π ) (−π΄) ππΌ (π‘1 + β − π ) π σ΅¨σ΅¨ π‘1 σ΅¨σ΅¨π σ΅¨ × (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 πΌ−1 πΌ−1 σ΅¨ + 3π−1 πΈ σ΅¨σ΅¨σ΅¨∫ [(π‘1 + β − π ) − (π‘1 − π ) ] (−π΄) ππΌ σ΅¨σ΅¨ 0 σ΅¨σ΅¨π σ΅¨ × (π‘1 + β − π ) π (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 πΌ−1 σ΅¨ + 3π−1 πΈ σ΅¨σ΅¨σ΅¨∫ (π‘1 − π ) (−π΄) σ΅¨σ΅¨ 0 ≤ 3π−1 πΈ (∫ π‘1 +β × (∫ σ΅¨σ΅¨π σ΅¨ × (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 +β πΌπ½−1 (π‘1 + β − π ) π‘1 × (π , π (π − π (π ))) ππ 0 π‘1 +β + 3π−1 πΎ (πΌ, π½) πππ σ΅¨π σ΅¨ πΈσ΅¨σ΅¨σ΅¨πΉ3 (π‘1 + β) − πΉ3 (π‘1 )σ΅¨σ΅¨σ΅¨ π‘1 σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨(−π΄)π½ π (π , π (π − π (π )))σ΅¨σ΅¨σ΅¨ ππ ) σ΅¨ σ΅¨ ππ ) πΈ|π (π − π (π ))|π ππ π−1 πΈ|π (π − π (π ))|π ππ , (20) Abstract and Applied Analysis π π 5 π where πΎ(πΌ, π½) = πΌπ Γ(1+π½) πΆ1−π½ /Γ(1+πΌπ½) . Since π is sufficiently small, the right hand side of the above equation tends to zero as |β| → 0. Next we consider π‘1 0 σ΅¨σ΅¨ π‘1 +β σ΅¨ πΌ−1 = πΈ σ΅¨σ΅¨σ΅¨σ΅¨∫ (π‘1 + β − π ) ππΌ (π‘1 + β − π ) σ΅¨σ΅¨ 0 πΌ−1 − (π‘1 − π ) ]πΈ × |π (π − π (π ))|π ππ + σ΅¨π σ΅¨ πΈσ΅¨σ΅¨σ΅¨πΉ4 (π‘1 + β) − πΉ4 (π‘1 )σ΅¨σ΅¨σ΅¨ πΌ−1 × ∫ ππ‘1 +β−π [(π‘1 + β − π ) πΌ π−1 π−1 π π π‘1 3 π πΏ 1( ) πΌ π‘1 πΌ−1 × ∫ (π‘1 − π ) 0 πΈ|π (π − π (π ))|π ππ . (22) × π (π , π (π − π (π ))) ππ π‘1 πΌ−1 − ∫ (π‘1 − π ) 0 σ΅¨σ΅¨π σ΅¨ ππΌ (π‘1 − π ) π (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 +β σ΅¨ πΌ−1 ≤ 3π−1 πΈ σ΅¨σ΅¨σ΅¨σ΅¨∫ (π‘1 + β − π ) ππΌ (π‘1 + β − π ) σ΅¨σ΅¨ π‘1 σ΅¨σ΅¨σ΅¨π ×π (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 πΌ−1 πΌ−1 σ΅¨ + 3π−1 πΈ σ΅¨σ΅¨σ΅¨∫ [(π‘1 + β − π ) − (π‘1 − π ) ] σ΅¨σ΅¨ 0 σ΅¨ σ΅¨π πΈσ΅¨σ΅¨σ΅¨πΉ5 (π‘1 + β) − πΉ5 (π‘1 )σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 +β σ΅¨ πΌ−1 = πΈ σ΅¨σ΅¨σ΅¨σ΅¨∫ (π‘1 + β − π ) ππΌ (π‘1 + β − π ) σ΅¨σ΅¨ 0 × π (π , π (π − π (π ))) ππ (π ) π‘1 − ∫ (π‘1 − π ) σ΅¨σ΅¨π σ΅¨ ×ππΌ (π‘1 + β − π ) π (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ 0 σ΅¨σ΅¨ π‘1 πΌ−1 σ΅¨ + 3π−1 πΈ σ΅¨σ΅¨σ΅¨∫ (π‘1 − π ) [ππΌ (π‘1 + β − π ) − ππΌ (π‘1 − π )] π σ΅¨σ΅¨ 0 σ΅¨σ΅¨σ΅¨π × (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 + 3π−1 πΈ (∫ [(π‘1 + β − π ) πΌ−1 πΌ−1 − (π‘1 − π ) 0 ] σ΅¨ σ΅¨ σ΅¨σ΅¨ × σ΅¨σ΅¨σ΅¨ππΌ (π‘1 + β − π )σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨σ΅¨π (π , π (π − π (π )))σ΅¨σ΅¨σ΅¨ ππ ) π‘1 + 3π−1 πΈ (∫ (π‘1 − π ) πΌ−1 0 Therefore, the right hand side of the above equation tends to zero as |β| → 0 and π sufficiently small. Further, we have π σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ππΌ (π‘1 + β − π ) − ππΌ (π‘1 − π )σ΅¨σ΅¨σ΅¨ π σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨π (π , π (π − π (π )))σ΅¨σ΅¨σ΅¨ ππ ) . (21) σ΅¨σ΅¨ π‘1 +β σ΅¨ πΌ−1 ≤ 3π−1 πΈ σ΅¨σ΅¨σ΅¨σ΅¨∫ (π‘1 + β − π ) ππΌ (π‘1 + β − π ) σ΅¨σ΅¨ π‘1 σ΅¨σ΅¨σ΅¨π ×π (π , π (π − π (π ))) ππ (π ) σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 πΌ−1 πΌ−1 σ΅¨ + 3π−1 πΈ σ΅¨σ΅¨σ΅¨∫ [(π‘1 + β − π ) − (π‘1 − π ) ] σ΅¨σ΅¨ 0 σ΅¨σ΅¨π σ΅¨ ×ππΌ (π‘1 + β − π ) π (π , π (π − π (π ))) ππ (π ) σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 πΌ−1 σ΅¨ + 3π−1 πΈ σ΅¨σ΅¨σ΅¨∫ (π‘1 − π ) [ππΌ (π‘1 + β − π ) − ππΌ (π‘1 − π )] σ΅¨σ΅¨ 0 σ΅¨σ΅¨σ΅¨π ×π (π , π (π − π (π ))) ππ (π ) σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π‘1 +β π‘1 π ≤ 3π−1 πΏ 1 ππ πΌπ (∫ π‘1 +β π‘1 ×∫ π‘1 +β π‘1 ππ‘1 +β−π (π‘1 + β − π ) πΌ−1 ππ‘1 +β−π (π‘1 + β − π ) πΌ−1 π−1 π‘1 + 3π−1 πΆπ πΈ (∫ [(π‘1 + β − π ) πΈ|π (π − π (π ))|π ππ 0 σ΅¨σ΅¨2 σ΅¨σ΅¨ππΌ (π‘1 + β − π )σ΅¨σ΅¨ πΌ−1 π/2 πΌ−1 2 − (π‘1 − π ) σ΅¨ σ΅¨2 × σ΅¨σ΅¨σ΅¨ππΌ (π‘1 + β − π )σ΅¨σ΅¨σ΅¨ π πΌ−1 × (∫ ππ‘1 +β−π [(π‘1 + β − π ) 0 2(πΌ−1) σ΅¨σ΅¨ (π‘1 + β − π ) ×|π (π , π (π − π (π )))|2 ππ ) ππ ) + 3π−1 πΏ 1 ππ πΌπ π‘1 ππΌ (π‘1 − π ) σ΅¨σ΅¨π σ΅¨ ×π (π , π (π − π (π ))) ππ (π ) σ΅¨σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ ≤ 3π−1 πΆπ πΈ (∫ By the Holder’s inequality, we obtain πΌ−1 − (π‘1 − π ) πΌ−1 π−1 ] ππ ) π/2 ×|π (π , π (π − π (π )))|2 ππ ) ] 6 Abstract and Applied Analysis π‘1 σ΅¨σ΅¨ π‘ σ΅¨σ΅¨σ΅¨π σ΅¨ + 6π−1 πΈσ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ 0 σ΅¨σ΅¨ σ΅¨σ΅¨ π‘ σ΅¨ + 6π−1 πΈ σ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) σ΅¨σ΅¨ 0 σ΅¨σ΅¨σ΅¨π ×π (π , π (π − π (π ))) ππ (π ) σ΅¨σ΅¨σ΅¨ . σ΅¨σ΅¨ (24) 2(πΌ−1) + 3π−1 πΆπ πΈ (∫ (π‘1 − π ) 0 σ΅¨ σ΅¨2 × σ΅¨σ΅¨σ΅¨ππΌ (π‘1 + β − π ) − ππΌ (π‘1 − π )σ΅¨σ΅¨σ΅¨ ×|π (π , π (π − π (π )))|2 ππ ) π/2 π ≤ 3π−1 πΆπ πΏ 1 ππ πΌπ × (∫ π‘1 +β π‘1 ×∫ π‘1 +β π‘1 πΌ−1 π/(π−2) (ππ‘1 +β−π (π‘1 + β − π ) ) Now, we estimate the terms on the right hand side of (24) by using the assumptions (H1), (H3), and (H4). Now, we have (π−2)/2 ππ ) σ΅¨π σ΅¨ 6π−1 πΈσ΅¨σ΅¨σ΅¨ππΌ (π‘) π (0)σ΅¨σ΅¨σ΅¨ πΌ σ΅¨ σ΅¨π ≤ 6π−1 ππ (∫ ππΌ (π) π−πΌπ‘ π ππ) σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨B 0 ) σ³¨→ 0 π × πΈ|π (π − π (π ))|π ππ + 3π−1 πΆπ πΏ 1 ππ πΌπ π‘1 πΌ−1 π ∞ πΌ σ΅¨ σ΅¨π σ΅¨ σ΅¨π ≤ 6π−1 ππ (∫ ππΌ (π) π−πΌπ‘ π ππ) σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)−π½ σ΅¨σ΅¨σ΅¨σ΅¨ πππ σ΅¨σ΅¨σ΅¨πσ΅¨σ΅¨σ΅¨B 0 0 π‘1 πΌ−1 πΌ−1 × ∫ (ππ‘1 +β−π [(π‘1 + β − π ) 0 π/(π−2) ]) (π−2)/2 σ³¨→ 0 ππ ) − (π‘1 − π ) πΌ−1 π π‘1 × ∫ (π‘1 − π ) 0 ππΌ−2/π−2 π/2 σ΅¨ σ΅¨π ≤ 6π−1 σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)−π½ σ΅¨σ΅¨σ΅¨σ΅¨ πππ πΈ|π (π‘ − π (π‘))|π . ]) (π−2)/2 σ΅¨π σ΅¨ 6π−1 πΈσ΅¨σ΅¨σ΅¨π (π‘, π (π‘ − π (π‘)))σ΅¨σ΅¨σ΅¨ σ³¨→ 0 as π‘ σ³¨→ ∞. (23) As above, the right hand side of the above inequality tends to zero. Similarly, we have πΉ2 → 0 as β → 0. Thus Ψ is continuous in πth moment on [0, ∞). Next we show that Ψ(B) ∈ B. Let π ∈ B. From (18), we have σ΅¨σ΅¨π σ΅¨σ΅¨ π‘ σ΅¨ σ΅¨ 6π−1 πΈσ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 (−π΄) ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ 0 π‘ σ΅¨ σ΅¨ ≤ 6π−1 πΈ (∫ (π‘ − π )πΌ−1 σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)1−π½ ππΌ (π‘ − π )σ΅¨σ΅¨σ΅¨σ΅¨ 0 σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)π½ π (π , π (π − π (π )))σ΅¨σ΅¨σ΅¨σ΅¨ ππ ) π−1 +6 σ΅¨π σ΅¨ πΈσ΅¨σ΅¨σ΅¨π (π‘, π (π‘ − π (π‘)))σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π‘ σ΅¨ + 6π−1 πΈ σ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 (−π΄) ππΌ (π‘ − π ) σ΅¨σ΅¨ 0 σ΅¨σ΅¨π σ΅¨ ×π (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π π−1 π‘ σ΅¨π σ΅¨π σ΅¨ σ΅¨ ≤ 6π−1 πΈσ΅¨σ΅¨σ΅¨ππΌ (π‘) π (0)σ΅¨σ΅¨σ΅¨ + 6π−1 πΈσ΅¨σ΅¨σ΅¨ππΌ (π‘) π (0, π)σ΅¨σ΅¨σ΅¨ (26) For the fourth term of (24), we have πΈ|π (π − π (π ))|π ππ . πΈ|(Ψπ) (π‘)|π (25) For π(π‘) ∈ B and for any π > 0 there exists a π‘1 > 0 such that πΈ|π(π‘ − π(π‘))|π ≤ π for π‘ ≥ π‘1 . Therefore, π‘1 ) ππΌ − 2/π − 2 π(πΌ−1)/2 as π‘ σ³¨→ ∞, σ΅¨π σ΅¨ 6π−1 πΈσ΅¨σ΅¨σ΅¨π (π‘, π (π‘ − π (π‘)))σ΅¨σ΅¨σ΅¨ × πΈ|π (π − π (π ))|π ππ + 3π−1 ππ πΆπ πΏ 1 ( as π‘ σ³¨→ ∞, σ΅¨ σ΅¨π 6π−1 πΈσ΅¨σ΅¨σ΅¨ππΌ (π‘) π (0, π)σ΅¨σ΅¨σ΅¨ × (∫ (ππ‘1 +β−π [(π‘1 + β − π ) −(π‘1 − π ) π ∞ πΌ−1 π/2 (ππ‘1 +β−π (π‘1 + β − π ) ≤ 6π−1 πππ πΎ (πΌ, π½) (∫ (π‘ − π )πΌπ½−1 ππ ) 0 π‘ × ∫ (π‘ − π )πΌπ½−1 πΈ|π (π − π (π ))|π ππ 0 ≤ 6π−1 πππ πΎ (πΌ, π½) ( π−1 ππΌπ½ ) πΌπ½ π‘ × ∫ (π‘ − π )πΌπ½−1 πΈ|π (π − π (π ))|π ππ σ³¨→ 0 as π‘ σ³¨→ ∞. 0 (27) Abstract and Applied Analysis 7 σ΅¨σ΅¨ π‘ σ΅¨ + 4π−1 sup πΈ σ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) π‘∈[0,π] σ΅¨σ΅¨ 0 Also, we have σ΅¨σ΅¨ π‘ σ΅¨σ΅¨π σ΅¨ σ΅¨ 6π−1 πΈσ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ 0 σ΅¨σ΅¨ π−1 ≤6 π‘ πΈ (∫ (π‘ − π ) πΌ−1 0 σ΅¨σ΅¨π σ΅¨ −π (π , π (π − π (π )))] ππ (π ) σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨ σ΅¨σ΅¨ππΌ (π‘ − π )σ΅¨σ΅¨σ΅¨ σ΅¨ σ΅¨ × σ΅¨σ΅¨σ΅¨π (π , π (π − π (π )))σ΅¨σ΅¨σ΅¨ ππ ) π × [π (π , π (π − π (π ))) π‘ σ΅¨ σ΅¨π ≤ 4π−1 σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)−π½ σ΅¨σ΅¨σ΅¨σ΅¨ πππ sup πΈ|π (π‘) − π (π‘)|π π ≤ 6π−1 πΌπ ππ πΏ 1 (∫ ππ‘−π (π‘ − π )πΌ−1 ππ ) π‘∈[0,π] π‘ σ΅¨ σ΅¨ + 4π−1 sup πΈ (∫ (π‘ − π )πΌ−1 σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)1−π½ ππΌ (π‘ − π )σ΅¨σ΅¨σ΅¨σ΅¨ π−1 0 π‘∈[0,π] 0 σ΅¨ × σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)π½ [π (π , π (π − π (π ))) π‘ × ∫ ππ‘−π (π‘ − π )πΌ−1 πΈ|π (π − π (π ) ))|π ππ , σ΅¨ −π (π , π (π −π (π )))] σ΅¨σ΅¨σ΅¨σ΅¨ ππ ) 0 σ΅¨σ΅¨ π‘ σ΅¨σ΅¨π σ΅¨ σ΅¨ 6π−1 πΈσ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) π (π , π (π − π (π ))) ππ (π )σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ 0 σ΅¨σ΅¨ σ΅¨σ΅¨ π‘ σ΅¨ σ΅¨2 σ΅¨ ≤ 6π−1 πΆπ πΈ σ΅¨σ΅¨σ΅¨∫ (π‘ − π )2(πΌ−1) σ΅¨σ΅¨σ΅¨ππΌ (π‘ − π )σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ 0 π‘ σ΅¨ σ΅¨ + 4π−1 sup πΈ (∫ (π‘ − π )πΌ−1 σ΅¨σ΅¨σ΅¨ππΌ (π‘ − π )σ΅¨σ΅¨σ΅¨ 0 π‘∈[0,π] σ΅¨ × σ΅¨σ΅¨σ΅¨π (π , π (π − π (π ))) σ΅¨σ΅¨π/2 σ΅¨ ×|π (π , π (π − π (π )))|2 ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π‘ π ≤ 6π−1 πΆπ πΏ 1 πΌπ ππ (∫ [ππ‘−π (π‘ − π )πΌ−1 ] π/(π−2) 0 π σ΅¨ −π (π , π (π − π (π )))σ΅¨σ΅¨σ΅¨ ππ ) π−2/π ππ ) π‘ σ΅¨2 σ΅¨ + 4π−1 πΆπ sup πΈ (∫ (π‘ − π )2(πΌ−1) σ΅¨σ΅¨σ΅¨ππΌ (π‘ − π )σ΅¨σ΅¨σ΅¨ 0 π‘∈[0,π] π‘ × ∫ ππ‘−π (π‘ − π )πΌ−1 πΈ|π (π − π (π ))|π ππ . 0 × |π (π , π (π − π (π ))) (28) By the same discussion as above, we have that (28) tends to zero as π‘ → ∞. Thus πΈ|Ψπ(π‘)|π → 0 as π‘ → ∞. We conclude that Ψ(B) ∈ B. Finally, we prove that Ψ has a unique fixed point. Indeed, for any π, π ∈ B, we have π sup πΈ|(Ψπ) (π‘) − (Ψπ) (π‘)| π‘∈[0,π] −π (π , π (π − π (π )))|2 ππ ) ππΌπ½ σ΅¨π σ΅¨σ΅¨(−π΄)−π½ σ΅¨σ΅¨σ΅¨ πππ + 4π−1 πππ πΎ (πΌ, π½) ( ) σ΅¨ σ΅¨ πΌπ½ π−1 σ΅¨σ΅¨ ≤ [4 ≤4 σ΅¨σ΅¨π σ΅¨ sup πΈσ΅¨σ΅¨σ΅¨π (π‘, π (π‘ − π (π‘))) − π (π‘, π (π‘ − π (π‘)))σ΅¨σ΅¨ × [π (π , π (π − π (π ))) σ΅¨σ΅¨π σ΅¨ −π (π , π (π − π (π )))] ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ σ΅¨σ΅¨ π‘ σ΅¨ + 4π−1 sup πΈ σ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 ππΌ (π‘ − π ) π‘∈[0,π] σ΅¨σ΅¨ 0 × [π (π , π (π − π (π ))) σ΅¨σ΅¨π σ΅¨ −π (π , π (π − π (π )))] ππ σ΅¨σ΅¨σ΅¨ σ΅¨σ΅¨ π π +4π−1 πΆπ πΌπ ππ πΏ 1 πΏσΈ π/2 ] sup πΈ|π (π‘) − π (π‘)|π . π‘∈[0,π] π‘∈[0,π] σ΅¨σ΅¨ π‘ σ΅¨ + 4π−1 sup πΈ σ΅¨σ΅¨σ΅¨∫ (π‘ − π )πΌ−1 (−π΄) ππΌ (π‘ − π ) π‘∈[0,π] σ΅¨σ΅¨ 0 π/2 + 4π−1 πΌπ ππ πΏ 1 πΏπ π π−1 π (29) Therefore, Ψ is a contradiction mapping and hence there exists a unique fixed point, which is a mild solution of (3) with π(π ) = π(π ) on [π(0), 0] and πΈ|π(π‘)|π → 0 as π‘ → ∞. To show the asymptotic stability of the mild solution of (3), as the first step, we have to prove the stability in πth moment. Let π > 0 be given and choose πΏ > 0 such that πΏ < π satisfies 6π−1 [ππ + ππ |(−π΄)−π½ |π πππ ]πΏ + 6π−1 [|(−π΄)−π½ |π πππ + π π π πππ πΎ(πΌ, π½)(ππΌπ½ /πΌπ½) + πΌπ ππ πΏ 1 πΏπ + πΆπ πΌπ ππ πΏ 1 πΏσΈ π/2 ]π < π. π If π(π‘) = π(π‘, π) is mild solution of (3), with |π|B < πΏ, then (Ψπ)(π‘) = π(π‘) satisfies πΈ|π(π‘)|π < π for every π‘ ≥ 0. Notice that πΈ|π(π‘)|π < π on π‘ ∈ [π(0), 0]. If there exists π‘ 8 Abstract and Applied Analysis such that πΈ|π(π‘)|π = π and πΈ|π(π )|π < π for π ∈ [π(0), π‘]. Then (24) show that σ΅¨π σ΅¨ πΈσ΅¨σ΅¨σ΅¨π (π‘)σ΅¨σ΅¨σ΅¨ π πΌ ≤ 6π−1 [ππ (ππΌ (π) π−πΌπ‘ π ) +ππ (ππΌ (π) π−πΌπ‘ πΌ π· (π΄) = {π€ ∈ π; π€, π€σΈ are absolutely continuous, πσ΅¨ σ΅¨π π σ΅¨ ) σ΅¨σ΅¨σ΅¨(−π΄)−π½ σ΅¨σ΅¨σ΅¨σ΅¨ πππ ] πΏ πΌπ½ π€σΈ σΈ ∈ π, π€ (0) = π€ (π) = 0} , π π σ΅¨π σ΅¨ + 6π−1 [σ΅¨σ΅¨σ΅¨σ΅¨(−π΄)−π½ σ΅¨σ΅¨σ΅¨σ΅¨ πππ + πππ πΎ (πΌ, π½) ( ) πΌπ½ π π +πΌπ ππ πΏ 1 πΏπ + πΆπ πΌπ ππ πΏ 1 πΏσΈ π/2 where π(π‘) denotes a standard cylindrical Wiener process and a standard one-dimensional Brownian motion. To write the system (32) into the abstract form of (3), we consider the space π» = πΎ = πΏ2 [0, π] and define the operator π΄ : π·(π΄) ⊂ π» → π» by π΄π€ = π€σΈ σΈ with domain (30) ∞ π΄π€ = ∑ π2 (π€, π€π ) π€π , where π€π (π ) = √2 sin(ππ ), π = 1, 2, . . . is the orthogonal set of eigenvectors in π΄. It is well known that π΄ generates a compact, analytic semigroup {π(π‘), π‘ ≥ 0} in π and ]π ∞ which contradicts the definition of π‘. Therefore, the mild solution of (3) is asymptotically stable in πth moment. In particular, when π = 2 from Theorem 9 we have the following. Theorem 10. Suppose that the conditions (H1)–(H3) hold. Then, the stochastic fractional differential equations (3) are mean square asymptotically stable if 4ππ2 [|(−π΄)−π½ |2 + 2 π(πΌ, π½)(ππΌπ½ /πΌπ½) ] + 4πΌ2 π2 πΏ21 [πΏ2 + πΏσΈ ] < 1, where π(πΌ, π½) = 2 2 2 πΆ1−π½ /Γ(1+πΌπ½) . πΌ2 Γ(1+π½) When π ≡ 0, π = 2, (3) reduces to π·π‘πΌ π (π‘) = π΄π (π‘) + π (π‘, π (π‘ − π (π‘))) + π (π‘, π (π‘ − π (π‘))) ππ (π‘) , ππ‘ π‘ ≥ 0, (31) π0 (⋅) = π ∈ BF ([π (0) , 0] , π») . From Theorems 9 and 10, we can easily get the following result. Corollary 11. Suppose the assumptions (H1) and (H2) hold. Then, the stochastic equations (8) are mean square asymptotically stable if 2πΌ2 π2 πΏ21 [πΏ2 + πΏσΈ ] < 1. Example 12. Consider the following stochastic nonlinear fractional partial differential equation with infinite delay in the following form π Μ π’ (π‘ − π, π¦)] π·π‘πΌ [π’ (π‘, π¦) + π(π‘, = π2 π’ (π‘, π¦) Μ + π (π‘, π’ (π‘ − π, π¦)) ππ¦2 + πΜ (π‘, π’ (π‘ − π, π¦)) ππ (π‘) , ππ‘ π’ (π‘, 0) = π’ (π‘, π) = 0, π’ (π‘, π¦) = π (π‘, π¦) , π¦ ∈ [0, π] , π‘ ≤ 0, (34) π=1 <π π π€ ∈ π· (π΄) , (33) (32) 2 π (π‘) π€ = ∑ π−π π‘ (π€, π€π ) π€π . (35) π=1 2 It is well known that |π(π‘)| ≤ π−π π‘ . Take π = 2. Since π = 1, 2 we can get the inequality 4[|(−π΄)−π½ |2 + π(πΌ, π½)(ππΌπ½ /πΌπ½) + πΌ2 (πΏ2 + πΏσΈ )] < 1. Further, if we impose suitable conditions Μ and πΜ to verify assumptions of Theorem 10, then we Μ π, on π, can conclude that the mild solution of (32) is mean square asymptotically stable. References [1] J. Bao, Z. Hou, and C. 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